I cannot understand why my query
SELECT SUM(DATE(date) = '2014-11-2') AS `rate` FROM `ratings` UNION SELECT COUNT(*) AS `users` FROM `user`
doesn't create two values - rate, users as in query but only one - rate - with two values.
Result:
rate
6
10
Expected result:
rate users
6 10
Do you know, what's wrong with my query?
You should do a JOIN instead of an UNION.
Based on the information you shared and the result you want to achieve, your query could look something like this:
SELECT SUM(DATE(date) = '2014-11-2') AS `rate`, (
SELECT COUNT(*) FROM `user`
) AS `users`
FROM `ratings`
...but this lacks of some relations/conditions between the too tables
Because union is used to 'collect' several rows from different queries into 1 result set:
Something like this might do the trick:
SELECT (SUM(DATE(date) = '2014-11-2') AS `rate` FROM `ratings`)
, (COUNT(*) AS `users` FROM `user`)
Does that work?
SELECT (COUNT(DATE(date) = '2014-11-2') AS `rate`
FROM `ratings`), (COUNT(*) AS `users` FROM `user`)
Related
I have a table like this
http://sqlfiddle.com/#!9/052381/1
I need to create a request that will find VIN codes that meet the following conditions:
VIN starts with XTA%
I have registration history: date_reg_last values: 1306440000,1506715200,1555963200. You need to select only those VIN codes that have exactly these values. If there are more or less records - VIN does not match
I have an owner_type that matches the values 1306440000,1506715200,1555963200: 2, 2, 2. Ie. for record 1306440000 owner_type must be 2, for record 1506715200 also 2, etc. The type can be different for each entry.
Similarly to the third point, I have regions: УЛЬЯНОВСК Г.,УЛЬЯНОВСК Г.,С РУНГА
I have a year, it should be in all records.
I tried making a request like this
SELECT *
FROM `ac_gibdd_shortinfo`
WHERE `vin` LIKE 'XTA%'
AND `model` LIKE '%1119%'
AND `date_reg_first` IN (0,1506715200,1555963200)
AND `date_reg_last` IN (1306440000,1506715200,1555963200)
AND `year` LIKE '2011'
AND `location` IN ('УЛЬЯНОВСК Г.','С РУНГА')
But it finds records that have a different number of registration records. There is only one thought: get all the matching records and then filter them by number with an additional request.
Test this:
SELECT *
FROM `ac_gibdd_shortinfo` t0
WHERE `vin` LIKE 'XTA%'
AND `model` LIKE '%1119%'
AND `date_reg_first` IN (0,1506715200,1555963200)
AND `date_reg_last` IN (1306440000,1506715200,1555963200)
AND `year` LIKE '2011'
AND `location` IN ('УЛЬЯНОВСК Г.','С РУНГА')
AND NOT EXISTS ( SELECT NULL
FROM ac_gibdd_shortinfo t1
WHERE t0.vin = t1.vin
AND t1.date_reg_first NOT IN (0,1506715200,1555963200) )
AND NOT EXISTS ( SELECT NULL
FROM ac_gibdd_shortinfo t2
WHERE t0.vin = t2.vin
AND t2.date_reg_last NOT IN (1306440000,1506715200,1555963200) )
AND NOT EXISTS ( SELECT NULL
FROM ac_gibdd_shortinfo t3
WHERE t0.vin = t3.vin
AND t3.location NOT IN ('УЛЬЯНОВСК Г.','С РУНГА') )
PS. According indices will improve.
and have count (1306440000,1506715200,1555963200) - 3 records in total by VIN – blood73
SELECT vin, model, date_reg_first, date_reg_last, `year`, location
FROM `ac_gibdd_shortinfo` t0
WHERE `vin` LIKE 'XTA%'
AND `model` LIKE '%1119%'
AND `date_reg_first` IN (0,1506715200,1555963200)
AND `date_reg_last` IN (1306440000,1506715200,1555963200)
AND `year` LIKE '2011'
AND `location` IN ('УЛЬЯНОВСК Г.','С РУНГА')
AND 3 = ( SELECT COUNT(*)
FROM ac_gibdd_shortinfo t1
WHERE t0.vin = t1.vin );
The table structure is as below,
My first SQL query is as below,
SELECT DISTINCT(IndustryVertical)
, COUNT(IndustryVertical) AS IndustryVerticalCount
, City
FROM `records`
WHERE City!=''
GROUP
BY IndustryVertical
, City
ORDER
BY `IndustryVerticalCount` DESC
by running the above query I'm getting the below,
What I'm trying to achieve is to get the List of all the DISTINCT CITY with ONLY ONE MAX(IndustryVerticalCount) and IndustryVertical.
Tried several things with no hope.
Anyone, please guide me.
There're several records in each City values. what I'm trying to achieve is that getting,
All the distinct City Values
The MAX COUNT of industryVertical
Name of industryVertical
The record I'm getting is as below,
What I'm trying to get,
The above record is reference purpose. Here, you can see only distinct city values with only one the vertical name having max count.
Since you are using group by, it will automatically select only distinct rows. Since you are using group by on two columns, you will get rows in which only combination of both columns is distinct.
What you now have to do is use this resulting table, and perform a query on it to find the maximum count grouped by city.
SELECT IndustryVertical, IndustryVerticalCount, City from
( SELECT IndustryVertical
, COUNT(IndustryVertical) AS IndustryVerticalCount
, City
FROM `records`
WHERE City!=''
GROUP
BY IndustryVertical
, City) as tbl where IndustryVerticalCount IN (Select max(IndustryVerticalCount) from ( SELECT IndustryVertical
, COUNT(IndustryVertical) AS IndustryVerticalCount
, City
FROM `records`
WHERE City!=''
GROUP
BY IndustryVertical
, City) as tbl2 where tbl.City=tbl2.city)
This may not be the most efficient method, but I think it will work.
How about this? I think it should be worked:
DECLARE #DataSet TABLE (
City VARCHAR(50),
IndustryVertical VARCHAR(50),
IndustryVerticalCount INT
)
INSERT INTO #DataSet SELECT 'Bangalore', 'Consumer Internet', 279
INSERT INTO #DataSet SELECT 'Bangalore', 'Technology', 269
INSERT INTO #DataSet SELECT 'Bangalore', 'Logistics', 179
INSERT INTO #DataSet SELECT 'Mumbai', 'Technology', 194
INSERT INTO #DataSet SELECT 'Mumbai', 'Consumer Internet', 89
SELECT
table_a.*
FROM #DataSet table_a
LEFT JOIN #DataSet table_b
ON table_a.City = table_b.City
AND table_a.IndustryVerticalCount < table_b.IndustryVerticalCount
WHERE table_b.IndustryVerticalCount IS NULL
I think you simply want a HAVING clause:
SELECT r.IndustryVertical,
COUNT(*) AS IndustryVerticalCount,
r.City
FROM records r
WHERE r.City <> ''
GROUP BY r.IndustryVertical, r.City
HAVING COUNT(*) = (SELECT COUNT(*)
FROM records r2
WHERE r2.City = r.City
ORDER BY COUNT(*) DESC
LIMIT 1
)
ORDER BY IndustryVerticalCount DESC;
I have a MySQL view with the fields id and set. Because it's a view, most ids are repeated and have duplicate entries. For example, and id = 120158 may have 5 rows, 3 where set = A and 2 where set = B. I want to run a query off of the view to display the number of rows each id has associated with its corresponding sets.
I tried:
SELECT `id`,
`set`,
(SELECT COUNT(set)) AS `CountOfSet`
FROM `view1`
However, this simply returns the same view (duplicate rows still exist) with CountOfSet equal to 1 for every row. Any ideas?
You should be grouping your results by id and set to get the desired result:
SELECT `id`, `set`, COUNT(*) AS `CountOfSet` FROM `view1`
GROUP BY `id`, `set`
This would return the results as
120158 A 3
120158 B 2
You need to group your data using GROUP BY clause:
GROUP BY `id`, `set`
Composing all together:
SELECT `id`,
`set`,
COUNT(*) AS `CountOfSet`
FROM `view1`
GROUP BY `id`, `set`
We can use GREATEST to get greatest value from multiple columns like below
SELECT GREATEST(mark1,mark2,mark3,mark4,mark5) AS best_mark FROM marks
But now I want to get two best marks from all(5) marks.
Can I do this on mysql query?
Table structure (I know it is wrong - created by someone):
student_id | Name | mark1 | mark2 | mark3 | mark4 | mark5
This is not the most elegant solution but if you cannot alter the table structure then you can unpivot the data and then apply a user defined variable to get a row number for each student_id. The code will be similar to the following:
select student_id, name, col, data
from
(
SELECT student_id, name, col,
data,
#rn:=case when student_id = #prev then #rn else 0 end +1 rn,
#prev:=student_id
FROM
(
SELECT student_id, name, col,
#rn,
#prev,
CASE s.col
WHEN 'mark1' THEN mark1
WHEN 'mark2' THEN mark2
WHEN 'mark3' THEN mark3
WHEN 'mark4' THEN mark4
WHEN 'mark5' THEN mark5
END AS DATA
FROM marks
CROSS JOIN
(
SELECT 'mark1' AS col UNION ALL
SELECT 'mark2' UNION ALL
SELECT 'mark3' UNION ALL
SELECT 'mark4' UNION ALL
SELECT 'mark5'
) s
cross join (select #rn := 0, #prev:=0) c
) s
order by student_id, data desc
) d
where rn <= 2
order by student_id, data desc;
See SQL Fiddle with Demo. This will return the top 2 marks per student_id. The inner subquery is performing a similar function as using a UNION ALL to unpivot but you are not querying against the table multiple times to get the result.
I think you should change your database structure, because having that many marks horizontally (i.e. as fields/columns) already means you're doing something wrong.
Instead put all your marks in a separate table where you create a many to many relationship and then perform the necessary SELECT together with LIMIT.
Suggestions:
Create a table that you call mark_types. Columns: id, mark_type. I
see that you currently have 5 type of marks; it would be very simple
to add additional types.
Change your marks table to hold 3 columns: id,
mark/grade/value, mark_type (this column foreign constraints to
mark_types).
Write your SELECT query with the help of joins, and GROUP BY mark_type.
you can create a temporary table and then
Create a temporary table in a SELECT statement without a separate CREATE TABLE
query that table as follows
SELECT TOP 2 * FROM temp
ORDER BY mark DESC
then
drop temp table
Okay here's a new answer that's should work with the current table structure:
SELECT `student_id`, `Name`, `mark` FROM (SELECT `student_id`, `Name`, `mark1` AS `mark` FROM `marks`
UNION ALL
SELECT `student_id`, `Name`, `mark2` AS `mark` FROM `marks`
UNION ALL
SELECT `student_id`, `Name`, `mark3` AS `mark` FROM `marks`
UNION ALL
SELECT `student_id`, `Name`, `mark4` AS `mark` FROM `marks`
UNION ALL
SELECT `student_id`, `Name`, `mark5` AS `mark` FROM `marks`) AS `marks`
ORDER BY `mark` DESC
LIMIT 2
I have a table of data which contains numbers from 0 to 100.
I would like to write a query that gets counts of records in the bands 0 to 10, 11 to 20 ......and 91 to 100
Is this possible?
Many thanks for any help.
Dave
Assuming your table looks something like this...
CREATE TABLE `test1` (
`ts` BIGINT(20) DEFAULT NULL
) ENGINE=INNODB;
...you could tackle this with a mathematical approach:
SELECT ROUND((T.ts-1)/10) AS "tt",
COUNT(*)
FROM test1 AS T
GROUP BY tt;
sub query would do the job for you
SELECT
(SELECT COUNT(brands) FROM data_table where brands BETWEEN 1 and 10 ) as '1-10',
...
(SELECT COUNT(brands) FROM data_table where brands BETWEEN 90 and 100 ) as '90-100',
Select count from(
Select * from (select * from table where val >= 'lowerlimit') where val<='upperlimit')
This should give you the results:
SELECT MIN(`id`) `id_from`, MAX(`id`) as `id_to`, COUNT(1) `count_id`
FROM `session`
GROUP BY (FLOOR(IF(id>0, id-1, id) / 10));
Please feel free to change the table and column names as per your schema.
Hope this helps.