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I want to make a minigame where the background (maze) is always rotating around the same point, an immovable playerMC that's in the middle of the stage. To get the rotation I am using two MCs, one parent, that I rotate, and one nested maze that I would like to move according to mouse/keyboard movement
Unfortunately, the x and y axes on the maze are moved so at 90deg any movement 'up' will change to 'right'.
I do realise sin and cos or translation matrix should do the trick, but for some reason I can't get it right.
Here is a short gif summarising my problem: http://blackdragonschronicles.strefa.pl/Public/Vertigo.gif
I would greatly appreciate any help in the matter
You could use a Matrix which solves this pretty nicely.
In my small example I have an movieclip called box sitting on the stage. Its pivot is in the top left corner (0,0). If I want to rotate the cube from the center I would first translate the matrix by half of its width and height. I then rotate it by some arbitrary angle, and finally apply the matrix transformation to my box.
var angle:Number = Math.PI/64;
var m:Matrix = new Matrix();
m.translate(-box.width >> 1, -box.height >> 1);
stage.addEventListener(Event.ENTER_FRAME, loop);
function loop(e:Event):void {
m.rotate(angle);
box.transform.matrix = m;
}
In the same spirit you could translate a matrix with your current world position. And rotate around that point.
m.translate(position.x, position.y);
You can learn more about Matrices in AS3 here.
Thanks to the link you provided, Iggy, I've managed to understand what and how I want to do it. I used an additional method that was made for situations like this. Here's the code
import flash.events.Event;
import flash.geom.Matrix;
import fl.motion.MatrixTransformer;
addEventListener(Event.ENTER_FRAME,eF);
//Set rotation pivot
var RotationAt:Point = new Point(player.x,player.y);
//Center the MC at the player/pivot
mc.x = player.x
mc.y = player.y
function eF(e:Event){
var my_matrix = mc.transform.matrix;//needs to be refreshed all the time
MatrixTransformer.rotateAroundExternalPoint(my_matrix,player.x,player.y,1);
mc.transform.matrix = my_matrix; // changes the rotation
}
Later I just needed to add code for ading/subtracting x and y with the mouse current position.
Thank you!
Related
I need some help with a really specific problem.
I've looked and found some answers, but nothiung as specific as what I need.
I'm using flashdevelop, and for now, I've a rectangle (it's a Sprite) following my mouse cursor (centered).
I'd like to apply a rotation on it when I scroll my mouse wheel, but I need the rotation to apply on it's center, and I need the object to stay centered on my mouse cursor at the same time.
And I also need to apply the rotation in radians, not in degree.
For now I got this :
var mod:Number;
if (e.delta <= 0) {
mod = -0.1;
}else {
mod = 0.1;
}
Could someone help me with it please ? After what I've seen it seems that I've to use matrix, and complex maths, but I've no idea how to do what I want to do with this.
You just need to keep the registration point of the sprite in center of the rectangle to rotate it about it's center. When you draw a sprite from (0,0) the registration point is top-left and not center. Here's how you make it center:
var rectangleSprite:Sprite = new Sprite();
rectangleSprite.graphics.lineStyle(3,0x00ff00);
rectangleSprite.graphics.beginFill(0x0000FF);
//please note that i am not drawing the sprite from (0,0),
//instead i start from (-width/2,-height/2)
rectangleSprite.graphics.drawRect(-150,-75,300,150);
rectangleSprite.graphics.endFill();
And for degree to radian conversion you just need multiply your value in radians by (180/Math.PI) before applying your rotation.
var rotationInDegrees = rotationInRadians*(180/Math.PI);
Here's what i want to do:
I want to load a model (most likely .3ds) into my .swf and be able to rotate it with the mouse.
This works fine at first glance, but there's problem, the rotations 'switch' over. Or to say it differently:
Imagine we have a model in the shape of a pipe.
If we drag the mouse to the right, the model rotates along its X-Axis to the left, mouse to the left, X-Axis rotation to the right, moving the mouse up, Y-Axis rotation downward, mouse down, Y-Axis rotation upward.
Now, lets say we turn the pipe to the right or left, until we face the (former) 'backside' of the pipe, and then we move the mouse down. The model will rotate downward instead of upward.
I hope you understand what i mean with this. I've been looking around for a good while now and never found a satisfying solution. There was talk about quaternions, but i can't grasp them.
Another suggestion i read somewhere is the following:
create a Matrix3D object, apply rotation on it, then multiply it with the desired Matrix3D of my 3d-Model.
I tried to do it, but the result stays the same, the directions of rotation switches depending on what side i'm facing.
private function update(e:Event):void
{
xCalc = (0.3*(stage.mouseX - lastMouseX));
yCalc = (0.3*(stage.mouseY - lastMouseY));
if(move)
{
var objTransform:Matrix3D = new Matrix3D();
objTransform.prependRotation(xCalc, Vector3D.Y_Axis, objC.pivotPoint);
objTransform.prependRotation(yCalc, Vector3D.X_Axis, objC.pivotPoint);
mesh.transform = multiply3DMatrices(mesh.transform, objTransform);
}
lastMouseX = stage.mouseX;
lastMouseY = stage.mouseY;
view.render();
}
multiply3DMatrices simply multiplies two 4x4 Matrices together.
objC is the ObjectContainer3D that holds my model. For some reason i cannot rotate it properly, unless i manipulate the rotationX/Y/Z properties.
mesh is the mesh inside of the Model (which is very simple, a single mesh).
Also, i'm aware that i could try another Framework for this (like papervision) but this project requires me to use Away3D.
Solved it by myself, the problem was that i created a new Matrix3D Object every time. The fixed code looks like this:
private function update(e:Event):void
{
...
if(move)
{
var objTransform:Matrix3D = mesh.transform;
objTransform.appendRotation(xCalc, Vector3D.Y_Axis, objC.pivotPoint);
objTransform.appendRotation(yCalc, Vector3D.X_Axis, objC.pivotPoint);
mesh.transform = objTransform;
}
...
}
And yes, the user bwroga was actually right, i should've used appendRotation instead of prependRotation, as well.
I am trying to use these easing functions from this page;
https://gist.github.com/gre/1650294
In my canvas project, I am wondering if anyone could shed some light on how to use these with say a rectangle on my canvas which has an x and y property.
I understand t is time, (I have successfully managed to get the delta time of my frame intervals, not sure if this is needed).
How can I use these functions to make the easing effects be applied to my rectangle which has an x and y property which are the co-ordinates of where it should be placed onto the canvas?
I know this question is kinda vague, but I really do not understand these functions and how they should be integrated with a rectangle on the canvas.
Thanks
You can use it like this -
(Click here to see working example at jsfiddle)
var x = 100; //final position
var t = 0; //0-1, this is what you change in animation loop
In your loop:
function myLoop() {
var tx = EasingFunctions.easeInQuad(t) * x;
// set element by tx
if (t < 1) {
t += 0.1; //determines speed
requestAnimationFrame(myLoop);
//setTimeout(myLoop, 16); //option to above
}
}
See also:
http://greweb.me/2012/02/bezier-curve-based-easing-functions-from-concept-to-implementation/
I know it's nice to write you own code; but should you want to use a library then this one is pretty good:
Tween JS
It uses the easing methods you referenced as supports chaining.
I'm currently struggling on a problem that seems far beyond my maths capacities (been a long time since I've made some proper maths...) and I would appreciate some help on that.
Here's my setting :
I got some simple shapes (rectangles), and I "project" their bottom points on a line, coming from an Origin point.
Up to this point everything is fine.
But now I'd like to draw the original shape distorted as if it was projected with some perspective on a plane.
Please consider that I have nothing related to any rotation, isometric or any 3D or fake 2D perspective in my code, I'm only trying to draw some shapes using the graphics library to only have a feeling of something real.
Here's a quick drawing of what I'm trying to do :
What I know :
Origin point coordinates
the rect position & sizes
the red line position
the A & B points coordinates
What I want to determine is the coordinates of the C & D points, thing that could be easy if I wasn't struggling to find the "Origin bis" coordinates.
What I'm trying to do is to fake the projection of my rectangle on something that can be considered as a "floor" (related to the plane where my original rectangle is that can be seen as a wall).
Maybe I'm over-complicating the problem or maybe I fail to see any other easier way to do it, but I'm really not good anymore in any geometry or maths thing... :-(
Thanks a lot for your answers !
hmm i don't know if I undestood it correctly but I think you have too few input parameters:
you said the following information is given:
Origin point coordinates
the rect position & sizes
the red line position
the A & B points coordinates
I don't think it is possible to get your projected rectangle with this information alone.
Additionally, I think your green lines and the 'origin Bis' aren't helpful as well.
Perhaps, try this:
Supose, a blue line going through the points C & D is given as well.
Then you could find your projected rectangle by projecting the top of the rectangle onto that blue line.
So in summary:
You define an origin + two parallel lines, a red and a blue one.
Then you can project the top of the rect onto the blue line and the bottom of the rect onto the red line, yielding the points A,B,C,D
I hope this helps.
If I'm right, this code will show what you wanted to see.
First of all, I've ignored your initial setup of objects and information, and focused on the example situation itself; fake-projecting shadow for a "monolith" (any object is possible with the example below, even textured)
My reason was that it's really quite easy with the Matrix class of ActionScript, a handy tool worth learning.
Solution:
You can use the built-in Matrix class to do skew transform on DisplayObjects.
Try this example:
(The "useful" part lies in the _EF EnterFrame handler ;) )
import flash.display.MovieClip;
import flash.geom.Matrix;
import flash.events.Event;
import flash.display.BitmapData;
const PIP180:Number = Math.PI / 180;
const MAX_SHADOW_HEIGHT_MULTIPLIER:Number = 0.25; // you can also calculate this from an angle, like ... = Math.sin(angle * PIP180);
const ANIM_DEG_PER_FRAME:Number = 1.0 * PIP180; // the shadow creeps at a +1 degree per frame rate
var tx:BitmapData = new MonolithTexture(); // define this BitmapData in the library
var skew:Number = -10 * PIP180; // initial
var mono:MovieClip = new MovieClip();
mono.graphics.beginBitmapFill(tx);
// drawn that way the registration point is 0,0, so it's standing on the ground
mono.graphics.drawRect(0, -tx.height, tx.width, tx.height);
mono.graphics.endFill();
// align monolith to the "ground"
mono.x = stage.stageWidth / 2;
mono.y = stage.stageHeight - 100;
// make it be 100x300 pixel
mono.width = 100;
mono.height = 300;
var shad:MovieClip = new MovieClip();
// colored:
shad.graphics.beginFill(0x000000);
// or textured:
//shad.graphics.beginBitmapFill(tx);
shad.graphics.drawRect(0, -tx.height, tx.width, tx.height);
shad.graphics.endFill();
addChild(shad); // shadow first
addChild(mono); // then the caster object
addEventListener(Event.ENTER_FRAME, _EF);
function _EF(e:Event):void {
// animate skew on the positive half circle
skew = (skew + ANIM_DEG_PER_FRAME) % Math.PI;
// Matrix takes 6 parameters: a, b, c, d, x, y
// for this shadow trick, use them as follows:
// a = width scaling (as mono and shad are drawn in the same way, copy mono.scaleX for a perfect fit
// b = 0, because we don't want to project the vertical axis of transformation to the horizontal
// c = horizontal skew
// d = height scaling * skew * making it a bit flat using the constant
// x = mono.x, ...
// y = mono.y since originally mono and shad look alike, only the Matrix makes shad render differently
var mtx:Matrix = new Matrix(mono.scaleX, 0, Math.cos(skew), mono.scaleY * Math.sin(skew) * MAX_SHADOW_HEIGHT_MULTIPLIER, mono.x, mono.y);
shad.transform.matrix = mtx;
}
Now all you got to know to utilize this in your case, is the following N factors:
Q1: from what angle you want to project the shadow?
A1: horizontal factor is the skew variable itself, while vertical angle is stored as constant here, called MAX_SHADOW_HEIGHT_MULTIPLIER
Q2: do you want to project shadow only "upwards", or freely?
A2: if "upwards" is fine, keep skew in the positive range, otherwise let it take negative values as well for a "downward" shadow
P.S.: if you render the internals of the objects that they don't snap to 0 y as a base point, you can make them seem float/sink, or offset both objects vertically with a predefined value, with the opposite sign.
You face 1 very simple problem, as you said:
'What I want to determine is the coordinates of the C & D points, thing that could be easy if I wasn't struggling to find the "Origin bis" coordinates.'
But these co-ordinates relate to each other, so without one (or another value such as an angle) you cannot have the other. If you are to try this in 3D you are simply allowing the 3D engine to define 'Origin bis' and do your calculating for C and D itself.
So regardless you will need an 'Original bis', another value relating to the redline or your Rect for which to calculate the placement of C and D.
I remember making stuff like this and sometimes it's better to just stick with simple, you either make an 'Original bis' defines by yourself (it can be either stationary or move with the player/background) and get C and D the way you got A and B only that you use a lower line than the red line, or as I would of done, once you have A and B, simple skew/rotate your projection from those points down a bit further, and you get something the same as an 'Original bis' that follows the player. This works fine at simulating 'feeling of something real' but sadly as has been said, it looking real depends on what you are portraying. We do not know what the areas above or below the red line are (sky/ground, ground/water) and whether 'Origin' and 'Origin bis' is your light source, vanishing point, etc.
I have a task:
I need to place about 100 sprites on one canvas (with prepared grid on it). I need to place them as invisible (circles) stones, on the board, and make visible only on mouseover.
The problem I come across is following, I can't place those objects accurately into the nodes on the grid.
E.g.
if I define stones (it's just a sprite, as I said earlier) this way:
var stone:StoneSprite = new StoneSprite();
stone.x = this.x + 2*cellWidth;
stone.graphics.beginFill( 0x000000 );
stone.graphics.drawCircle(stone.x , this.y + cellWidth, cellWidth/3 );
stone.graphics.endFill();
rawChildren.addChild(stone);
They don't sit on the node...
See image:
http://img.skitch.com/20091014-kuhfyjeg1g5qmrbyxbcerp4aya.png
And if I do it this way:
var stone:StoneSprite = new StoneSprite();
stone.graphics.beginFill( 0x000000 );
stone.graphics.drawCircle(this.x + 2*cellWidth , this.y + cellWidth, cellWidth/3 );
stone.graphics.endFill();
rawChildren.addChild(stone);
The stone is displayed correctly in the grid node... See image 2:
http://img.skitch.com/20091014-f595tksjxramt98s7yfye591bh.png
So I wonder what is the difference between these 2 approaches.
Also, I think I need to pass correct coordinates to the stone class... In case I would like to change some properties of the stone object. E.g. visibility, or radius.
Could you please suggest, what's wrong in defining coordinates as stone.x, stone.y
How to fix the problem with incorrect positioning.
Would really appreciate ideas about the problem, I am trying to solve for so long :(
Assume x & y are 30 and cellWidth is 30.
First Example:
stone.x = 30 + 60; //90
drawCircle(90, 60, 10);
This means if you were to draw a rectangle around your circle, it would be at [170,50]. (x,y).
Second Example:
stone.x = 0;
drawCircle(90, 60, 10)
This means the rectangle around your circle is at [80,50];
In the first example, you are moving the sprite to position x==90. Then drawing a circle whose center is at x==90 inside the sprite. So relative to this, you're at x==180. But because a circle's x,y coords are the center, subtract 10 for the radius to get the boundary x position.
In the second example, the sprite defaults to position x==0 relative to this and you're drawing the circle inside the sprite at position x==90. (therefore it begins at x==80).
I am not sure what's causing the issue - might be some padding induced by the container - can't say without testing. But I believe that adding a Sprite (say board) to canvas.rawChildren and using it as the parent for the grid and stones would fix the issue.