Delete row in other sheets based on 2 values on main file - google-apps-script

Question

Is it possible to delete rows on other sheets based on 2 values? Say I have 3 sheets. In the main sheet (sheet 1), there will be 2 columns: Branch and Manager same with the remaining sheets.
SAMPLE SPREADSHEET HERE.
Example data:
SHEET 1: (main sheet)
--- BRANCH --- MANAGER ---
California Tom Chang
Brooklyn Jon Sieg
New York Raq Craig
SHEET 2:
--- BRANCH --- MANAGER ---
California Jane Cali
California Tom Chang
San Francisco James Chao
SHEET 2:
--- BRANCH --- MANAGER ---
California Jane Cali
California Tom Chang
New York Daniel Trevor
What should happen is that:
Branch column values should NOT duplicate in all sheets. So what we need to do is delete the row on sheet 2 and 3 if branch column is equal with the main sheet (sheet1) IF AND ONLY IF the manager is not the same/equal. So in my given data above, Branch California and Manager Tom Chang exists in all sheets therefore it should not be touched. But California branch was repeated in the remaining 2 sheets with a different Manager. Therefore, row California ---- Jane Cali should be deleted on Sheets 2 and 3.
Came upon a script borrowed from this post but can't seem to work. Here:
function removeDupsInOtherSheets() {
var ss = SpreadsheetApp.getActiveSpreadsheet();
var mainsheet = ss.getSheetByName("Sheet3").getDataRange().getValues();
var sheet2 = ss.getSheetByName("Sheet2").getDataRange().getValues();
var sheet3 = ss.getSheetByName("Sheet3").getDataRange().getValues();
// iterate mainsheet and check in sheet2 & sheet3 if duplicate values exist
var nsheet2 = [];
var nsheet3 = [];
var mainsheetCol1 = [];// data in column1 of main sheet
var mainsheetCol2 = [];// data in column2 of main sheet
for(var n in mainsheet){
mainsheetCol1.push(mainsheet[n][0]); //column1
mainsheetCol2.push(mainsheet[n][3]); //column2
}
for(var n in sheet2){ // iterate sheet2 and test col 1 vs col 1 and co2 1 vs co2 1in sheet2
var noDup1 = checkForDup(sheet2[n],mainsheetCol1,mainsheetCol2)
if(noDup1){nsheet2.push(noDup1)};// if not present in sheet3 then keep
}
for(var n in sheet3){ // iterate sheet3 and test col 1 vs col 1 and co2 1 vs co2 in sheet3
var noDup2 = checkForDup(sheet3[n],mainsheetCol1,mainsheetCol2)
if(noDup2){nsheet3.push(noDup2)};// if not present in sheet3 then keep
}
// view result
Logger.log(nsheet2);
Logger.log(nsheet3);
// clear and update sheets
ss.getSheetByName("Sheet2").getDataRange().clear();
ss.getSheetByName("Sheet3").getDataRange().clear();
ss.getSheetByName("Sheet2").getRange(1,1,nsheet2.length,nsheet2[0].length).setValues(nsheet2);
ss.getSheetByName("Sheet3").getRange(1,1,nsheet3.length,nsheet3[0].length).setValues(nsheet3);
}
//Here can't seem to make it work to check if column 2 is not equal to the other sheets
//item is sheet2[n]
// s is mainsheetCol1
// s2 is mainsheetCol2
function checkForDup(item,s,s2){
Logger.log(s+' = '+item[0]+' ?')
Logger.log(s2+' = '+item[1]+' ?')
if((s.indexOf(item[0])>-1) && (s2.indexOf(item[1])>-1))){
return null;
}
return item;
}
Hoping someone could help/guide me. Thank you!

Answer 1

Try this:
function removeDuplicate(){
var ss = SpreadsheetApp.getActiveSpreadsheet();
var mainsheet = ss.getSheetByName("Sheet1");
var sheet2 = ss.getSheetByName("Sheet2");
var sheet3 = ss.getSheetByName("Sheet3");
var masterData = mainsheet.getDataRange().getValues();
var sheetsToCheck = [sheet2,sheet3];
for(var i in sheetsToCheck){
var valuesToCheck = sheetsToCheck[i].getDataRange().getValues();
for(var j=0;j<valuesToCheck.length;j++){
for(var k in masterData){
if(masterData[k][0] == valuesToCheck[j][0] && !(masterData[k][1] == valuesToCheck[j][1])){
sheetsToCheck[i].deleteRow(j+1);
}
}
}
}
}

Answer 2

Code given at Post is not working. I have modified it little bit to make it work.
Here it is,
function removeDupsInOtherSheets() {
var ss = SpreadsheetApp.getActiveSpreadsheet();
var s1 = ss.getSheetByName("Sheet1").getDataRange().getValues();
var s2 = ss.getSheetByName("Sheet2").getDataRange().getValues();
var s3 = ss.getSheetByName("Sheet3").getDataRange().getValues();
// iterate s3 and check in s1 & s2 if duplicate values exist
var nS1 = [];
var nS2 = [];
var s3Col1 = [];// data in column1 of sheet3
for(var n=0; n<s3.length; ++n){
s3Col1.push(s3[n][0]);
}
for(var n=0; n<s1.length; ++n){ // iterate sheet1 and test col 1 vs col 1 in sheet3
var noDup1 = checkForDup(s1[n],s3Col1)
if(noDup1){nS1.push(noDup1)};// if not present in sheet3 then keep
}
for(var n=0; n<s2.length; ++n){ // iterate sheet2 and test col 1 vs col 1 in sheet3
var noDup2 = checkForDup(s2[n],s3Col1)
if(noDup2){nS2.push(noDup2)};// if not present in sheet3 then keep
}
Logger.log(nS1);// view result
Logger.log(nS2);
ss.getSheetByName("Sheet1").getDataRange().clear();// clear and update sheets
ss.getSheetByName("Sheet2").getDataRange().clear();
var nS1Length = nS1.length;
var nS2Length = nS2.length;
// This is the change needed in code you have copied from,
**if(nS1 != undefined){
data = []
data[0] = nS1;
var range = ss.getSheetByName("Sheet1").getRange(1,1);
range.setValues(data);
}
if(nS2 != undefined){
data = []
data[0] = nS1;
var range = ss.getSheetByName("Sheet2").getRange(1,1);
range.setValues(data);
}**
}
function checkForDup(item,s){
Logger.log(s+' = '+item[0]+' ?')
if(s.indexOf(item[0])>-1){
return null;
}
return item;
}