I am trying to do two WHERE clauses after each other and its not displaying what I want.
SELECT FROM users LEFT JOIN table2 on users.user = table2.total AND $table2.date = CURDATE() WHERE users.value = '$value' WHERE users.user = 'marketing' OR users.user = 'sales'";
I want to display all users that match what is stored in $value, along with this I also want all users that have a user value of 'marketing' OR 'sales'. Currently it is displaying all users, even ones that don't have the correct value in $variable. It looks like it is grouping my two WHERE clauses together but I want them to be separate. Any thoughts?
There were a few problems in your query I fixed. You can't use two where clauses. In this specific case, use in to select all rows where one field can be one of a specific list:
SELECT *
FROM users
LEFT
JOIN table2
on users.user = table2.total
AND table2.date = CURDATE()
WHERE users.value = '$value'
AND users.user in ( 'marketing', 'sales' )
You can add more conditions concatenating them by the 'AND' keyword. Like this:
SELECT *
FROM
users
LEFT JOIN table2 on
users.user = table2.total AND
table2.date = CURDATE()
WHERE
users.value = '$value' AND
(users.user = 'marketing' OR users.user = 'sales')
But I think this could be a bit easier to read and maybe meeting better your requirements:
SELECT *
FROM
users
LEFT JOIN table2 on
users.user = table2.total
WHERE
users.value = '$value' AND
users.user in ('marketing', 'sales') AND
table2.date = CURDATE()
Related
I want to use a query similar to the following to retrieve all rows in events that have at least one corresponding event_attendances row for 'male' and 'female'. The below query returns no rows (where there certainly are some events that have event_attendances from both genders).
Is there a way to do this without a subquery (due to the way the SQL is being generated in my application, a subquery would be considerably more difficult for me to implement)?
SELECT * FROM events e
LEFT JOIN event_attendances ea ON (e.id = ea.event_id)
GROUP BY e.id
HAVING ea.gender = 'female' AND ea.gender = 'male'
Use
HAVING sum(ea.gender = 'female') > 0
AND sum(ea.gender = 'male') > 0
or
HAVING count(distinct ea.gender) = 2
BTW you should use a subquery to get all data when you group.
SELECT *
FROM events
where id in
(
SELECT events.id
FROM events
LEFT JOIN event_attendances ON (events.id = event_attendances.event_id)
GROUP BY events.id
HAVING count(distinct event_attendances.gender) = 2
)
HAVING generally used with aggregate functions.
You should do self-jointo get the desired results, since ea.gender = 'female' AND ea.gender = 'male' is contradictory,which always returns empty set.
You can try this
SELECT T1.*
FROM events T1
INNER JOIN
(SELECT events.id
FROM events
LEFT JOIN event_attendances ON (events.id = event_attendances.event_id)
GROUP BY events.id
HAVING COUNT(DISTINCT event_attendances.gender) = 2) T2 ON T1.events.id=T1.events.id
Hope this helps.
I am working with Expression Engine and the query module which allows you to use MySQL to get results. I have a set of data which I'm trying to associate with a user. My query is currently as follows:
SELECT COUNT(*)
FROM exp_channel_grid_field_11
INNER JOIN exp_member_data
WHERE `col_id_12` = 'Race' && `member_id` = '1'
So, I'm not too clued up when it comes to joins, but I am just looking for the count. Thanks.
Not sure what you're after - you don't necessarily need an 'ON' to do a JOIN but perhaps you do need to define the tables. I don't know which columns belong to which tables (and neither does mysql, perhaps that's the problem)
Assuming that 'member_id' is in exp_member_data and 'col_id_12' is in exp_channel_grid_field_11, you probably need to do something like this:
SELECT COUNT(*)
FROM exp_channel_grid_field_11
INNER JOIN exp_member_data
WHERE `exp_channel_grid_field_11.col_id_12` = 'Race'
&& `exp_member_data.member_id` = '1'
and you can "pretty it up" with "table aliases" such as like this:
SELECT COUNT(*)
FROM exp_channel_grid_field_11 e11
INNER JOIN exp_member_data ed
WHERE `e11.col_id_12` = 'Race'
AND `ed.member_id` = '1'
Or, maybe there should be an 'ON' member_id?
SELECT COUNT(*)
FROM exp_channel_grid_field_11 e11
INNER JOIN exp_member_data ed
ON e11.member_id = ed.member_id
WHERE `e11.col_id_12` = 'Race'
AND `ed.member_id` = '1'
In stead of WHERE col_id_12 = 'Race', use: on col_id_12 = 'Race'
SELECT COUNT(*)
FROM exp_channel_grid_field_11
INNER JOIN exp_member_data ON `col_id_12` = 'Race'
WHERE `member_id` = '1'
I'm having a bit of a problem with the following MySQL query and I can't find the source of it.
MySQL tells me that
SQLSTATE[42S21]: Column already exists: 1060 Duplicate column name
'annonce_dispo_id'
SELECT MAX(max_price) AS `max_price`,
COUNT(*) AS `nb_annonces`,
SUM(nb_dispo) AS `nb_dispo`
FROM
(SELECT `annonce`.`id`,
CEIL(MAX(price)*1.16) AS `max_price`,
COUNT(DISTINCT annonce.id) AS `nb_annonces`,
COUNT(annonce_dispoo.annonce_dispo_id) AS `nb_dispo`,
`annonce_dispo1`.*,
`annonce_dispo2`.*
FROM `annonce`
LEFT JOIN `annonce_dispo` AS `annonce_dispoo` ON (annonce_dispoo.annonceId = annonce.id
AND STR_TO_DATE(annonce_dispoo.dispo_date, '%d/%m/%Y') >= CURDATE())
INNER JOIN `annonce_dispo` AS `annonce_dispo1` ON annonce.id = annonce_dispo1.annonceId
INNER JOIN `annonce_dispo` AS `annonce_dispo2` ON annonce.id = annonce_dispo2.annonceId
WHERE ((annonce.city IN
(SELECT `cities`.`id`
FROM `cities`
WHERE (cities.label LIKE 'lyon%'))
OR annonce.zipcode = 'lyon')
OR (annonce.city LIKE '28674'
OR annonce.zipcode = '28674'))
AND (annonce_dispo1.dispo_date = '27/05/2014')
AND (annonce_dispo1.disponibility = 'available')
AND (annonce_dispo2.dispo_date = '31/05/2014')
AND (annonce_dispo2.disponibility = 'available')
AND (annonce.visible = 1)
AND (annonce.completed = 1)
GROUP BY `annonce`.`id` HAVING (nb_dispo >= 1)) AS `t`
I thought gave a different alias for the table in each JOIN I use them in, and can't really put my finger on what else is possible to output such an error.
Don't select annonce_dispo1.* and annonce_dispo2.* in your subquery, duplicated column names are being returned. Instead select the fields you need and alias accordingly.
SELECT MAX(max_price) AS `max_price`,
COUNT(*) AS `nb_annonces`,
SUM(nb_dispo) AS `nb_dispo`
FROM
(SELECT `annonce`.`id`,
CEIL(MAX(price)*1.16) AS `max_price`,
COUNT(DISTINCT annonce.id) AS `nb_annonces`,
COUNT(annonce_dispoo.annonce_dispo_id) AS `nb_dispo`,
`annonce_dispo1`.field, `annonce_dispo1`.otherfield,
`annonce_dispo1`.field as field2, `annonce_dispo1`.otherfield as otherfield2
FROM `annonce`
LEFT JOIN `annonce_dispo` AS `annonce_dispoo` ON (annonce_dispoo.annonceId = annonce.id
AND STR_TO_DATE(annonce_dispoo.dispo_date, '%d/%m/%Y') >= CURDATE())
INNER JOIN `annonce_dispo` AS `annonce_dispo1` ON annonce.id = annonce_dispo1.annonceId
INNER JOIN `annonce_dispo` AS `annonce_dispo2` ON annonce.id = annonce_dispo2.annonceId
WHERE ((annonce.city IN
(SELECT `cities`.`id`
FROM `cities`
WHERE (cities.label LIKE 'lyon%'))
OR annonce.zipcode = 'lyon')
OR (annonce.city LIKE '28674'
OR annonce.zipcode = '28674'))
AND (annonce_dispo1.dispo_date = '27/05/2014')
AND (annonce_dispo1.disponibility = 'available')
AND (annonce_dispo2.dispo_date = '31/05/2014')
AND (annonce_dispo2.disponibility = 'available')
AND (annonce.visible = 1)
AND (annonce.completed = 1)
GROUP BY `annonce`.`id` HAVING (nb_dispo >= 1)) AS `t`
See here for an example that doesn't work:
http://sqlfiddle.com/#!2/9bb13/1
The problem is that you are selecting all columns in the tables annonce_dispo1 and annonce_dispo2.
The fact that you have attributed different table names doesn't mean that there aren't duplicate column names.
I mean, you should use [Table name].[column name]
Example:
(SELECT `annonce`.`id`,
CEIL(MAX(price)*1.16) AS `max_price`,
COUNT(DISTINCT annonce.id) AS `nb_annonces`,
COUNT(annonce_dispoo.annonce_dispo_id) AS `nb_dispo`,
`annonce_dispo1`.annonce_dispo_id AS `column1`,
`annonce_dispo2`.annonce_dispo_id AS `column2`
I hope I've helped
i have problem with join table and use multiple conditions...
My code:
SELECT * FROM
(SELECT sid, MAX(info_date_add) AS max_info_date_add FROM skiresort GROUP BY sid) skiresort_max
INNER JOIN skiresort
ON
skiresort_max.sid = skiresort.sid AND
skiresort_max.max_info_date_add = skiresort.info_date_add
JOIN skiresort_theme_value
ON skiresort_theme_value.skiresort_id = skiresort.id
WHERE
skiresort_theme_value.skiresort_theme_id = '1' AND
skiresort_theme_value.skiresort_theme_id = '2' AND
skiresort_theme_value.skiresort_theme_id = '4'
GROUP BY skiresort.sid
ORDER BY skiresort.title_en
In this code, the conditions are in WHERE clausule. I also tried to put in into JOIN ON (...) but it also didn't work.
When i have only one condition it works. I read some articles about using OR instead of AND, it worked but not as i expected. I need to search only rows with certain IDs (multiple).
why not use this instead of many conditions.
WHERE
skiresort_theme_value.skiresort_theme_id in (1, 2,4)
GROUP BY skiresort.sid
HAVING COUNT(DISTINCT skiresort_theme_value.skiresort_theme_id) = 3
ORDER BY skiresort.title_en
when add condition to WHERE, condition must be from FROM tbl
add condition JOIN ON
Try this:
SELECT * FROM
(SELECT sid, MAX(info_date_add) AS max_info_date_add FROM skiresort GROUP BY sid) skiresort_max
INNER JOIN skiresort
ON
skiresort_max.sid = skiresort.sid AND
skiresort_max.max_info_date_add = skiresort.info_date_add
JOIN skiresort_theme_value
ON (skiresort_theme_value.skiresort_id = skiresort.id AND skiresort_theme_value.skiresort_theme_id = '1' AND skiresort_theme_value.skiresort_theme_id = '2' AND skiresort_theme_value.skiresort_theme_id = '4')
GROUP BY skiresort.sid
ORDER BY skiresort.title_en
I have two tables that I believe I want to JOIN. I'm very new to this and am not completely sure…
The first table is called venues with the variables id, slug, name, etc. The second table is venue_terms with the variables id, option, venue, value. The matching variables are obviously venues.id and venue_terms.venue.
What I want to do is query venue_terms for matching values and then SELECT * FROM venues that match.
I've been working with the following query, but haven't been able to get it to work. I know INTERSECT isn't the solution, but I'm nut sure which JOIN I should use.
SELECT venue
FROM venue_terms
WHERE `option` = '1' AND `value` = '10'
INTERSECT
SELECT venue
FROM venue_terms
WHERE `option` = '2' AND `value` = '4';
I want to match those venue_terms.venue to the venues table. Can someone point me in the right direction?
UPDATE: To clarify, I'm trying to search multiple option/value combinations that ultimately have the same venue.id's. Basically, I want to able to find all of the venues where (option = 1 and value = 4) AND (option = 2 and value = 10) AND etc… where all of these are true.
You want to find venues that match conditions in two rows in table venue_terms. This can be accomplished by various methods. The most usual is by joining that table twice (another would be by a grouping query).
Here's the first way. Join twice to the venue_terms table:
SELECT v.id --- whatever columns you need
, v.slug --- from the venues table
, v.name
FROM venues AS v
INNER JOIN venue_terms AS vt1
ON vt1.venue = v.id
INNER JOIN venue_terms AS vt2
ON vt2.venue = v.id
WHERE ( vt1.option = 1 AND vt1.value = 10 )
AND ( vt2.option = 2 AND vt2.value = 4 ) ;
If you have 3 conditions, join thrice. If you have 10 conditions, join 10 times. It would be good for the efficiency of the query to have a compound index on (option, value, venue) in the terms table.
try this
SELECT venue.*, venue_terms.*
FROM venue
INNER JOIN venue_terms ON venue.id = venue_terms.venue
WHERE venue_terms.option IN ( 1 ,2)
AND venue_terms.value IN (10,4)
GROUP BY venue.id
How about this?
SELECT t1.*, t2.*
FROM venue t1 JOIN venue_terms t2
ON t1.id = t2.venue
WHERE (t2.option = 1 AND t2.value = 10)
NOTE: I believe option and value are of type INT.
If they are of type varchar then change above query to
SELECT t1.*, t2.*
FROM venue t1 JOIN venue_terms t2
ON t1.id = t2.venue
WHERE (t2.option = '1' AND t2.value = '10')
Update 1
As per your new requirement, you will just need to add that condition with OR option as shown below.
SELECT t1.*, t2.*
FROM venue t1 JOIN venue_terms t2
ON t1.id = t2.venue
WHERE
(t2.option = 1 AND t2.value = 10)
OR
(t2.option = 3 AND t2.value = 14)
This will join the two tables and print out the venues which matches the attributes (option, value) in venue_terms:
SELECT v.* FROM venue v, venue_terms vt
WHERE v.id = vt.venue
AND vt.option = 1
AND vt.value = 10