I am trying to count of coupons sold by each store from the list of stores within 20 miles range. I know the following syntax will work if there is only 1 store.
SELECT sum(couponscount) as count where restaurant IN (SELECT storename where bhal bhal bhal and output is one value)
What is I the IN (SELECTstorenamewhere bhal bhal bhal and output is multiple values) will return multiple values?
Like in my case the complete SQL is like and its not working
SELECT sum(couponscount) as count FROM `coupons` having `restaurant` IN (SELECT `storename`, ((ACOS(SIN(-27.561264299999998 * PI()/180) * SIN(latitude * PI()/180) + COS(-27.561264299999998 * PI()/180) * COS(latitude * PI()/180) * COS((153.07304890000003 – longitude) * PI()/180)) *180 / PI( )) *60 * 1.1515) AS `distance` FROM `stores` WHERE `status`=’active’ HAVING `distance` <=20)
Is there anyway to make it working?
SELECT sum(couponscount) AS COUNT,restaurant
FROM `coupons`
WHERE `restaurant` IN
(SELECT `storename`
FROM `stores`
WHERE `status`='active'
AND
((ACOS(SIN(-27.561264299999998 * PI()/180) * SIN(latitude * PI()/180) + COS(-27.561264299999998 * PI()/180) * COS(latitude * PI()/180) * COS((153.07304890000003 – longitude) * PI()/180)) *180 / PI()) *60 * 1.1515) <=20)
GROUP BY restaurant
Also use proper quotes for active.
Presumably, you want to get the count of coupons from stores within a distance of 20. Moving the having condition to a where clause should do what you want:
SELECT sum(couponscount) as count
FROM `coupons`
WHERE `restaurant` IN (SELECT `storename`
FROM `stores`
WHERE `status` = 'active' AND
((ACOS(SIN(-27.561264299999998 * PI()/180) * SIN(latitude * PI()/180) + COS(-27.561264299999998 * PI()/180) * COS(latitude * PI()/180) * COS((153.07304890000003 – longitude) * PI()/180)) *180 / PI( )) *60 * 1.1515) <= 20
);
You had a major syntax problem because your subquery returned two columns. When you use a subquery with in, you can only return one column, in this case, storename. I moved the code for the distance calculation to the where clause. No having clause is needed either in the subquery or the outer query.
Related
this is Lat and Lon example in mysql database
ID | Lat | Lon
1 | 3.1412 | 101.6865
2 | 1.2897 | 103.8501
The formula below calculates the distance between two Lat (latitudes) and Lon (longitudes) and gets the result that I want. But this formula doesn't extract my Lat and Lon from the database. I would like to ask, how to get the distance result by using ID and calculate two Lat and Lon? My friend told me using Join table, but I still don't get the answer..
SELECT ROUND(6353 * 2 * ASIN(SQRT( POWER(SIN((3.1412 -
abs(1.2897)) * pi()/180 / 2),2) + COS(3.1412 * pi()/180 ) * COS(
abs(1.2897) * pi()/180) * POWER(SIN((101.6865 - 103.8501) * pi()/180 / 2), 2) )), 2);
Thanks for advance
You can join the same table two time one for Id 1 and one for id 2 assigning different alias name
then use the related column name
SELECT ROUND(6353 * 2 * ASIN(SQRT( POWER(SIN((a.lat -
abs(b.lat)) * pi()/180 / 2),2) + COS(a.lat * pi()/180 ) * COS(
abs(b.lat) * pi()/180) * POWER(SIN((a.lng - b.lng) * pi()/180 / 2), 2) )), 2);
from my_table a
inner join my_table b on a.id = 1 and b.id = 2
It is working for me
SELECT *,(((acos(sin((12.942999*pi()/180)) * sin((`Lat`*pi()/180))+cos((12.942999*pi()/180)) * cos((`Lat`*pi()/180)) * cos(((74.82994- `Lon`)* pi()/180))))*180/pi())*60*1.1515*1.609344 ) as distance FROM ven_vendor HAVING distance <= 10
I'm trying to select events in a 5 km radius and order them by likes and from oldest to newest. I know how to select events and order them by likes, but I can't figure this one out. The problem maybe is that the location is stored in a different table.
Database structure:
event plusone (like) location
id_event id_plusone id_location
location_id event_id lat
... user_id lon
... city_id
full_name
....
The SQL statement I'm trying:
SELECT 3956 * 2 * ASIN(
SQRT(POWER(SIN((50.127946 - abs(l.lat)) * pi()/180 / 2),2) + COS(50.127946 * pi()/180 ) *
COS(abs(l.lat) * pi()/180) * POWER(SIN((14.4882912 - l.lon) * pi()/180 / 2), 2) )) AS distance,e.*,COUNT( p.id_plusone ) AS
likes
FROM
event e,location l
LEFT JOIN plusone p ON p.event_id = e.id_event
WHERE
e.location_id = l.id_location AND distance<=5 GROUP BY e.id_event
ORDER BY e.timestamp DESC,likes DESC
The huge column at the beginning is calculation of distance of the event from user position using latitude and longitude.
This is what I get from the SQL debugger:
#1054 - Unknown column 'distance' in 'where clause'
Does anybody know how to do this?
Is hard to track where the error is, you should try to solve the distance part first.
SELECT
event_id,
3956 * 2 * ASIN(SQRT( POWER(SIN((50.127946 - abs(l.lat)) * pi()/180 / 2),2)
+ COS(50.127946 * pi()/180 ) * COS(abs(l.lat) * pi()/180) * POWER(SIN((14.4882912 – l.lon) * pi()/180 / 2), 2) )) AS distance,
FROM event e
JOIN location l
WHERE distance <= 5
And then join to back to the event table
SELECT e.*, count(p.id_plusone)
FROM event e
LEFT JOIN plusone p
ON p.event_id = e.id_event
JOIN ( Previous Distance Query) d
ON e.event_id = d.event_id
GROUP BY e.id_event
ORDER BY e.timestamp DESC, likes DESC
and btw, this group_by will bring you event_id plus random values for e.* so be carefull
$latitudeD= latitude;
$longitudeD = longitude;
SELECT event,
SQRT(
POW(69.1 * (coordX - $latitudeD), 2) +
POW(69.1 * ($longitudeD - coordY) * COS(coordX / 57.3), 2)) AS distance
FROM db.table WHERE SQRT(
POW(69.1 * (coordX - $latitudeD), 2) +
POW(69.1 * ($longitudeD - coordY) * COS(coordX / 57.3), 2)) < 50 ORDER BY distance
;
I have a query that selects all locations within a 30 mile radius of a GPS pt. I want to get the id's of those locations, but it's also returning the distance from the center pt.
Is there anyway to perform the distance calculation without returning it?
Query:
SELECT id, 3956 * 2 * ASIN(SQRT(
POWER(SIN((34.1844709 - abs(dest.lat)) * pi()/180 / 2),
2) + COS(37.7749295 * pi()/180 ) * COS(abs(dest.lat) *
pi()/180) * POWER(SIN((-118.131809 - dest.lng) *
pi()/180 / 2), 2) )) as distance
FROM location dest
having distance < 30
ORDER by distance
LIMIT 30
Output:
---------------------------
id | distance
---------------------------
1 | 2.310
2 | 2.356
17 | 4.298
Query based off:
http://www.notaires.fr/sites/default/files/geo_searchjkkjkj_0.pdf
Can you just do another select on this?
Select id
From (SELECT id, 3956 * 2 * ASIN(SQRT(
POWER(SIN((34.1844709 - abs(dest.lat)) * pi()/180 / 2),
2) + COS(37.7749295 * pi()/180 ) * COS(abs(dest.lat) *
pi()/180) * POWER(SIN((-118.131809 - dest.lng) *
pi()/180 / 2), 2) )) as distance
FROM location dest
having distance < 30
ORDER by distance
LIMIT 30) dst
I recently posted this question: getting distance between two points using google gps api with php
and I received a reply which was awesome however I had some questions about the person's response and due to my low/new status to this site I wasn't able to comment back. In response to my question the other user posted this query
**
SELECT a.*, 3956 * 2 * ASIN(SQRT( POWER(SIN(($lat - lat) * pi()/180 / 2), 2) + COS($lat * pi()/180) * COS(lat * pi()/180) *
POWER(SIN(($long - longi) * pi()/180 / 2), 2) )) as distance
FROM table
GROUP BY id HAVING distance <= 500
ORDER by distance ASC**
I had a few questions about this query and was hoping somebody could help.
1.What is the a.*? I'm not super advanced in sql but pretty efficient and have never seen something like this. I don't know if it is supposed to represent an arbritrary field or an actual field in my table
2.Since I'm doing this in php the query will go in quotes which will then make this query syntax slightly different. I was wondering if someone knew what the query would look like in quotes.
3.There is also "GROUP BY id" in this query. I do have an id field in my table that I'm querying from. Is this "id" associated with my id field in my table?
any help would be awesome.
Your query should be like this :-
a is table alias here.
SELECT a.*, 3956 * 2 * ASIN(SQRT( POWER(SIN(($lat - lat) * pi()/180 / 2), 2) + COS($lat * pi()/180) * COS(lat * pi()/180) *
POWER(SIN(($long - longi) * pi()/180 / 2), 2) )) as distance
FROM table AS a
GROUP BY id HAVING distance <= 500
ORDER by distance ASC
Or you can use simple
SELECT *, 3956 * 2 * ASIN(SQRT( POWER(SIN(($lat - lat) * pi()/180 / 2), 2) + COS($lat * pi()/180) * COS(lat * pi()/180) *
POWER(SIN(($long - longi) * pi()/180 / 2), 2) )) as distance
FROM table
GROUP BY id HAVING distance <= 500
ORDER by distance ASC
I'm using a slightly-modified version of the geocoded gem which returns this query when I call near on my model (calling Deal.near(southwest), where southwest is an array of geo coordinates):
SELECT
deals.*,
3958.755864232 * 2 * ASIN(SQRT(POWER(SIN((37.772476604436974 - addresses.lat) * PI() / 180 / 2), 2) + COS(37.772476604436974 * PI() / 180) * COS(addresses.lat * PI() / 180) * POWER(SIN((-122.42336332798004 - addresses.lng) * PI() / 180 / 2), 2) )) AS distance,
CAST(DEGREES(ATAN2( RADIANS(addresses.lng - -122.42336332798004), RADIANS(addresses.lat - 37.772476604436974))) + 360 AS decimal) % 360 AS bearing
FROM "deals"
INNER JOIN "companies" ON "companies"."id" = "deals"."company_id"
INNER JOIN "addresses" ON "addresses"."addressable_id" = "companies"."id" AND "addresses"."addressable_type" = 'Company'
WHERE (
addresses.lat BETWEEN 37.483013038215276 AND 38.06194017065867
AND addresses.lng BETWEEN -122.78956461309022 AND -122.05716204286986
)
GROUP BY
deals.id,
deals.created_at,
deals.updated_at,
deals.active,
deals.company_id,
deals.title,
deals.limitations,
deals.redemption_count,
addresses.lat,
addresses.lng
HAVING 3958.755864232 * 2 * ASIN(SQRT(POWER(SIN((37.772476604436974 - addresses.lat) * PI() / 180 / 2), 2) + COS(37.772476604436974 * PI() / 180) * COS(addresses.lat * PI() / 180) * POWER(SIN((-122.42336332798004 - addresses.lng) * PI() / 180 / 2), 2) )) <= 20
ORDER BY 3958.755864232 * 2 * ASIN(SQRT(POWER(SIN((37.772476604436974 - addresses.lat) * PI() / 180 / 2), 2) + COS(37.772476604436974 * PI() / 180) * COS(addresses.lat * PI() / 180) * POWER(SIN((-122.42336332798004 - addresses.lng) * PI() / 180 / 2), 2) )) ASC
My issue is that this will return multiple Deal records if that Deal's company has multiple Addresses, which I don't want.
In MySQL, I could just omit address.lat, address.lng in the GROUP_BY clause and it will properly group the records, but I can't do this in PostgreSQL.
I know I could wrap the whole query above in another SELECT and GROUP_BY, like this:
SELECT
id, created_at, updated_at, active, title, punches_to_complete, company_id, description, lat, lng, MIN(distance), bearing
FROM ( ... ) AS t
GROUP BY company_id
... where the ellipsis is the query from above. That (I believe) should get me the desired result in both MySQL and PostgreSQL.
The only problem is that I have no idea how to write this in ARel!
I had tried the following, a la this tip from the ARel guru, but I couldn't really make it work quite right (calling to_sql as the OP had said fixed his issue escapes the quotes, which freaks PostgreSQL out).
Can anyone help me with this???
UPDATE:
I've managed to get this done with an additional scope, like so:
scope :nearest, lambda { |coords|
subquery = "(#{Deal.near(coords).to_sql}) AS t1"
columns = Deal.columns.map{ |c| c.name }.join(',')
Deal.select(columns)
.select('MIN(distance) AS distance')
.from(subquery)
.group(columns)
.order('distance ASC')
}
However, this totally breaks chainability, as now I cannot call something like current_user.deals.nearest(coords), since that tags on an additional WHERE deals.user_id = 1 to the query outside of the subselect. I tried compensating for this by moving this logic into a class method and blanking the wheres clause on the SelectManager manually, like this:
def self.nearest(coords)
subquery = "(#{Deal.near(coords).to_sql}) AS t1"
columns = Deal.columns.map{ |c| c.name }.join(',')
query = Deal.select(columns)
.select('MIN(distance) AS distance')
.from(subquery)
.group(columns)
.order('distance ASC')
query.arel.ast.cores[0].wheres = []
query
end
... but that doesn't seem to work either: the additional WHERE clause is still appended:
Failure/Error:
#user.deals.nearest(southwest).first.distance.to_f.round(2).should ==
ActiveRecord::StatementInvalid:
Mysql2::Error: Unknown column 'deals.user_id' in 'where
clause': SELECT id,created_at,updated_at,user_id,company_id,
MIN(distance) AS distance FROM (SELECT deals.*, 3958.755864232 * 2 *
ASIN(SQRT(POWER(SIN((37.772476604436974 - addresses.lat) * PI() / 180
/ 2), 2) + COS(37.772476604436974 * PI() / 180) * COS(addresses.lat *
PI() / 180) * POWER(SIN((-122.42336332798004 - addresses.lng) * PI() /
180 / 2), 2) )) AS distance, CAST(DEGREES(ATAN2( RADIANS(addresses.lng
- -122.42336332798004), RADIANS(addresses.lat - 37.772476604436974)))
+ 360 AS decimal) % 360 AS bearing FROM deals INNER JOIN companies
ON companies.id = deals.company_id INNER JOIN addresses ON
addresses.addressable_id = companies.id AND
addresses.addressable_type = 'Company' WHERE deals.user_id =
26 AND (addresses.lat BETWEEN 37.483013038215276 AND 38.06194017065867
AND addresses.lng BETWEEN -122.78956461309022 AND -122.05716204286986)
GROUP BY
deals.id,deals.created_at,deals.updated_at,deals.user_id,deals.company_id,
addresses.lat, addresses.lng HAVING 3958.755864232 * 2 *
ASIN(SQRT(POWER(SIN((37.772476604436974 - addresses.lat) * PI() / 180
/ 2), 2) + COS(37.772476604436974 * PI() / 180) * COS(addresses.lat *
PI() / 180) * POWER(SIN((-122.42336332798004 - addresses.lng) * PI() /
180 / 2), 2) )) <= 20 ORDER BY 3958.755864232 * 2 *
ASIN(SQRT(POWER(SIN((37.772476604436974 - addresses.lat) * PI() / 180
/ 2), 2) + COS(37.772476604436974 * PI() / 180) * COS(addresses.lat *
PI() / 180) * POWER(SIN((-122.42336332798004 - addresses.lng) * PI() /
180 / 2), 2) )) ASC) AS t1 WHERE deals.user_id = 26 GROUP BY
id,created_at,updated_at,user_id,company_id ORDER BY distance ASC
LIMIT 1
Is what I'm trying to do even possible with ARel? The additional scopes above feel really dirty to me (parsing the subquery to raw SQL? I thought ARel was supposed to make it so I never did that!)
Related question: Can ARel formulate cross-db queries for CTEs (Common Table Expressions)?