Combine two result sets into one in mysql - html

Question

Fiddle Example 1
Fiddle Example 2
Can anyone please tell me if it's possible to combine the following two result sets into one in order not to use two separate queries?
PRODUCT_PAGE_ID PRODUCT_PAGE_NAME SIMILAR_PRODUCT SIMILAR_PRODUCT_ID RESULT
22 Nokia 8234 E821 777 2
22 Nokia 8234 HTC 2811 444 2
PRODUCT_PAGE_ID PRODUCT_PAGE_NAME VOTER_NAME COMMENT
22 Nokia 8234 John blahblahblah
22 Nokia 8234 David xxxxxxxxxxxx
22 Nokia 8234 Peter yyyyyyyyyyyy
22 Nokia 8234 John zzzzzzzzzzzz
My expected outcome should be:
PRODUCT_PAGE_ID PRODUCT_PAGE_NAME SIMILAR_PRODUCT SIMILAR_PRODUCT_ID RESULT VOTER_NAME COMMENT
22 Nokia 8234 E821 777 2 NULL NULL
22 Nokia 8234 HTC 2811 444 2 NULL NULL
22 Nokia 8234 NULL NULL NULL John blahblahblah
22 Nokia 8234 NULL NULL NULL David xxxxxxxxxxxx
22 Nokia 8234 NULL NULL NULL Peter yyyyyyyyyyyy
22 Nokia 8234 NULL NULL NULL John zzzzzzzzzzzz
The first result set uses this query,
SELECT p.product_page_id,p.name AS product_page,
p2.name AS similar_product,
p2.product_page_id AS similar_product_id,COUNT(poll.choice) AS result
FROM poll
INNER JOIN product p ON poll.product_page_id = p.product_page_id
INNER JOIN product p2 ON poll.choice = p2.product_page_id
WHERE poll.product_page_id = 22
GROUP BY poll.choice
ORDER BY result DESC
While the second one uses
SELECT pc.product_page_id,p.name AS product_page_name,
u.name AS voter_name,pc.comment
FROM `poll_comment` pc INNER JOIN `user` u
ON u.user_id = pc.user_id
INNER JOIN `product` p ON pc.product_page_id = p.product_page_id
WHERE pc.product_page_id = 22
LIMIT 10;
I have a poll that allows users to vote for any suggested products similar to the product they are browsing. They are allowed to vote multiple items at a time and leave a comment. Each voted item uses a single row inserted into table poll. I'm trying to pull the vote counts as well as 10 comments from the voters in one single query. The problem is that the query that I have come up with is not able to get the correct vote counts or the comments on the product.
Table Schema:
CREATE TABLE poll
(`user_id` int,`product_page_id`int,`choice` int)
;
INSERT INTO poll
(`user_id`,`product_page_id`,`choice`)
VALUES
(1,22,444),
(1,22,777),
(2,22,444),
(3,22,777)
;
CREATE TABLE poll_comment
(`user_id` int,`product_page_id`int,`comment` varchar(40))
;
INSERT INTO poll_comment
(`user_id`,`product_page_id`,`comment`)
VALUES
(1,22,'blahblahblah'),
(2,22,'xxxxxxxxxxxx'),
(3,22,'yyyyyyyyyyyy'),
(1,33,'zzzzzzzzzzzz'),
(2,33,'kkkkkkkkkkkk')
;
CREATE TABLE user
(`user_id` int, `name` varchar(30))
;
INSERT INTO user
(`user_id`, `name`)
VALUES
(1,'John'),
(2,'David'),
(3,'Peter'),
(4,'May')
;
CREATE TABLE product
(`product_page_id` int, `name` varchar(30))
;
INSERT INTO product
(`product_page_id`, `name`)
VALUES
(1,'Sony A821'),
(22,'Nokia 8234'),
(444,'HTC 2811'),
(777,'E821')
;
Here's my attempt (Fiddle):
SELECT * FROM (
SELECT p.name AS product_page,poll.product_page_id,p2.name AS similar_product,
COUNT(poll.choice) As vote_result
FROM `poll`
INNER JOIN product p ON poll.product_page_id = p.product_page_id
INNER JOIN `product` p2 ON poll.choice = p2.product_page_id
GROUP BY poll.choice
ORDER By vote_result desc
)TAB1
JOIN
(
SELECT pc.comment,pc.product_page_id,u.name
FROM `poll_comment` pc
INNER JOIN `product` p ON pc.product_page_id = p.product_page_id
INNER JOIN `user` u ON u.user_id = pc.user_id
LIMIT 10
)TAB2
ON TAB1.product_page_id = TAB2.product_page_id
WHERE TAB1.product_page_id = 22

Answer 1

Try the following approach by using result of two querys and union all:
select PRODUCT_PAGE_ID,PRODUCT_PAGE_NAME,SIMILAR_PRODUCT,SIMILAR_PRODUCT_ID,RESULT,null as VOTER_NAME , null as COMMENT from query1
UNION ALL
select PRODUCT_PAGE_ID,PRODUCT_PAGE_NAME,null as SIMILAR_PRODUCT,null as SIMILAR_PRODUCT_ID,null as RESULT,VOTER_NAME,COMMENT from query2
Exact answer based on your data:
select PRODUCT_PAGE_ID,product_page as PRODUCT_PAGE_NAME,SIMILAR_PRODUCT,SIMILAR_PRODUCT_ID,RESULT,null as VOTER_NAME , null as COMMENT from (SELECT p.product_page_id,p.name AS product_page,
p2.name AS similar_product,
p2.product_page_id AS similar_product_id,COUNT(poll.choice) AS result
FROM poll
INNER JOIN product p ON poll.product_page_id = p.product_page_id
INNER JOIN product p2 ON poll.choice = p2.product_page_id
WHERE poll.product_page_id = 22
GROUP BY poll.choice
ORDER BY result DESC)temp
UNION ALL
select PRODUCT_PAGE_ID,PRODUCT_PAGE_NAME,null as SIMILAR_PRODUCT,null as SIMILAR_PRODUCT_ID,null as RESULT,VOTER_NAME,COMMENT from (SELECT pc.product_page_id,p.name AS product_page_name,
u.name AS voter_name,pc.comment
FROM `poll_comment` pc INNER JOIN `user` u
ON u.user_id = pc.user_id
INNER JOIN `product` p ON pc.product_page_id = p.product_page_id
WHERE pc.product_page_id = 22)TEMP2