I want to get the maximum id from table with ought use of any function like max or else.I need simple pure query.Any one help me to solve this problem .
We simply write
select max(id) from table
but i don't want to use max()
Use ORDER BY and LIMIT
SELECT id
FROM table
ORDER BY id DESC
LIMIT 1
ORDER BY with LIMIT will do the job for u just fine
SELECT id FROM table
ORDER BY id DESC LIMIT 1;
But as you asked the question from interview's point of view , they may even ask you to do the same without using LIMIT , TOP or max() .
In thay case you should go with subquery approach . Here' s how u should do it :
SELECT id FROM table
WHERE id >= ALL
(SELECT id FROM table)
In this query an id is matched with all the id's in the table and it will be printed only if the value is greater than or equal to all the id's in the table. Only the max will satisfy the condition.
Use ORDER BY clause with LIMIT to fetch latest ID of table
Try this:
SELECT id
FROM table
ORDER BY id DESC
LIMIT 1;
SELECT id FROM table ORDER BY id DESC LIMIT 1
This should do it
I added 0 to solve the problem,
select max(id + 0) from table
Related
I have issue there with select from table. I want to select all rows except for first row. So .. There is my code
SELECT * FROM table ORDER BY id DESC
So this code select and order id's from table which give me id feedback "5>4>3>2>1". And there is issue .. How I can select and echo just 4>3>2>1 rows.
So if I had rows with id's 1,2,6,8,10 , echo will be 10,8,6,2,1 and I want select to echo just 8,6,2,1.
There is my full wrong code for select.
$other = mysql_query("SELECT * FROM table ORDER BY id DESC LIMIT 1, 1");
This should do it.
SELECT * FROM table WHERE id NOT IN (SELECT MAX(id) FROM table) ORDER BY id DESC
Try this:
SELECT *
FROM
(
SELECT *, row_number()
OVER (ORDER BY id DESC) row
FROM table
)
WHERE row != 1
It gives numbers to your selected rows and takes all of them without the one with row number 1
Try this
$other = mysql_query("SELECT * FROM table ORDER BY id DESC OFFSET 1");
THE ABOVE QUERY WONT WORK AS A LIMIT IS NEEDED
Refer to this answer
All you need is offset 1, but offset cannot be used without limit. So, I'd suggest something like:
SELECT * FROM table ORDER BY id DESC LIMIT 99999999 OFFSET 1
Warning: make sure your table doesn't contain lots of records, otherwise you will run into performance issues. Or, change the limit to something reasonable, like 10.
EDIT:
Read: How to use offset without limit
SELECT *
FROM table
WHERE id NOT IN ( SELECT id
FROM table
ORDER BY id DESC
LIMIT 1 )
ORDER BY id DESC;
You can try this.
In this case I am selecting all the rows, except the one with the biggest id.
In the example of [1,2,3,4,5], it will be :
SELECT *
FROM table
WHERE id NOT IN ( 5 )
ORDER BY id DESC;
Hope this helps!
I try to program a solution where I have multiple linked tables.
Now I have another problem:
I want to limit count of returned lines to 1000.
But I want to show ID 1-1000, next page 1001-2000.
IDs may be stored in iregular order in database (ID 1 does not have to be the first row)
Not any problem so far:
SELECT * FROM table ORDER BY id ASC LIMIT 1000
BUT
Now I have to sort resulty by another column:
SELECT * FROM table ORDER BY name ASC LIMIT 1000
which might return other IDs than 1-1000
or I do
SELECT * FROM table ORDER BY id ASC, ORDER BY name ASC LIMIT 1000
But this will only sort by ID an then by name. So if I would have any ID as duplicate (which is not possible) I would then have those sorted by name.
How can I achive that I get the first 1000 IDs (some IDs might not exist as they might have been deleted before!) and those thousand rows sorted by name?
Is that even possible?
Try this:
SELECT * FROM table WHERE id IN (
SELECT ID FROM table ORDER BY ID ASC LIMIT 0, 1000
) ORDER BY name ASC
As mentioned in comments that subquery is not supported, 'This version of MySQL doesn't yet support 'LIMIT & IN/ALL/ANY/SOME subquery'. Using JOINs is the only alternative left, like this:
SELECT table.* FROM tab JOIN (
SELECT ID FROM table ORDER BY ID LIMIT 1000
) temp
ON table.ID = temp.ID
ORDER BY table.name
I want to select last 50 rows from MySQL database within column named id which is primary key. Goal is that the rows should be sorted by id in ASC order, that’s why this query isn’t working
SELECT
*
FROM
`table`
ORDER BY id DESC
LIMIT 50;
Also it’s remarkable that rows could be manipulated (deleted) and that’s why following query isn’t working either
SELECT
*
FROM
`table`
WHERE
id > ((SELECT
MAX(id)
FROM
chat) - 50)
ORDER BY id ASC;
Question: How is it possible to retrieve last N rows from MySQL database that can be manipulated and be in ASC order ?
You can do it with a sub-query:
SELECT * FROM
(
SELECT * FROM table ORDER BY id DESC LIMIT 50
) AS sub
ORDER BY id ASC;
This will select the last 50 rows from table, and then order them in ascending order.
SELECT * FROM table ORDER BY id DESC LIMIT 50
save resources make one query, there is no need to make nested queries
SELECT * FROM table ORDER BY id DESC, datechat DESC LIMIT 50
If you have a date field that is storing the date (and time) on which the chat was sent or any field that is filled with incrementally (order by DESC) or de-incrementally (order by ASC) data per row put it as second column on which the data should be ordered.
That's what worked for me!!!! Hope it will help!!!!
Use it to retrieve last n rows from mysql
Select * from tbl order by id desc limit 10;
use limit according to N value.
if anyone need this
you can change this into
SELECT
*
FROM
`table`
WHERE
id > ((SELECT
MAX(id)
FROM
chat) - 50)
ORDER BY id ASC;
into
SELECT
*
FROM
`table`
WHERE
id > (SELECT MAX(id)- 50 FROM chat)
ORDER BY id ASC;
select * from Table ORDER BY id LIMIT 30
Notes:
* id should be unique.
* You can control the numbers of rows returned by replacing the 30 in the query
I have a table full of users and, using the below query, I'm able to get the result of the highest score divided by points:
SELECT MAX(points/score) FROM table
However, I'd like to grab the user associated with the result; any suggestions?
SELECT *
FROM table
ORDER BY points/score DESC
LIMIT 1
just order by points/score and limit the result to one:
SELECT
*
FROM
table
ORDER BY
points/score DESC
LIMIT 1
How can I select the row with the highest ID in MySQL? This is my current code:
SELECT * FROM permlog WHERE max(id)
Errors come up, can someone help me?
SELECT * FROM permlog ORDER BY id DESC LIMIT 0, 1
if it's just the highest ID you want. and ID is unique/auto_increment:
SELECT MAX(ID) FROM tablename
For MySQL:
SELECT *
FROM permlog
ORDER BY id DESC
LIMIT 1
You want to sort the rows from highest to lowest id, hence the ORDER BY id DESC. Then you just want the first one so LIMIT 1:
The LIMIT clause can be used to constrain the number of rows returned by the SELECT statement.
[...]
With one argument, the value specifies the number of rows to return from the beginning of the result set
SELECT *
FROM permlog
WHERE id = ( SELECT MAX(id) FROM permlog ) ;
This would return all rows with highest id, in case id column is not constrained to be unique.
SELECT MAX(id) FROM TABLENAME
This identifies the largest id and returns the value
Suppose you have mulitple record for same date or leave_type but different id and you want the maximum no of id for same date or leave_type as i also sucked with this issue,
so Yes you can do it with the following query:
select * from tabel_name where employee_no='123' and id=(
select max(id) from table_name where employee_no='123' and leave_type='5'
)
SELECT MAX(ID) FROM tablename LIMIT 1
Use this query to find the highest ID in the MySQL table.
Since both SELECT MAX(id) FROM table and SELECT id FROM table ORDER BY id DESC LIMIT 0,1 fulfill the goal, the interesting part is, which performs better.
SELECT MAX(id) FROM table: 152ms
SELECT id FROM table ORDER BY id DESC LIMIT 0,1: 25ms
(InnoDB-table with 55M rows on MySQL 8.0, 10 runs, average result)
Of course thats not representive, but gives an idea, that the ORDER BY method performs significantly better.
This is the only proposed method who actually selects the whole row, not only the max(id) field. It uses a subquery
SELECT * FROM permlog WHERE id = ( SELECT MAX( id ) FROM permlog )
SELECT * FROM `permlog` as one
RIGHT JOIN (SELECT MAX(id) as max_id FROM `permlog`) as two
ON one.id = two.max_id