Using data from 5 different tables on a mysql query - mysql

I need some help on doing multiple Joins, im not very good at this and need a way to get it to work.
There are 5 tables with data and need to get data to output from each table. There is a person, visit, center, date and seenby table. The visit table has ID's to fetch data from other tables. I want to use this table to get the status of the person, to see what date they visited, at what center, their name, and who they were seen by. (i hope this makes sense).
The output should look hopefully like this:
> Person FirstName
> Person LastName
> Seen By
> Date
> Center
> Status
EDIT// Here is a mockup of what i want to see
Ive already read up on pivot tables and would prefer not to use that. Ive created a SQL fiddle here:
http://www.sqlfiddle.com/#!2/d19d2c
EDIT//
Ive managed to write half a query but i doubt it works but i guess its a starting point.
SELECT d.date
, p.Firstname
, p.Lastname
, c.centername
, v.status
, s.FirstName
, s.LastName
FROM visit v
LEFT
JOIN date d
ON v.dateID = d.id
LEFT
JOIN centerName c
ON c.centerID = c.id
Thanks!

From your table structure it would seem you want a query like this:
SELECT
d.date,
CONCAT_WS(' ', p.Firstname ,p.Lastname) AS "Person",
v.status,
CONCAT_WS(' ', s.FirstName, s.LastName) AS "Seenby",
c.centername
FROM visit v
JOIN person p ON v.PersonID = p.ID
JOIN seenby s ON v.seenbyID = s.ID
LEFT JOIN date d ON v.dateID = d.id
LEFT JOIN center c ON v.centerID = c.id
The last two joins should maybe be normal inner joins and not left joins, adjust as appropriate.
TheCONCAT_WS()function concatenates its parameters into a string, using the value of the first parameter as separator (a space in this case).
Sample SQL Fiddle

Related

NOT LIKE on mysql query

I have a big problem understanding why a query works when using LIKE in query and not working when using NOT LIKE.
I will post query below:
select DISTINCT (mails), name
from disposable
JOIN (
SELECT DISTINCT (mail) as mails,
CONCAT(toys.firstname, ' ' , toys.lastname) as name
FROM toys2
join toys ON toys.userid = toys2.id
where ( (toyid = '27' or toyid = '29')
and status != 'Sold'
and toys.regdate >= '2017-01-01'
)
) as tab
WHERE tab.mails LIKE CONCAT('%#', disposable.email)
I think what you want is something more like the following. Note that I simplified the schema a bit so as to do a bit less work for the SQL Fiddle.
SELECT c.email, c.name
FROM customer c LEFT JOIN disposable d
ON SUBSTR(c.email, INSTR(c.email, '#')+1, LENGTH(c.email)-INSTR(c.email, '#')) = d.email
WHERE d.email IS NULL;
Basically, here you're getting the domain of the customer and matching it to the entry in the disposable table. The final WHERE clause uses IS NULL to determine the customer email addresses that are not disposable - use IS NOT NULL to find the ones that are.
Hope this helps.

Order using count from another table

Hi I need to Order using count from another table. i found this great example, im using it as model for a query i need. SQL - How To Order Using Count From Another Table
The model im using for query is:
SELECT bloggers.*, COUNT(post_id) AS post_count
FROM bloggers LEFT JOIN blogger_posts
ON bloggers.blogger_id = blogger_posts.blogger_id
GROUP BY bloggers.blogger_id
ORDER BY post_count
But i have a syntax problem in mine, i guess, im trying to replace the next query, with the one that counts another table... but i cant manage to do it. Original query:
$res3=$db->execute_query("select id,scode,sname from ".TABLE_PREFIX."states where ccode=? order by sname asc",array($country));
Trying to replace with this query..
$res3=$db->execute_query("select ".TABLE_PREFIX."states.* , COUNT(".TABLE_PREFIX."items.state) AS state_count FROM ".TABLE_PREFIX."states LEFT JOIN ".TABLE_PREFIX."items ON ".TABLE_PREFIX."states.id = ".TABLE_PREFIX."items.state GROUP BY ".TABLE_PREFIX."states.id ORDER BY state_count DESC",array($country));
Try this:
$res3=$db->execute_query("select a.* , COUNT(b.state) AS state_count FROM states a
LEFT JOIN items b ON a.id = b.state
GROUP BY a.id
ORDER BY state_count DESC",array($country));

MySQL - Trying to show results for rows that have 0 records...across 3 columns

There's a lot of Q&A out there for how to make MySQL show results for rows that have 0 records, but they all involve 1-2 tables/fields at most.
I'm trying to achieve the same ends, but across 3 fields, and I just can't seem to get it.
Here's what I've hacked together:
SELECT circuit.circuit_name, county.county_name, result.adr_result, count( result.adr_result ) AS num_results
FROM
(
SELECT cases.case_id, cases.county_id, cases.result_id
FROM cases
WHERE cases.status_id <> "2"
) q1
RIGHT JOIN county ON q1.county_id = county.county_id
RIGHT JOIN circuit ON county.circuit_id = circuit.circuit_id
RIGHT JOIN result ON q1.result_id = result.result_id
GROUP BY adr_result, circuit_name, county_name
ORDER BY circuit_name, county_name, adr_result
What I need to see is a list of ALL circuits in the first column, a list of ALL counties per circuit in the second column, a list of ALL possible adr_result entries for each county (they're the same for every county) in the third column, and then the respective count for the circuit/county/result combination-- even if it is 0. I've tried every combination of left, right and inner join (I know inner is definitely not the solution, but I'm frustrated) and just can't see where I'm going wrong.
Any help would be appreciated!
Here is a start. I can't follow your problem statement completely. For instance, what is the purposes of the cases table? None the less, when you say "ALL" records for each of those tables, I interpret it as a Cartesian product - which is implemented through the derived table in the FROM clause (notice the lack of the JOIN in that clause)
SELECT everthingjoin.circuit_name
, everthingjoin.county_name
, everthingjoin.adr_result
, COUNT(result.adr_result) AS num_results
FROM
(SELECT circuit.circuit_name, county.county_name, result.adr_result,
FROM circuit
JOIN county
JOIN result) AS everthingjoin
LEFT JOIN cases
ON cases.status_id <> "2"
AND cases.county_id = everthingjoin.county_id
LEFT JOIN circuit
ON everthingjoin.circuit_id = circuit.circuit_id
LEFT JOIN result
ON cases.result_id = result.result_id
GROUP BY adr_result, circuit_name, county_name
ORDER BY circuit_name, county_name, adr_result
try this, see if it provides some ideas:
SELECT
circuit.circuit_name
, county.county_name
, result.adr_result
, ISNULL(COUNT(result.*)) AS num_results
, COUNT(DISTINCT result.adr_result) AS num_distinct_results
FROM cases
LEFT JOIN county
ON cases.county_id = county.county_id
LEFT JOIN circuit
ON county.circuit_id = circuit.circuit_id
LEFT JOIN result
ON cases.result_id = result.result_id
WHERE cases.status_id <> "2"
GROUP BY
circuit.circuit_name
, county.county_name
, result.adr_result
ORDER BY
circuit_name, county_name, adr_result

return results of same ID from 2 tables

I'm using an opensource database, so it's setup is a bit over my head.
Its basically like this.
A persons normal information is in the table 'person_per'
There is custom information in the table 'person_custom'
both use 'per_ID' to organize.
select per_ID from person_custom where c3 like '2';
gives my the IDs of people who fit my search, I want to "join" (I think) their name, phone, ect from the 'person_per' table using the ID as the "key"(terms I read that seem to fit).
How can I do that in a single query?
select per.*
from person_per per
inner join person_custom cus on cus.per_id = per.per_id
where cus.c3 = 2
You can retrieve all the columns from both tables with a single query:
SELECT p.name
, p.phone
, p.ect
, c.custom_col
FROM person_per p
JOIN person_custom c
ON c.per_ID = p.per_ID
WHERE c.c3 LIKE '2'
Use a JOIN operator between the table names, and include the "matching" criteria (predicate) in the ON clause.

MySQL: UPDATE with a JOIN and a GROUP_CONCAT

Is this possible?
I have 2 tables, Customers and Orders. Now I want to fill a column in Customers with all order id's of that customer (comma separated).
I tried something like this, but it doesnt work:
UPDATE customers AS c
LEFT JOIN orders AS o ON o.customerid=c.customerid
SET c.orders = GROUP_CONCAT(DISTINCT o.orderid)
I get 'Invalid use of group function'.
PS. I know it's better to always dynamically get the GROUP_CONCAT values in a SELECT/JOIN, but I'm just wondering if I can fill this column in some way.
You will need to add an order by in the group_concat as shown in the example below
Note: group_concat(version ORDER BY version SEPARATOR ',')
UPDATE
items i,
(SELECT pduid, group_concat(version ORDER BY version SEPARATOR ',') AS 'versions'
from items GROUP BY pduid) AS version_lookup
SET i.versions = version_lookup.versions
WHERE version_lookup.pduid = i.pduid
None of the given answers here were working for me, possibly because my case was more complicated (I needed more than one join), so I used Dennis' solution but split it into a temporary table:
CREATE TEMPORARY TABLE version_lookup
SELECT pduid, group_concat(version ORDER BY version SEPARATOR ',') AS 'versions'
from items GROUP BY pduid;
UPDATE
items i, version_lookup
SET i.versions = version_lookup.versions
WHERE version_lookup.pduid = i.pduid;
Basically you should not use the GROUP_CONCAT function in this manner, that's not the right way of making your work done.
In this scenario you can use nested queries approach instead of trying with JOINs as I specified below, try this query, hopefully this should do your work correctly.
UPDATE customers AS c
SET c.orders =
(SELECT GROUP_CONCAT(DISTINCT o.orderid)
FROM orders AS o
WHERE o.customerid = c.customerid
GROUP BY o.customerid);
Try this query once and then let me know if you are facing any more issues.
Siva
You forget to tell the GROUP BY clause.
UPDATE customers AS c
LEFT JOIN orders AS o ON o.customerid=c.customerid
SET c.orders = GROUP_CONCAT(DISTINCT o.orderid)
GROUP BY o.customerid