Order a VARCHAR column numerically - mysql

Current SQL: SELECT code FROM myTable ORDER BY code ASC
code
---
11
113
12
13A
This is the current order I have of a MySQL table.
I want the order to be A-Z, 1-10 however, numerically, like this:
code
---
11
12
13A
113
The reason I cannot achieve this effect in the first place is because the code column is varchar and not int. However as shown in the example, some codes have a letter prepended to them so I cannot change this to integer.
How can I get around this problem without changing the data type?

The simplest way is to use silent conversion. Just add 0:
order by code + 0
In practice, you might want:
order by code + 0, code

This should work, sorting by number first and alpha after (if the same number):
select * from myTable
order by cast(replace(code,'[0-9]+','') as unsigned), code
See this SQL Fiddle

Related

Get least 10 values in mysql query

I have a table in mysql. Table Name is constitutive_table, it contains more than 40 columns and its type is varchar, it contains more than 25000 records. I wrote the query like this to get the 10 least value. But it showing like as you have seen in the picture.
SELECT `Sequence_Name`
, `Name_of_the_Protein`
, `Brain`
FROM `constitutive_table`
where `Brain` != 0
ORDER
BY cast(Brain AS int)
LIMIT 0,10
The data in the Brain column appears to be floating point, so you should be casting to the appropriate type:
SELECT Sequence_Name, Name_of_the_Protein, Brain
FROM constitutive_table
WHERE CAST(Brain AS DECIMAL(14, 8)) <> 0
ORDER BY CAST(Brain AS DECIMAL(14, 8))
LIMIT 10
Most likely what is happening now is that the 10 values you see all have the same value when cast to integer. As a result, MySQL is using some secondary sort to generate the order you do see.
While the above query may resolve your problem, ideally you should change the Brain column to some numeric type.

MySQL sorting with alphanumeric prefix

I've got a database with a column that contains the following data:
aaa-1
aaa-2
aaa-3
...
aaa-10
aaa-11
...
aaa-100
aaa-101
...
aaa-1000
When I query and sort the data in ascending order, I get:
aaa-1
aaa-10
aaa-11
...
aaa-100
aaa-101
...
aaa-1000
...
aaa-2
...
aaa-3
Is this actually the correct (machine) way of sorting? Is the order being screwed up because of the aaa- prefix? How do I go about sorting this the way a human would (ie something that looks like the first snippet)?
P.S. If the problem does lie in the prefix, is there a way to remove it and sort with just the numeric component?
P.P.S. It's been suggested to me that I should just change my data and add leading zeroes like aaa-0001 and aaa-0002, etc. However, I'm loathe to go that method as each time the list goes up an order of 10, I'd have to reformat this column.
Thank you all in advance! :)
You can extract the number part, convert it to numeric data type and then do an ORDER BY:
SELECT mytable.*,
CAST(SUBSTRING_INDEX(mycolumn, '-', - 1) AS UNSIGNED) mycolumnintdata
FROM
mytable
ORDER BY mycolumnintdata;
If there are expressions which does not match number, the CAST function would return 0 and those records would be displayed first. You may handle this separately if needed.
I had a similar issue and the trick that did it for me was this one
*"ORDER BY LENGTH(column_name), column_name
As long as the non-numeric part of the value is the same length, this will sort 1 before 10, 10 before 100, etc."*
as given by Andreas Bergström on this question.
Hope that helps someone.
this is the alphabetical order,
you want numerical order,
for do this you must in the ORDER BY clause
trim the costant "aaa-" part
convert it in number
convert(SUBSTRING(val, 3), integer)
I will give you a sample sorting. Not based on your data sample, but this could help you out.
Say you have data like this :
id
----
1
2
6
10
13
when you do ORDER BY id ASC would return :
id
----
1
10
13
2
6
I suggest, use LPAD.
This query : SELECT LPAD('12',5,'0') return 00012
So when you have table data like I provide above, you can sort them like this :
SELECT * FROM TABLE
ORDER BY LPAD(ID,7,'0') ASC
Based on your data.
SELECT SUBSTR('aaa-100',5,LENGTH('aaa-100') - 3) return 100
So, SELECT LPAD( SUBSTR('aaa-100',5,LENGTH('aaa-100') - 3), 7, '0') return 00000100
So you can combine string function such as SUBSTR and LPAD. Do have any clue now?

Need a help for sort in mysql

Hi I want to sort a table .The field contains numbers,alphabets and numbers with alphabets ie,
1
2
1a
11a
a
6a
b
I want to sort this to,
1
1a
2
6a
11a
a
b
My code is, SELECT * FROM t ORDER BY CAST(st AS SIGNED), st
But the result is,
a
b
1
1a
2
6a
11a
I found this code in this url "http://www.mpopp.net/2006/06/sorting-of-numeric-values-mixed-with-alphanumeric-values/"
Anyone please help me
This would do your required sort order, even in the presence of 0 in the table;
SELECT * FROM t
ORDER BY
st REGEXP '^[[:alpha:]].*',
st+0,
st
An SQLfiddle to test with.
As a first sort criteria, it sorts anything that starts with a letter after anything that doesn't. That's what the regexp does.
As a second sort criteria it sorts by the numerical value the string starts with (st+0 adds 0 to the numerical part the string starts with and returns an int)
As a last resort, it sorts by the string itself to get the alphabetical ones in order.
You can use this:
SELECT *
FROM t
ORDER BY
st+0=0, st+0, st
Using st+0 the varchar column will be casted to int. Ordering by st+0=0 will put alphanumeric rows at the bottom (st+0=0 will be 1 if the string starts with an alphanumeric character, oterwise it will be 0)
Please see fiddle here.
The reason that you are getting this output is that all the character like 'a', 'b' etc are converted to '0' and if you use order by ASC it will appear at the top.
SELECT CAST(number AS SIGNED) from tbl
is returning
1
2
1
11
0
6
0
Look at this fiddle:- SQL FIDDLE
I did small change in your query -
SELECT *, CAST(st AS SIGNED) as casted_column
FROM t
ORDER BY casted_column ASC, st ASC
this should work.
in theory your syntax should work but not sure why mysql doesn't accept these methods after from tag.
so created temp field and then sorted that one .
This should work as per my experience, and you can check it.
SQL FIDDLE

MySql ordering problem

Consider the situation i have a table name "test"
-------
content (varchar(30))
-------
1
abc
2
bcd
-------
if i use order by
Select * from test order by content asc
i could get result like
--------
content
--------
1
2
abc
bcd
---------
but is there any way i could get the following result using query
--------
content
--------
abc
bcd
1
2
---------
To get by the collation, you can do by testing the first character... it appears you want anything starting with a numeric to be after anything alhpa oriented... something like the ISNUMERIC() representation by Ted, but my quick check doesn't show such function in MySQL.. So an alternative... because numerics in ASCII list are less than "A" (char 65)
Select *
from test
order by
case when left( content, 1 ) < "A" then 2 else 1 end,
content
Although I've seen different CONVERT() calls, I don't have MySQL available to confirm. However, in addition to the above case/when, you can add a SECOND case/when and call some UDF() or other convert function on the "content" value. If the string starts as alpha, it should return a zero value so the first case/when will keep them to the top of the list, then since all are all non-convertible to numeric would have a value of zero... no impact on the sort, then finally the content itself which will keep in alpha order.
HOWEVER, if your second case/when / convert function call DOES return a numeric value, then it will be properly sorted within the numeric grouping segment... which will then supercede that of the content... However, if content was something like
100 smith rd and
100 main st
they will sort in the same "100" category numeric value, but then alphabetically by the content as
100 main st
100 smith rd
100
this will do it:
SELECT *
FROM test
ORDER BY CAST(field AS UNSIGNED), field ASC
select * from sometable order by content between '0' and '9', content
Not sure on MySql but on SQL Server you can do this...
SELECT * FROM test
ORDER BY IsNumeric(content), content
The order of results is defined by collation used, so if you can find the right collation then yes.
http://dev.mysql.com/doc/refman/5.0/en/charset-collate.html
//edit
This is tricky. I've done some research and it seems that no currently available collation can do that. However there's also possibility to add new collation to MySQL. Here's how.

mysql sort varchar with numbers

How can I sort this data numerically rather than lexicographically?
100_10A
100_10B
100_10C
100_11A
100_11B
100_11C
100_12A
100_12B
100_12C
100_13A
100_13B
100_13C
100_14A
100_14B
100_14C
100_15A
100_15B
100_15C
100_16A
100_16B
100_16C
100_1A
100_1B
100_1C
100_2A
100_2B
100_2C
100_3A
100_3B
100_3C
100_4A
100_4B
100_4C
100_5A
100_5B
100_5C
100_6A
100_6B
100_6C
100_7A
100_7B
100_7C
100_8A
100_8B
100_8C
100_9A
100_9B
100_9C
select generalcolum from mytable order by blockid, plotid ASC
What I need out of this sort order is
100_1A
100_1B
100_1C...
...
...
100_10A
100_10B
100_10C
What I need to do in some way is have a zero added before the sort happens so that, I can get them in the order I want.
There are two colums, one that stores the 100 (number before the underscore) and one that stores the 1A the value after the underscore.
My sudo crap select
select thiscolum this table
order by blockid, plotid(+1 zero to prefix if len(plotid) < 2)
For example if the plot value is 1A, to do the best sorting, i need it to be looked at as 01A so that it comes before 10A.
order by length(blockid), blockid, length(plotid), plotid