Using Alex Reisner's Ruby Geocoder, I have a model "Spot" which is geocoded using this gem
If I select the first spot into and object:
s = Spot.first
Then try to find all the spots within a 10 mile radius (let's say there should be 12 of them), then i would expect Spot.near(s,10) to return an active record object containing 12 spots. Instead it's just returning something like this every time:
Spot.near(s1,10)
=> {:select=>"spots.*, AS distance, CAST(DEGREES(ATAN2( RADIANS(spots.longitude - -6.88671972656243), RADIANS(spots.latitude - 55.1729431175342))) + 360 AS decimal) % 360 AS bearing", :conditions=>["spots.latitude BETWEEN 55.028211334423354 AND 55.31767490064505 AND spots.longitude BETWEEN -7.140145500612388 AND -6.633293952512472 AND <= ?", 10], :order=>"distance ASC"}
Basically it's returning some SQL but no results.
What's going wrong here? Even if i try something a lot wider, like:
Spot.near([40,0],10000)
I still basically get no results back...
EDIT
I am able to execute the query using this (not pretty) addition...
q = Spot.near(s1,10)
spots = Spot.select(q[:select]).where(q[:conditions]).order(q[:order])
Related
I am trying to write a trading strategy in Pine Script, but I am getting a compilation error on line 9. The error message states that there is "no viable alternative at character '{'". I have tried adding the keyword "function" before the function name, but the error still persists. The goal is to have the code look at the volatility of the market with MACD, 200 EMA and overall volume with in an hour to determine a safe amount to invest during that period. Can someone please help me fix this error and make my code compile successfully?
function calcTradeAmount(v) => {
tradeAmount = money * (v / 100)
return tradeAmount
}
If the function works properly my if(long) and if(shorts) should be able to pull a different number each time. I don't want to have 1 trade be the entire portfolio each time.
Sample:
if (long)
tradeAmount = calcTradeAmount(volatility)
entryPrice = low
calcTradeAmount(v) =>
tradeAmount = money * (v / 100)
tradeAmount
I had the task to code the following:
Take a list of integers and returns the value of these numbers added up, but only if they are odd.
Example input: [1,5,3,2]
Output: 9
I did the code below and it worked perfectly.
numbers = [1,5,3,2]
print(numbers)
add_up_the_odds = []
for number in numbers:
if number % 2 == 1:
add_up_the_odds.append(number)
print(add_up_the_odds)
print(sum(add_up_the_odds))
Then I tried to re-code it using function definition / return:
def add_up_the_odds(numbers):
odds = []
for number in range(1,len(numbers)):
if number % 2 == 1:
odds.append(number)
return odds
numbers = [1,5,3,2]
print (sum(odds))
But I couldn’t make it working, anybody can help with that?
Note: I'm going to assume Python 3.x
It looks like you're defining your function, but never calling it.
When the interpreter finishes going through your function definition, the function is now there for you to use - but it never actually executes until you tell it to.
Between the last two lines in your code, you need to call add_up_the_odds() on your numbers array, and assign the result to the odds variable.
i.e. odds = add_up_the_odds(numbers)
So i've been trying to create a sentence-count function which will cycle through the following 'story':
let story = 'Last weekend, I took literally the most beautiful bike ride of my life. The route is called "The 9W to Nyack" and it actually stretches all the way from Riverside Park in Manhattan to South Nyack, New Jersey. It\'s really an adventure from beginning to end! It is a 48 mile loop and it basically took me an entire day. I stopped at Riverbank State Park to take some extremely artsy photos. It was a short stop, though, because I had a really long way left to go. After a quick photo op at the very popular Little Red Lighthouse, I began my trek across the George Washington Bridge into New Jersey. The GW is actually very long - 4,760 feet! I was already very tired by the time I got to the other side. An hour later, I reached Greenbrook Nature Sanctuary, an extremely beautiful park along the coast of the Hudson. Something that was very surprising to me was that near the end of the route you actually cross back into New York! At this point, you are very close to the end.';
And I realise the problem I'm having but I cannot find a way around this. Basically I want my code to return a the total sCount below but seeing as I've returned my sCount after my loop, it's only adding and returning the one count as a total:
const sentenceTotal = (word) => {
let sCount = 0;
if (word[word.length-1] === "." || word[word.length-1] === "!" || word[word.length-1] === "?") {
sCount += 1;
};
return sCount;
};
// console.log(sentenceTotal(story)) returns '1'.
I've tried multiple ways around this, such as returning sentenceTotal(word) instead of sCount but console.log will just log the function name.
I can make it return the correct sCount total if I remove the function element of it, but that's not what I want.
I don't see any loop or iterator which would go through story to count the number of occurrences of ., ?, or !.
Having recently tackled "counting sentences" myself I know it is a non-trivial problem with many edge cases.
For a simple use-case though you can use split and a regular expression;
story.split(/[?!.]/).length
So you could wrap that in your function like so:
const sentenceTotal = (word) => {
return word.split(/[?.!]/).length
};
let story = 'Last weekend, I took literally the most beautiful bike ride of my life. The route is called "The 9W to Nyack" and it actually stretches all the way from Riverside Park in Manhattan to South Nyack, New Jersey. It\'s really an adventure from beginning to end! It is a 48 mile loop and it basically took me an entire day. I stopped at Riverbank State Park to take some extremely artsy photos. It was a short stop, though, because I had a really long way left to go. After a quick photo op at the very popular Little Red Lighthouse, I began my trek across the George Washington Bridge into New Jersey. The GW is actually very long - 4,760 feet! I was already very tired by the time I got to the other side. An hour later, I reached Greenbrook Nature Sanctuary, an extremely beautiful park along the coast of the Hudson. Something that was very surprising to me was that near the end of the route you actually cross back into New York! At this point, you are very close to the end.';
sentenceTotal(story)
=> 13
There a several strange things about you question so I'll do it in 3 steps :
First step : The syntax.
What you wrote is the assignement to a const of an anonymous variable. So what it does is :
Create a const name 'sentenceCount'
To this const, assign the anonymous function (words) => {...}
Now you have this : sentenceCount(words){...}
And that's all. Because what you wrote : ()=>{} is not the calling of a function, but the declaration of an anonym function, you should read this : https://www.w3schools.com/js/js_function_definition.asp
If you want a global total, you must have a global total variable(not constant) so that the total isn't lost. So :
let sCount = 0; //<-- have sCount as a global variable not a const
function isEndOfSentence(word) {
if (word[word.length-1] === "." || word[word.length-1] === "!" || word[word.length-1] === "?") {
sCount += 1;
};
};
If you are forbidden from using a global variable (and it's best to not do so), then you have to register the total as a return of your function and store the total in the calling 'CountWords(sentence)' function.
function isEndOfSentence(words) {...}
callingFunction(){
//decalaration
let total;
//...inside your loop
total += isEndOfSentence(currentWord)
}
The algorithm
Can you provide more context as how you use you function ?
If your goal is to count the words until there is a delimiter to mark the end of a sentence, your function will not be of great usage .
As it is written, your function will only ever be able to return 0 or 1. As it does the following :
The function is called.
It create a var called sCount and set it to 0
It increment or not sCount
It return sCount so 1 or 0
It's basically a 'isEndOfSentence' function that would return a boolean. It's usage should be in an algorithm like :
// var totalSentence = 0
// for each word
// if(isEndOfSentence(word))
// totalSentence + totalSentence = 1
// endfor
Also this comes back to just counting the punctuation to count the number of sentence.
The quick and small solution
Also I tried specifically to keep the program in an algorithm explicit form since I guess that's what you're dealing with.
But I feel that you wanted to write something small and with as little characters as possible so for your information, there are faster way of doing this with a tool called regex and the native JS 'split(separator)' function of a string.
A regex is a description of a string that it can match to and when used can return those match. And it can be used in JS to split a string:
story.split(/[?!.]/) //<-- will return an array of the sentences of your story.
story.split(/[?!.]/).length //<-- will return the number of element of the array of the sentences of your story, so the sentence count
That does what you wanted but with one line of code. But If you want to be smart about you problem, remember that I said
Also this comes back to just counting the punctuation to count the number of sentence.
So we'll just do that right ?
story.match(/(\.\.\.)|[.?!]/g).length
Have fun here ;) : https://regexr.com/
I hope that helps you ! Good luck !
I have the following custom method in the repo:
$query = $qb->select('Client', 'Organization')
->from(':Client', 'Client')
->leftJoin('Client.organizations', 'Organization');
--different searh conditions--
Then I use paginator to get the results:
$paginator = new \Doctrine\ORM\Tools\Pagination\Paginator($query->getQuery());
$clients = $paginator->getQuery()
->setMaxResults($length)
->setFirstResult($start);
Here where the magic comes.
I set length to 10 and first result to 0. So basicaly I should get 10 results on the page. However if there are 5 Organizations for the Client (Client mtm Organization), there will be 5 results, if there are 7 Organizations - 3 results.
But if I add
$query->groupBy('Client');
Then all is "ok" with the root level of results: i.e. there are 10 Clients on the page, but there is not all of the Organizations (max 1).
Did anyone experience the same issue? Any thoughts, suggestions?
It probably counts the same item several times.
Try once to add a distinct clause to your query.
$query = $qb->select('Client', 'Organization')
->from(':Client', 'Client')
->leftJoin('Client.organizations', 'Organization');
->distinct();
I have found many calculations here and some php examples and most are just over my head.
I found this example:
SELECT b.zip_code, b.state,
(3956 * (2 * ASIN(SQRT(
POWER(SIN(((a.lat-b.lat)*0.017453293)/2),2) +
COS(a.lat*0.017453293) *
COS(b.lat*0.017453293) *
POWER(SIN(((a.lng-b.lng)*0.017453293)/2),2))))) AS distance
FROM zips a, zips b
WHERE
a.zip_code = '90210' ## I would use the users submitted value
GROUP BY distance
having distance <= 5; ## I would use the users submitted value
But, I am having trouble understanding how to implement the query with my database.
It looks like that query has all I need.
However, I cannot even find/understand what b.zip_code actually is! (whats the b. and zips a, zips b?)
I also do not need the state in the query.
My mySQL db structure is like this:
ZIP | LAT | LONG
33416 | 26.6654 | -80.0929
I wrote this in attempt to return some kind of results (not based on above query) but, it only kicks out one zip code.
## Just for a test BUT, in reality I desire to SELECT a zip code WHERE ZIP = the users submitted zip code
## not by a submitted lat lon. I left off the $connect var, assume it's there.
my $set1 = (26.6654 - 0.20);
my $set2 = (26.6654 + 0.20);
my $set3 = (-80.0929 - 0.143);
my $set4 = (-80.0929 + 0.143);
my $test123 = $connect->prepare(qq{SELECT `ZIP` FROM `POSTAL`
WHERE `LAT` >= ? AND `LAT` <= ?
AND `LONG` >= ? AND `LONG` <= ?}) or die "$DBI::errstr";
$test123->execute("$set1","$set2","$set3","$set4") or die "$DBI::errstr";
my $cntr;
while(#zip = $test123->fetchrow_array()) {
print qq~$zip[$cntr]~;
push(#zips,$zip[$cntr]);
$cntr++;
}
As you can see, I am quite the novice so, I need some hand holding here with verbose explanation.
So, in Perl, how can I push zip codes into an array from a USER SUBMITTED ZIP CODE and user submitted DISTANCE in miles. Can be a square instead of a circle, not really that critical of a feature. Faster is better.
I'll tackle the small but crucial part of the question:
However, I cannot even find/understand what b.zip_code actually is! (whats the "b." and "zips a, zips b"?)
Basically, the query joins two tables. BUT, both tables being joined are in fact the same table - "zips" (in other words, it joins "zips" table to itself"). Of course, since the rest of the query needs to understand when you are referring to the first copy of the "zips" table and when to the second copy of the "zips" table, you are giving a table alias to each copy - to wit, "a" and "b"'.
So, "b.xxx" means "column xxx from table zips, from the SECOND instance of that table being joined".
I don't see what's wrong with your first query. You have latitude and longitude in your database (if I'm understanding, you're comparing a single entry to all others). You don't need to submit or return the state that's just part of the example. Make the first query work like this:
my $query = "SELECT b.zip_code,
(3956 * (2 * ASIN(SQRT(
POWER(SIN(((a.lat-b.lat)*0.017453293)/2),2) +
COS(a.lat*0.017453293) *
COS(b.lat*0.017453293) *
POWER(SIN(((a.lng-b.lng)*0.017453293)/2),2))))) AS distance
FROM zips a, zips b WHERE
a.zip_code = ?
GROUP BY distance having distance <= ?";
my $sth = $dbh->prepare($query);
$sth->execute( $user_submitted_zip, $user_submitted_distance );
while( my ($zip, $distance) = $sth->fetchrow() ) ) {
# do something
}
This won't be that fast, but if you have a small record set ( less than 30k rows ) it should be fine. If you really want to go faster you should look into a search engine such as Sphinx which will do this for you.
fetchrow_array returns a list of list references, essentially a two-dimensional array, where each row represents a different result from the database query and each column represents a field from the query (in your case, there is only one field, or column, per row).
Calling while ($test123->fetchrow_array()) will cause an infinite loop as your program executes the query over and over again. If the query returns results, then the while condition will be satisfied and the loop will repeat. The usual idiom would be to say something more like for my $row ($test123->fetchrow_array()) { ..., which will only execute the query once and then iterate over the results.
Each result is a list reference, and the zip code you are interested in is in the first (and only) column, so you could accumulate the results in an array like this:
my #zips = (); # for final results
for my $row ($test123->fetchrow_array()) {
push #zips, $row->[0];
}
or even more concisely with Perl's map statement:
my #zips = map { $_->[0] } $test123->fetchrow_array()
which does the same thing.