MySQL - Select only those that have not another value - mysql

Question

I'd need a query to SELECT all of these entries that are not repeated with another value. I explain the case in the next lines.
The situation
I've got a table of items and values. Each item can be repeated with different values. Let's say I have the following set of records in Table B:
item_id value type_value
ID Item A 0 0
ID Item B 0 0
ID Item A 1 0
ID Item C 1 1
These items, as probably you have already guessed, are IDs, so the "original" items with their information are in another table. What I'm trying to do is to select from the "original" table those items which are in this second table that I've explained.
What I need
As I introduced before, I need to select from a Table A all those items which IDs are IN Table B, but only those which have the value set to 0 and no other record is set to 1 with the same type of "type_value".
Because of the "original" table, I need to do so in a WHERE clause with an INNER SELECT. The result that would be output would be, in this case:
item_id value type_value
ID Item B 0 0
ID Item C 1 1
If we decided to only SELECT those with a specified type_value, I know how to do that, so do not worry about it.
The problem
I am able to do so, at least almost. My problem comes when I have the same item_id with different value fields, so when I try to say "WHERE value != 1", for example, this still gets selected as there is another record with value = 0.
The question
How could I SELECT the rows I'd like in an inner select in a WHERE clause of a main query without having to repeat the whole SELECT with a NOT IN and adding a "WHERE value = 1" to exclude those who have that value?
As it can be a long and complex query (the main one), I'd like to keep it as simple as possible. Of course, as I said before, I can copy the whole query and select those with value set to the one I do not want to, and put a "AND NOT IN" before that SELECT. But that'd repeated code and I think performance could be affected.
Thanks to all of you for your time!
If you need further explanation, please, let me know!
EDIT
Table_A
+----+--------+
| id | name |
+----+--------+
| 1 | Item A |
+----+--------+
| 2 | Item B |
+----+--------+
| 3 | Item C |
+----+--------+
Table_B
+---------+-------+
| item_id | value |
+---------+-------+
| 1 | 0 |
+---------+-------+
| 2 | 0 |
+---------+-------+
| 1 | 1 |
+---------+-------+
| 3 | 1 |
+---------+-------+
Sample query
SELECT name
FROM Table_A
WHERE id IN (SELECT item_id
FROM Table_B
WHERE "item_value is equal to 0 and no other row has this item_id with a item_value different from 0")
Result query
+---------+
| name |
+---------+
| Item B |
+---------+

Answer 1

You could do it by using GROUP BY and HAVING, for example:
SELECT a.*, b.itemid, SUM(b.value) AS vc FROM tableb b
INNER JOIN tablea a ON a.itemid = b.itemid
GROUP BY b.item_id
HAVING vc = 0

Answer 2

I used really simple query structure to make you understand the solution.
There might be better queries to do the job.
Here goes:
First you need to get the rows that you do not want to appear:
This is how it is done :
SELECT item_id,COUNT(item_id) how_many FROM my_table GROUP BY item_id HAVING (how_many>1)
Now you need to select from the table the rows that item_id does not appear in the above query, it is done this way:
SELECT T1.item_id,T1.value,T1.type_value
FROM my_table T1
WHERE (T1.item_id not in (SELECT T.item_id from (SELECT item_id,COUNT(item_id) how_many FROM my_table GROUP BY item_id HAVING (how_many>1))T ))
You can see that I used the "not in" operator and that I named the previous result table - T
Make sure you understand the above
Ask if you need more info