Split JSON data when comma is found - json

I want to separate and put data into array. Here's my AJAX code if it succeeded.
success : function(data){
alert (data);
$('#status').append("<p>Tax Declaration: "+data[0]
+ "<br/>Barangay: "+data[1]+"</p>"
);
},
sample out put is 08-09-0001-00047,BILAY. I want them to be separated.

If you have a string that is comma separated and you want to create an array of the items in the list, use split() like this:
var values = data.split(",");
$('#status').append(
"<p>Tax Declaration: "+values[0] + "<br/>Barangay: "+values[1]+"</p>"
);

As #Andy Jones mentioned, use .split() like so:
success : function(data){
data = data.split(/\s*,\s*/g);
$('#status').append("<p>Tax Declaration: "+data[0]
+ "<br/>Barangay: "+data[1]+"</p>"
);
},

Related

How to edit a JSON file in QT QML

I am new to QT, QML and JSON. I am trying to write a simple program that saves data into a JSON file. The programs has 3 files:
main.qml has 2 text input fields and 1 button that calls a function in script.js
storage.json {"sets":[{object Object},{object Object}]}
script.js holds this function:
function insertNewSet (name, description){
var newSet = {
setName: "name",
setDescription: "description",
setInput: []
}
var newJson = JSON.stringify(newSet);
}
name and description come from the input fields in main.qml
How can the variable newSet be inserted as a third object in newSet?
example: {"sets":[{object Object},{object Object},{object Object}]}
You need to use ' ' symbols to specify the properties.
These can be called up this way:
var newSet = {
'setName': 'name',
'setDescription': 'description',
'setInput': []
}
var newJson = JSON.stringify(newSet['setName']+newSet['setDescription']+newSet['setInput']);
If you didn't think about it, maybe this page will help you:
https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Global_Objects/Array

Use string as a JSON command

I have this string:
var test = "toAdd";
I want to use it to extract data from JSON, like:
console.log(value.stats.test);
As you see, test is not correct, as it is just a string and can't be used, it is just not recognized at all. How do I make it recognize?
What you are attempting to do is this:
var someVar;
someVar.test = 'Sample';
someVar.test.attribute = 'Another sample';
// this:
console.log(someVar['test']['attribute']);
// will produce the same as this:
console.log(someVar['test'].attribute);
// as well as the same as this:
console.log(someVar.test['attribute']);
This will print "Another sample".
This has nothing to do with JSON. This is just javascript, and like anything where the . notation won't work switch to array notation:
foo.bar.baz = 'qux';
alert(foo['bar'].baz); // popup with 'qux'
^-----^-- note these
In your case, value.stats[test]. Now "test" isn't an array key, it's a variable whose value gets used as the key.

Dynamic ng-Grid with JSON data in angularJS?

I want to make a dynamic ng-grid , which adjusts its columns according to the key values in my JSON object. JSON object is fetched from an api. the problem I am facing is defining columns at runtime i.e The columns are not available at design time but will only be available only at runtime. I want to have something like :
http://plnkr.co/edit/q1Ye10OsIn9NOJmrICyD?p=preview
So that, I have as many columns as keys in my Json object. API's can vary so I need to make a grid which adjusts its columns.
My plunker is not working, but I hope it gives you idea, what I am trying to do.
Unless I'm misunderstanding what you want, you don't need to mess with columnDefines. Just having this:
faculty.controller('facultycontroller', function facultycontroller($scope, $http, $window){
$scope.facdata = [];
$scope.gridOptions = {
data: 'facdata'
};
$http.get("http://mtapi.azurewebsites.net/api/institute").then(function (result) {
$scope.facdata = result.data;
console.log($scope.facdata[0]);
});
});
will create the grid with a column for each key in your json.
Update
If you want to filter out any columns that begin with '$', you can do something like this:
angular.forEach(result.data[0], function(value, key){
if(key.indexOf('$') != 0)
$scope.columnDefines.push({ field: key, displayName: key});
});
Actually, you were close with what you were trying to do. You just need to put the columnDefines variable on $scope, and assign it to the gridOptions using a string, like this:
$scope.columnDefines = [];
$scope.gridOptions = {
data: 'facdata',
columnDefs: 'columnDefines'
};
Plunker
Try attaching your columnDefines variable to the scope ($scope.columnDefines). Then in your options do this:
$scope.gridOptions =
{
data: 'facdata',
columnDefs: 'columnDefines' //Note the quotes
};
This will make ng-grid watch your columnDefs for changes

What is "compressed JSON"?

I see a lot of references to "compressed JSON" when it comes to different serialization formats. What exactly is it? Is it just gzipped JSON or something else?
Compressed JSON removes the key:value pair of json's encoding to store keys and values in seperate parallel arrays:
// uncompressed
JSON = {
data : [
{ field1 : 'data1', field2 : 'data2', field3 : 'data3' },
{ field1 : 'data4', field2 : 'data5', field3 : 'data6' },
.....
]
};
//compressed
JSON = {
data : [ 'data1','data2','data3','data4','data5','data6' ],
keys : [ 'field1', 'field2', 'field3' ]
};
This method of usage i found here
Content from link (http://www.nwhite.net/?p=242)
rarely find myself in a place where I am writing javascript applications that use AJAX in its pure form. I have long abandoned the ‘X’ and replaced it with ‘J’ (JSON). When working with Javascript, it just makes sense to return JSON. Smaller footprint, easier parsing and an easier structure are all advantages I have gained since using JSON.
In a recent project I found myself unhappy with the large size of my result sets. The data I was returning was tabular data, in the form of objects for each row. I was returning a result set of 50, with 19 fields each. What I realized is if I augment my result set I could get a form of compression.
// uncompressed
JSON = {
data : [
{ field1 : 'data1', field2 : 'data2', field3 : 'data3' },
{ field1 : 'data4', field2 : 'data5', field3 : 'data6' },
.....
]
};
//compressed
JSON = {
data : [ 'data1','data2','data3','data4','data5','data6' ],
keys : [ 'field1', 'field2', 'field3' ]
};
I merged all my values into a single array and store all my fields in a separate array. Returning a key value pair for each result cost me 8800 byte (8.6kb). Ripping the fields out and putting them in a separate array cost me 186 bytes. Total savings 8.4kb.
Now I have a much more compressed JSON file, but the structure is different and now harder to work with. So I implement a solution in Mootools to make the decompression transparent.
Request.JSON.extend({
options : {
inflate : []
}
});
Request.JSON.implement({
success : function(text){
this.response.json = JSON.decode(text, this.options.secure);
if(this.options.inflate.length){
this.options.inflate.each(function(rule){
var ret = ($defined(rule.store)) ? this.response.json[rule.store] : this.response.json[rule.data];
ret = this.expandData(this.response.json[rule.data], this.response.json[rule.keys]);
},this);
}
this.onSuccess(this.response.json, text);
},
expandData : function(data,keys){
var arr = [];
var len = data.length; var klen = keys.length;
var start = 0; var stop = klen;
while(stop < len){
arr.push( data.slice(start,stop).associate(keys) );
start = stop; stop += klen;
}
return arr;
}
});
Request.JSON now has an inflate option. You can inflate multiple segments of your JSON object if you so desire.
Usage:
new Request.JSON({
url : 'url',
inflate : [{ 'keys' : 'fields', 'data' : 'data' }]
onComplete : function(json){}
});
Pass as many inflate objects as you like to the option inflate array. It has an optional property called ’store’ If set the inflated data set will be stored in that key instead.
The ‘keys’ and ‘fields’ expect strings to match a location in the root of your JSON object.
Based in Paniyar's answer, we can convert a List of Objects in "compressed" Json format using C# like this:
var JsonString = serializer.Serialize(
new
{
cols = new[] { "field1", "field2", "field3"},
items = data.Select(x => new object[] {x.field1, x.field2, x.field3})
});
I used an array of object because the fields can be int, bool, string...
More Reduction:
If the field is repeated very often and it is a string type, you can get compressed a little be more if you add a distinct list of that field... for instance, a field name job position, city, etc are excellent candidate for this. You can add a distinct list of this items and in each item change the value for a reference number. That will make your Json more lite.
Compressed:
[["KeyA", "KeyB", "KeyC", "KeyD", "KeyE", "KeyF"],
["ValA1", "ValB1", "ValC1", "ValD1", "ValE1", "ValF1"],
["ValA2", "ValB2", "ValC2", "ValD2", "ValE2", "ValF2"],
["ValA3", "ValB3", "ValC3", "ValD3", "ValE3", "ValF3"],
["ValA4", "ValB4", "ValC4", "ValD4", "ValE4", "ValF4"]]
Uncompressed:
[{KeyA: "ValA1", KeyB: "ValB1", KeyC: "ValC1", KeyD: "ValD1", KeyE: "ValE1", KeyF: "ValF1"},
{KeyA: "ValA2", KeyB: "ValB2", KeyC: "ValC2", KeyD: "ValD2", KeyE: "ValE2", KeyF: "ValF2"},
{KeyA: "ValA3", KeyB: "ValB3", KeyC: "ValC3", KeyD: "ValD3", KeyE: "ValE3", KeyF: "ValF3"},
{KeyA: "ValA4", KeyB: "ValB4", KeyC: "ValC4", KeyD: "ValD4", KeyE: "ValE4", KeyF: "ValF4"}]
The most likely answer is that it really is just gzipped JSON. There is no other standard meaning to this phrase.
Re-organizing a homogenous array of JSON objects into a pair of arrays is a very useful technique to make the payload smaller and to speed up encoding and decoding, it is not commonly called "compressed JSON". I haven't run across it ever in open source or any open API, but we use this technique internally and call it "jsontable".

Displaying HTML content in a field

I'm getting a JSON response from the server. Inside that JSON string I have HTML content which I need to display in a field. How do I do this?
Is this what you need? What kind of field?
If it's a div or p
var yourContent = "";
$(".selector").html(yourContent);
If it's textbox use
$(".selector").val(yourContent);
That's of course if you using jQuery
If the JSON result is say:
({
name: 'John'
})
We grab it and operate on it like so:
$.getJSON("http://yourjsonresource",
function(data){
$('h1#foo').text( data.name );
}
);