I have a students table with following rows in it.
ID
Name
1
John Smith
2
Hellen Fernandis
3
Ali Abbas
4
Sameer Khan
I want that even if I use the below mentioned query
Select * from students where name like '%Abbas Ali%'
Row No. 3 should come in result.
You can't do it in a single LIKE, you need multiple conditions:
WHERE name LIKE '%Abbas%' AND name LIKE '%Ali%'
If you to do it in other manner, just try this:
SELECT * FROM students WHERE name LIKE '%Abbas' AND name LIKE 'Ali%'
Select * from students where name like '%Abbas%Ali%'
Related
I've tried to search for a solution to this but have been unable to find one. I guess it's basic SQL, but I can't seem to figure it out.
I have a table called people, this table has several columns:
ID Firstname Lastname Birthdate
1 John Stevenson 1860-07-30
2 Eric Johnson 1918-08-25
3 Adam Efron 1914-02-02
4 Michael Gray 1870-07-18
Now I want to make a query that looks at the Birthdate column, finds the lowest value and returns the firstname of the person that has the lowest birthdate (is oldest).
Can someone guide me in the right direction?
THanks in advance!
Use order by like
select Firstname
from people
order by Birthdate
limit 1
This will account for 2 paople having the same birthdate, returning 2 rows.
select Firstname
from people
where birthdate = (select min(birthdate) from people);
Another way to do it efficiently would be this (sqlfiddle):
select p.*, min(p.birthdate) from people p;
NOTE: You will have 1 extra column in the output.
To make it more clear, If I have this data in MySql:
name | allowance | age
----------------------
khan | 50 | 20
aal | 60 | 22
hyme | 50 | 21
khan | 61 | 20
notice that there are two 'khan' in the database with different allowance. I want to only show the name and the age but if I show it using the mysqli select statement, there would be two 'khan' but I only want to show only 1 'khan'. How can I do it?
You need to use GROUP_CONCAT to see agges of all Khans;
select name, GROUP_CONCAT(age) ages from Table group by name
or for minimum aged khan
select name , min(age) MiniumAge from Table group by name
or for elder khan
select name , max(age) MaxAge from Table group by name
or any khan
select name , age from Table group by name
.
Please try below query:-
SELECT name, age FROM table_name WHERE group by name
If you want any from multiple same record then simply used group by query.
I think you could do this:
SELECT name, age FROM table_name WHERE group by name,age
First thing: if both those "khan"s are the same person with two different allowances then your schema is not properly normalized and it will give you big troubles later - imagine you want to change "khan" to "Khan" - now you have to update it in multiple places instead once. Depending on your actual needs you may want one table of people (person_id, name, age), and table of allowances (person_id, allowance, [..some other parameters?..]).
Second, to really get what you want, either you use group by, to get one "random" row per each name as suggested in other answers, or you can do
SELECT DISTINCT name, age FROM table;
which will give you one row per each name-age combination, so khan-20 will be there only once - but if there were khan-25 then that is probably different person and you would have two khans returned, each with their own age.
You can try this mate:
SELECT DISTINCT
name, age
FROM
<your_table>;
or this one
SELECT
name, age
FROM
<your_table>
GROUP BY
name;
Q: Is there any chance that if there are 2 records of tha same name have difference value of age? If so, kindly update the question so that better answers will be given. Cheers!
I want to search the column Name of a certain table to see how many rows have a Name value that matches a certain pattern. For example, if the pattern I am looking for is %Peter% and in this table there are 5 rows with the Name values:
Peter
Peter Smith
George Peter
Peter Peter
Carl
I want to obtain the value 4. I tried to use COUNT, but don't know how to combine it for example with LIKE. How do I go about to do this?
Not sure why didn't LIKE work for you, but this SHOULD do the trick:
SELECT COUNT(*) FROM table
WHERE name LIKE '%Peter%'
I'd like to use MySQL to find duplicates and then display those items as one, combined record. For example, I have two columns: Name and Fruit. A sampling of records might look like this:
Joe - Peaches
Faye - Bananas
Joe - Starfruit
Sam - Apples
I want to display this data as:
Joe - Peaches, Starfruit
Faye - Bananas
Sam - Apples
Is that possible? Could you help me with the MySQL query to start? I'm using VB.NET for my application. Thank you.
Use GROUP_CONCAT for that.
SELECT personName, GROUP_CONCAT(fruitName) fruitList
FROM tableName
GROUP BY personName
You'll want to use group_concat here.
SELECT name, group_concat(fruit)
FROM table
GROUP BY name
I have two tables.
Table Emp
id name
1 Ajay
2 Amol
3 Sanjay
4 Vijay
Table Sports
Sport_name Played by
Cricket ^2^,^3^,^4^
Football ^1^,^3^
Vollyball ^4^,^1^
Now I want to write a query which will give me output like
name No_of_sports_played
Ajay 2
Amol 1
Sanjay 2
Vijay 2
So what will be Mysql query for this?
I agree with the above answers/comments that you are not using a database for what a database is for, but here is how you could calculate your table from your current structure in case you have no control over that:
SELECT Emp.name, IF(Played_by IS NULL,0,COUNT(*)) as Num_Sports
FROM Emp
LEFT JOIN Sports
ON Sports.Played_by RLIKE CONCAT('[[:<:]]',Emp.id,'[[:>:]]')
GROUP BY Emp.name;
See it in action here.
UPDATE: added the IF(Played_by IS NULL,0,COUNT(*)) instead of COUNT(*). This means that if an employee doesn't play anything they'll have a 0 as their Num_Sports. See it here (I also added in those ^ characters and it still works.
What it does is joins the Emp table to the Sports table if it can find the Emp.id in the corresponding Played_by column.
For example, if we wanted to see what sports Ajay played (id=1), we could do:
SELECT *
FROM Emp, Sports
WHERE Sports.Played_by LIKE '%1%'
AND Emp.id=1;
The query I gave as my solution is basically the query above, with a GROUP BY Emp.name to perform it for each employee.
The one modification is the use of RLIKE instead of LIKE.
I use RLIKE '[[:<:]]employeeid[[:>:]]' instead of LIKE '%employeeid%. The [[:<:]] symbols just mean "make sure the employeeid you match is a whole word".
This prevents (e.g.) Emp.id 1 matching the 1 in the Played_by of 3,4,11,2.
You do not want to store your relationships in a column like that. Create this table:
CREATE TABLE player_sports (player_id INTEGER NOT NULL, sport_id INTEGER NOT NULL, PRIMARY KEY(player_id, sport_id));
This assumes you have an id column in your sports table. So now a player will have one record in player_sports for each sport they play.
Your final query will be:
SELECT p.name, COUNT(ps.player_id)
FROM players p, player_sports ps
WHERE ps.player_id = p.id
GROUP BY p.name;