I have the following structs, which I use to communicate with an API:
type Object struct {
Id uint64
Type string
Class string
Properties []Property
}
type Property struct {
Name string
DataType string
Value interface{}
}
And I use json.MarshalIndent() to convert my struct into a json before sending it. this gives me something like:
{
"Id": 15,
"Type": "Node",
"Class": "Persona",
"Properties": [
{
"Name": "Nombre",
"DataType": "text",
"Value": "Oso"
},
{
"Name": "Edad",
"DataType": "int",
"Value": 45
},
{
"Name": "Fecha de Naciemiento",
"DataType": "date",
"Value": "1989-09-27T05:30:08-06:00"
}
]
}
I want to format the value value (because it is of type interface{} I need to format it depending on the value type) of the struct Property before marshaling it.
The first solution that occurred to me was to create a (Object) encode() string function or something, that iterates through []Property formatting the values, and marshaling each property separately, then reconstructing the Object with an []string instead of the []Property and then marshaling the object.
Is there any built-in way of doing this? If not, is there any idiomatic way of doing it?
The JSON encoder marshals interface{} values according to the actual type of the value. You can override the default encoding in a couple of ways.
The first is to create a wrapper around values to control how they are encoded using the Marshaler interface. Here's a wrapper that changes how integers are encoded:
type Value struct{ Value interface{} }
func (v Value) MarshalJSON() ([]byte, error) {
switch v := v.Value.(type) {
case int:
return []byte(fmt.Sprintf("\"#%d\"", v)), nil
default:
return json.Marshal(v)
}
}
Use it like this:
prop.Value = Value{45}
playground
A second approach is to implement the Marshaler on the Property type to override how all of the property is marshaled including the Value field.
func (p Property) MarshalJSON() ([]byte, error) {
var buf bytes.Buffer
buf.WriteString(`{"Name":`)
d, err := json.Marshal(p.Name)
if err != nil {
return nil, err
}
buf.Write(d)
buf.WriteString(`,"DataType":`)
d, err = json.Marshal(p.DataType)
if err != nil {
return nil, err
}
buf.Write(d)
buf.WriteString(`, "Value":`)
switch v := p.Value.(type) {
case int:
fmt.Fprintf(&buf, "\"#%d\"", v)
default:
d, err := json.Marshal(v)
if err != nil {
return nil, err
}
buf.Write(d)
}
buf.WriteString("}")
return buf.Bytes(), nil
}
playground
Related
I'm trying to unmarshal some nested JSON which looks like:
{
"id": "aRandomId",
"type": "aRandomType",
"aRandomField": {
"type": "someType",
"createdAt": "2020-07-07T15:50:02",
"object": "anObject",
"modifiedAt": "2020-07-07T15:50:02"
},
"aParameter": {
"type": "Property",
"createdAt": "2020-07-07T15:50:02",
"value": "myValue",
"modifiedAt": "2020-07-07T15:50:02"
},
"location": {
"type": "GeoProperty",
"value": {
"type": "Point",
"coordinates": [
7.0054,
40.9999
]
}
},
... other things with type, value ...
"createdAt": "2020-07-07T15:50:02",
"modifiedAt": "2020-07-07T15:50:02",
}
I would like to get all keys and values which are: type, createdAt, Value (also if they are nested)
Actually, I have 2 structs:
type Attribute struct {
Type string `json:"type"`
CreatedAt string `json:"createdAt"`
Value string `json:"value"`
ModifiedAt string `json:"modifiedAt"`
}
type Entity struct {
Id string `json:"id"`
Type string `json:"type"`
CreatedAt string `json:"createdAt"`
Attribute Attribute
}
in := []byte(buf.String())
var entity Entity
err := json.Unmarshal(in, &entity)
if err != nil {
panic(err)
}
frame.Fields = append(frame.Fields,
data.NewField("key", nil, []string{"type : ", "createdAt : ", "name : "}),
)
frame.Fields = append(frame.Fields,
data.NewField("value", nil, []string{entity.Type, entity.CreatedAt, entity.Attribute.Value}),
)
The problem is there can be several different Attribute struct andIi can't provide them all.
I would like to display all key (only type, createdAt and Value) in one frame and all their value in another.
Maybe have something like that?
type Entity struct {
attribute List<Attribute>
}
type Attribute struct{
Type string
CreatedAt string
Value string
ModifiedAt string
}
The problem is there can be several different Attribute struct andIi can't provide them all
It looks like your JSON data can have a set of keys with similar values (Attribute) and you can't know how many of them might be in the data.
For this case, you can use a map[string]json.RawMessage as the starting entity to unmarshal to
var e map[string]json.RawMessage
if err := json.Unmarshal([]byte(jsonData), &e); err != nil {
panic(err)
}
You can then range over the values to see if you can unmarshal them into Attribute type
for k, v := range e {
var a Attribute
if err := json.Unmarshal(v, &a); err == nil {
log.Printf("Got attribute %s: %s", k, string(v))
}
}
Run it on playground
I have json as following
"data": [
{
"id": "recent_search",
"items": [],
"name": ""
},
{
"id": "popular_search",
"items": [],
"name": ""
},
{
"id": "digital",
"items": [],
"name": "DIGITAL"
}
]
and the structs are as follows:
type universeTypeData struct {
Recent universeSearchInfo
Popular universeSearchInfo
Digital universeSearchInfo
}
type universeSearchInfo struct {
ID string `json:"id"`
Name string `json:"name"`
Items []universeSearchItem `json:"items"`
}
I want to unmarshal my json as "id" with value "recent_search" map to Recent, "id" with value "popular_search" map to Popular. Is there any way of doing this in golang?
My approach of doing it is
for _, v := range result.Data {
if v.ID == "in_category" {
finalResult.Universe.InCategory.ID = v.ID
finalResult.Universe.InCategory.Name = v.Name
for _, abc := range v.Items {
finalResult.Universe.InCategory.Items = append(finalResult.Universe.InCategory.Items, abc)
}
}
if v.ID == "recent_search" {
finalResult.Universe.Recent.ID = v.ID
finalResult.Universe.Recent.Name = v.Name
for _, abc := range v.Items {
finalResult.Universe.Recent.Items = append(finalResult.Universe.Recent.Items, abc)
}
}
if v.ID == "popular_search" {
finalResult.Universe.Popular.ID = v.ID
finalResult.Universe.Popular.Name = v.Name
for _, abc := range v.Items {
finalResult.Universe.Popular.Items = append(finalResult.Universe.Popular.Items, abc)
}
}
Is there any better way of doing it?
You want to unmurshal JSON array into Go struct which is not natural mapping. Any way, you most likely should be first unmurshal in slice and then parse this slice. Some workaround is to use json.Decoder
dec := json.NewDecoder(JSONdataReader)
var res universeTypeData
// read open bracket
dec.Token()
// while the array contains values
for dec.More() {
var m universeSearchInfo
// decode an array value
dec.Decode(&m)
switch m.ID {
case "recent_search":
res.Recent = m
case "popular_search":
res.Popular = m
case "digital":
res.Digital = m
}
}
// read closing bracket
dec.Token()
which allow you to decode on the fly, in one pass, without consuming intermediate slice representation. Working example
Implement Unmarshaler interface:
Unmarshaler is the interface implemented by types that can unmarshal a
JSON description of themselves. The input can be assumed to be a valid
encoding of a JSON value. UnmarshalJSON must copy the JSON data if it
wishes to retain the data after returning.
json unmarshaler interface assign the value from json to struct after parsing the result and applying conditions to fetch the value.
package main
import (
"encoding/json"
"fmt"
)
type Details struct {
Data []universeSearchInfo `json:"data"`
}
type universeTypeData struct {
Recent universeSearchInfo
Popular universeSearchInfo
Digital universeSearchInfo
}
type universeSearchInfo struct {
ID string `json:"id"`
Name string `json:"name"`
Items []string `json:"items"`
}
func main() {
var result universeTypeData
jsonBytes := []byte(`{"data": [
{
"id": "recent_search",
"items": [],
"name": ""
},
{
"id": "popular_search",
"items": [],
"name": ""
},
{
"id": "digital",
"items": [],
"name": "DIGITAL"
}
]}`)
if err := json.Unmarshal(jsonBytes, &result); err != nil {
fmt.Println(err)
}
fmt.Println(result)
}
func (universeData *universeTypeData) UnmarshalJSON(data []byte) error {
var result Details
if err := json.Unmarshal(data, &result); err != nil {
return err
}
for _,value := range result.Data{
switch value.ID {
case "recent_search":
universeData.Recent = value
}
}
return nil
}
Working code on Go Playground
I am trying to unmarshal JSON of the following format:
{
"fixedString": {
"uselessStuff": {},
"alsoUseless": {},
"dynamicField": [
{ "name": "jack" }
],
"dynamicToo": [
{ "name": "jill" }
]
}
}
I would like to drop the fields "uselessStuff" and "alsoUseless", and get everything else. The other keys are user-defined and can take any value.
I can remove the fields I don't want using a custom UnmarshalJSON (based on this answer), but I have a feeling that this is unnecessarily complicated:
package main
import (
"encoding/json"
"fmt"
)
type Response struct {
Things map[string]interface{} `json:"fixedString"`
}
type _R Response
func (f *Response) UnmarshalJSON(bs []byte) (err error) {
foo := _R{}
if err = json.Unmarshal(bs, &foo); err == nil {
*f = Response(foo)
}
delete(f.Things, "uselessStuff")
delete(f.Things, "alsoUseless")
return err
}
func main() {
j := []byte(`{ "fixedString": { "uselessStuff": {}, "alsoUseless": {}, "dynamicField": [ { "name": "jack" } ], "dynamicToo": [ { "name": "jill" } ] } }`)
var r Response
err := json.Unmarshal(j, &r)
if err != nil {
panic(err.Error())
}
for x, y := range r.Things {
fmt.Println(x, y)
}
}
Is there a way to ignore those two keys using annotations, rather than deleting them in a custom UnmarshalJSON function (and having to add the extra type alias _R to avoid a stack overflow)?
You could remove your "uselessStuff" and "alsoUseless" from the map and use them as unexported (lowercase) fields in your struct. Most likely not interface{}
json package ignores unexported fields
type Response struct {
Things map[string]interface{} `json:"fixedString"`
uselessStuff interface{}
alsoUseless interface{}
}
I have to unmarshal a series of Json objects, but one of the objects contain a json array which is not really structured in a good way.
"labels": [
{
"key": "owner",
"value": "harry"
},
{
"key": "group",
"value": "student"
}
]
I am unmarshalling it using this struct -
type StudentDetails struct {
Id string `json:"id"`
Name string `json:"name"`
Labels []Label `json:"labels,omitempty"`
}
type Label struct {
Key string `json:"key"`
Value string `json:"value"`
}
And I have to access it using x.Labels[0].key == "owner" inside a for loop which is very annoying.
I want to be able to do x.Labels.Owner == "harry" instead. How do I go about achieving this? The rest of JSON is unmarshalled fine using the default unmarshal function, so I don't think writing custom function will be good option.
With the constraints you have here, this is about as close as you will get (run in playground):
package main
import (
"encoding/json"
"fmt"
)
func main() {
j := `
{
"id": "42",
"name": "Marvin",
"labels": [
{
"key": "owner",
"value": "harry"
},
{
"key": "group",
"value": "student"
}
]
}`
d := StudentDetails{}
err := json.Unmarshal([]byte(j), &d)
if err != nil {
panic(err)
}
fmt.Println(d.Labels["owner"])
fmt.Println(d.Labels["group"])
}
type StudentDetails struct {
Id string `json:"id"`
Name string `json:"name"`
Labels Labels `json:"labels"`
}
type Labels map[string]string
func (l *Labels) UnmarshalJSON(b []byte) error {
a := []map[string]string{}
err := json.Unmarshal(b, &a)
if err != nil {
return err
}
t := map[string]string{}
for _, m := range a {
t[m["key"]] = m["value"]
}
*l = t
return nil
}
How about to define custom []Label type and add function on it.
For instance
type Labels []Label
func (l Labels) Owner() string {
if len(l) > 1 {
return l[0].Value
}
return ""
}
I'm using JSON files to store/load my config. Let's say I have the following:
type X interface
// implements interface X
type Y struct {
Value string
}
// implements interface X
type Z struct {
Value string
}
type Config struct {
interfaceInstance X `json:"X"`
}
Config file example:
{
"config1": {
"X": {
"type": "Z",
"Value": "value_1"
}
},
"config2": {
"X": {
"type": "Y",
"Value": "value_2"
}
}
}
I want to be able to define config files something like this example, and be able to dynamically load the JSON as either struct Y or struct Z. Any suggestions on how to accomplish this? I'm using a simple json.Decoder to load the JSON as a struct.
decoder := json.NewDecoder(file)
err = decoder.Decode(&config)
One possible strategy would be to implement json.Unmarshaler for the Config type in such a way that you first unmarshal into a generic object and inspect the "type" attribute then, switching on the type string, unmarshal the same byte array into the known type and assign to the "interfaceInstance" member of the config.
For example (Go Playground):
// Note the slightly different JSON here...
var jsonstr = `{
"config1": {
"type": "Z",
"Value": "value_1"
},
"config2": {
"type": "Y",
"Value": "value_2"
}
}`
func main() {
config := map[string]Config{}
err := json.Unmarshal([]byte(jsonstr), &config)
if err != nil {
panic(err)
}
fmt.Printf("OK: %#v\n", config)
// OK: map[string]main.Config{
// "config1": main.Config{interfaceInstance:main.Z{Value:"value_1"}},
// "config2": main.Config{interfaceInstance:main.Y{Value:"value_2"}},
// }
}
func (c *Config) UnmarshalJSON(bs []byte) error {
// Unmarshal into an object to inspect the type.
var obj map[string]interface{}
err := json.Unmarshal(bs, &obj)
if err != nil {
return err
}
// Unmarshal again into the target type.
configType := obj["type"].(string)
switch configType {
case "Y":
var y Y
if err = json.Unmarshal(bs, &y); err == nil {
c.interfaceInstance = y
}
case "Z":
var z Z
if err = json.Unmarshal(bs, &z); err == nil {
c.interfaceInstance = z
}
default:
return fmt.Errorf("unexpected type %q", configType)
}
return err
}