I have three tables which are interlinked :
1) First is order table that contains 2 columns, id and vendor_id
2) Second table is order_products that contains product detail of order table and has columns order_id (foreign key of id from order table) and product_id.
3) Third table is vendors_product that contains prices of products for different vendor like vendor_1 has $10 for product_a and vendor_2 has $20 for product_a so each vendor has different prices of same products. This table has columns, vendor_id (foreign key of vendor_id from order table), product_id (foreign key of product_id from order_products table) and product_amount columns
Now I want to get the sum of product_amount for all order and should be based on vendor of each order.
I tried this by using below query but I couldn't get the result
SELECT
a.id, a.vendor_id, (
SELECT
SUM(product_amount)
FROM
vendors_product
WHERE
vendor_id = a.vendor_id
AND product_id IN (
SELECT
product_id
FROM
order_products
WHERE
order_id = a.id
)
) as total_price
FROM
`order` a
Can somebody help me out ???
Try this:
SELECT o.id, o.vendor_id, SUM(product_amount) product_amount
FROM `order` o
INNER JOIN order_products op ON o.id = op.order_id
INNER JOIN vendors_product vp ON a.vendor_id = vp.vendor_id AND op.product_id = vp.product_id
GROUP BY o.id, o.vendor_id;
Try this:
SELECT a.id, a.vendor_id, SUM(product_amount) AS 'product amount'
FROM `order` a
INNER JOIN order_products vp1 ON a.id = vp1.order_id
INNER JOIN vendors_product vp2 ON a.vendor_id = vp2.vendor_id AND vp1.product_id = vp2.product_id
GROUP BY a.id, a.vendor_id
Related
SELECT avg(Product.product_price)
From product
Where (
SELECT from customer
customer.city = "Tucson"
and Customer.cust_id = orders.cust_id
and Product.product_id = Orderline.product_id
)
group by product_name
UNION
SELECT sum(product.product_price)
From product
Where (
SELECT from customer
customer.city = "Tucson"
and Customer.cust_id = orders.cust_id
and Product.product_id = Orderline.product_id
)
group by product_name
I'm trying to display the average order from customers who order from tucson and the sum of the products going to tuscon
I have these tables with these (rows )orders (order_id, order_date, cust_id), product (product_id, product_name, product_price), orderLine (order_id, product_id, quantity), customer (cust_id, cust_name, street, city, state, zip) I need to 8. Show the average price and total price of products bought by customers from ‘Tucson’(Use Union) –
The problem is not with UNION - it's with the two queries you're attempting to UNION together. It looks to me like the AVG query should be something like:
SELECT avg(p.product_price)
From product p
INNER JOIN orderline ol
ON ol.product_id = p.product_id
INNER JOIN orders o
ON o.??????? = ol.???????
INNER JOIN customer c
ON c.cust_id = o.cust_id
WHERE c.city = 'Tuscon'
What's not clear from the code you posted is how the orders and orderline tables are to be joined - that is, what the common field(s) are in those tables. You'll need to fill that in.
Make similar changes to your SUM query.
I have 2 table - orders and orderdetail.
I need to join them together and show the total. I can join them but how do I calculate the total?
SELECT *
FROM Orders as o
INNER JOIN OrderDetails as od on o.order_id = od.order_id
WHERE o.table_id = 1
select a.order_id,
order_date,
order_status,
table_id,
item_id,
item_price,
quantity,
b.item_price*b.quantity as total
from dbo.orders as a inner join dbo.orderdetails as b
on a.order_id=b.order_id
WHERE table_id = 1
Update : as you mentioned in comment if you want a computed column which automatically multiply quantity and item_price, then you need
execute this query :
ALTER TABLE dbo.orderdetails ADD Total AS (quantity* item_price);
I need some help with the following in SQL:
I have 3 tables which have the following data:
table name:customer
customer ID - 1,2,3,4,5,6
customer Name - customer 1, customer 2,customer 3, customer 4, customer 5, customer 6
table name: transactions
Transaction ID -1, 2,3,4,5,6,7,8
Product ID - 2,2,3,4,2,1,4,2
customer ID - 1,2,4,4,5,6,2,5
table name: product
Product ID - 1,2,3,4
product Name - product 1, product 2, product 3, product 4
I want to know which customer(s) bought product 3 and 4 - the result should be just the customer with an ID of 4.
I have the lines below, however it will only work for 3 OR 4 due to the IN function which means displays customer ID 4 and customer ID 2. I am not sure where to use the AND function in this scenario
select distinct c.customer ID
, c.customer Name
FROM transactions t
LEFT
JOIN customer c
on c.customer ID = t.customer ID
LEFT
JOIN product p
on p.product ID = t.product ID
where p.product ID IN (3,4)`
Thanks
Vishal
Straight forward: select customers that are both in the set of product 3 buyers and product 4 buyers:
select *
from customer
where customer_id in (select customer_id from transactions where product_id = 3)
and customer_id in (select customer_id from transactions where product_id = 4);
It is often faster, however, to query the transaction table only once (by aggregating it by customer).
select *
from customer
where customer_id in
(
select customer_id
from transactions
where product_id in (3,4)
group by customer_id
having count(distinct product_id) = 2
);
use joins:
Select c.CustomerName
from Customer c join Transacation t
on c.Customer_ID = t.Customer_ID
where Product_ID in (3,4)
group by c.CustomerName
having count(distinct Product_ID) = 2
Another way, but not so optimal:
select *
from customer
where customer_id in (select customer_id from transactions where product_id = 3
INTERSECT
select customer_id from transactions where product_id = 4);
One possible query to do that is the following. The inner subquery extracts only customers who have the two products (see last WHERE A.RC=2), simulating the sort of "and condition" you need.
SELECT DISTINCT A.customer_ID, C.customer_Name
FROM (SELECT customer_ID, COUNT(DISTINCT product_ID) AS RC
FROM transactions
WHERE t.product ID IN (3,4)
GROUP BY customer_ID) A
INNER JOIN transactions t ON A.customer_ID = t.customer_ID
LEFT JOIN customer c on c.customer ID = A.customer ID
LEFT JOIN product p on p.product ID = A.product ID
WHERE A.RC=2 AND t.product ID IN (3,4)
You need this instead of IN
where p.product ID = '3' AND p.product ID ='4'
IN uses the OR logic between values thats why you're returning both
I am trying to show the average price of products bought by customers from ‘Tucson’, however this query returns null even though there are two customers that have placed orders from Tuscon.
select AVG(product_price) from product where product_id in
(select product_id from orderline where order_id in
(select order_id from ordertable where cust_id in
(Select cust_id from customer where city = 'Tuscon')))
You're using fom instead of from in your query: select order_id fom ordertable where cust_id in
This should be select order_id from ordertable where cust_id in
fom is not a recognized keyword. The MySQL parser doesn't know what to do with that, so it throws an error about "invalid syntax".
Consider using join operations in place of nested IN subqueries. If we are guaranteed:
product_id is unique in product table
order_id is unique in ordertable table
cust_id is unique in customer table
then we can get an equivalent result set, the average of the price of distinct products that were ordered...
SELECT AVG(p.product_price)
FROM ( SELECT l.product_id
FROM orderline l
JOIN ordertable o
ON o.order_id = l.order_id
JOIN customer c
ON c.cust_id = o.cust_id
WHERE c.city = 'Tuscon'
GROUP BY l.product_id
) q
JOIN product p
ON p.product_id = l.product_id
If we want that "average price" of all products ordered (a different result, with the average taking into account the number of times a product was ordered...then we could use a query like this:
SELECT AVG(p.product_price)
FROM product p
JOIN orderline l
ON l.product_id = p.product_id
JOIN ordertable o
ON o.order_id = l.order_id
JOIN customer c
ON c.cust_id = o.cust_id
WHERE c.city = 'Tuscon'
I try to get a list of products with each newest and lowest offer price
Table product:
id | name
Table offer:
id | product_id | price | created | dealer_id
Table invalids:
id | offer_id | status
I have tried:
SELECT * FROM product INNER JOIN
(
SELECT offer.product_id , offer.price
FROM offer
LEFT JOIN invalids
ON offer.id = invalids.offer_id
WHERE invalids.id IS NULL
GROUP BY offer.dealer_id
ORDER BY offer.created DESC
) o
ON o.product_id = product.id
ORDER BY product.name
I have tried an sqlfiddle http://sqlfiddle.com/#!9/32658/3 with this offer values:
(`id`, `price`, `dealer_id`, `product_id`, `created`)
(1,12.60,1,1,'2015-05-17 08:44:45'),
(2,13.00,1,1,'2015-08-17 08:44:45'),
(3,20.00,1,1,'2015-08-17 08:45:30'),
(4,10.00,1,1,'2015-08-17 08:45:46'),
(5,4.00,2,1,'2015-05-17 08:44:11'),
(6,11.00,2,1,'2015-08-17 08:44:46'),
(7,5.00,2,1,'2015-08-17 08:45:31'),
(9,110.00,2,2,'2015-08-17 08:46:58'),
(10,11.00,2,2,'2015-08-17 08:47:12');
Expected value for product ID 1 is offer ID 7 with price 5.
These steps I think I must realize:
Order offers by created and group by dealer_id to get newest entries
Take result from step 1 and order it by price to get smallest price.
Make this for all products
Maybe I must use a second SELECT FROM offer with GROUP BY and ORDER BY but how do I get I the product_id from the first (outer) select?
Well I would start by getting the latest date for each product offer like this:
SELECT product_id, MAX(created) AS latestOffer
FROM offer
GROUP BY product_id;
Once you have that, you can join it to the original table to get that offer:
SELECT o.*
FROM offer o
JOIN(
SELECT product_id, MAX(created) AS latestOffer
FROM offer
GROUP BY product_id) tmp ON tmp.product_id = o.product_id AND tmp.latestOffer = o.created;
Here is an SQL Fiddle example.
This query should help you:
SELECT *
FROM product
JOIN (
SELECT product_id, min(price) as minPrice, max(created) as newestOffer
FROM offer
WHERE id NOT IN (SELECT offer_id FROM invalids)
GROUP BY 1
) as b
ON product.id = b.product_id
A shot in the dark based on what I understand you to be after...
lots of nested subqueries.. keep thinking there's got to be a better way...
SELECT OO.ID, OO.Price, OO.Dealer_Id, OO.Product_ID, OO.created, P.name
FROM Offer OO
INNER JOIN (
SELECT Min(Price) as MinP
FROM offer O
INNER JOIN (
SELECT max(OI.created) as LatestOffer, OI.Dealer_ID, OI.Product_ID
FROM Offer OI
LEFT JOIN invalids I
on OI.Id = I.offer_Id
WHERE I.ID is null
GROUP BY OI.Dealer_Id, OI.Product_Id
) B
on O.Dealer_Id = B.Dealer_Id
and O.Product_Id = B.Product_Id
and O.Created = B.LatestOffer
) Z
on OO.Price = Z.MinP
INNER JOIN product P
on P.ID = OO.Product_ID
SQL FIDDLE