I've got tables:
Table1= USER_ID ITEM_ID
1 12
1 13
2 12
3 12
3 1
3 2
etc..
And second table:
Products = ITEM_ID PRICE
1 1.3
2 0.1
4 22
12 33
13 45
It is just example. How can I get ID's of clients who paid more than average order value?
I tried many times, but I always get errors.
You can do a JOIN between the tables and comparing the average price with specific user price paid like
select t1.user_id
from table1 t1
join products p on t1.item_id = p.item_id
group by t1.user_id
having p.price > avg(p.price);
Related
I have 2 tables.
table customer have. id , name , age
table order have . id, customer_id , order_amount , order date.
I want to show all name from customer table and sum of order amount from order table according to customer.
customer_id
Name
age
1
Alice
24
2
Bob
52
3
Carol
45
4
Dave
51
order_id
customer_id
order_amount
order_date
1
2
50
2012-4-5
2
1
27
2012-8-1
3
2
12
2013-5-20
4
4
25
2014-1-25
5
4
30
2014-5-30
6
1
20
2014-6-22
EDIT
I tried this but it gives me only bob and sum of all columns instead of separate sum of customers
SELECT customers.name, SUM(orders.order_amount) FROM `orders` INNER JOIN customers WHERE orders.customer_id = customers.customer_id;
Joining condition must be on ON clause, not in WHERE.
You must specify for what group the sum must be calculated.
SELECT customers.name, SUM(orders.order_amount)
FROM `orders`
INNER JOIN customers ON orders.customer_id = customers.customer_id
GROUP BY customers.name;
I m new to this community and also new to MySQL.
Need to COUNT the clients and SUM the commission for each referrer respectively using MySQL query.
referrer table
id
referrer_name
1
referre1
2
referre2
3
referre3
4
referre4
client table
id
referrer_id
client_name
1
1
client1
2
1
client2
3
2
client3
4
3
client4
5
4
client5
commission table
id
client_id
commission
1
1
20
2
1
32
3
3
24
4
4
15
I want to achieve below output using above 3 tables.
referrer_id
referrer_name
total_client
total_commission
1
referre1
2
52
2
referre2
1
24
3
referre3
1
15
4
referre4
1
0
I have tried the following query
SELECT referrer.referrer_name as name,
(SELECT COUNT(*) FROM client WHERE client.referrer_id=referrer.id) as total_client,
(SELECT SUM(commission) FROM commission WHERE commission.client_id=client.id) as total_commission FROM referrer LEFT JOIN client ON client.referrer_id=referrer.id GROUP BY name;
Read Mysql join and Aggregate Functions
SELECT t2.referrer_id,
t1.referrer_name,
COUNT(DISTINCT t2.id) AS total_client,
SUM(t3.commission) AS total_commission
FROM referrer t1
JOIN client t2 ON t1.id = t2.referrer_id
JOIN commission t3 ON t2.id = t3.client_id
GROUP BY t1.referrer_id
I have 2 tables (example):
users:
ID company_ID
1 7
2 6
3 7
activity_rewards:
user_ID points activity_type_ID
1 1 7
1 2 7
1 1 7
1 1 8
2 1 7
2 1 7
2 2 8
2 1 7
3 2 7
3 1 7
3 2 8
3 1 8
(There are also tables for company and activity_types, but they shouldn't be relevant here)
I need a MYSQL query that will sum the total points for each user WHERE all users have a certain company_ID and for a certain activity_type_ID AND it will return the MAX and the AVG of the sum of all the users points
I have for example:
SELECT SUM(activity_rewards.points) AS totalpoints,
MAX(activity_rewards.points) AS maxpoints,
AVG(activity_rewards.points) AS avgpoints
FROM activity_rewards
INNER JOIN users
ON activity_rewards.user_ID = users.ID
WHERE ( (users.company_ID = "7") && (activity_rewards.activity_type_ID LIKE '8') )
In the example query only 3 results are involved. They are:
user_ID points activity_type_ID
1 1 8
3 2 8
3 1 8
I want to get:
user 1 has 1 point
user 3 has 3 points
Max is 3 average is 2
instead I'm getting Max is 2 and average is 1.33
The results are in line with your query, but your query is not in line with your requirements.
Your query calculates the max and the average of points across the relevant records. But you seem to want the max and the average of the points summed by user id.
This means that you need to calculate the sum of points per user in a subquery and then calculate the max and average in the outer query.
SELECT SUM(sumpoints) as totalpoints, max(sumpoints) as maxpoints, avg(sumpoints) as avgpoints
FROM
(SELECT users.ID, SUM(activity_rewards.points) AS sumpoints
FROM activity_rewards
INNER JOIN users ON activity_rewards.user_ID = users.ID
WHERE users.company_ID = 7 and activity_rewards.activity_type_ID = 8
GROUP BY users.ID) t
Do it like this:
SELECT MAX(sum_points) max, AVG(sum_points) avg, SUM(sum_points) sum_all FROM (SELECT SUM(t2.points) sum_points FROM users t1 JOIN activity_rewards t2 ON (t1.ID = t2.user_ID) WHERE ( (t1.company_ID = "7") AND (t2.activity_type_ID = '8') ) GROUP by t1.ID) as summation
I've the two tables orders
id article amount
1 1 1
2 2 50
and prices
id article min_amount price
1 1 1 42.99
2 2 1 5.06
3 2 5 4.55
4 2 10 4.3
5 2 25 4.05
6 2 100 2.66
The prices tables contains IDs of articles and a minimum amount you would have to buy to get a bulk discount (which would change the price for the order). I would like to join prices into orders, so that the result looks like:
id article amount price
1 1 1 42.99
2 2 50 4.05
The order id 2 is above the minimum (25) to get the article for 4.05€, but still below 100 at which you would get a bigger discount, so the query would to have pick the next-lower value.
I've tried this query so far
SELECT
orders.id AS id,
orders.article,
orders.amount,
prices.price,
(orders.amount - prices.min_amount) AS discount_diff
FROM orders
LEFT JOIN prices ON (prices.article = orders.article) AND (prices.min_amount <= orders.amount)
which gives this result
id article amount price discount_diff
1 1 1 42.99 0
2 2 50 5.06 49
2 2 50 4.55 45
2 2 50 4.3 40
2 2 50 4.05 25
You can find this example on "js"fiddle: http://sqlfiddle.com/#!9/1b2bf/8
The query you need is this:
SELECT orders.id AS id,
orders.article,
orders.amount,
prices.price
FROM orders
INNER JOIN prices ON ( prices.article = orders.article
and prices.min_amount <= orders.amount)
INNER JOIN ( SELECT orders.article,
orders.amount,
min(prices.price) minprince
FROM orders
INNER JOIN prices ON (prices.article = orders.article
AND prices.min_amount <= orders.amount)
GROUP BY orders.article,
orders.amount) b
ON ( prices.article = b.article
AND orders.amount = b.amount
AND prices.price = b.minprince)
See it here: http://sqlfiddle.com/#!9/1b2bf/27
I have this working query
SELECT t1.id as stockid, t1.description as stockdescription, t2.inkoop as price , COUNT(t2.inkoop) as cnt,
(t2.inkoop * COUNT(t2.inkoop)) as totalamount
FROM database1.table_products t1
LEFT JOIN database1.table_stock t2 ON t1.id = t2.stock_id
WHERE 1
GROUP BY t2.inkoop
ORDER BY t1.id ASC
1 database, 2 tables:
t1 is the products 'description' database with ids and description
t2 is the stock, which has a lot of products for what price (purchased) and referenced by stock_id
Output:
id stockdescription price cnt totalamount
1 Product1 1067 15 16005
1 Product1 1290 103 132870
2 Product2 2750 70 192500
3 Product3 500 0 0
But now i have this 2nd database (database2) with a second inventory table (stock2) (exactly the same structure as database1.table_stock)
How do i alter my query so i can also add 'cnt2' and change total to my results?
Like this:
id stockdescription price cnt cnt2 totalcnt totalamount
1 Product1 1067 15 0 15 16005
1 Product1 1290 103 0 103 132870
2 Product2 2750 70 5 75 206250
3 Product3 500 0 4 4 2000
You can join multiple tables, but you'd get the full join of the two stock tables, which means you'd get wrong counts after the GROUP BY. You can avoid that by nesting your queries, e.g. along these lines:
SELECT sub.*, COUNT(stock2.inkoop) AS cnt2
FROM ( <paste your query here> ) AS sub
LEFT JOIN database2.stock2 AS stock2 ON sub.stockid = stock2.stock_id
GROUP BY sub.stockid
ORDER BY sub.stockid ASC
Now you have two left joins, each with its own GROUP BY. So each left join only sees a single left hand table factor, and you won't get duplicates caused by joining too many tables at once.