The table doesn't have any date time column. I want to if there is any inbuilt keyword which can does that.
I want to know all commits done after a particular date.
If flashback is enabled on the database you can get records on the table in an around a particular date range in Oracle.(It purely depends on if its enabled and for how long the flashback needs to be kept)
You can query to see the data in the table as of 3 days back as follows
select *
from table as of timestamp sysdate-3
I have a table that I use for statistical purposes.
Its columns are id and 1,2,3,..,31 and pivot.
This table gives the number of views on each day for the last 31 days.
1 gives the number of views for yesterday.
14 gives the number of views for 14 days ago.
etc ...
(pivot is just used to calculate the number of views)
I would use a cron job every day to update this table, but how would I go about "shifting" all the values to the side ( value column 15 would become value column 16; new value for column 1; delete value for column 31)
Define a table with only two columns — "date" and "views"
INSERT a new row in the table with the view count for that day when the CRON job runs
Modify your application query to read through this new table over a custom date range, which could be 31 days or anything else either — please have a look at this link to get an idea:
MySQL Query - Records between Today and Last 30 Days
Not really sure how pivot is being used here. However, I'm almost certain that if you're using it to store the sum of the views, it could as well be computed by using SUM() or GROUP BY without having to need a separate column in the table
As far as data archival / removal is concerned, your daily CRON job could be modified to include a DELETE query (as the last step) which cleans up records older than a certain date. Again, you could use the link above to get your "target" date
.
I apologise that this might sound like a little too long a solution to what you've asked for. However, I feel, this approach should help you organise and maintain the table in question in a better way.
I am writing a script which will counts the number of ticket as per as different conditions and store the count in a summary table. I am unable to understand how to structure my table since there will be more than 1 variables.
The script will run every week and with each execution a new week will be added. Once the new month starts and scripts execute, a new month will be added and once new year starts a new year will be added. So in a nutshell I have columns which are also variables. Not sure how to handle it and structure my db.
Have columns Date Service Count.
Like so.
Date Service Count
16 May 2016 Service1 35
Then when you go to display them in the report pivot them as you want. Probably better to make date an INT and either an auto number PK or composite PK of Date and Service.
Wrong approach. Do not splay an array across columns. Instead have rows for the data. This lets you trivially "add" another month.
For displaying, well that is an application problem, no a MySQL problem. Sure, you can write specialized queries to "pivot" the data from rows to columns, but it is messy.
I started building a search engine monitor. I'm pulling data from the google rest api into a mysql database with the following fields: date, search-keyword, domain, url, position.
Now I got into trouble querying and outputting the data for charting. The results go up and down, new results from google come into the list which haven't been there on the first day. However for charting I have to assign the first days at least blank values to output a chart.
What I do right now: First I select every domain showing up in the period. Lets say the for the keyword searchengine I get the domains wikipedia.org, ixquick.com, yahoo.com, searchenginewatch.com When I make another request for ever domain to query an array of rankings grouped by day. leading to the ...
Problem: Is where any query (mysql/nosql) which returns for each day an average and if where is no row a default value e.g. blank?
Result should look like:
dates={01/01/2014,02,03,04,05,06,07,08,...,31}
wikipedie={1,1,1,1,1,1,1,1,...,1}
yahoo = {"","",7,5,3,3,3,...,3}
You can create a date table, select the date range you'd like, and outer join your data to it, filling in 0s for values that do not exist for a given term/date.
Edit:
Some more details.
1) Create a table that has a row for every date +- 10 years (or whatever is appropriate). You can make this one column if you'd like, or many columns (date, month, year, etc.). The second approach makes this extensible if you want to summarize by various rollups in the future.
2) Outer join your table to the date table and use a NVL statement to coerce any null averages to 0.
3) Profit!
If your results are grouped by date, how can MySQL know there's (for example) 31 days in that month?
On the other hand, you can somehow fill the holes in PHP by loop through the array and fill a zero if the value does not exist.
I have a field in a MySQL database which i want to add a certain number each day or week whichever is easier to achieve. For example i have a field with the number 2000 in it and everyday or week i want to add 200 to that number.
Is this possible and if so how can i achieve it?
Just write a SQL function which will return the field times number of week for example.
I do not post a complete function because the question is not that clear about what you expected to return