I need help , I have date ,number ,duration and cost
i want to see a result where a number has been dialed more than once and total cost added together
date number duration cost
17/11/2014 10:32:19 am 0800 00:00:00 0.00
17/11/2014 11:06:47 am 071991 00:02:42 3.54
13/11/2014 02:47:40 pm 060302874 00:00:00 0.00
6/11/2014 11:53:28 am 0100601555 00:00:47 0.50
24/11/2014 12:06:27 pm 0113151407 00:00:46 0.50
19/11/2014 08:37:34 am 0113941905 00:00:47 0.50
24/11/2014 02:48:43 pm 0113941905 00:00:29 0.50
19/11/2014 08:39:16 am 0113949182 00:01:03 0.50
24/11/2014 02:41:57 pm 0113949182 00:00:36 0.50
24/11/2014 12:08:09 pm 0113949182 00:00:43 0.50
24/11/2014 02:50:29 pm 0114922660 00:03:26 1.72
A simple group by number should do it
select number,
sum(cost) total_cost,
count(*) times_dialed,
min(date) earliest_date,
max(date) latest_date
from mytable
group by number
having count(*) > 1
SELECT number
, SUM(cost) total
FROM my_table
GROUP
BY number
HAVING COUNT(*) > 1;
+------------+-------+
| number | total |
+------------+-------+
| 0113941905 | 1.00 |
| 0113949182 | 1.50 |
+------------+-------+
Here you go:
SELECT
number, sum(cost)
FROM myTable as a,
(SELECT
number, count(*) as dials
FROM myTable
GROUP BY 1) as b
WHERE a.number = b.number
and b.dials > 1
GROUP BY 1
Related
How can we query a set of records to get data for particular dates where there might be gaps in dates.
Example Data
date | Price
------------------
2018-03-31 | 115
2018-03-29 | 114
2018-03-28 | 113
...
2017-03-29 | 117
2017-03-28 | 118
...
2016-12-30 | 143
2016-12-29 | 140
...
2015-12-31 | 110
2015-12-30 | 111
Required Data for dates: 2018-03-31, 2017-03-31, 2016-12-31, 2015-12-31
date | Price
------------------
2018-03-31 | 115
2017-03-31 | 117
2016-12-31 | 143
2015-12-31 | 110
You can do this with correlated sub query. The following will return the price for the exact date or the closest prior date:
SELECT dates.dt, (
SELECT price
FROM t
WHERE date <= dates.dt
ORDER BY date DESC
LIMIT 1
) AS price
FROM (
SELECT '2018-03-31' AS dt UNION ALL
SELECT '2017-03-31' UNION ALL
SELECT '2016-12-31' UNION ALL
SELECT '2015-12-31'
) AS dates
Demo on db<>fiddle
You can use MySQL Last day function and date_format to achieve the desired result. Check out the query :-
select last_day(a11.d_date), a11.price
from test a11
join
(select MAX(d_date) d_date, DATE_FORMAT(d_date, "%M %Y")
from test
group by DATE_FORMAT(d_date, "%M %Y")
) a12
on a11.d_date = a12.d_date
SQL Fiddle
seem you need the max price for year
select max(date), max(price)
from my_table m
inner join (
select max(date), year(date) my_year
from my_table
group by year(date)
) t on t.my_year = year(m.date)
group by year(m.date)
I would like know how to get the last value for each week.
Let's say I have the next values
-- Table 1 --
day value
2018-03-12 32
2018-02-14 42
2018-03-16 62
2018-03-19 82
2018-03-20 92
2018-03-21 102
2018-03-27 112
2018-03-28 122
2018-03-29 132
How can I get the next values which are the last values for each week. Assuming the week start on Monday.
Day Value
2018-03-16 62
2018-03-21 102
2018-03-29 132
I have everything settled here SQL Fiddle
You can get the week number of day then get the max value per week number.
select t1.*
from table1 t1
join (
select week(day) as wknum,
max(day) as day
from table1
group by week(day)
) t2
on t1.day=t2.day
Result:
day value
2018-03-16 62
2018-03-21 102
2018-03-29 132
You can group by YEARWEEK()
create table tbl (day date, value int);
✓
insert into tbl values
('2018-03-12', 32),
('2018-02-14', 42),
('2018-03-16', 62),
('2018-03-19', 82),
('2018-03-20', 92),
('2018-03-21', 102),
('2018-03-27', 112),
('2018-03-28', 122),
('2018-03-29', 132);
✓
select day, yearweek(day) from tbl;
day | yearweek(day)
:--------- | ------------:
2018-03-12 | 201810
2018-02-14 | 201806
2018-03-16 | 201810
2018-03-19 | 201811
2018-03-20 | 201811
2018-03-21 | 201811
2018-03-27 | 201812
2018-03-28 | 201812
2018-03-29 | 201812
select day, value
from tbl
join (select max(day) mday
from tbl
group by yearweek(day)) t
on day = mday
day | value
:--------- | ----:
2018-02-14 | 42
2018-03-16 | 62
2018-03-21 | 102
2018-03-29 | 132
dbfiddle here
This solution uses window functions and picks the latest date within the week.
https://dev.mysql.com/doc/refman/8.0/en/window-functions-usage.html
I use SQL Server, but I believe this is the MySQL equivalent:
with cte AS (
SELECT *, ROW_NUMBER() OVER(PARTITION BY WEEKOFYEAR([day]) ORDER BY DAYOFWEEK([day]) DESC) AS counter_
from #table1
)
SELECT [day], [value]
FROM cte
WHERE counter_ = 1
Here's how you would do it in SQL Server - Use mysql equivalent
select b.day, b.value from (
select datepart(ww,day) a, max(day) b
from yourtable
group by datepart(ww,day))a
join yourtable b on a.a=datepart(ww,b.day) and a.b=b.day
Try this FIDDLE:
= Order by the closest to the end of every week
= Group by week
SELECT day, value
FROM (SELECT * FROM table1 ORDER BY DATEDIFF(day + INTERVAL 6 - weekday(day) DAY, day) ASC) t
GROUP BY week(day);
Expenses table
1/1/2016 exp1 2000
13/1/2016 exp11 2500
1/2/2016 exp2 1500
1/3/2016 exp3 1000
10/3/2016 exp1 2000
Income table
1/1/2016 income1 2500
1/2/2016 income2 3500
1/3/2016 income3 1500
10/3/2016 income3 1000
1/4/2016 income4 5000
From single query what I need is group by month, this is what I need
Expenses Incomes Month
4500 2500 Jan
1500 3500 Feb
3000 2500 Mar
0 5000 April
I need the above query to show the data in Google graph
Terrible data structure and format, but not impossible:
SELECT
IFNULL(exp.Expenses,0) Expenses,
IFNULL(inc.Incomes,0) Incomes,
inc.`monthname` `Month`
FROM
(
SELECT
SUM(i.amount) Incomes,
MONTHNAME(STR_TO_DATE(i.`date`, '%d/%m/%Y')) `monthname`,
MONTH(STR_TO_DATE(i.`date`, '%d/%m/%Y')) `month`
FROM
incomes i
GROUP BY
MONTHNAME(STR_TO_DATE(i.`date`, '%d/%m/%Y')),
MONTH(STR_TO_DATE(i.`date`, '%d/%m/%Y'))
) inc
LEFT JOIN
(
SELECT
SUM(e.amount) Expenses,
MONTHNAME(STR_TO_DATE(e.`date`, '%d/%m/%Y')) `monthname`,
MONTH(STR_TO_DATE(e.`date`, '%d/%m/%Y')) `month`
FROM
expenses e
GROUP BY
MONTHNAME(STR_TO_DATE(e.`date`, '%d/%m/%Y')),
MONTH(STR_TO_DATE(e.`date`, '%d/%m/%Y'))
) exp
ON exp.`month` = inc.`month`
ORDER BY
inc.`month`
Output of this simplicity:
+----------+---------+----------+
| Expenses | Incomes | Month |
+----------+---------+----------+
| 4500 | 2500 | January |
| 1500 | 3500 | February |
| 3000 | 2500 | March |
| 0 | 5000 | April |
+----------+---------+----------+
4 rows in set
Anyway better thing seriously how to improve and normalize your data.
In my solution, I give the number of the month rather than text. I'll leave it to you to convert it to text (using a CASE expression, for example) if you wish:
SELECT
sum(expense) AS total_expense, sum(income) AS total_income, trans_month
FROM (
SELECT
month(trans_date) AS trans_month,
0 AS income,
sum(amount) AS expense
FROM expense
GROUP BY month(trans_date)
UNION ALL
SELECT
month(trans_date) AS trans_month,
sum(amount) AS income,
0 AS expense
FROM income
GROUP BY month(trans_date)
) AS a
GROUP BY trans_month;
There is a query I am trying to implement in which I am not having much success with in trying to find the MAX and MIN for each week.
I have 2 Tables:
SYMBOL_DATA (contains open,high,low,close, and volume)
WEEKLY_LOOKUP (contains a list of weeks(no weekends) with a WEEK_START and WEEK_END)
**SYMBOL_DATA Example:**
OPEN, HIGH, LOW, CLOSE, VOLUME
23.22 26.99 21.45 22.49 34324995
WEEKLY_LOOKUP (contains a list of weeks(no weekends) with a WEEK_START and WEEK_END)
**WEEKLY_LOOKUP Example:**
WEEK_START WEEK_END
2016-01-25 2016-01-29
2016-01-18 2016-01-22
2016-01-11 2016-01-15
2016-01-04 2016-01-08
I am trying to find for each WEEK_START and WEEK_END the high and low for that particular week.
For instance, if the WEEK is WEEK_START=2016-01-11 and WEEK_END=2016-01-15, I would have
5 entries for that particular symbol listed:
DATE HIGH LOW
2016-01-15 96.38 93.54
2016-01-14 98.87 92.45
2016-01-13 100.50 95.21
2016-01-12 99.96 97.55
2016-01-11 98.60 95.39
2016-01-08 100.50 97.03
2016-01-07 101.43 97.30
2016-01-06 103.77 100.90
2016-01-05 103.71 101.67
2016-01-04 102.24 99.76
For each week_ending (2016-01-15) the HIGH is 100.50 on 2016-01-13 and the LOW is 92.45 on 2016-01-14
I attempted to write a query that gives me a list of highs and lows, but when I tried adding a MAX(HIGH), I had only 1 row returned back.
I tried a few more things in which I couldn't get the query to work (some sort of infinite run type). For now, I just have this that gives me a list of highs and lows for every day instead of the roll-up for each week which I am not sure how to do.
select date, t1.high, t1.low
from SYMBOL_DATA t1, WEEKLY_LOOKUP t2
where symbol='ABCDE' and (t1.date>=t2.START_DATE and t1.date<=t2.END_DATE)
and t1.date<=CURDATE()
LIMIT 30;
How can I get for each week (Start and End) the High_Date, MAX(High), and Low_Date, MIN(LOW) found each week? I probably don't need a
full history for a symbol, so a LIMIT of like 30 or (30 week periods) would be sufficient so I can see trending.
If I wanted to know for example each week MAX(High) and MIN(LOW) start week ending 2016-01-15 the result would show
**Result:**
WEEK_ENDING 2016-01-15 100.50 2016-01-13 92.45 2016-01-14
WEEK_ENDING 2016-01-08 103.77 2016-01-06 97.03 2016-01-08
etc
etc
Thanks to all of you with the expertise and knowledge. I greatly appreciate your help very much.
Edit
Once the Week Ending list is returned containing the MAX(HIGH) and MIN(LOW) for each week, is it possible then on how to find the MAX(HIGH) and MIN(LOW) from that result set so it return then only 1 entry from the 30 week periods?
Thank you!
To Piotr
select part1.end_date,part1.min_l,part1.max_h, s1.date, part1.min_l,s2.date from
(
select t2.start_date, t2.end_date, max(t1.high) max_h, min(t1.low) min_l
from SYMBOL_DATA t1, WEEKLY_LOOKUP t2
where symbol='FB'
and t1.date<='2016-01-22'
and (t1.date>=t2.START_DATE and t1.date<=t2.END_DATE)
group by t2.start_date, t2.end_date order by t1.date DESC LIMIT 1;
) part1, symbol_data s1, symbol_data s2
where part1.max_h = s1.high and part1.min_l = s2.low;
You will notice that the MAX and MIN for each week is staying roughly the same and not changing as it should be different for week to week for both the High and Low.
SQL Fiddle
I have abbreviated some of your names in my example.
Getting the high and low for each week is pretty simple; you just have to use GROUP BY:
SELECT s1.symbol, w.week_end, MAX(s1.high) AS weekly_high, MIN(s1.LOW) as weekly_low
FROM weeks AS w
INNER JOIN symdata AS s1 ON s1.zdate BETWEEN w.week_start AND w.week_end
GROUP BY s1.symbol, w.week_end
Results:
| symbol | week_end | weekly_high | weekly_low |
|--------|---------------------------|-------------|------------|
| ABCD | January, 08 2016 00:00:00 | 103.77 | 97.03 |
| ABCD | January, 15 2016 00:00:00 | 100.5 | 92.45 |
Unfortunately, getting the dates of the high and low requires that you re-join to the symbol_data table, based on the symbol, week and values. And even that doesn't do the job; you have to account for the possibility that there might be two days where the same high (or low) was achieved, and decide which one to choose. I arbitrarily chose the first occurrence in the week of the high and low. So to get that second level of choice, you need another GROUP BY. The whole thing winds up looking like this:
SELECT wl.symbol, wl.week_end, wl.weekly_high, MIN(hd.zdate) as high_date, wl.weekly_low, MIN(ld.zdate) as low_date
FROM (
SELECT s1.symbol, w.week_start, w.week_end, MAX(s1.high) AS weekly_high, MIN(s1.low) as weekly_low
FROM weeks AS w
INNER JOIN symdata AS s1 ON s1.zdate BETWEEN w.week_start AND w.week_end
GROUP BY s1.symbol, w.week_end) AS wl
INNER JOIN symdata AS hd
ON hd.zdate BETWEEN wl.week_start AND wl.week_end
AND hd.symbol = wl.symbol
AND hd.high = wl.weekly_high
INNER JOIN symdata AS ld
ON ld.zdate BETWEEN wl.week_start AND wl.week_end
AND ld.symbol = wl.symbol
AND ld.low = wl.weekly_low
GROUP BY wl.symbol, wl.week_start, wl.week_end, wl.weekly_high, wl.weekly_low
Results:
| symbol | week_end | weekly_high | high_date | weekly_low | low_date |
|--------|---------------------------|-------------|---------------------------|------------|---------------------------|
| ABCD | January, 08 2016 00:00:00 | 103.77 | January, 06 2016 00:00:00 | 97.03 | January, 08 2016 00:00:00 |
| ABCD | January, 15 2016 00:00:00 | 100.5 | January, 13 2016 00:00:00 | 92.45 | January, 14 2016 00:00:00 |
To get the global highs and lows, just remove the weekly table from the original query:
SELECT wl.symbol, wl.high, MIN(hd.zdate) as high_date, wl.low, MIN(ld.zdate) as low_date
FROM (
SELECT s1.symbol, MAX(s1.high) AS high, MIN(s1.low) as low
FROM symdata AS s1
GROUP BY s1.symbol) AS wl
INNER JOIN symdata AS hd
ON hd.symbol = wl.symbol
AND hd.high = wl.high
INNER JOIN symdata AS ld
ON ld.symbol = wl.symbol
AND ld.low = wl.low
GROUP BY wl.symbol, wl.high, wl.low
Results:
| symbol | high | high_date | low | low_date |
|--------|--------|---------------------------|-------|---------------------------|
| ABCD | 103.77 | January, 06 2016 00:00:00 | 92.45 | January, 14 2016 00:00:00 |
The week table seems entirely redundant...
SELECT symbol
, WEEK(zdate)
, MIN(low) min
, MAX(high) max_high
FROM symdata
GROUP
BY symbol, WEEK(zdate);
This is a simplified example. In reality, you might use DATE_FORMAT or something like that instead.
http://sqlfiddle.com/#!9/c247f/3
Check if following query produces desired result:
select part1.end_date,part1.min_l,part1.max_h, s1.date, part1.min_l,s2.date from
(
select t2.start_date, t2.end_date, max(t1.high) max_h, min(t1.low) min_l
from SYMBOL_DATA t1, WEEKLY_LOOKUP t2
where symbol='ABCDE'
and (t1.date>=t2.START_DATE and t1.date<=t2.END_DATE)
group by t2.start_date, t2.end_date
) part1, symbol_data s1, symbol_data s2
where part1.max_h = s1.high and part1.min_l = s2.low
and (s1.date >= part1.start_date and part1.end_date)
and (s2.date >= part1.start_date and part1.end_date)
I have the next query:
SELECT
a.Date,
(SELECT SUM(Used), SUM(Max) FROM Switch_Statistic b WHERE Date = (SELECT MAX(Date) FROM Switch_Statistic WHERE Switch_ID = b.Switch_ID AND Date <= a.Date))
FROM Switch_Statistic a
GROUP BY Date;
As you see I need to select SUM(Used), SUM(Max) from subquery. With CONCAT is not good solution!
Table schema:
ID --- Switch_ID --- Date --- Max --- Used
Some data:
1 641 2014-10-04 2 16
20 630 2014-10-04 1 7
24 634 2014-10-04 0 8
26 641 2014-10-06 2 16
32 641 2014-10-07 2 16
35 641 2014-10-08 3 16
39 641 2014-10-09 2 16
64 293 2014-10-10 1 22
...
557 38 2014-10-12 3 22
559 293 2014-10-12 1 22
563 294 2014-10-12 6 22
565 641 2014-10-12 2 16
What I need:
Example with CONCAT_WS
mysql> SELECT
a.Date,
(SELECT CONCAT_WS('/', SUM(Used), SUM(Max)) FROM Switch_Statistic b WHERE Date = (SELECT MAX(Date) FROM Switch_Statistic WHERE Switch_ID = b.Switch_ID AND Date <= a.Date)) AS Result
FROM Switch_Statistic a
GROUP BY Date;
+------------+----------+
| Date | Result |
+------------+----------+
| 2014-10-04 | 3/31 |
| 2014-10-06 | 3/31 |
| 2014-10-07 | 3/31 |
| 2014-10-08 | 4/31 |
| 2014-10-09 | 3/31 |
| 2014-10-10 | 249/1587 |
| 2014-10-11 | 354/2147 |
| 2014-10-12 | 360/2185 |
+------------+----------+
8 rows in set (0.26 sec)
Query logic:
1) Select all date's from table
2) SUM - Used and Max for current date, if Switch_ID don't have record for this date, then select the last which exists in table
Link to sqlfiddle - http://sqlfiddle.com/#!2/c3d479
You should be able to do this with just aggregation and no subqueries or joins:
SELECT date, sum(used) as used, sum(max) as max
FROM switch_statistic ss
where ss.date = (select max(date) from Switch_Statistics ss2 where ss2.Switch_id = ss.SwitchId
GROUP BY ss.date;
EDIT:
You seem to want a cumulative sum. In MySQL, this is often best done using variables:
SELECT date, used, max, (#u := #u + used) as cumeused, #m := #m + max) as cumemax
fROM (SELECT date, sum(used) as used, sum(max) as max
FROM switch_statistic ss
GROUP BY ss.date
) ss CROSS JOIN
(SELECT #u := 0, #m := 0) vars
ORDER BY date;