I have a table constructed by the followinng:
CREATE TABLE IF NOT EXISTS test_table (
ID int(11) NOT NULL AUTO_INCREMENT,
ProfileID int(11) NOT NULL,
ForeignID int(11) NOT NULL,
PRIMARY KEY (ProfileID,ForeignID) )
ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;
I want to do something a little peculiar though, say there are 4 records in the database:
RecA, RecB, RecC, RecD
I would like to run the following query and have the insert behavior stop when a duplicate key was encountered:
INSERT IGNORE INTO test_table (ProfileID, ForeignID) VALUES(RecE, RecF, RecA, RecB, RecG);
So the query would only insert RecE and RecF, is there a way to do this in MySQL, perhaps using ON DUPLICATE KEY? Ideally the execution would just be terminated once a duplicate has been found, I am not too familiar with SQL syntax though.
Where RecG was explicitly not inserted.
Related
I got a MySQL database with some tables.
In one of these tables i want to insert by a SQL script some new rows.
Unfortunately i have to insert in two columns an empty string and the two columns are part of an unique key for that table.
So i tried to set UNIQUE_CHECKS before and after the insert, but i'm getting errors because of duplicate entries.
Here is the definition of the table:
CREATE TABLE `Table_A` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(100) NOT NULL,
`number` varchar(25) DEFAULT NULL,
`changedBy` varchar(150) DEFAULT NULL,
`changeDate` datetime NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,
PRIMARY KEY (`id`),
UNIQUE KEY `name` (`name`,`number`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
And the INSERT statement which causes error:
SET UNIQUE_CHECKS = 0;
INSERT INTO `Table_A`
(`name`, `number`, `changedBy`, `changeDate`)
SELECT DISTINCT '', 'myUser', CURRENT_TIMESTAMP
FROM Table_A
AND id NOT IN
(
SELECT DISTINCT id
FROM Table_A
);
SET UNIQUE_CHECKS = 1;
As You can see, i'm using UNIQUE_CHECKS.
But as i said this doesn't work properly.
Any help or suggestion would be appreciated.
Patrick
Switching off Unique Keys for the insert operation doesn't indicate that it will check uniqueness only for the operations that happen after you switch it on again. It just means that database will not waste time to check the constraint during the time it is switch off but it will check the constraint when you switch it on again.
What it measn is that you nead to ensure that column has unique value in a columns with Unique Keys before you can turn it on. Which you don't do.
If you want to maintain Uniqueness somehow for new records you insert after some point in time you would need to create trigger and manually check the new records against already existing data. The same possibly goes for updates. But I don't recommend it - you should probably redesign data so either the Unique Key is not there or the data is truly unique for all the records there are and will be.
I'm running MySQL 5.5 and found behaviour I didn't know of before.
Given this create:
CREATE TABLE `test` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(128) DEFAULT NULL,
PRIMARY KEY (`id`),
UNIQUE KEY `name_UQ` (`name`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
With these inserts:
insert into test (name) values ('b');
insert into test (name) values ('a');
And this select:
select * from test;
MySQL does something I wasn't aware of:
2 a
1 b
It sorts automatically.
Given a table with one extra, non-unique column:
CREATE TABLE `test` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(128) DEFAULT NULL,
`other_column` varchar(128) DEFAULT NULL,
PRIMARY KEY (`id`),
UNIQUE KEY `name_UQ` (`name`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
And the same inserts (see above), the select (see above) gives this result:
1 b NULL
2 a NULL
Which is kind of expected.
Where is the behaviour of the first query (SQL Fiddle) documented? I'd like to see more of these peculiar things.
MySQL does not sort result sets automatically. The ordering of a result set is indeterminate unless the query specifies an order by clause.
You should never rely on any sort of "implicit" ordering. Just because you see it in 1 (or 100 queries). In fact, without an order by, the same query can return results in different orders on subsequent runs (although I'll admit that this regularly occurs in other database, it is unlikely in MySQL).
Instead, add the ORDER BY. Ordering by a primary key is remarkably efficient, so you don't have to worry about performance.
I'm encountering an unexpected situation with inserting/querying particular records in the following table during periods of high contention. I believe there is a race condition in the database.
CREATE TABLE `business_objects` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`obj_id` varchar(255) DEFAULT NULL,
`obj_type` varchar(255) DEFAULT NULL,
`created_at` datetime(6) NOT NULL,
PRIMARY KEY (`id`),
UNIQUE KEY `index_business_objects_on_obj_type_and_obj_id`
(`obj_type`,`obj_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
The steps to reproduce are:
Check if record exists in table using this query
SELECT *
FROM business_objects
WHERE obj_type = 'Tip'
AND obj_id = '7616904'
If this query is null, attempt to create
INSERT INTO business_objects (obj_type, obj_id)
VALUES ('Tip', '7616904')
If another thread has already created a record with the same attributes this insert will fail and raise a uniqueness MySQL error. In this scenario, I catch the error and run the same query in step 1 to get the record.
SELECT *
FROM business_objects
WHERE obj_type = 'Tip'
AND obj_id = '7616904'
The query returns an empty result.
My expectation is that if the index uniqueness constraint is violated than the record should be committed to the table. What am I missing?
I've been getting this error from an insert on duplicate update query in MYSQL randomly every now and then.
Any idea what's going on? I can't seem to reproduce the error consistently it occurs sometimes and then sometimes not.
Here is the query in question:
INSERT INTO friendships (u_id_1,u_id_2,status) VALUES (?,?,'active') ON DUPLICATE KEY UPDATE id=LAST_INSERT_ID(id);
And the schema describing the table is:
DROP TABLE IF EXISTS `friendships`;
CREATE TABLE `friendships` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`u_id_1` int(11) NOT NULL,
`u_id_2` int(11) NOT NULL,
`status` enum('active','pending','rejected','blocked') DEFAULT 'pending' NOT NULL,
`initiatiator` enum('1','2','system') DEFAULT 'system' NOT NULL,
`terminator` enum('1','2','system') DEFAULT NULL,
`confirm_timestamp` timestamp DEFAULT NULL,
`created` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (`id`),
UNIQUE KEY (`u_id_1`,`u_id_2`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
Your ON DUPLICATE KEY UPDATE statement isn't helping you at all here.
You are taking the LAST_INSERT_ID, which is the auto inc of the last successfully inserted row, and trying to update the duplicated row with that id. This will always cause a duplicate primary (you're trying to change the id of some row to match the id of the last thing you added)
If your goal is to either
Insert a new row, or
Update an existing row with 'active'
Then
INSERT INTO friendships (u_id_1,u_id_2,status)
VALUES ( ? , ? ,'active')
ON DUPLICATE KEY UPDATE
status = 'active'; -- I changed this
A separate consideration is to check the source for duplicates. I had a simple audit table
INSERT INTO table
field1, field2, ... , field3
ON DUPLICATE KEY UPDATE row_id=row_id;
where field1 is an INDEX but not UNIQUE with row_ID as INTEGER UNSIGNED AUTO_INCREMENT PRIMARY KEY.
Ran for years, but an unexpected duplicate row triggered this error.
Fixed by de-duping the source.
Possibly a trivial point to many readers here, but it cost me some head-scratching (followed by a facepalm).
If I create a table with the following syntax,
CREATE TABLE IF NOT EXISTS `hashes` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`hash` binary(20) NOT NULL,
PRIMARY KEY (`id`,`hash`),
UNIQUE KEY (`hash`)
) ENGINE=InnoDB ROW_FORMAT=COMPRESSED KEY_BLOCK_SIZE = 4 AUTO_INCREMENT=1
PARTITION BY KEY(`hash`)
PARTITIONS 10;
And insert queries with the following syntax
INSERT INTO hashes (hash) VALUES ($value) ON DUPLICATE KEY UPDATE hash = hash
Then the auto increment column works as expected both if the row is inserted or updated.
Although creating the table without the partition like below and inserting with the query above the auto increment value will increase by 1 on every update or insert causing the A_I column to be all over place as the query could do 10 updates and then 1 insert causing the column value to jump 10 places.
CREATE TABLE IF NOT EXISTS `hashes` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`hash` binary(20) NOT NULL,
PRIMARY KEY (`id`,`hash`),
UNIQUE KEY (`hash`)
) ENGINE=InnoDB AUTO_INCREMENT=1;
I understand why the value increases on an update with INNO_DB but I do not understand why it doesn't when the table is partitioned?
you cannot change that, but you can try something like this:
mysql> set #a:= (select max(id) + 2 from hashes);
mysql> insert into hashes (id) values ($value) on duplicate key update id=#a;
NOTE: the partitions change a little bit after mysql 5.6, which version do you have?