Select query with left outer join and sum with group by - mysql

Question

I have 3 tables for example
Parent Table :TEST_SUMMARY
Child Tables : TEST_DETAIL, TEST_DETAIL2
I have data show in image, and want output result shown in image,
I tried below 2 query, but not giving expected output
SELECT s.NAME, sum(s.AMT), sum(d.d_amt), sum(d2.d2_amt)
FROM TEST_SUMMARY s LEFT OUTER JOIN TEST_DETAIL d
ON s.ID = d.SUMMARY_ID
LEFT OUTER JOIN TEST_DETAIL2 d2
ON s.ID =d2.SUMMARY_ID
GROUP BY s.NAME
ORDER BY s.NAME;
select rs1.*,rs2.total1,rs3.total2
FROM
(select id, name,amt from TEST_SUMMARY a) RS1,
(select SUMMARY_ID, sum(d_amt) over(partition by summary_id ) total1 from TEST_DETAIL a) RS2,
(select SUMMARY_ID, sum(d2_amt) over(partition by summary_id ) total2 from TEST_DETAIL2 a) RS3
where rs1.id(+)= RS2.SUMMARY_ID
and rs1.id(+)= RS3.SUMMARY_ID;
Create table and insert data test Queries
CREATE TABLE TEST_SUMMARY(ID NUMBER, NAME VARCHAR2(20 BYTE),AMT NUMBER(10,2));
CREATE TABLE TEST_DETAIL (ID NUMBER, SUMMARY_ID NUMBER, NAME VARCHAR(20), D_AMT NUMBER(10,2));
CREATE TABLE TEST_DETAIL2 (ID NUMBER, SUMMARY_ID NUMBER, NAME VARCHAR(20), D2_AMT NUMBER(10,2));
INSERT INTO TEST_SUMMARY VALUES (1, 'NAME1', 100);
INSERT INTO TEST_SUMMARY VALUES (4, 'NAME1', 150);
INSERT INTO TEST_SUMMARY VALUES (6, 'NAME1', 50);
INSERT INTO TEST_SUMMARY VALUES (2, 'NAME2', 200);
INSERT INTO TEST_SUMMARY VALUES (3, 'NAME3', 300);
INSERT INTO TEST_DETAIL VALUES (1, 1, 'NAME11', 11);
INSERT INTO TEST_DETAIL VALUES (2, 1, 'NAME12', 12);
INSERT INTO TEST_DETAIL2 VALUES (1, 1, 'NAME_2_11', 1);
INSERT INTO TEST_DETAIL2 VALUES (2, 1, 'NAME_2_12', 1);

Answer 1

One way to solve it for both MySQL and Oracle is to use subqueries to help solve the duplication for you by aggregating the sums from the details tables by name, so you can summarise with a normal join;
SELECT ts.name, SUM(ts.amt) amt1, MAX(td1.amt) amt2, MAX(td2.amt) amt3
FROM TEST_SUMMARY ts
LEFT JOIN (
SELECT ts.name, SUM(td.d_amt) amt
FROM TEST_DETAIL td JOIN TEST_SUMMARY ts ON td.summary_id = ts.id
GROUP BY ts.name) td1 ON ts.name = td1.name
LEFT JOIN (
SELECT ts.name, SUM(td.d2_amt) amt
FROM TEST_DETAIL2 td JOIN TEST_SUMMARY ts ON td.summary_id = ts.id
GROUP BY ts.name) td2 ON ts.name = td2.name
GROUP BY ts.name
ORDER BY ts.name
A MySQL SQLfiddle and an Oracle SQLfiddle to test with.

Answer 2

You could try this:
SELECT
TEST_SUMMARY.NAME,
TEST_SUMMARY.AMT AS AMT1,
(
SELECT
SUM(TEST_DETAIL.D_AMT)
FROM
TEST_DETAIL
WHERE
TEST_DETAIL.SUMMARY_ID=TEST_SUMMARY.ID
) AS AMT2,
(
SELECT
SUM(TEST_DETAIL2.D2_AMT)
FROM
TEST_DETAIL2
WHERE
TEST_DETAIL2.SUMMARY_ID=TEST_SUMMARY.ID
) AS AMT3
FROM
TEST_SUMMARY
Update
You could basically do this if you have many name that are the same. But the question comes what you should do with the other fields (AMT1,AMT2)? Should you sum them for the same name or maybe a max is enough. Depends on what your requirement are :
SELECT
TEST_SUMMARY.NAME,
SUM(TEST_SUMMARY.AMT) AS AMT,
SUM(tblAMT2.AMT2) AS AMT2,
SUM(tblAMT3.AMT3) AS AMT3
FROM
TEST_SUMMARY
LEFT JOIN
(
SELECT
SUM(TEST_DETAIL.D_AMT) AS AMT2,
TEST_DETAIL.SUMMARY_ID
FROM
TEST_DETAIL
GROUP BY
TEST_DETAIL.SUMMARY_ID
) AS tblAMT2
ON TEST_SUMMARY.ID=tblAMT2.SUMMARY_ID
LEFT JOIN
(
SELECT
SUM(TEST_DETAIL2.D2_AMT) AS AMT3,
TEST_DETAIL2.SUMMARY_ID
FROM
TEST_DETAIL2
GROUP BY
TEST_DETAIL2.SUMMARY_ID
) AS tblAMT3
ON TEST_SUMMARY.ID=tblAMT3.SUMMARY_ID
GROUP BY
TEST_SUMMARY.NAME

Answer 3

Try this:
SELECT TS.NAME, TS.AMT AS AMT1, SUM(TD.D_AMT) AS AMT2, SUM(TD2.D2_AMT) AS AMT3
FROM TEST_SUMMARY TS LEFT OUTER JOIN TEST_DETAIL TD ON TS.ID = TD.SUMMARY_ID
LEFT OUTER JOIN TEST_DETAIL2 TD2 ON TS.ID = TD2.SUMMARY_ID
GROUP BY TS.NAME, TS.AMT
ORDER BY TS.NAME, TS.AMT