I want to send all (inclduing unchanged) records of an Ext.data.store using the sync-method to the server.
In extjs4 you coud do the following (answer from this question):
store.each(function(record){
record.setDirty();
});
store.sync();
But in extjs5 the setDirty()-method is deprecated, and I wasn't able to find an alternative solution.
You could override getModifiedRecords to always return all store records.
You could also add extra field into model, not stored anywhere, and change it before sync.
Related
I'm getting this exception when trying to ->write() a DataObject called 'ModelSheet', it says the name should be Models\ModelSheet instead of ModelSheet only (i am under the same namespace (Models) and even try with an use statement)
Hi Guilherme and welcome to stackoverflow,
it seems that the ClassName saved to your database record does not match your PHP classname.
When changing classnames (adding or changing a namespace is changing the classname), you need to update the database to reflect this changes, as the classname is saved in the DB, so Silverstripe knows which PHP-Object is related to the data record.
If you used Silverstripe's upgrader tool, you should have an .upgrade.yml in your module's directory (e.g. in app or mysite). If not, you can add it manually (see e.g. https://github.com/wernerkrauss/silverstripe-onepage/blob/master/.upgrade.yml as a random example). The structure is like
mappings:
OldClassName: My\Namespace\NewClassname
After that all you need is to run dev/build/?flush and your database should be updated.
My goal is very simple and I would guess it is a very common goal among web developers.
I am creating a Rails (5.1) application, and I simply want to use AJAX to get the value of a specific cell in a specific row of a specific table in my database (later I am going to use that value to highlight some text on the current page in the user's browser).
I have not been able to find any documentation online explaining how to do this. As I said, it seems like a basic task to ask of jquery and ajax, so I'm confused as to why I'm having so much trouble figuring it out.
For concreteness, say I have a table called 'animals', and I want to get the value of the column 'species' for the animal with 'id' = 99.
How can I construct an AJAX call to query the database for the value of 'species' for the 'animal' with 'id' = 99 .
Though some DBs provide a REST API, what we commonly do is define a route in the app to pull and return data from the DB.
So:
Add a route
Add a controller/action for that route
In that action, fetch the data from the DB and render it in your preferred format
On the client-side, make the AJAX call to that controller/action and do something with the response.
Let's say I want to have a provide CActiveDataProvider for a CGridView. I need to put a SUM(invitesCount) AS invites into a Provider result. How to retrieve it? I guess I cannot just use $dataProvider->invites?
You need to specify the following in your relationinvites
'invites '=>array(self::BELONGS_TO, 'CampaignFund', 'campaign_id', 'select' => 'SUM(invitesCount)'),
and use this relation in your criteria.
Several other options:
Use CStatRelation
invitesCount=>array(self::STAT,'Invites','foreign_key_field');
The addition of a public property can work. However, the field would only be set if you altered the default find query to include this new condition. This can be done by overriding defaultScope() or creating a new scope and using it whenever invitesCount is required.
Another option would be to create a database view from the required query and create a new Model from that database view.
So I already have a database setup with a few columns and a few rows already inserted in. I'm trying to create a view that you would just input information into a form and press Submit, then a row would be added to the MySQL database with the information you just typed in.
I believe you can do this with admin, but I would like to try without admin and I'm not sure if this is possible? I've been using the MySQL commandline to add rows as of now..
Of coures this is possible this is a building block for data driven websites. You can use a ModelForm as Daniel suggested (they offer built in validation and HTML markup for FREE) to easily map your model to a front end form. It would probably be beneficial to start with django tutorial or documentation first.
At the the very basic, all you have to do is instantiate your model
new_entry = YourModel(name='me', age='222', about='stackoverflow')
then save it
new_entry.save()
This adds it as a new row to your db.
https://docs.djangoproject.com/en/dev/topics/db/models/
Why would it not be possible?
You probably want a modelform (but see the general form introduction first).
Try out this example of Generic Views: http://postneo.com/2005/08/17/django-generic-views-crud (assumes a model named Task)
With Generic Views you get Insert, Update and Delete for free without any real work. give it a try and let me know what you think.
from django.conf.urls.defaults import *
info_dict = {
'app_label': 'tasks',
'module_name': 'tasks',
}
urlpatterns = patterns('',
(r'^tasks/create/?$', 'django.views.generic.create_update.create_object', info_dict ),
(r'^tasks/update/(?P<object_id>\d+)/?$', 'django.views.generic.create_update.update_object', info_dict),
(r'^tasks/delete/(?P<object_id>\d+)/?$', 'django.views.generic.create_update.delete_object', info_dict ),
)
Django Docs: https://docs.djangoproject.com/en/1.2/ref/generic-views/#create-update-delete-generic-views
When developing a Data Flow I don't always want to output the results to a destination - but I would like to see the data.
Is there a way to attach a Data viewer to an output without having to have a destination?
The file and raw destination have limitations on the data type they accept - and I don't want to attach conversions just to test/build code.
Is there some kind of output to null ? i could then get a data view on the result set
There is a (free) custom "trash" destination available from a third party:
http://www.sqlis.com/post/Trash-Destination-Adapter.aspx
I usually use Export column transform - if left with default configuration, it does nothing, so it is equivalent to the custom "Trash" destination mentioned by Ed, but you don't have to install anything.
When debugging and wanting to view the data in the buffer, I usually throw in a Union All and connect it below the component who's output I want to see. Then add a Data Viewer on the connector and voila, there it is!
There isn't really. You can use a RecordSet Destination, or a Row Count transform instead.