in array with mysql fetch object - mysql

Hi gus this is my first question in this coumunity i hope someone answer me
when i want to search from array of mysql_fetch_arrray he give me on error
this is the code
$key = "Meca";
$query = "SELECT * FROM subject WHERE `name` LIKE '%$key%' Or `sale` LIKE '%$key%' Or `Emphet` LIKE '%$key%' ";
$sql = mysql_query($query);
$num = mysql_num_rows($sql);
while ($num >0)
{
$row = mysql_fetch_object($sql);
$num--;
$row = mysql_fetch_object($sql);
in_array($row , "Meca");
}`

You are not clear with your question;
Anyway I give a try:
$key = "Meca";
$query = "SELECT * FROM subject WHERE name LIKE '%$key%' Or sale LIKE '%$key%' Or Emphet LIKE '%$key%'";
$result = mysql_query($query);
while ($row = mysql_fetch_array($result)) {
if(in_array($row , "Meca")){
echo "$key is present this time."
}
}
Note that:
I am not on your requirement. So I just make a rough sketch.
You have not provided your error message.
You may have error in your code(SQl or PHP)[like usage of names
'Emphet'].
Anyway give a try.

Related

PDO query returns multiple arrays. How to uniquely identify them?

This query returns 13 individual arrays:
$array = array($pgff_id, $pgfm_id, $pgmf_id, $pgmm_id, $mgff_id, $mgfm_id, $mgmf_id, $mgmm_id, $pgf_id, $pgm_id, $mgf_id, $mgm_id, $fid, $mid);
foreach($array as $id) {
$stmt = $db->prepare("SELECT birth_year, death_year FROM index WHERE id = ?");
$stmt->execute([$id]);
$data = $stmt->fetch(PDO::FETCH_ASSOC);
print_r shows that they look like this:
Array ([birth_year] => 1750 [death_year] => 1824)
Array ([birth_year] => 1770 [death_year] => 1836)
... etc
Is it possible to assign a number or name to these individual arrays? The results are not useful without a way to identify them.
I tried doing it like shown below. This way does number the arrays but orders the results as they are found in the table. I really need the results ordered as they are in $array (which the first method does manage).
$in = str_repeat('?,', count($array) - 1) . '?';
$sql = "SELECT birth_year, death_year FROM index WHERE id IN ($in)";
$stmt = $db->prepare($sql);
$stmt->execute($array);
$data = $stmt->fetchAll();
Taking your code and adding in id as an expression in the query would result in this:
$in = str_repeat('?,', count($array));
$sql = "SELECT id, birth_year, death_year FROM index WHERE id IN ($in)";
$stmt = $db->prepare($sql);
$stmt->execute($array);
$rows = $stmt->fetchAll();
foreach ($rows as $row) {
echo "here starts another row:<br>";
echo "id = ".$row["id"]."<br>";
echo "birth_year = ".$row["birth_year"]."<br>";
echo "death_year = ".$row["death_year"]."<br>";
}
So, that's how you can access it.
You can rearrange the data in the rows after you've received them from the database, again by using a foreach loop:
$birth = [];
$death = [];
foreach ($rows as $row) {
$id = $row["id"];
$birth[$id] = $row["birth_year"];
$death[$id] = $row["death_year"];
}
Now you can access both arrays to get the birth or death year based on the id like this:
echo $birth[4]. 'and '. $death[4];
where id is 4.

Can't get a simple SELECT to work

I have done this type of SELECT many times, but this time I can't get it to work. Any ideas, please?
$Name = "Dick";
$conn = mysqli_connect($server, $dbname, $dbpw, $dbuser);
$sql = "SELECT id FROM table WHERE $Name = table.first_name";
$result = $conn->query($sql);
$row = $result->fetch_assoc();
$customer_id = $row['id'];
Database::disconnect();
echo "customer id = " . $customer_id;
If you really DO have a table named table it would be more appropriate to use back ticks around the name since the word TABLE is a reserved word in MySQL. You should also use single quotes around your variable if it contains a string:
$sql = "SELECT `id` FROM `table` WHERE `first_name` = '$Name'";
Other possible reasons if the query still doesn't work for you:
Make sure you have the connection parameters in the right order. It should be: mysqli_connect($server, $dbuser, $dbpw, $dbname).
You should be using fetch_array() instead of fetch_assoc() if you expect a one row result.
You are mixing PROCEDURAL STYLE with Object Oriented Style when using mysqli_connect() instead of mysqli(), at the same time using $result-> which is object oriented style. You should decide one style and stick with it.
This would be the procedural style of your query:
$Name = "Dick";
$conn = mysqli_connect($server, $dbuser, $dbpw, $dbname); // NOTE THE CHANGED ORDER OF CONNECTION PARAMETERS!
$sql = "SELECT `id` FROM `table` WHERE `first_name` = '$Name'";
$result = mysqli_query($conn, $sql);
$row = mysqli_fetch_array($result, MYSQLI_ASSOC);
$customer_id = $row['id']; // YOUR CUSTOMER ID
mysqli_free_result($result); // FREE RESULT SET
mysqli_close($conn); // CLOSE CONNECTION
And this would be the object oriented style:
$Name = "Dick";
$conn = new mysqli($server, $dbuser, $dbpw, $dbname);
$sql = "SELECT `id` FROM `table` WHERE `first_name` = '$Name'";
$result = $conn->query($sql);
$row = $result->fetch_array(MYSQLI_ASSOC);
$customer_id = $row['id']; // YOUR CUSTOMER ID
$result->free(); // FREE RESULT SET
$conn->close(); // CLOSE CONNECTION
I would recommend naming your table something else than table since it's a reserved word and could get you into parsing problems. The same goes with field names. More reading: https://dev.mysql.com/doc/refman/5.5/en/keywords.html
More about mysqli_fetch_array() and differences in procedural style and object oriented style use: http://php.net/manual/en/mysqli-result.fetch-array.php
$sql = "SELECT id FROM table WHERE '$Name' = table.first_name";
You simply need to concat the variable like this:
$sql = "SELECT id FROM table WHERE " . $Name . " = table.first_name";

How to look for values in database and return an array of values

I'm looking for a way to search a MySQL database for specific values and put these in an array.
The contacts table has name,email,group,Phone...
I would like to search the database by group and return the email adresses in an array, separated by , (comma) to use further in my code.
What is the best way to do this?
$result = mysqli_query($link,"SELECT * FROM Contacts WHERE Group='Group 1'")
or die(mysqli_error());
...
while($row = mysqli_fetch_array( $result ))
{
array ( row->email,...)
}
Here you have different options beginning with:
Update your select query to only display the email, if you don't require the other fields this is the way to go
In your loop just add only the email field to the array
$dataArray[] = $row->email;
$result = mysqli_query($link,"SELECT email FROM Contacts WHERE Group='Group 1'")
or die(mysqli_error());
$emailArray = [];
while($row = mysqli_fetch_array( $result ))
{
array_push($emailArray,$row->email);
}
$responseEmail = implode(",", $emailArray);
Hope this will works!
I found the way of what I was trying to do. I needed a selectbox with values from the database.
....
$query = mysqli_query($link,"SELECT * FROM XXX WHERE category='$category' AND stelplaats='$stelplaats'");
echo '<td><select name ="collega" required>';
echo '<option value"">---</option>';
while ($row2 = mysqli_fetch_array( $query ))
{
echo '<option value =" '.$row2['id'].'"';
echo '>'.$row2['name'].'</option>';
}
echo '</select></td></tr>';
....

how would I change this over to do a full text search instead of LIKE?

after some researching I put this code together to search a mysql table in the db. while it works fine, it limit itself to match the words exactly as the user enters it. anyone know how to make it so that it matches my some sort of relevancy? I have been reading about the full text search but I cant really seem to grasp it.
for example, if you search for 'unanswered questions' in two fields, I want to be able to get result like that include the searched word(s) in any string that it show up in, and list it according to relevancy, like so (search results example output):
- unanswered questions
- answered questions
- answer question
- unanswered questions
- unanswered questions
- questions
- answer
$k = trim ($_GET['search']);
$i = "";
$terms = explode (" ", $k);
$query = "SELECT * FROM table1 WHERE ";
foreach ($terms as $each){
$i++;
if ($i == 1)
$query .= "fld_title LIKE '%$each%' OR fld_keyword LIKE '%$each%' ";
else
$query .= "OR fld_title LIKE '%$each%' OR fld_keyword LIKE '%$each%' ";
}
// connect
include_once "connect.php"; //connect 2 db
$query = mysql_query($query);
$numrows = mysql_num_rows ($query);
if ($numrows > 0){
while ($row = mysql_fetch_assoc ($query)){
//
//
// echo out something here
//
//
}
}else
{
echo "No results found for <b>$k</b>";
}
to do a fulltext search you have to:
Create a Fulltext index in the table (note the fields can't be BLOB)
ALTER TABLE tablename ADD FULLTEXT(field1, field2,...);
in your case:
ALTER TABLE table1 ADD FULLTEXT(fld_title, fld_keyword);
in php change
$k = trim ($_GET['search']);
$i = "";
$terms = explode (" ", $k);
$query = "SELECT * FROM table1 WHERE ";
foreach ($terms as $each){
$i++;
if ($i == 1)
$query .= "fld_title LIKE '%$each%' OR fld_keyword LIKE '%$each%' ";
else
$query .= "OR fld_title LIKE '%$each%' OR fld_keyword LIKE '%$each%' ";
}
for
$k = trim ($_GET['search']);
$query="SELECT * FROM table1 WHERE MATCH(fld_title, fld_keyword) AGAINST ('".$k."')";
if you want to see the relevancy of the results:
$query="SELECT *, MATCH(fld_title, fld_keyword) AGAINST ('".$k."') as relevancy FROM table1 WHERE MATCH(fld_title, fld_keyword) AGAINST ('".$k."')";
The MATCH-AGAINST returns a number: 0 for no match or other depending on matching.
You can "order by relevancy", change the query for make more relevant the search... MATCH(fld_title, fld_keyword) AGAINST ('".$k."') > 0.5
Only one problem: the AGAINST part ($k for you) must be greater than 3 characters.

MySql LIKE returns false if search term is same as entire string in the column, why is that?

So I have following as part of my query
SELECT * FROM $table WHERE columname LIKE '%$searchterm%'
I have tried taking out leading and/or ending wildcards meaning
SELECT * FROM $table WHERE columname LIKE '$searchterm%'
AND
SELECT * FROM $table WHERE columname LIKE '%$searchterm'
AND
SELECT * FROM $table WHERE columname LIKE '%$searchterm%' OR columname LIKE '$searchterm'
and also tried adding following to the query with no luck
OR columname = '$searchterm'
So when my search term is "myval" and if column has whole string "myval", I would like to have that selected. But ALL of my queries above, return false/return nothing where myval is searchterm and column value as full.
I can not use MATCH because this is not Full-Text index.
EDIT:
PHP Code:
$sterm = NULL;
$table = 'mytable';
if(isset($_GET['s'])) { $sterm = explode(" ", mysql_real_escape_string($_GET['s'])); }
if(isset($_POST['s'])) { $sterm = explode(" ", mysql_real_escape_string($_POST['s'])); }
if(!empty($sterm)){
$getdata = "SELECT * FROM $table WHERE termsi != 'Special' ";
foreach ($sterm as $value){
$getdata .= "AND netid_all LIKE '%$value%' OR netid_all = '$value' ";
} //End foreach
$getdata .= "LIMIT 10";
$result = mysql_query($getdata) or die(mysql_error());
$row = mysql_fetch_array($result, MYSQL_ASSOC);
while($row = mysql_fetch_array($result, MYSQL_ASSOC))
{
echo <<<PRINTALL
{$row[0]}, {$row[1]}, {$row[2]}, {$row[3]}, {$row[4]}, {$row[5]}, {$row[6]}, {$row[7]}, ' <br />'
PRINTALL;
} //End While
} //End If search exists
Okay So As you guys suggested, i tried PHPMyAdmin sql console and it works fine, so it would have to be by PHP!? so here it is.
I'd suggest writing your query building like this:
$fullvalues = array();
$partials = array();
foreach ($sterm as $value){
$partials[] = "(netid_all LIKE '%" . mysql_real_escape_string($value) . "%')";
$fullvalues[] = "'" . mysql_real_escape_string($value) . "'";
}
$partials = implode(' OR ', $partials);
$fullvalues = implode(', ', $fullvalues);
$sql = <<<EOL
SELECT *
FROM $table
WHERE (termsi != 'Special')
AND (($partials) OR (netid_all IN ($fullvalues));
EOL;
Assuming your search string is a b c, you'd get this query:
SELECT *
FROM yourtable
WHERE (termsi != 'Special')
AND (((netid_all LIKE '%a%') OR (netid_all LIKE '%b%') OR (netid_all LIKE '%C%')) OR (netid_all IN ('a', 'b', 'c')))
If your search requires that all terms be present, then change the 'OR' to 'AND' in the implode.
Well found it,
$row = mysql_fetch_array($result, MYSQL_ASSOC);
while($row = mysql_fetch_array($result, MYSQL_ASSOC))
Was the problem, earlier when I was testing things, anyhow, it should have been the following
$row = mysql_fetch_array($result, MYSQL_ASSOC);
while($row)