MySQL results by date - mysql

Question

Maybe there is a simple fix but I can't seam to figure it out. I'll try my best to explain my situation.
I'm working on a MySQL query that will return results within date range (in column A), and for date range - 1 year (in column B). I need to group results by month day and not by year. So I would like to have something like this:
2014 2013
----------------
01-01 6 8
01-03 7 0
01-04 4 1
01-08 0 13
01-21 11 7
In my current query (below) I get results like this (because of ELSE in CASE):
2014 2013
----------------
01-01 0 8
01-03 7 0
01-04 0 1
01-08 0 13
01-21 0 7
QUERY:
SELECT
DATE_FORMAT(table.date, '%e.%c.') AS date,
(CASE WHEN DATE(table.date) BETWEEN '2014-01-01' AND '2014-02-01' THEN ROUND(SUM(table.field), 2) ELSE 0 END) AS field_2014,
(CASE WHEN DATE(table.date) BETWEEN '2013-01-01' AND '2013-02-01' THEN ROUND(SUM(table.field), 2) ELSE 0 END) AS field_2013
FROM table
WHERE
(DATE(table.date) BETWEEN '2014-05-01' AND '2014-06-01' OR DATE(table.date) BETWEEN '2013-05-01' AND '2013-06-01')
GROUP BY
DATE_FORMAT(table.date, '%c.%e.')
What should I put in ELSE and how can I achieve this functionality?
Thank you for your time

Answer 1

You need aggregation functions. I would recommend:
SELECT DATE_FORMAT(t.date, '%e.%c.') AS date,
SUM(CASE WHEN year(t.date) = 2014 THEN ROUND(SUM(t.field), 2) ELSE 0 END) AS field_2014,
SUM(CASE WHEN year(t.date) = 2013 THEN ROUND(SUM(t.field), 2) ELSE 0 END) AS field_2013
FROM table t
WHERE year(t.date) in (2013, 2014) and month(t.date) = 5
GROUP BY DATE_FORMAT(t.date, '%c.%e.');
I would also recommend using the format '%m-%d'. Having the month then the year means that order by will work on the column. Having all the dates be the same width ("05/01" rather than "5/1") better corresponds to your desired output.