empty response on model using union - cakephp-3.0

I have the following code
public function findAccessible(Query $query, array $options){
return $this->findPublic($query, $options)
->union($this->findMyAdmin($query, $options));
}
public function findPublic(Query $query, array $options){
return $query
->where(['public' => true]);
}
public function findMyAdmin(Query $query, array $options){
return $query
->where(['admin_user_id' => $options['User.id']]);
}
The findAccessible call gives me this error message in Chrome: ERR_EMPTY_RESPONSE
No other error message, no entry in error log. I am sure that is because of the union call. How to do it?
What I want to achieve:
groups hasAndBelongsTo users
groups: id, name, admin_user_id, public
I would like to get groups
1) what are public groups (This is ok, findPublic method)
2) where admin_user is the given user (This is ok, findMyAdmin method)
3) in where the given user is a member (This is ok, I could do it with an other find()->matching call)
4) which are accessible for the user, eg. public OR the given user is admin OR a member - meaning the union of 1), 2) and 3) - that is with what I am struggling. If I put all these to one find method I can not define OR relationship for the membership, as that is done by matching what is translated into an inner join.

I found a really ugly but working solution.
public function findAccessible(Query $query, array $options){
$qq = $this->query($query);
$memberships = $qq->matching('Users', function($q) use ($options){
return $q->where(['Users.id' => $options['User.id']]);
});
foreach($memberships as $m){
$memberInGroup[] = $m->id;
}
return $query
->where(['public' => true])
->orWhere(['admin_user_id' => $options['User.id']])
->orWhere(['Groups.id IN' => $memberInGroup]);
}
I hope somebody will find a better solution and post here.

Related

Accessing to the `latest` record stored in DB table right after recording it

In Laravel After recording last row to a DB table, can I safely access same recorded data right after recording it by calling latest() queries? Because transactions by other users may occur at the same time, and it may not really be the last record anymore?
Edit:
For example:
Public function StoreNotif($data){
auth()->user()->Notif()->create(store $data here..)
}
Public function SendNotif(){
$data="123";
$this->StoreNotif($data)
event(new Notification(stored Notif instance?));
}
No, you cannot rely on the database to return the record from your current script.
The ->latest() method will always sort the records with the most recent created_at date first.
https://laravel.com/docs/6.x/queries#ordering-grouping-limit-and-offset
But you haven't provided any code or explanation as to why this is a concern. If you just created a new record, why do you need to query it again? You should already have access to an instance of the model.
EDIT: I've made a few edits to demonstrate how you would pass the model from a controller to an event as referenced in the comments. Please post your code if you want more specific help.
SomeController.php
function store()
{
$model = Model::create([
'some_data' => 1
]);
// fire an event with the newly created model
event(new SomeEvent($model));
dd($model);
}
------------------------
Model {
// ...
attributes: [
'id' => 101,
'some_data' => 1
'created_at' => '2019-10-06 12:48:01',
'updated_at' => '2019-10-06 12:48:01',
]
// ...
}
SomeEvent.php
<?php
namespace App\Events;
use App\Model;
use Illuminate\Queue\SerializesModels;
class SomeEvent
{
use SerializesModels;
public $model;
public function __construct(Model $model)
{
$this->model = $model;
// ...
}
}
EDIT: Per your newly added code, you just need to pass the new model back to the original method. You could do something like this.
Public function StoreNotif($data)
{
// add a return statement
return auth()->user()->Notif()->create(store $data here..);
}
Public function SendNotif()
{
$data="123";
// store the returned data to a variable
$model = $this->StoreNotif($data);
// call the event with the model instance
event(new Notification(model));
}
I'm not sure what 'latest' is but I do know that MySQL uses SELECT LAST_INSERT_ID as the query to get the 'per-connection' id of the last inserted item. Under the covers it's using mysql_insert_id so if you are in a language that supports it, you could use that too.

Yii2 Model search query

How can I add where condition to my Articles model so that slug(From category model) is equal to $slug?
And this is a function that Gii generated:
public function getCategory()
{
return $this->hasOne(Categories::className(), ['id' => 'category_id']);
}
Here's my code:
public function specificItems($slug)
{
$query = Articles::find()->with('category');
$countQuery = clone $query;
$pages = new Pagination(['totalCount' => $countQuery->count(),'pageSize' => 12]);
$articles = $query->offset($pages->offset)
->limit($pages->limit)
->all();
return ['articles' => $articles,'pages' => $pages];
}
Your SQL query should contain columns from both article and category table. For that you need to use joinWith().
$result = Articles::find()
->joinWith('category')
->andWhere(['category.slug' => $slug])
->all();
Where 'category' is then name of your category table.
However, in your code you deviate from certain best practices. I would recommend the following:
Have both table name and model class in singular (Article and article). A relation can be in plural, like getCategories if an article has multiple categories.
Avoid functions that return result sets. Better return ActiveQuery class. If you have a query object, all you need to get the actual models is ->all(). However, you can further manipulate this object, add more conditions, change result format (->asArray()) and other useful stuff. Returning array of results does not allow that.
Consider extending ActiveQuery class into ArticleQuery and implementing conditions there. You'll then be able to do things like Article::find()->joinWith('category')->byCategorySlug('foo')->all().

Yii 2 Gridview - Search Query generates ambiguous fields

I am generating related records search query for Gridview use
I get this error :
SQLSTATE[23000]: Integrity constraint violation: 1052 Column 'dbowner' in where clause is ambiguous
The SQL being executed was: SELECT COUNT(*) FROM tbl_iolcalculation LEFT JOIN tbl_iolcalculation patient ON tbl_iolcalculation.patient_id = patient.id WHERE (dbowner=1) AND (dbowner=1)
I have two related models 1) iolcalculation and patient - each iolcalculation has one patient (iolcalculation.patient_id -> patient.id)
The relevant code in my model IolCalculationSearch is :
public function search($params)
{
$query = IolCalculation::find();
$dataProvider = new ActiveDataProvider([
'query' => $query,
]);
$dataProvider->sort->attributes['patient.lastname'] = [
'asc' => ['patient.lastname' => SORT_ASC],
'desc' => ['patient.lastname' => SORT_DESC],
];
$query->joinWith(['patient'=> function($query) { $query->from(['patient'=>'tbl_iolcalculation']); } ]);
if (!($this->load($params) && $this->validate())) {
return $dataProvider;
}
$query->andFilterWhere([
'id' => $this->id,
'patient_id' => $this->patient_id,
'preop_id' => $this->preop_id,
'calculation_date' => $this->calculation_date,
'iol_calculated' => $this->iol_calculated,
The reason this error is generated is that each model has an override to the default Where clause as follows, the reason being that multiple users data needs to be segregated from other users, by the field dbowner:
public static function defaultWhere($query) {
parent::init();
$session = new Session();
$session->open();
$query->andWhere(['t.dbowner' => $session['dbowner']]);
}
this is defined in a base model extending ActiveRecord, and then all working models extend this base model
How Can I resolve this ambiguous reference in the MySQL code?
Thanks in advance
$query->andFilterWhere([
// previous filters
self::tableName() . '.structure_id' => $this->structure_id,
// next filters
]);
I think, that you are searching for table aliases.
(https://github.com/yiisoft/yii2/issues/2377)
Like this, of course you have to change the rest of your code:
$query->joinWith(['patient'=> function($query) { $query->from(['patient p2'=>'tbl_iolcalculation']); } ]);
The only way I can get this to work is to override the default scope find I had set up for most models, so that it includes the actual table name as follows - in my model definition:
public static function find() {
$session = new Session();
$session->open();
return parent::find()->where(['tbl_iolcalculation.dbowner'=> $session['dbowner']]);
}
There may be a more elegant way using aliases, so any advice would be appreciated - would be nice to add aliases to where clauses, and I saw that they are working on this....

Eloquent where clause to use related model's column when using with() -laravel 4

I have 2 models
Truck
class Truck extends \Eloquent {
// Add your validation rules here
public static $rules = [
'trucktype_id' => 'required',
'weight'=> 'required',
'truck_no'=> 'required'
];
// Don't forget to fill this array
protected $fillable = ['trucktype_id','weight','picture_path','remarks','truck_no'];
public function TruckType(){
return $this->belongsTo('TruckType','trucktype_id');
}
}
TruckType
class Trucktype extends \Eloquent {
// Add your validation rules here
public static $rules = array(
'type' => 'required|unique:trucktypes,type',
'max_weight' => 'required'
);
// Don't forget to fill this array
protected $fillable = ['type','max_weight'];
}
I need to lookup related table records i.e TruckType
$trucksobj = Truck::with('TruckType');
if($truck_no!="")
$trucksobj->where("truck_no",'=',$truck_no);
if($start_date!="" && $end_date!="")
$trucksobj->whereBetween('created_at', array($start_date, $end_date));
if($truck_type!="")
$trucksobj->where("trucktype_id",'=',$truck_type);
if($overweight=="on")
$trucksobj->where('TruckType.max_weight', '>=', 0);
But the above query didnt resolve TruckType.max_weight and throws following error
SQLSTATE[42S22]: Column not found: 1054 Unknown column 'TruckType.max_weight' in 'where clause' (SQL: select count(*) as aggregate from trucks where TruckType.max_weight >= 0)
I think you misunderstand how with() actually works. It is only used to alleviate the N+1 query problem, and does not make the contents of the table available for querying. After your first query has ran to select all of the trucks, the with() simply causes the following query to be automatically ran:
select * from TruckType where TruckType.id in (...)
Here the list at the end will contain all of the different truck.trucktype_id values that were found in your first query, and then they'll automatically be available for you to use via $truck->TruckType->{property} etc.
Now, if you actually have a look at the query that's being generated for you, you can clearly see that there is no TruckType table referenced anywhere:
select count(*) as aggregate from trucks where TruckType.max_weight >= 0
This is why the error is being thrown.
You have two options:
(1) Use a join
$trucksobj = Truck::with('TruckType')->join('TruckType', 'truck.trucktype_id', '=', 'TruckType.id')->where('TruckType.max_weight', '>=', 0);
(2) Use whereHas() to place a constraint on your relationship
$trucksobj = Truck::with('TruckType')->whereHas('TruckType', function($q) {
$q->where('max_weight', '>=', 0);
});
If you don't actually need to know anything about the truck type, and you only want to use it to sieve through the trucks, then you can get rid of with('TruckType') and just keep the rest of the query.

Zend Framework - join query

I build a function
public function getBannedByLogin($commentId)
{
$sql = $this->getDbAdapter()->select()
->from(array('comments' => 'comments'), array())
->join(array('users' => 'qengine_users'),
'comments.bannedBy = users.userId',
array())
->where('commentId = ?', $commentId)
;
$row = $this->fetchRow($sql);
return $row['login'];
}
And there are problems, that does'nt work! :D
Let's I explain you. Column 'bannedBy' from comments returns id of user, who give a ban. I need to join this with table users to load a login field. Where i have mistakes?
I assume the code works in the sense of not throwing an exception. If so, your code is OK, you just specifically tell Zend_Db not to select any columns.
public function getBannedByLogin($commentId)
{
$sql = $this->getDbAdapter()->select()
->from(array('comments' => 'comments'))
->join(array('users' => 'qengine_users'),
'comments.bannedBy = users.userId')
->where('commentId = ?', $commentId)
;
$row = $this->fetchRow($sql);
return $row['login'];
}
The last argument to from() and join() functions is an array of columns you wish to select. If you pass in an empty array, no columns are selected. No argument = select everything. You can, of course, specify only the columns you need too.