I have 3 tables.
Accounts :
id
1
2
3
Customers :
id | account | email
76276 | 1 | test1#mail.com
143158 | 2 | test2#mail.com
143159 | 3 | test3#mail.com
Payments :
id | customer | date
285041 | 76276 | 2014-12-01 00:13:41
285042 | 76276 | 2014-12-01 00:15:55
285043 | 143158 | 2014-12-01 00:18:52
285044 | 143159 | 2014-12-02 12:21:47
I want to get all the accounts whose customer's first payment is between 2014-12-01 00:00:00 and 2014-12-01 23:59:59
I tried
SELECT a.id
FROM account a
JOIN customer c ON c.account = a.id
JOIN payment p ON p.id = (
SELECT p.id
FROM payment p
WHERE p.customer = c.id
AND p.date BETWEEN '2014-12-01 00:00:00' AND '2014-12-01 00:59:59'
ORDER BY date ASC
LIMIT 1
)
But this query runs for ages.. and i'm pretty sure this is not how I should join payment table. Some help would be appreciated.
Find the first payment date by using min(). Then just get the appropriate information:
select account
from customers c join
payments p
on p.customer = c.id
group by account
having min(p.date) >= '2014-12-01' and min(p.date) < '2014-12-02';
this query might be helpful.
SELECT a.id FROM accounts a
INNER JOIN Customers c ON c.account=a.id
INNER JOIN payments p ON p.customer=c.id
WHERE p.date BETWEEN '2014-12-01 00:00:00' AND '2014-12-01 23:59:59';
Related
So I need to display all my customers and with the associated booking number (null if there is no booking) without duplicated custome. If the customer has lot of bookings I need to display only the nearest booking date. I don't understand why my query doesn't work.
Here is what is did : http://sqlfiddle.com/#!9/df0455/19
SELECT c.name, x.number, x.start_date
FROM customer c
LEFT JOIN
(SELECT b.customer_id, b.number, b.start_date
FROM booking b
INNER JOIN (
SELECT customer_id, MIN(ABS(TIME_TO_SEC(TIMEDIFF(NOW(), start_date)))) as mindiff
FROM booking
GROUP BY customer_id
) nearest ON b.customer_id = nearest.customer_id AND ABS(TIME_TO_SEC(TIMEDIFF(NOW(), start_date))) = mindiff
) AS x ON c.id = x.customer_id
Actually Paul is displayed three times and what is need is to display Paul just once with the nearest booking number who is booking-1 2019-11-05 21:45:00
I hope you can help me
You can filter with a row-limiting correlated subquery:
select c.name, b.number, b.start_date
from customer c
inner join booking b on b.customer_id = c.id
where b.start_date = (
select b1.start_date
from booking b1
where b1.customer_id = b.customer_id
order by abs(timestampdiff(second, now(), b1.start_date))
limit 1
)
In your DB Fiddle, this produces:
name number start_date
Paul booking-1 2019-11-05T21:45:00Z
John booking-3 2019-09-27T21:45:00Z
Morgan booking-5 2019-09-27T21:45:00Z
If you wanted to also display customers without bookings, then you would left join and move the filtering to the on clause of the join:
select c.name, b.number, b.start_date
from customer c
left join booking b
on b.customer_id = c.id
and b.start_date = (
select b1.start_date
from booking b1
where b1.customer_id = b.customer_id
order by abs(timestampdiff(second, now(), b1.start_date))
limit 1
)
You can use NOT EXISTS to get the nearest booking and join to customer:
SELECT c.id, c.name, t.number, t.start_date
FROM customer c
LEFT JOIN (
SELECT b.* FROM booking b
WHERE NOT EXISTS (
SELECT 1 FROM booking
WHERE customer_id = b.customer_id
AND ABS(TIMESTAMPDIFF(SECOND, NOW(), start_date)) < ABS(TIMESTAMPDIFF(SECOND, NOW(), b.start_date))
)
) t ON t.customer_id = c.id
See the demo.
Results:
| id | name | number | start_date |
| --- | ------ | --------- | ------------------- |
| 1 | Paul | booking-1 | 2019-11-05 21:45:00 |
| 2 | John | booking-3 | 2019-09-27 21:45:00 |
| 3 | Morgan | booking-5 | 2019-09-27 21:45:00 |
| 4 | Jane | | |
| 5 | Mike | | |
I'm having a trouble with this join. Basically I just need to know if "warehouse" exists on both tables, but just take the last entry of the desired 'warehouse' between 2 dates.
Select c.warehouse, p.id, p.status FROM control c LEFT JOIN payment p ON c.warehouse = p.warehouse WHERE p.date BETWEEN '2018-06-26' AND '2018-06-27'
I also tried (It says: Invalid use of group function):
Select c.warehouse, p.id, p.status FROM control c LEFT JOIN payment p ON c.warehouse = p.warehouse WHERE p.date BETWEEN '2018-06-26' AND '2018-06-27' && p.id = MAX(p.id)
Those are my tables:
payments control
+---------------------------------------+ +-----------+
| id | warehouse | status | date | | warehouse |
+---------------------------------------+ +-----------+
|19006| 226975 | DUE |2018-06-26| | 226975 |
MAX ID-> |19066| 226975 | PAID |2018-06-27| | 226976 |
+---------------------------------------+ +-----------+
Result Obtained:
+--------------------------------------+
| warehouse | id | status | date |
+--------------------------------------+
| 226975 |19006 | DUE |2018-06-26|
+--------------------------------------+
In this case I'm obtaining the "first entry", the lower one (id: 19006) and I want "the last" (id: 19066) the max.
Result expected:
+--------------------------------------+
| warehouse | id | status | date |
+--------------------------------------+
| 226975 |19066 | PAID |2018-06-27|
+--------------------------------------+
Any ideas?
Two requirements.
rows where the warehouse column is in both tables. Exclude others. That's done with an inner JOIN.
the latest entry from the payments table. The id of that latest entry for each warehouse can be retrieved with this subquery.
SELECT MAX(id) id, warehouse
FROM payments
GROUP BY warehouse
Putting it all together:
SELECT p.warehouse, p.id, p.status, p.date
FROM payments p
JOIN ( SELECT MAX(id) id, warehouse
FROM payments
GROUP BY warehouse
) mm ON p.id = mm.id AND p.warehouse = mm.warehouse
JOIN control c ON p.warehouse = c.warehouse
My version with slight differences from O. Jones.
SELECT *
FROM control c
LEFT JOIN payments p ON p.warehouse=c.warehouse AND
p.date = (SELECT MAX(p1.date)
FROM payments p1
WHERE p1.warehouse=c.warehouse)
WHERE p.date IS NOT NULL;
I have the following tables
TABLE: appointments
ID | PRICE | PAID
48 | 100 | 180
TABLE: appointments_products
ID | APPOINTMENT_ID | PRODUCT_ID | TOTAL
10 | 48 | 1 | 30
11 | 48 | 9 | 30
12 | 48 | 6 | 30
I Would like to somehow run a MySQL query that will:
a) join the two tables, SUM the "TOTAL" of appointments_products for each appointment_id and if the "PAID" is not equal of the PRICE (from appointments table) + TOTAL (from appointments_products table) then to show it.
This is what I have done so far:
select a.*, b.appointment_id as AppId, b.total as ProdTotal
from appointments a
INNER JOIN appointments_products b ON a.id = b.appointment_id
But this query does not sum the total for each appointment_id
select a.ID,a.PRICE,a.PAID,a.id as AppId,
sum(b.total) as ProdTotal
from appointments a
INNER JOIN appointments_products b ON a.id = b.appointment_id
group by a.ID,a.PRICE,a.PAID;
Use where to check if price is equal to paid and the use group by to group with appointment_id.
select b.Appointment_Id, a.price, a.PAID, a.id, sum(b.total) AS TotalProd FROM appointments_products AS b inner join appointments as a On Appointment_Id = a.Id group by Appointment_Id, a.Price , a.PAID , a.id HAVING a.PAID != (a.Price + sum(b.Total))
I need to get all the details from the orders table, with the latest status ID in the orders statuses table, and then the name of that status from the states table.
orders
id | customer | product
-----------------------
1 | David | Cardboard Box
Order_to_statuses
id | order | status | updated_at
--------------------------------
1 | 1 | 1 | 2017-05-30 00:00:00
2 | 1 | 3 | 2017-05-28 00:00:00
3 | 1 | 4 | 2017-05-29 00:00:00
4 | 1 | 2 | 2017-05-26 00:00:00
5 | 1 | 5 | 2017-05-05 00:00:00
order_states
id | name
---------
1 | Pending
2 | Paid
3 | Shipped
4 | Refunded
In this instance, I would need to get the customer and product, with the latest status ID from the order statuses table, and then the name of that state.
How can I do this?
I'd break this down by first getting the max(updated_at) for each order, then work to everything else you need. You can get the max date for each order by using subquery:
select
s.`order`,
s.`status`,
s.updated_at
from order_to_statuses s
inner join
(
select
`order`,
max(updated_at) as updated_at
from order_to_statuses
group by `order`
) m
on s.`order` = m.`order`
and s.updated_at = m.updated_at
Once you get this you now have the order, the status id, and the most recent date. Using this you can then JOIN to the other tables, making your full query:
select
o.customer,
o.product,
ots.updated_at,
os.name
from orders o
inner join
(
select
s.`order`,
s.`status`,
s.updated_at
from order_to_statuses s
inner join
(
select
`order`,
max(updated_at) as updated_at
from order_to_statuses
group by `order`
) m
on s.`order` = m.`order`
and s.updated_at = m.updated_at
) ots
on o.Id = ots.`order`
inner join order_states os
on ots.`status` = os.id;
See a demo
It may have some typo, but the idea of the query should be something like this:
select orders.id, orders.customer, orders.product,
order_to_status.status, staus.name
from orders, order_to_status, status
where orders.id = order_to_status.order
and order_to_status.status = status.id
and order_to_status.updated_at in (
SELECT MAX(order_to_status.updated_at)
FROM order_to_status
where order_to_status.order = orders.id
group by order_to_status.order
);
I ussually don't use joins but with joins it should be like this:
select orders.id, orders.customer, orders.product,
order_to_status.status, staus.name
from orders
JOIN order_to_status ON orders.id = order_to_status.order
JOIN status ON order_to_status.status = status.id
where
order_to_status.updated_at in (
SELECT MAX(order_to_status.updated_at)
FROM order_to_status
where order_to_status.order = orders.id
group by order_to_status.order
);
Note I added a group by I had missed.
EDIT 2
I had an error in the subquery condition.
changed to where order_to_status.order = orders.id
also moved the group by after the where clause.
i have three tables
customer
id | name
1 | john
orders
id | customer_id | date
1 | 1 | 2013-01-01
2 | 1 | 2013-02-01
3 | 2 | 2013-03-01
order_details
id | order_id | qty | cost
1 | 1 | 2 | 10
2 | 1 | 5 | 10
3 | 2 | 2 | 10
4 | 2 | 2 | 15
5 | 3 | 3 | 15
6 | 3 | 3 | 15
i need to select data so i can get the output for each order_id the summary of the order
sample output. I will query the database with a specific customer id
output
date | amount | qty | order_id
2013-01-01 | 70 | 7 | 1
2013-02-01 | 50 | 4 | 2
this is what i tried
SELECT
orders.id, orders.date,
SUM(order_details.qty * order_details.cost) AS amount,
SUM(order_details.qty) AS qty
FROM orders
LEFT OUTER JOIN order_details ON order_details.order_id=orders.id AND orders.customer_id = 1
GROUP BY orders.date
but this returns the same rows for all customers, only that the qty and cost dont hav values
Maybe
SELECT
orders.id, orders.date,
SUM(order_details.qty * order_details.cost) AS amount,
SUM(order_details.qty) AS qty
FROM orders
LEFT JOIN order_details ON order_details.order_id=orders.id
AND orders.customer_id = 1
GROUP BY orders.date
HAVING amount is not null AND qty is not null
SQL Fiddle
NOTE: In the following query, it is assumed that the dates are stored in the database as a string in the format specified in the OP. If they are actually stored as some type of date with time then you'll want to modify this query such that the time is truncated from the date so the date represents the whole day. You can use the date or date_format functions. But then you'll need to make sure that you modify the query appropriately so the group by and select clauses still work. I added this modification as comments inside the query.
select
o.date -- or date(o.date) as date
, sum(odtc.total_cost) as amount
, sum(odtc.qty) as qty
, o.order_id
from
orders o
inner join (
select
od.id
, od.order_id
, od.qty
, od.qty * od.cost as total_cost
from
order_details od
inner join orders _o on _o.id = od.order_id
where
_o.customer_id = :customer_id
group by
od.id
, od.order_id
, od.qty
, od.cost
) odtc on odtc.order_id = o.id
where
o.customer_id = :customer_id
group by
o.date -- or date(o.date)
, o.order_id
;
I don't think you want an outer join just a simple inner join on all 3 tables:
FROM orders, order_details, customer
WHERE orders.customer_id=customer.id
AND order_details.order_id=orders.id