Barcode Incoming Outgoing Stock Date
1 10 5 5 2015-1-3
2 3 2 1 2015-1-3
1 2 1 1 2015-1-4
My current Query's output is shown above. What i need is to add the stock from the previous date of the same barcode to the latest. As Shown below
Barcode Incoming Outgoing Stock Date
1 10 5 5 2015-1-3
2 3 2 1 2015-1-3
1 2 1 6 2015-1-4
Is there a way to make this possible? my current query is nested but looks like this. not working though
Select
Barcode,
incoming,
outgoing,
(incoming - outgoing + Stock_prev_value) as Stock,
currentDate
from (select ....
)as myquery
Help me please.
currentDate => DATE_SUB(NOW(),INTERVAL 1 DAY)
instead of requesting you can also trigger/add a table 'stock_history' per day :
-barcode
-stock
-date
Related
My requirement is to compute the total months and then broken months separately between 2 dates (ie first date from table and second date is current date). If broken months total count is > 15 then account it as one month experience and if its les than 15 don't account that as 1 month experience.
Assume I have a date on table as 25/11/2018 and current date is 06/01/2019;
the full month in between is December, so 1 month experience; and broken months are November and January, so now I have to count the dates which is 6 days in Nov and 6 days in Jan, so 12 days and is <= (lte) 15 so total experience will be rounded to 1 month experience
I referred multiple questions related to calculating date difference in MYSQL from stackoverflow, but couldn't find any possible options. The inbuilt functions in MYSQL TIMESTAMPDIFF, TIMEDIFF, PERIOD_DIFF, DATE_DIFF are not giving my required result as their alogrithms are different from my calculation requirement.
Any clue on how to perform this calculation in MYSQL and arrive its result as part of the SQL statement will be helpful to me. Once this value is arrived, in the same SQL, that value will be validated to be within a given value range.
Including sample table structure & value:
table_name = "user"
id | name | join_date
---------------------
1| Sam | 25-11-2017
2| Moe | 03-04-2017
3| Tim | 04-07-2018
4| Sal | 30-01-2017
5| Joe | 13-08-2018
I wanted to find out the users from above table whose experience is calculated in months based on the aforementioned logic. If those months are between either of following ranges, then those users are fetched for further processing.
table_name: "allowed_exp_range"
starting_exp_months | end_exp_months
-------------------------------------
0 | 6
9 | 24
For ex: Sam's experience till date (10-12-2018) based on my calculation is 12+1 month = 13 months. Since 13 is between 9 & 24, Sam's record is one of the expected output.
I think this query will do what you want. It uses
(YEAR(CURDATE())*12+MONTH(CURDATE()))
- (YEAR(STR_TO_DATE(join_date, '%d-%m-%Y'))*12+MONTH(STR_TO_DATE(join_date, '%d-%m-%Y'))) -
- 1
to get the number of whole months of experience for the user,
DAY(LAST_DAY(STR_TO_DATE(join_date, '%d-%m-%Y')))
- DAY(STR_TO_DATE(join_date, '%d-%m-%Y'))
+ 1
to get the number of days in the first month, and
DAY(CURDATE())
to get the number of days in the current month. The two day counts are summed and if the total is > 15, 1 is added to the number of whole months e.g.
SELECT id
, name
, (YEAR(CURDATE())*12+MONTH(CURDATE())) - (YEAR(STR_TO_DATE(join_date, '%d-%m-%Y'))*12+MONTH(STR_TO_DATE(join_date, '%d-%m-%Y'))) - 1 -- whole months
+ CASE WHEN DAY(LAST_DAY(STR_TO_DATE(join_date, '%d-%m-%Y'))) - DAY(STR_TO_DATE(join_date, '%d-%m-%Y')) + 1 + DAY(CURDATE()) > 15 THEN 1 ELSE 0 END -- broken month
AS months
FROM user
We can use this expression as a JOIN condition between user and allowed_exp_range to find all users who have experience within a given range:
SELECT u.id
, u.name
, a.starting_exp_months
, a.end_exp_months
FROM user u
JOIN allowed_exp_range a
ON (YEAR(CURDATE())*12+MONTH(CURDATE())) - (YEAR(STR_TO_DATE(u.join_date, '%d-%m-%Y'))*12+MONTH(STR_TO_DATE(u.join_date, '%d-%m-%Y'))) - 1
+ CASE WHEN DAY(LAST_DAY(STR_TO_DATE(u.join_date, '%d-%m-%Y'))) - DAY(STR_TO_DATE(u.join_date, '%d-%m-%Y')) + 1 + DAY(CURDATE()) > 15 THEN 1 ELSE 0 END
BETWEEN a.starting_exp_months AND a.end_exp_months
Output (for your sample data, includes all users as they all fit into one of the experience ranges):
id name starting_exp_months end_exp_months
1 Sam 9 24
2 Moe 9 24
3 Tim 0 6
4 Sal 9 24
5 Joe 0 6
I've created a small demo on dbfiddle which demonstrates the steps in arriving at the result.
I want to write query to fetch user from table who register before week interval.
For ex. todays date is 2017-08-17, then I need user who register on 2017-08-10, 2017-08-03,2017-07-27 and so on. Like this if todays date is 2017-08-20 then user will be register on 2017-08-13, 2017-08-06.
id name date
1 ABC 2018-08-16
2 PQR 2018-08-10
3 LMN 2018-07-27
4 AAA 2018-01-01
Output will be
id name date
2 PQR 2018-08-10
3 LMN 2018-07-27
One way to express this problem is to recognize that we want to retain dates whose difference from today are multiple of 7 days. We can compare the UNIX timestamps of each record and check to see if the number of seconds, when divided by the number of seconds in 7 days, is zero.
SELECT *
FROM yourTable
WHERE
MOD(UNIX_TIMESTAMP(CURDATE()) -
UNIX_TIMESTAMP(DATE(reg_date)), 7*24*60*60) = 0
Demo here:
Rextester
SELECT * FROM user WHERE WEEKDAY(`date`) = WEEKDAY(NOW());
This will get you all users that registered 0, 7, 14, 21 etc. days ago.
The mysql table we work on has data in the following format:
entityId status updated_date
-------------------------------
1 1 29/05/2017 12:00
1 2 29/05/2017 03:00
1 3 29/05/2017 07:00
1 4 29/05/2017 14:00
1 5 30/05/2017 02:00
1 6 30/05/2017 08:00
2 1 31/05/2017 03:00
2 2 31/05/2017 05:00
.
.
So every entity id has 6 statuses, and every status has an update datetime. Each status has an activity attached to it.
For example 1 - Started journey
2 - Reached first destination
3 - Left Point A, moving towards B. etc
I need to get an output in the below format for specific entity id eg 3 and 4. I need the time for status 3 and 4 independently.
entity_id time_started_journey time_reached_first_destination
(update time of status 3) (update time of status 4)
--------------------------------------------------------------
1 29/05/2017 7:00 29/05/2017 14:00
2 30/05/2017 7:00 30/05/2017 16:00
Later I need to calculate the total time which would be the difference of the two.
How can I achieve the desired result using mysql.
I tried using Union operator but cannot do it separate columns.
Also, tried using case when operator with the below query but failed.
select distinct entityid,
(case status when 3 then freight_update_time else 0 end)
as starttime,
(case status when 4 then freight_update_time else 0 end) as endtime
from table ;
Can anyone throw light on this?
Conditional aggregation is one way to return a resultset that looks like that.
SELECT t.entityid
, MAX(IF(t.status=3,t.updated_date,NULL)) AS time_started_journey
, MAX(IF(t.status-4,t.updated_date,NULL)) AS time_reached_first_destination
FROM mytable t
WHERE t.status IN (3,4)
GROUP BY t.entityid
ORDER BY t.entityid
This is just one suggestion; the specification is unclear about what the query should do with duplicated status values for a given entityid.
There are other query patterns that will return similar results.
My query in MySQL
SELECT
e3.updated_date AS sta3,
e4.updated_date AS sta4
FROM
`prueba` AS e3
LEFT JOIN prueba AS e4
ON
e3.entityId = e4.entityId AND e4.status = 4
WHERE
e3.status = 3
OUTPUT:
Is it possible to retrieve the records from the table using month no and week no
for example I have a table
CustomerID CustomerName date(data type date)
1 sam 2016-06-1
2 dam 2016-06-2
3 kam 2016-06-8
4 ram 2016-06-9
4 ram 2016-07-8
how can i retrieve the month no 6 and week no 1 records
after the select query expected result is
CustomerID CustomerName date
1 sam 2016-06-1
2 dam 2016-06-2
it will give 2 records because date 1 and 2 fall under first week
if question is not clear please reply
thanks !
You can use month and week functions. Documentation here.
select * from table where month(`date`) = 6 and week(`date`) = 1
I have a table that's structured like so:
id value hour
1 4 176475
2 2 176475
3 3 176475
4 2 176475
1 2 184563
2 1 184563
3 4 184563
4 3 184563
... ... ...
1 2 N
2 3 N
3 1 N
4 4 N
The key property is that the data is split into hours which are in ascending order. The 'hours' are timestamps truncated to enforce 24 buckets per day. I want to do several things:
Pull all of the rows for the first hour
Sum values for each ID over 3 hours, 8 hours...N hours.
Is there a simple way to do this? I am aware that I could use NTILE to label the data but that's a very expensive operation in Spark.
EDIT:
Expected Result for aggregating hours 1-3:
id value
1 9
2 7
3 10
4 8
The values are made up, but the idea is to sum the values of the IDs in each of the 3 hours, so that I have one value per ID, instead of three.
This is the query you're looking for:
SELECT id, SUM(value) as `value`
FROM yourTableHere
WHERE hour between (NOW() - INTERVAL X HOUR) AND NOW()
GROUP BY id, hour
Breaking the query down.
Select the ID and count the value from yourTable.
Where hour is between X hours ago and now.
Group the results by id and hour between the given timestamps.
Replace X with 1/3/8 or more for the hours you wish.