I've got a permission/privileges - table looking like this:
+----+----------+----------+------+-------+
| id | name | usertype | read | write |
+----+----------+----------+------+-------+
| 1 | test | A | 0 | 0 |
| 2 | test | MU | 1 | 1 |
| 3 | test | U | 1 | 1 |
| 4 | apple | A | 1 | 1 |
| 5 | apple | MU | 1 | 0 |
| 6 | apple | U | 0 | 0 |
| 7 | flower | A | 0 | 0 |
| 8 | flower | MU | 0 | 0 |
| 9 | flower | U | 1 | 1 |
+----+----------+----------+------+-------+
there are 3 usertypes: A (admin), MU (maintenance user), U (standard user)
the usertypes are hierarchical: A > MU > U
(the usertypes are saved as CHAR(2) in the database, and unfortunately I can't change that)
now i want to build a query which implements the hierarchical logic of my usertypes.
e.g. usertype 'A' got no permission to read or write on stuff with the name 'test', thus usertypes 'MU' AND 'U' also should have no permission for that and their read = 1 and write = 1 should be ignored.
I know which usertype is currently logged in.
I somehow have to check for the minimum of read/write rights to the name for all hierarchical predecessors, i guess. but i don't know how to check that since usertype is not a number field.
this is what I've tried so far:
SELECT
name,
MIN(read),
MIN(write),
CASE
WHEN usertype = 'A' THEN 0
ELSE (CASE
WHEN usertype = 'WU' THEN 1
ELSE 2
END)
END userval
FROM
permissions
-- WHERE usertype <= :current_usertype
GROUP BY name
this seems to work, but i don't know how i can get my condition WHERE usertype <= :current_usertype working, so a usertype down in the hierarchy can't get more privileges on a name than a "higher" usertype.
any ideas?
thanks in advance!
This is how I solved my problem:
1. I added another table "permission_groups" to the database:
+----+----------+--------+
| id | usertype | value |
+----+----------+--------+
| 1 | A | 100 |
| 2 | MU | 20 |
| 3 | U | 10 |
+----+----------+--------+
2. Then I joined this table to my original table "permissions" which i showed in my question:
here i get the value of my "permission_groups" table with a subquery. this value symbolizes the hierarchical order of my different usertypes.
SELECT
perm.name,
MIN(perm.`read`),
MIN(perm.`write`),
group .value
FROM
permissions perm
LEFT JOIN permission_groups group ON group.usertype = perm.usertype
WHERE
group.value >= (SELECT value from permission_groups WHERE usertype = :current_usertype)
GROUP BY perm.name
:current_usertype is a PDO parameter in my case, which is replaced by the usertype of the current user.
Related
I have mysql with a user table with answers from a poll saved as a bitwise. How do I find the user with most or least common answers with the reference bitwise?
+------+---------+--+
| User | Answers | |
+------+---------+--+
| A | 1 | |
| B | 5 | |
| C | 10 | |
+------+---------+--+
Assuming by 'reference bitwise' you mean that you have another value that is a bitmask that you are trying to match against the Answers column, something like this should do it for you. In this case, I'm using '4' as the reference bitmask and myTable as the name of your table..
SELECT User, BIT_COUNT(Answers & 4) AS MatchedBits FROM myTable ORDER BY MatchedBits DESC
This returns:
+------+-------------+
| User | MatchedBits |
+------+-------------+
| B | 1 |
| A | 0 |
| C | 0 |
+------+-------------+
You can also add a LIMIT 1 clause to get just the top result, but of course that won't tell you if there is more than one top result with the same number of bits matched.
I have inherrited a DB that I've been tasked to mine for Data.
There are 2 tables that are loosely associated - atm and dslams.
The atm table contains "remotename", "rst", and "CardNumber" fields that relate to the dslams "hostname" field.
The atm table contains the port information for the dslam cards and the dslams table contains the information about the dslam card itself.
I've been tasked with printing out all the locations (dslams.name) that have a certain type of card (dslams.model="6256") and a count of all the ports on that card that have a certain level of service (atm.speed LIKE "RI_%%09" OR atm.speed LIKE "RI%%1%").
I've crafted the following statement which almost works...
SELECT distinct(dslams.name) AS Remote, Count(atm.speed) AS Customers, dslams.model
FROM dslams
LEFT JOIN atm
ON (dslams.hostname = CONCAT(atm.remotename,'-',atm.rst,'-S',atm.CardNumber)) AND (atm.speed LIKE "RI_%_%09" OR atm.speed LIKE "RI_%_%1_%")
GROUP BY dslams.name
HAVING dslams.model="6256"
ORDER BY dslams.name;
This prints out exactly what I need for all but 1 of the locations.
ie.
MariaDB [dsl]> SELECT distinct(dslams.name) AS Remote, Count(atm.speed) AS Customers, dslams.model
-> FROM dslams
-> LEFT JOIN atm
-> ON (dslams.hostname = CONCAT(atm.remotename,'-',atm.rst,'-S',atm.CardNumber)) AND (atm.speed LIKE "RI_%_%09" OR atm.speed LIKE "RI_%_%1_%")
-> GROUP BY dslams.name
-> HAVING dslams.model="6256"
-> ORDER BY dslams.name;
+---------+-----------+-------+
| Remote | Customers | model |
+---------+-----------+-------+
| ANTH-C2 | 1 | 6256 |
| BETY-C2 | 1 | 6256 |
| BHOT-C2 | 6 | 6256 |
| BNSH-C2 | 1 | 6256 |
| BUG2-C2 | 1 | 6256 |
| CCRK-C2 | 0 | 6256 |
...
| STLN-C2 | 1 | 6256 |
| SUMR-C2 | 2 | 6256 |
...
| WGRV-C2 | 0 | 6256 |
+---------+-----------+-------+
63 rows in set (0.34 sec)
For some reason there's one location that's not getting counted - STWL-C2.
MariaDB [dsl]> SELECT distinct(name), model FROM dslams WHERE model="6256" order by name;
+---------+-------+
| name | model |
+---------+-------+
| ANTH-C2 | 6256 |
| BETY-C2 | 6256 |
| BHOT-C2 | 6256 |
| BNSH-C2 | 6256 |
| BUG2-C2 | 6256 |
| CCRK-C2 | 6256 |
...
| STWL-C2 | 6256 |
...
| WGRV-C2 | 6256 |
+---------+-------+
64 rows in set (0.00 sec)
There's no difference in the tables between the STWL-C2 location and the other locations so it should print out with a count of 0.
Can anyone help me figure out why that 1 location is being missed?
Any help or direction would be appreciated as I am a rookie SQL programmer trying to understand this as best I can.
Best Regards,
Joe
Don't use HAVING dslams.model = '6256', put that in the WHERE clause. When you use HAVING, it filters after grouping. When you group by name, the result can contain the model from any row in the group, and it won't necessarily choose model = '6256'.
SELECT dslams.name AS Remote, Count(atm.speed) AS Customers, dslams.model
FROM dslams
LEFT JOIN atm
ON (dslams.hostname = CONCAT(atm.remotename,'-',atm.rst,'-S',atm.CardNumber)) AND (atm.speed LIKE "RI_%_%09" OR atm.speed LIKE "RI_%_%1_%")
WHERE dslams.model = '6256'
GROUP BY dslams.name
ORDER BY dslams.name;
I have these three tables:
user_submitted_value
id | owner_id | value |
-----------------------
1 | 1 | 1337 |
2 | 2 | 1337 |
3 | 2 | 1337 |
4 | 1 | 1337 |
tag
id | owner_id | text |
---------------------------
1 | 1 | 'Tag 01' |
2 | 1 | 'Tag 02' |
3 | 1 | 'Tag 03' |
4 | 2 | 'Tag 04' |
user_submitted_value_tag
id | owner_id | tag_id | value_id |
-----------------------------------
1 | 1 | 1 | 1 |
2 | 1 | 2 | 1 |
3 | 1 | 3 | 1 |
So basically, users can submit values and enter any number of freetext tags to attach to that value. I need to store the tags as belonging to a specific user, and I need to be able to count how many times they've used each tag.
What I want to accomplish is a query that gets rows from user_submitted_value with the tags appended onto them. For example:
Query value with id 1:
id | owner_id | value | tags |
------------------------------------------------------
1 | 1 | 1337 | "'Tag 01','Tag 02','Tag 03'" |
Query all values belonging to user with id 1:
id | owner_id | value | tags |
------------------------------------------------------
1 | 1 | 1337 | "'Tag 01','Tag 02','Tag 03'" |
4 | 1 | 1337 | "" |
I know I need to JOIN one or more times, somehow, but I am not comfortable enough with SQL to figure out exactly how.
This seems like a rather arcane data format -- particularly because owner_id is repeated in all the tables.
In any case, I think the basic query that you want to get the values and tags for a given user looks like this:
select usv.owner_id,
group_concat(distinct usvt.value_id) as values,
group_concat(distinct t.text) as tags
from user_submitted_value usv join
user_submitted_value_tag usvt
on usv.value_id = usvt.value_id and usv.owner_id = usvt.owner_id join
tags t
on usvt.tag_id = t.id and usvt.owner_id = t.owner_id
group by usv_owner_id;
Here's the final solution in my case. Heavily based on the answer submitted by Gordon Linoff.
SELECT
user_submitted_value.id,
user_submitted_value.creator_id,
user_submitted_value.value,
group_concat(tag.text) AS tags
FROM user_submitted_value
LEFT JOIN user_submitted_value_tag
ON user_submitted_value.id = user_submitted_value_tag.value_id
AND user_submitted_value.creator_id = user_submitted_value_tag.creator_id
LEFT JOIN tag
ON user_submitted_valuetag.tag_id = tag.id
AND user_submitted_value_tag.creator_id = tag.creator_id
WHERE user_submitted_value.id = ?
GROUP BY user_submitted_value.id
The WHERE clause on the second JOIN can be modified to get all values for a given user.
I have two tables:
| USER |
| _id | - int id PK
| id | - String id
| name |
| SUBSCRIBE |
| user |
| subscribe |
and I want to extract this data:
| _id | id | name | subscribe
Simple example
| USER |
| 1 | 10212551 | Mike
| 2 | 21022145 | Nick
| SUBSCRIBE |
| 1 | 2
get_info($user, $sub );
| EXPECTED RESULT |
| $user | id | name | 0 or 1 (false or true, if $sub has subscribed to $user)
My best try was with count():
SELECT u._id,u.id,u.name,u.email,u.country,count(s.subscribe) AS subscribe
FROM user u,subscribe s
WHERE u._id='$user' AND s.subscribe='$user' AND s.user='$sub'
But this works only if there's any record in subscribe table. So for
get_info(2,1)
it will give right result but for:
get_info(1,2)
there's nothing :/
Can somebody please help me with this ?
Use left join in order to return user even if he has not subscribed and use case to check for subscribed
select u._id,u.id,u.name,u.email,u.country,
case when s.subscribe is not null then 1 else 0 end as subscribe
from user u
left join subscribe s on (u._id = s.user and s.subscribe ='$sub')
where u._id='$user'
Demo
I have the following table structure (simplified version)
+----------------+ +-----------------+ +------+
| fee_definition | | user_fee | | user |
+----------------+ +-----------------+ +------+
| id | | user_id | | id |
| label | | fee_id | | ... |
| case1 | | case | +------+
| case2 | | manual_override |
| case3 | +-----------------+
| case4 |
| case5 |
+----------------+
Base on a pretty simple algorithm id determine which case fits the user to determine the amount of money they have to pay. A user_fee can be base on 1 to no limit number of fees definitions. which mean i can have the following content in the intersection table
+-----------+----------+--------+-------------------+
| user_id | fee_id | case | manual_override |
+-----------+----------+--------+-------------------+
| 1 | 1 | case1 | |
| 1 | 3 | case1 | |
| 1 | 5 | case1 | 50.22 |
| 2 | 1 | case5 | |
| 3 | 1 | case2 | |
| 3 | 2 | case2 | 18.50 |
+-----------+----------+--------+-------------------+
If a user is setted to have the case 1, all the fees listed under the case 1 where the value is different from 0 get picked. Same goes for the four other cases.
Just for reference on how i did things here is the actual query that I execute which is written in french (sorry for that but since we are a team of french speaking developpers, we mostly write in our code and queries in french).:
SELECT
`etudiant_etu`.*,
`session_etudiant_set`.*,
SUM(ROUND(frais_session_etudiant.fse_frais_manuel*100)/100) AS `fse_frais_manuel`,
`frais_session_etudiant`.`des_colonne`,
SUM(ROUND(definition_frais_des.des_quebecCanada*100)/100) AS `des_quebecCanada`,
SUM(ROUND(definition_frais_des.des_etranger*100)/100) AS `des_etranger`,
SUM(ROUND(definition_frais_des.des_non_credite*100)/100) AS `des_non_credite`,
SUM(ROUND(definition_frais_des.des_visiteur*100)/100) AS `des_visiteur`,
SUM(ROUND(definition_frais_des.des_explore*100)/100) AS `des_explore`,
`type_etudiant_tye`.*,
`type_formation_tyf`.*,
`pays_pys`.*,
`province_prc`.*
FROM `etudiant_etu`
INNER JOIN `session_etudiant_set`
ON session_etudiant_set.etu_id = etudiant_etu.etu_id
INNER JOIN `frais_session_etudiant`
ON frais_session_etudiant.set_id = session_etudiant_set.set_id
INNER JOIN `definition_frais_des`
ON definition_frais_des.des_id = frais_session_etudiant.des_id
LEFT JOIN `type_etudiant_tye`
ON type_etudiant_tye.tye_id = session_etudiant_set.tye_id
LEFT JOIN `type_formation_tyf`
ON type_formation_tyf.tyf_id = session_etudiant_set.tyf_id
LEFT JOIN `pays_pys`
ON pays_pys.pys_code = etudiant_etu.pys_adresse_permanente_code
LEFT JOIN `province_prc`
ON province_prc.prc_code = etudiant_etu.prc_adresse_permanente_code
WHERE (set_session = 'P11')
GROUP BY `session_etudiant_set`.`set_id`
ORDER BY `etu_nom` asc, `etu_prenom` ASC
as for reference from the actual query with the simplified version:
simplified version actual version
fee_definition.id definition_frais_des.des_id
fee_definition.case1 definition_frais_des.des_quebecCanada
fee_definition.case2 definition_frais_des.des_etranger
fee_definition.case3 definition_frais_des.des_non_credite
fee_definition.case4 definition_frais_des.des_visiteur
fee_definition.case5 definition_frais_des.des_explore
user_fee.user_id frais_session_etudiant.set_id
user_fee.fee_id frais_session_etudiant.des_id
user_fee.case frais_session_etudiant.des_colonne
user_fee.manual_override frais_session_etudiant.fes_frais_manuel
user.id session_etudiant_set.set_id
The problem I have is when it comes to handling the manual override setting. What would be the best way of doing this?
I would rather this to be handled in the query itself than in the programmation.
the logic behind what I am looking for goes as follow
get the SUM of the fees to be charged for a user and if an override value as been set, use that value instead of the actual value setted in the fee_definition, else use the value in the fee_definition.
I don't mind to loose the 4 not used cases and only keep the right column
Edited to display final result
This is the query I ended with, five levels of IF's
'IF(`frais_session_etudiant`.des_colonne= "des_quebec_canada",
SUM(IF(`frais_session_etudiant`.fse_frais_manuel > 0,
ROUND(`frais_session_etudiant`.fse_frais_manuel*100)/100,
ROUND(definition_frais_des.des_quebec_canada*100)/100)
),
IF(`frais_session_etudiant`.des_colonne= "des_etranger",
SUM(IF(`frais_session_etudiant`.fse_frais_manuel > 0,
ROUND(`frais_session_etudiant`.fse_frais_manuel*100)/100,
ROUND(definition_frais_des.des_etranger*100)/100)
),
IF(`frais_session_etudiant`.des_colonne= "des_non_credite",
SUM(IF(`frais_session_etudiant`.fse_frais_manuel > 0,
ROUND(`frais_session_etudiant`.fse_frais_manuel*100)/100,
ROUND(definition_frais_des.des_non_credite*100)/100)
),
IF(`frais_session_etudiant`.des_colonne= "des_visiteur",
SUM(IF(`frais_session_etudiant`.fse_frais_manuel > 0,
ROUND(`frais_session_etudiant`.fse_frais_manuel*100)/100,
ROUND(definition_frais_des.des_visiteur*100)/100)
),
IF(`frais_session_etudiant`.des_colonne= "des_explore",
SUM(IF(`frais_session_etudiant`.fse_frais_manuel > 0,
ROUND(`frais_session_etudiant`.fse_frais_manuel*100)/100,
ROUND(definition_frais_des.des_explore*100)/100)
),
0
)
)
)
)
) as frais'
That's a monster! as said by Ted Hopp :D
You can use IFNULL(manual_override,non-override-value)