MYSQL Query Matching Count - mysql

Question

I have a MySQL-question which I can't seem to figure out.
I have two query's and some PHP and I think it should be possible to merge this into one query.
The thing I want to do is: show all users that completed all modules of a certain programm with id=1
Query 1 -> this gives all modules of the programm:
SELECT `id`
FROM `modules`
JOIN `linkModuleProgramm` ON `module`.`id` = `linkModuleProgramm`.`module`
WHERE `linkModuleProgramm`.`programm` = 1
Query 2 -> this gives the user and the number of modules of the programm that are completed by this user:
SELECT `user`.`id`,
COUNT(*) as 'count'
FROM `user`
JOIN `linkUserModule` ON `user`.`id` = `linkUserModule`.`user`
WHERE `linkUserModule`.`status` = 1
AND `linkUserModule`.`module` IN (Query1)
GROUP BY `user`.`id`
Then PHP filters the users from Query2 where 'count' is equal to the number of results from Query1.
Anyone has a suggestion?

Answer 1

Looks like I haven't understood your question right the first time. Another try, using two queries and MySQL variable:
SET #MODULESCOUNT = (
SELECT COUNT(*)
FROM `modules`
JOIN `linkModuleProgramm` ON `module`.`id` = `linkModuleProgramm`.`module`
WHERE `linkModuleProgramm`.`programm` = 1
);
SELECT `user`.`id`,
FROM `user`
JOIN `linkUserModule` ON `user`.`id` = `linkUserModule`.`user`
WHERE `linkUserModule`.`status` = 1
AND `linkUserModule`.`module` IN (Query1)
GROUP BY `user`.`id`
HAVING COUNT(*)=#MODULESCOUNT ;
There is also a possibility to use 'subquery' instead of variable:
SELECT `user`.`id`,
FROM `user`
JOIN `linkUserModule` ON `user`.`id` = `linkUserModule`.`user`
WHERE `linkUserModule`.`status` = 1
AND `linkUserModule`.`module` IN (Query1)
GROUP BY `user`.`id`
HAVING COUNT(*)=
(
SELECT COUNT(*)
FROM `modules`
JOIN `linkModuleProgramm` ON `module`.`id` = `linkModuleProgramm`.`module`
WHERE `linkModuleProgramm`.`programm` = 1
)
but I don't like subqueries inside 'where' or 'having' sections, mysql sometimes decides to do unreasonably inefficient things because of them.