MYSQL | Get two different records from single table - mysql

Question

Ok. This is kind of complicated.. I have been trying to achieve it and got no where so far.
I have three tables.
leave_approval
leave_applications
ml_leave_type
Here is leave_approval Table
which is then linked to leave_application from leave_application_id
Now here comes the Tricky Question,
i want two records from table.
I want Total leaves taken by employee in year 2014
I want Total Leaves taken by employee in month november of 2014
so means need two columns with two different approaches yearly and monthly.
i have query so far.
SELECT
LA.employee_id,
DATEDIFF(
LA.approved_to,
LA.approved_from
) AS TotalLeavesTaken,
LAPP.`entitlement_id`,
LAPP.`ml_leave_type_id`,
LA.leave_application_id,
LA.approved_from AS LeaveFrom,
LA.approved_to AS LeaveTo
FROM
leave_approval LA
INNER JOIN leave_application LAPP
ON LAPP.application_id = LA.leave_application_id
WHERE YEAR(LA.approval_date) = 2014
AND LA.`employee_id` = 1
and here is the result i am getting for the query..
=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-
UPDATE
May i could not clearly explain my problem.
What i am trying to achieve is add two extra columns not remove the columns i have. i mean i am using most/All of the select fields i have
Plus i want the Total Leaves in Year 2014 in one column and Total Leaves in the month in different field for that given year.
so here is kind of example i want.>
ml_leave_type_id | Total Leaves Taken in Year (e-g 2014) | Total Leaves taken in Month (e-g November)
1 10 2
2 6 0
3 4 1

Answer 1

Would something like that do?
Total leaves for employee_id = 1, Year 2014
SELECT
LA.employee_id,
SUM(
DATEDIFF(
LA.approved_to,
LA.approved_from
)
) AS TotalLeavesTaken,
LAPP.`entitlement_id`,
LAPP.`ml_leave_type_id`,
LA.leave_application_id,
LA.approved_from AS LeaveFrom,
LA.approved_to AS LeaveTo
FROM
leave_approval LA
INNER JOIN leave_application LAPP
ON LAPP.application_id = LA.leave_application_id
WHERE YEAR(LA.approval_date) = 2014
AND LA.`employee_id` = 1
GROUP BY LA.`employee_id` = 1
Total leaves for employee_id = 1, Year = 2014 AND Month = 11
SELECT
LA.employee_id,
SUM(
DATEDIFF(
LA.approved_to,
LA.approved_from
)
) AS TotalLeavesTaken,
LAPP.`entitlement_id`,
LAPP.`ml_leave_type_id`,
LA.leave_application_id,
LA.approved_from AS LeaveFrom,
LA.approved_to AS LeaveTo
FROM
leave_approval LA
INNER JOIN leave_application LAPP
ON LAPP.application_id = LA.leave_application_id
WHERE YEAR(LA.approval_date) = 2014
AND MONTH(LA.approval_date) = 11
AND LA.`employee_id` = 1
GROUP BY LA.`employee_id` = 1
I do notice in your dataset however that there are some dates that are ovelapping. For example:
employee_id = 1 is on leave 2014/11/01 - 2014/11/06 AND 2014/11/05 - 2014/11/08. What's the deal with the dates 2014/11/05 and 2014/11/06. How will the system handle this scenario

Answer 2

Edit2: updated select statement after requirements clarified. The update consist of reorganizing with using a JOIN instead of UNION ALL
select a.*, b.*
from (
SELECT
LA.employee_id,
DATEDIFF(
LA.approved_to,
LA.approved_from
) AS TotalLeavesTaken,
LAPP.`entitlement_id`,
LAPP.`ml_leave_type_id`,
LA.leave_application_id,
LA.approved_from AS LeaveFrom,
LA.approved_to AS LeaveTo
FROM
leave_approval LA
INNER JOIN leave_application LAPP
ON LAPP.application_id = LA.leave_application_id
WHERE YEAR(LA.approval_date) = 2014
AND LA.`employee_id` = 1
) a
JOIN (
SELECT
LA.employee_id,
DATEDIFF(
LA.approved_to,
LA.approved_from
) AS TotalLeavesTaken,
LAPP.`entitlement_id`,
LAPP.`ml_leave_type_id`,
LA.leave_application_id,
LA.approved_from AS LeaveFrom,
LA.approved_to AS LeaveTo
FROM
leave_approval LA
INNER JOIN leave_application LAPP
ON LAPP.application_id = LA.leave_application_id
WHERE MONTHNAME(LA.approval_date) = 'November'
AND LA.`employee_id` = 1
) b
ON a.employee_id = b.employee_id