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How do I POST JSON data with cURL?
(31 answers)
Closed 6 years ago.
I'm not sure if this is possible, but i am trying to curl a post, but with a json as the parameters, like such:
curl -X POST 'https://myserver/action?params={"field1":"something","whatever":10,"description":"body","id":"random","__oh__":{"session":"12345678jhgfdrtyui"}}'
however, i keep getting some error curl: (3) [globbing] nested braces not supported at pos X
how do i do this?
The curl error is due to braces {} and square brackets [] being special curl globbing characters. Use the -g option to turn off globbing and you should be fine.
Same issue as this post:
How to PUT a json object with an array using curl
There two ways to approach this.
Ensure that your JSON is properly escaped so that it can be sent as a parameter.
Set the HTTP header to accept json.
For example:
curl -X POST -H "Content-Type: application/json" \
--data '{"field1":"something","whatever":10,"description":"body","id":"random","__oh__":{"session":"12345678jhgfdrtyui"}}' \
https://example.com/action
Related
Hi I need to send JSON format through the CURL command but I am getting an error.
curl --request POST "https://app.io/api/graphql?accountId=Xzg" --header "x-api-key: WHpnV=" --header "Content-Type: application/json" --data-raw "{applications(limit: 2) {nodes {name}}}"
So the problematic part is data-raw, although I have checked it online it's Valid JSON.
--data-raw "{applications(limit: 2) {nodes {name}}}"
Response:
{"metaData":null,"resource":null,"responseMessages":[{"code":"DEFAULT_ERROR_CODE","level":"ERROR",
"message":"Unable to process JSON Unexpected character ('a' (code 97)):
was expecting double-quote to start field name","exception":null,"failureTypes":[]}]}
I tried different ways how I could change this request data but without success.
Can someone please assist me how I should change this query which was definitely generated as the proper one from some app.
Thanks!
Solution:
--data-raw '{"query": "{applications(limit: 2) {nodes {name}}}" }'
Using GET I need to pass a json value to a URL via the command line within a bash script.
This works:
curl -i "http://MYURL:8080/admin/rest_api/api?api=trigger_dag&dag_id=spark_submit&conf=\{\"filename\":\"myfile.csv\"\}"
If I want to expand on the json value, I would prefer to pass a variable via the URL parameter for readability. Somethig like ... but this doesn't appear to work correctly.
generate_post_data =
{
"filename": "myfile.csv"
}
curl -i "http://MYURL:8080/admin/rest_api/api?api=trigger_dag&dag_id=spark_submit&conf=${generate_post_data}"
You need to properly set the variable and you should url encode it using the --data-urlencode option.
#!/bin/bash
generate_post_data="filename=myfile.csv"
curl -G "http://MYURL:8080/admin/rest_api/api?api=trigger_dag&dag_id=spark_submit" --data-urlencode $generate_post_data
From the manpage:
--data-urlencode <data>
(HTTP) This posts data, similar to the other -d, --data options with
the exception that this performs URL-encoding.
To be CGI-compliant, the part should begin with a name followed
by a separator and a content specification. The part can be
passed to curl using one of the following syntaxes:
For more info you can use man curl and then /data-urlencode to jump to the section on it.
I'm trying to POST data from a bash variable using curl, however, I'm unable to get this to work. This is the command that I'm using:
escape() { printf "%q" "$1"; }
curl -d "$(escape "$client")" -X POST -v https://$server/clients
The client variable look like this:
{"roles":["test"],"softwareName":"Some Soft","passwordSalt":"aaa","clientID":"full-client-2","contactPerson":"Test","contactPersonEmail":"a#b.org","description":"test","name":"Full Client-2","organization":"Some Org","passwordAlgorithm":"sha512","passwordHash":"bbb"}
And on the server I'm receiving the following:
{ '{"roles":': { '"test"': { '\"test\"\': '' } } }
I think its a problem with the escaping but I can't figure this out.
I've had a look at a number of other questions about this on here, but it seems most people need to insert variable into a literal that they are then trying to post. My problem is around using an entire variable as the json body. I've tried to use their answers to help me out but I haven't had any luck so far.
Don't try to quote it; use a here document:
curl -d#- -X POST -v https://"$server"/clients <<JSON
{"roles":["test"],"softwareName":"Some Soft","passwordSalt":"aaa","clientID":"full-client-2","contactPerson":"Test","contactPersonEmail":"a#b.org","description":"test","name":"Full Client-2","organization":"Some Org","passwordAlgorithm":"sha512","passwordHash":"bob"}
JSON
#- tells the -d option to look in standard input for the data, rather than using a hard-coded string.
If the text is in a variable, nothing more needs to be done; just quote the variable to prevent the shell from processing it:
curl -d "$client" -X POST -v https://"$server"/clients
I'm trying to create a script that will use the Github API to post a comment containing the output of a command. This output has multiple lines.
Here's what I'm trying to do:
curl -H "Authorization: token oauthtoken" \
-H "Content-Type: application/json" \
-X POST -d#- \
https://api.github.com/repos/company/repo/issues/14/comments <<EOF
{
"body":"$OUTPUT"
}
EOF
How can I output the variable in such a way that it respects the multiple lines contained within? Now when I run that command, all of the newlines get squished on to one line.
I don't think that the basic cause of the problem are the newlines, the issues is that the value of $text is not properly formatted json.
Follow this simple example:
test="
Hello
World
"
curl -X POST -d '{"body": "'"$test"'"}' http://server.com/...
to see new lines working.
To make it possible to send the result of arbitrary commands using json, you need to json-encode the text before.
I know I can use
curl --data "param1=value1¶m2=value2" http://hostname/resource
or
curl --request POST https://$url?param1=value1¶m2=value2
But what do I need to do if param1 is value and param2 is a JSON?
It just does not work(tm) if I just toss the JSON in there, even using a variable
$json='{"data":"value"}'
curl --request POST https://$url?param1=value1¶m2=$json
What is the trick here?
Note that I HAVE TO make only one call.
Thank you!
Ok, if we escape everything (using python) here's what it looks like
>>> x
'{"data": "value"}'
>>> urllib.urlencode({'param1':'value1', 'param2':x})
'param2=%7B%22data%22%3A+%22value%22%7D¶m1=value1'
Or, using the curl option
curl localhost:8080 --data-urlencode 'param1={"data":"value"}'
Will send to the server
param1=%7B%22data%22%3A%22value%22%7D
You may notice that the first version has a +, which probably comes from the space in the json encoded, not sure it works or if it can be removed