here is my problem:
I have two tables. Every entry of table A has several entries in table B matched over an ID. I now want to get all entries of table A with one data entry of table B - the one with the highest ID in this table.
Table A has an ID
Table B has an own ID and ID_OF_TABLE_A (for the relation between both)
Table A has one to many relation to Table B. I want all Entries of Table A, matched with the one with the highest ID out of B. Is there any way to realize this in an SQL Statement? I tried all kinds of joins since I need the information of that matched entry in the outcome of the select.
How about
SELECT *
FROM tableA a
INNER JOIN tableB b ON a.ID = b.ID_OF_TABLE_A
WHERE b.ID = (SELECT MAX(ID) FROM tableB c WHERE b.ID = c.ID)
Try this:
SELECT a.*, b.*
FROM tableA a
LEFT OUTER JOIN (SELECT b.*
FROM tableB b
INNER JOIN (SELECT ID_OF_TABLE_A, MAX(ID) bID
FROM tableB
GROUP BY ID_OF_TABLE_A
) c ON b.ID_OF_TABLE_A = c.ID_OF_TABLE_A AND b.ID = c.bID
) AS b ON a.ID = b.ID_OF_TABLE_A;
You can use an inline view where you filter the rows you need from table b with the help of the grouping clause and max function like so:
select a.*, b.*
from a
join (
select max(id) as id_b_max, id_a
from b
group by id_a
) b
on a.id = b.id_a;
Tested with:
create table a(id int);
create table b(id int, id_a int);
insert a values (1);
insert b values(1, 1);
insert b values(2, 1);
insert b values(3, 1);
select a.id, max(b.id)
from table_a a join table_b b on a.id = b.table_a_id
group by a.id
This should work. prefilter out the max id of the ID_OF_TABLE_A. and then join on that id.
SELECT A.*, B.*
FROM A
INNER JOIN ( SELECT max( ID ) AS id, ID_OF_TABLE_A
FROM B
GROUP BY ID_OF_TABLE_A) AS grp_b
ON grp_b.ID_OF_TABLE_A = a.ID
INNER JOIN B ON b.ID = grp_b.id
Related
I am currently retrieving data from multiple tables using a cus_id as the initial query. From here I have multiple tables that can have various rows of data that I would like to retrieve and use GROUP_CONCAT to return this data in a single row. At the moment, my query is returning duplicate data based on the max number of rows returned by one of the group concats.
SELECT a.id,c.x,c.y,c.z
GROUP_CONCAT(a.column_a) AS aca,
GROUP_CONCAT(a.column_b) AS acb,
GROUP_CONCAT(b.column_a) AS bca,
GROUP_CONCAT(b.column_b) AS bcb,
FROM `table_a` a
INNER JOIN `table_b` b ON a.id = b.id
INNER JOIN `table_c` c ON a.id = c.id
WHERE a.id = ?
Also, in this scenario, what is the correct join method to use. I am expecting all the fields I am requesting to have some sort of data.
Problem was resolved by using sub queries to isolate the GROUP_CONCAT requests. This allowed me to get only the data I wanted without duplicate results manipulated by other JOIN requests.
SELECT a.id,c.x,c.y,c.z
(SELECT GROUP_CONCAT(column_a) FROM table_a) AS aca,
(SELECT GROUP_CONCAT(column_b) FROM table_a) AS acb,
(SELECT GROUP_CONCAT(column_a) FROM table_b) AS bca,
(SELECT GROUP_CONCAT(column_b) FROM table_b) AS bcb,
FROM table_a a
INNER JOIN `table_c` c ON a.id = c.id
WHERE a.id = ?
Aggregate before joining. Somthing along the lines of:
select
a.*,
b.grp_a,
b.grp_b,
c.grp_x,
b.grp_y
from table_a a
join
(
select
a_id,
group_concat(a order by b_id) as grp_a,
group_concat(b order by b_id) as grp_b
from table_b
group by a_id
) b on b.a_id = a.id
join
(
select
a_id,
group_concat(x order by c_id) as grp_x,
group_concat(y order by c_id) as grp_y
from table_c
group by a_id
) c on c.a_id = a.a_id
order by a.a_id;
I have 2 tables in my SQL database. Let's call them Table A and Table B.
I have joined both the tables using left join on ID = AID. Table A has a field by name ID and Table B has field AID and Price.
The problem is Table B can have multiple prices for the ID present in Table A.
The requirement is - If only one price is present in Table B corresponding to ID in table A then it should return that price.
If more than one price is present in table B for an ID in table A then I should get the price as Zero/null.
Query -
SELECT DISTINCT A.ID,B.Price
from A
left join B
on A.ID = B.AID
where "some condition"
Use Count() with Over() window function to find the count of records for each ID then based on count return the price
Try this way
SELECT DISTINCT A.ID,
case when count(1) over(partition by A.ID) > 1 then NULL else B.Price end
from A
left join B
on A.ID = B.AID
For Mysql
SELECT DISTINCT a.id,
CASE
WHEN c.aid IS NULL THEN NULL
ELSE b.price
END
FROM a
LEFT JOIN b
ON a.id = b.aid
LEFT JOIN (SELECT aid
FROM b
GROUP BY aid
HAVING Count(1) = 1) c
ON a.id = c.aid
For SQL Server (should work for MySQL too). One sub-query (you can put in CTE) that shows only AIDs that have only one price:
SELECT A.ID,
B.Price
FROM A
LEFT JOIN (
SELECT AID
FROM B
GROUP BY AID
HAVING COUNT(Price) = 1
) as C
ON C.AID = A.ID
LEFT JOIN B
ON C.AID = B.AID
Use below query. It should work.
SELECT A.ID, o.Price
FROM A
OUTER APPLY
(
SELECT IIF(COUNT(B.Price)>1,NULL,MAX(B.Price)) AS Price
FROM B
WHERE B.AID = A.ID
) AS o;
I have two tables. Primary key from table A is primary key in table B with another column.
So structure is like this.
Table A
id - PRIMARY
total_amount
Table B
id - PRIMARY
another_id PRIMARY
status
So i can have id from table A appear multiple times in table B.
My problem is that this query
SELECT IFNULL(SUM(total_amount), 0) AS amount
FROM tableA AS a
INNER JOIN tableB AS b
ON a.id = b.id
WHERE a.id = 10
AND status <> 'UNKNOWN'
sometimes returns more in amount the it should.
If total_amount on id 10 is 2, and that same id 10 repeats in table b three times my amount will be 6 instead of 2.
Is there a way I can avoid that. Some other way to write this query.
Thank you.
Use exists instead:
SELECT IFNULL(SUM(total_amount), 0) AS amount
FROM tableA a
WHERE EXISTS (SELECT 1
FROM tableB AS b
WHERE a.id = b.id AND b.status <> 'UNKNOWN'
);
DISTINCT the list of ids returned from tableB
SELECT
IFNULL(SUM(total_amount), 0) AS amount
FROM
tableA AS a INNER JOIN (SELECT DISTINCT id FROM tableB WHERE [status] <> 'UNKNOWN') AS b ON a.id = b.id
WHERE
a.id = 10
So I have two tables like this:
create table A
{
id int;
...
}
create table B
{
id int;
a_id int;
t timestamp;
...
}
A is one-to-many with B
I want to:
SELECT * FROM A LEFT JOIN B ON A.id = B.a_id ???
But I want to return exactly one row for each entry in A which has the B with the newest t field (or null for Bs fields if it has no B entry).
That is rather than returning all A-B pairs, I want to only select the newest one with respect to A (or A-null if no B entry).
Is there some way to express this in SQL? (I'm using MySQL 5.5)
LEFT JOIN is only concerned with ensuring every row in A is returned, even if there is no corresponding joined row in B.
The need for just one row needs another condition. MySQL is limitted in its options, but one could be:
SELECT
*
FROM
A
LEFT JOIN
B
ON B.id = A.id
AND B.t = (SELECT MAX(lookup.t) FROM B AS lookup WHERE lookup.id = A.id)
Another could be...
SELECT
*
FROM
A
LEFT JOIN
(
SELECT id, MAX(t) AS t FROM B GROUP BY id
)
AS lookup
ON lookup.id = A.id
LEFT JOIN
B
ON B.id = lookup.id
AND B.t = lookup.t
You could do the following:
SELECT A.*, B.*
FROM
A
LEFT JOIN
(SELECT B.a_id, MAX(t) as t FROM B GROUP BY B.a_id) BMax
ON A.id = BMax.a_id
JOIN B
ON B.a_id = BMax.a_id AND B.t = BMax.t
you first need to get the newest t from tableB in a subquery, then join it with tableA and tableB.
SELECT a.*, c.*
FROM tableA a
LEFT JOIN
(
SELECT a_ID, max(t) maxT
FROM tableB
GROUP BY a_ID
) b on a.a_id = b.a_ID
LEFT JOIN tableB c
ON b.a_ID = c.a_ID AND
b.maxT = c.t
try this:
SELECT *
FROM tableA A LEFT JOIN
(select a_id ,max(t) as max_t
from tableB
group by a_id )b
on A.id = b.a_id
and A.t=b.max_t
I have two tables.. Table A and Table B (MySQL)
Table-A has id,value,name.. and
Table-B has id,name,email,address..
I like to insert 'id' from Table B as 'Value' in Table A only if that 'id'(TableB) does not exist as'Value' in TableA
So can i use this
INSERT INTO `TableA`( `value`, `name`)
SELECT id,name FROM TableB
WHERE TableB.id NOT IN TableA.value
You need to use code along the lines of the following:
WHERE NOT EXISTS (select * from TableA where TableA.value = TableB.id)
You can use this solution:
INSERT INTO TableA (value, name)
SELECT b.id, b.name
FROM TableB b
LEFT JOIN TableA a ON b.id = a.value
WHERE a.id IS NULL