I have a table named nca_totals.
Table: nca_totals
+----------+-----------+------------+--------------+
| total_id | nca_total | nca_date | account_type |
+----------+-----------+------------+--------------+
| 13 | 10450 | 2015-01-21 | DBP-TRUST |
| 14 | 5000 | 2015-02-05 | DBP-TRUST |
| 15 | 7000 | 2015-04-02 | DBP-TRUST |
| 16 | 4000 | 2015-05-02 | DBP-TRUST |
+----------+-----------+------------+--------------+
Now I want to display all the data by quarter base on its date. Let's say I want to display all the records who belong to 1st Quarter like this:
+----------+-----------+------------+--------------+
| total_id | nca_total | nca_date | account_type |
+----------+-----------+------------+--------------+
| 13 | 10450 | 2015-01-21 | DBP-TRUST |
| 14 | 5000 | 2015-02-05 | DBP-TRUST |
+----------+-----------+------------+--------------+
This date belongs to the 1st quarter of the year (Jan, Feb, March). I only have this query to select the date and return its quarter number as:
SELECT QUARTER('2015-01-11'); /* returns 1 */
How can I combine that query to display all the records by quarter ? Can anyone help ? Thanks.
select *
from nca_totals
where QUARTER(nca_date) = 1
SELECT
CEIL(MONTH(`nca_date`) / 3) AS `quarter`
FROM `nca_totals`;
Related
I have two table one contains updated_at (can be more than one row) datetime And second contains started_date and stopped_date(one or more records).
I want select updated_at date which should not in between started_date and stopped_date.
Thanks in advance.
I saw the other Question "Check overlap of date ranges in MySQL".
But this not what I want.
user_location
+---+-----+-----+---------------------+
|id | lat | lon | updated_date |
+---+-----+-----+---------------------+
| 1 |16.45|75.45|2018-01-09 12:50:57 |
| 2 |16.85|75.15|2018-01-09 12:53:45 |
| 3 |16.78|75.25|2018-01-09 12:55:48 |
| 4 |16.43|75.35|2018-01-09 13:57:35 |
| 5 |16.48|75.47|2018-01-09 14:59:30 |
| 6 |16.49|75.49|2018-01-10 05:59:58 |
| 7 |16.50|75.50|2018-01-10 07:35:15 |
+---+-----+-----+---------------------+
location_blocked_datetime
+---+--------------------+---------------------+
|id | start_date | stopped_date |
+---+--------------------+---------------------+
| 1 |2018-01-09 05:55:48 | 2018-01-09 07:55:48 |
| 2 |2018-01-09 12:51:48 | 2018-01-09 12:56:48 |
| 3 |2018-01-10 04:30:48 | 2018-01-04 06:55:48 |
+---+--------------------+---------------------+
I want select location from user_location table where updated_date should not be there in start_date and stopped_date.start_date and stopped dates are not fixed and contain more than 1 records
The result of above query should look like this:-
If I want to select locations On 2018-01-09
Result Of Above Query
+---+-----+-----+---------------------+
|id | lat | lon | updated_date |
+---+-----+-----+---------------------+
| 1 |16.45|75.45|2018-01-09 12:50:57 |
| 2 |16.43|75.35|2018-01-09 13:57:35 |
| 3 |16.48|75.47|2018-01-09 14:59:30 |
+---+-----+-----+---------------------+
So I get this right, that the tables are not actually connected and you want to get the records where updated_date is not between any start_date - stopped_date range?
If so, then use not exists like this:
SELECT
l.*
FROM
user_location l
WHERE DATE(l.updated_date) = '2018-01-09'
and not exists (select 1 from location_blocked_datetime
where l.updated_date between start_date and stopped_date)
| id | lat | lon | updated_date |
|----|-----|-----|---------------------|
| 1 | 16 | 75 | 2018-01-09 12:50:57 |
| 4 | 16 | 75 | 2018-01-09 13:57:35 |
| 5 | 16 | 75 | 2018-01-09 14:59:30 |
see it working live in an sqlfiddle
Report Table
+----+-------------------+--------+---------------------+
| id | mac_address |quantity| zaman |
+----+-------------------+--------+---------------------+
| 12 | 26-C0-B7-1E-7A-8C | 001 | 2017-12-07 10:22:09 |
| 14 | 26-C0-B7-1E-7A-8C | 001 | 2017-12-07 10:28:44 |
| 15 | 26-C0-B7-1E-7A-8D | 001 | 2017-12-07 10:44:54 |
| 19 | 26-C0-B7-1E-7A-AC | 001 | 2017-12-08 10:11:00 |
| 20 | 26-C0-B7-1E-7A-AD | 002 | 2017-12-08 10:32:12 |
| 24 | 26-C0-B7-1E-7A-8D | 001 | 2017-12-09 10:29:54 |
| 25 | 26-C0-B7-1E-7A-8E | 002 | 2017-12-09 10:39:11 |
I want to find average of quantity between days according to this equation:
Sum of quantity(9)/Number of day(3) = 3
So far I have this query:
SELECT ROUND(AVG(quantity),2) AS quantity, DATE(zaman) as DateOnly
FROM report WHERE DATE(zaman) BETWEEN ? AND ?
GROUP BY DateOnly
How can I achieve this?
try using sum of the quantity divided by number of days
select sum(quantity) /( datediff(max(zaman), min(zaman))) as quantity
FROM report WHERE DATE(zaman) BETWEEN ? AND ?
Try this:
SELECT ROUND((SUM(Quantity)*1.0)/datediff(MAX(Zaman), MIN(Zaman)),0)
FROM report
WHERE zaman BETWEEN ? AND ?
I'm trying to create a MySQL query to select the daily price from a table that is between a date range from another. I only want to use 'starting-ending' months and days from the table "seasons" and I want to pass the year dynamically to the query.
This is my query: (I'm giving it the Year to exclude the one on the table)
SELECT a.season, b.base_price
FROM seasons a
JOIN pricebyseason b ON a.id=b.season_id
WHERE b.prop_id='6' AND '2015-11-29' BETWEEN DATE_FORMAT(a.starting,'2015-%m-%d') AND DATE_FORMAT(a.ending,'2016-%m-%d')
ORDER BY b.base_price DESC
It works but not with all dates.
These are the tables:
seasons (these are static date values)
+----+--------------+------------+------------+
| id | season | starting | ending |
+----+--------------+------------+------------+
| 1 | Peak Season | 2015-12-11 | 2016-01-09 |
| 2 | High Season | 2015-11-27 | 2016-04-15 |
| 3 | Mid Season | 2015-04-16 | 2015-09-01 |
| 4 | Low Season | 2015-09-02 | 2015-11-26 |
| 5 | Spring Break | 2015-03-05 | 2015-03-21 |
+----+--------------+------------+------------+
pricebyseason
+----+---------+-----------+------------+
| id | prop_id | season_id | base_price |
+----+---------+-----------+------------+
| 1 | 6 | 1 | 950 |
| 2 | 6 | 2 | 750 |
| 3 | 6 | 3 | 450 |
| 4 | 6 | 4 | 400 |
| 5 | 6 | 5 | 760 |
+----+---------+-----------+------------+
What I want to achive is query the dialy price between checkin, checkout selection
I create this sqlfiddle: http://sqlfiddle.com/#!9/4a6f4
This is a previuos query that is not working either:
SELECT a.base_price,b.season,b.starting,b.ending
FROM pricebyseason a JOIN seasons b ON a.season_id=b.id
WHERE a.prop_id='6' AND
(DATE_FORMAT(b.starting,'%m-%d') <= '12-27' OR DATE_FORMAT(b.starting,'2016-%m-%d') >= '2015-12-27')
AND
(DATE_FORMAT(b.ending,'%m-%d') >= '12-27' OR DATE_FORMAT(b.ending,'2016-%m-%d') <= '2015-12-27')
ORDER BY base_price DESC
And here are some sample dates for each season: '2016-01-08','2015-12-27','2016-04-14','2015-11-29','2016-04-15','2015-09-01','2016-09-02','2015-11-26','2016-10-10','2016-03-18','2016-06-22','2015-06-15'
Thank a lot
I have table in mysql like
| service_code | charges | caller_number | duration | minutes |
+--------------+---------+---------------+----------+---------+
| 10 | 15 | 8281490235 | 00:00:00 | 1.0000 |
| 11 | 12 | 9961621709 | 00:00:00 | 0.0000 |
| 10 | 15 | 8281490235 | 01:00:44 | 60.7333 |
| 11 | 2 | 9744944316 | 01:00:44 | 60.7333 |
+--------------+---------+---------------+----------+---------+
from this table I want to get charges*minutes for each separate caller_number.
I have done like this
SELECT sum(charges*minutes) as cost from t8_m4_bill groupby caller_number
but I am not getting expected output. Please help?
SELECT caller_number,sum(charges*minutes) as cost
from t8_m4_bill
group by caller_number
order by caller_number
I want to list top 6 race records with unique holder only. I mean a holder gets in the list shouldn't be listed with his another record. I currently use the query below to list top 6 times.
mysql> select * from racerecords order by record_time asc, date asc;
+----+---------+------------+-------------+---------------------+----------+
| id | race_id | holder | record_time | date | position |
+----+---------+------------+-------------+---------------------+----------+
| 2 | 10 | Stav | 15 | 2014-08-11 19:43:49 | 1 |
| 1 | 10 | Jennifer | 15 | 2014-08-13 19:43:19 | 1 |
| 4 | 10 | Jennifer | 16 | 2014-08-02 19:44:27 | 1 |
| 5 | 10 | Osman | 17 | 2014-08-04 19:44:57 | 1 |
| 7 | 10 | Gokhan | 18 | 2014-08-15 19:45:37 | 1 |
| 3 | 10 | MotherLode | 25 | 2014-08-01 19:44:11 | 1 |
+----+---------+------------+-------------+---------------------+----------+
6 rows in set (0.00 sec)
As you can see the holder "Jennifer" is listed twice. I want mySQL to skip her after she got in the list. The result I want to be generated is:
+----+---------+------------+-------------+---------------------+----------+
| id | race_id | holder | record_time | date | position |
+----+---------+------------+-------------+---------------------+----------+
| 2 | 10 | Stav | 15 | 2014-08-11 19:43:49 | 1 |
| 1 | 10 | Jennifer | 15 | 2014-08-13 19:43:19 | 1 |
| 5 | 10 | Osman | 17 | 2014-08-04 19:44:57 | 1 |
| 7 | 10 | Gokhan | 18 | 2014-08-15 19:45:37 | 1 |
| 3 | 10 | MotherLode | 25 | 2014-08-01 19:44:11 | 1 |
+----+---------+------------+-------------+---------------------+----------+
I tried everything. GROUP BY holder generates wrong results. It gets the very first record of the holder, even though is not the best. In this table it generates an output like above because id:1 is the first record I inserted for Jennifer.
How can I generate output a result like above?
Desired result can be achieved through this query but it performance intensive. I have reproduced the result in SQLFilddle http://sqlfiddle.com/#!2/f8ee7/3
select * from racerecords
where
(HOLDER, RECORD_TIME) in (
select HOLDER,min(RECORD_TIME) from racerecords
group by HOLDER)
Seems you have missed to include the Where clause in the sub-query. Try this
select * from racerecords
where
(HOLDER, RECORD_TIME) in (
select HOLDER,min(RECORD_TIME) from racerecords where race_id =17
group by HOLDER )
And race_id =17
Order by RECORD_TIME
you should use distinct clause
SELECT DISTINCT column_name,column_name
FROM table_name;
looks this http://www.w3schools.com/sql/sql_distinct.asp