Google visualization API's include 'Formatters' which allow you to use things like colored text and arrows representing qualities of data. More information on formatters can be found here.
Now, when I edit the CSS values of the table, or use configurtion options (found here), tables that use fomatters seem to have trouble displaying certain CSS properties i.e, width of cells and text size. An example I've noticed where this is the case when the entire tables text is a smaller than default font, and a row is selected. That row which was selected will revert back to a 10pt Arial font when deselected.
Although this specific instance is annoying, I am curious about ALL formatter css properties and their class names. There is no information, to my knowledge, on the Google developer site.
These are my class names:
'headerRow': 'header-cells',
'tableRow': '.even-background all-cells',
'oddTableRow': 'odd-background all-cells',
'selectedTableRow': 'all-cells',
'hoverevenTableRow': '',
'hoveroddrTableRow': '',
'headerCell': 'header-cells white bold darkgreen-background',
'tableCell': 'all-cells'
};
These are the formatters being used.
var changecolor = new google.visualization.ColorFormat();
changecolor.addRange(null, 0, 'red', 'none');
changecolor.addRange(0.000001, null, 'green', 'none');
changecolor.format(dt, 1); // Apply formatter to second column
var parens = new google.visualization.NumberFormat({
prefix: "$",
negativeParens: true
});
parens.format(dt, 1); // Apply formatter to second column
var arrow = new google.visualization.ArrowFormat();
arrow.format(dt, 1); // Apply formatter to second column
var FormatAll = new google.visualization.NumberFormat({
prefix: "$",
pattern: '#.00##'
});
Style properties:
<style>
.all-cells {
border: 0px;
border-collapse: collapse;
font-size: 9px;
padding-right: 0;
}
.header-cells {
border: 0px;
border-collapse: collapse;
font-size: 9px;
padding-right: 0;
color: white;
font-weight: bold;
}
.darkgreen-background {
background-color: #0B3B0B;
}
.odd-background {
background-color: #E6F8E0;
}
.even-background {
background-color: #FFF5E3;
}
.bold {
font-weight: bold
}
.White {
fontcolor: white;
}
</style>
JS fiddle script in action
If you notice, when a cell is selected, the font size changes. This only happens when the google.visualization.ArrowFormat is applied.
I'd like to get rid of the boarder of the table, but that is not affected by classname or class properties (refer to the fiddle),
There is also a conflict with the parens.format and google.visualization.NumberFormat. Decimals places do not display with parentheses.
Not directly shown in code or fiddle: cell width properties become offset with cells that have formatters applied to them.
There are a couple things going on here. First, the ArrowFormat overrides all other classes placed on a cell, so those cells do not have the all-cells class. This is fine, as long as the <tr> has the all-cells class. The <tr>'s lose the all-cells class when you deselect them, because all-cells is part of both the even/odd row and selected row classes (and deselecting a row removes whatever classes you put on it.
If the reason you put all-cells as the selected row class is because you don't want the style from the default class, I suggest changing the class to something that has no styles associated with it, like this:
'selectedTableRow': 'noStyle'
Also, on a side note, you have a typo in the even row classes: there should not be a . before even-background:
'tableRow': 'even-background all-cells'
see it working here: http://jsfiddle.net/asgallant/1q8yk4f5/3/
Related
By default Ag-grid sets a fixed column menu width. Their documentation has an example of setting the column menu width to a different fixed value. The issue with this approach is that every column will have the same menu width.
Is there a way to dynamically set the column menu width based upon the column's filter list values? The following has no effect:
.ag-set-filter-list {
width: auto;
}
Similarly word wrapping could also solve this issue, but is also not working:
.ag-set-filter-list {
overflow-wrap: break-word;
}
I also tried using the postPopup callback to adjust styling after rendering, with no luck:
created() {
this.postProcessPopup = (params) => {
if (params.type !== 'columnMenu') {
return;
}
params.ePopup.style.overflowWrap = "break-word";
params.ePopup.style.width = "auto";
}
}
Digging into Ag-grid's filter list styling more, I realized that the filter items are absolutely positioned and use top values for placement. This made it difficult to wrap filter values without having them collide with each other.
I contacted Ag-grid support and they confirmed that dynamic filter list widths are not supported. They did mention their tooltips feature though, which works for my use case.
I modified that example in two ways:
Only show tooltips for filter list values that are longer and will be cut off by the edge of the filter menu.
Only show tooltips for values in the filter list, not for rows in the grid.
Here's my version of a custom tooltip with the above modifications:
export class GridColumnFilterTooltip {
init(params) {
const FILTER_VALUE_CHARACTER_LIMIT = 28;
this.tooltip = document.createElement("div");
if (
params.location === "setFilterValue" &&
params.value.length > FILTER_VALUE_CHARACTER_LIMIT
) {
this.tooltip.classList.add("grid-column-filter-tooltip");
this.tooltip.innerHTML = params.value;
}
}
getGui() {
return this.tooltip;
}
}
We are doing POC in which we ask client to add just the script tag in there website. The script tag refers to the javascript file in our website. When our script tag gets executed we inject the HTML code in the Parent website using the location of script tag.
The HTML code we injected, contains css classes which do not have any definition in our site and hence it gets the inherited css of basic HTML tags from the parent site.
The problem is how to check if parent site has classes implemented in there stylesheet file so that if there are no classes defined in parent site then we can add default definitions for our classes.
Example:
Let's say our injected HTML code snippet contains the following div.
<p>Property Details</p>
Lets say parent site has css definition for tag like below
p
{
font-size: 16px;
font-weight: bold;
}
And lets say we refered our own css file path, which also has the definition for like below
p
{
background-color: yellow;
}
(Note: stylesheet reference of parent site will always be above the stylesheet reference of our HTML code snippet.)
In above case style of should be with font size 16px and font weight bold, which is defined in parent site css file.
But in case, parent site css file does not have a definition for then style of should be background yellow, which is defined in our HTML code snippet.
You can try something like this (as suggested by Cray in the comments)
function isDefined(selector) {
for (var i = 0; i < document.styleSheets.length; i++) {
var sheet = document.styleSheets[i];
for (var j = 0; j < sheet.cssRules.length; j++) {
return sheet.cssRules[j].selectorText == selector;
}
}
}
var styleElement = document.createElement("style");
styleElement.type = 'text/css';
document.head.appendChild(styleElement);
var myStylesheet = document.styleSheets[document.styleSheets.length - 1];
if (!isDefined("p")) {
myStylesheet.insertRule("p { background-color: yellow; }")
}
if (!isDefined("h1")) {
myStylesheet.insertRule("h1 { background-color: yellow; }")
}
p {
font-size: 12px;
}
<h1>hello</h1>
<p>world</p>
This is a simple example, but you'll need to expand it if you want to deal with cases in which the client defines a p.class-name or div p selector.
Note that since these selectors have higher precedence, the client could override your changes as a workaround.
I have a boolean array that I am displaying in a razor foreach loop. Within the loop I am displaying the different values within the array. Is it possible,if so how, to change the css based on the value it is displaying?
For example
if (#status == true) THEN color = green; if (#status == false) THEN color = red.
If I understand your question correctly, you could add a data-attribute to the HTML element and alter the value (for example with Javascript) to/from "true/false" and use that in your CSS like so:
<element data-status="true">Content</element>
<element data-status="false">Content</element>
[data-status="true"] {
color: green;
}
[data-status="false"] {
color: red;
}
$('.test').each(function() {
if(parseInt($(this).css('font-size')) > 16) {
$(this).css('color', 'green');
}
});
.test {
font-size: 18px;
color: red;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<p class="test">Javascript manipulation: Green when largen than 16px</p>
I came across this question having the same problem, however I have implemented another solution, using c#/razor/css and no javascript. Someone might like this better.
First: define the possible values as an enumeration:
public class enum MyRateTyp{
Level1,
Level2,
Level3
}
Second:
Find a place where, given the number on which the style will be based, the conversion will take place. In my case I added an extension method to the int type.
public MyRate Evaluate(this int i)
{
MyRate answer = MyRate.Level1;
if(i<50)
{
answer = MyRate.Level1;
}
.
//All if statements here
.
if (i>100)
{
answer = MyRate.Level3;
}
return answer;
}
Third: On your .css file, define the style for each possible value, like so:
.Level1{
/*Style here for level 1*/
}
.Level2{
/* Style here for level 2*/
}
/*
Other Styles here
*/
Finally On the Razor page, assign the extension method to the css class of the element you want to change the style based on the value.
For example.
The level is <p class="#(myInt_variable.Evaluate())"> #(myInt_Variable) </p>
It is possible to change the color by putting an event on the box. This is done in javascript "AddEventListener"
I have created a table in Eclipse with the help of Vaadin.
I managed to remove the borders of the table with following line:
tblResetButton.addStyleName(Reindeer.TABLE_BORDERLESS) ;
but this still leaves me with a vertical line like this:
Is there a way to hide all the cell borders? And an extra bonus, would it be possible to give the first cell (the one with "Gebruiker") the color #F4F4F4 and the second cell (the textbox) the color #E2E2E2
EDIT:
the formlayout would be good, but I can't seem to get the background colors working so I reverted to the tables. This is the code:
JAVA
tblReset.addContainerProperty("Gebruiker", String.class, null);
tblReset.setCellStyleGenerator(new Table.CellStyleGenerator() {
#Override
public String getStyle(Table source, Object itemId, Object propertyId) {
if("Gebruiker".equals(propertyId)){
return "style-name-with-black-background";
} else {
return "style-name-with-yellow-background" ;
}
}
});
CSS
.style-name-with-black-background {
background-color: black ;
}
.style-name-with-yellow-background {
background-color: yellow ;
}
Supposing the answer to cfrick's comment is no, looks like it depends on what theme you're using:
If it's valo (recommended for a few reasons and from the screenshot seems like you're already using it but not 100% sure) then there are 2 other styles, ValoTheme.TABLE_NO_VERTICAL_LINES & ValoTheme.TABLE_NO_HORIZONTAL_LINES.
In reindeer they seem to be missing so you'll probably have to manually define custom style(s) in your theme. See below a simple/naive attempt:
add the style to the table
table.setStyleName("no-vertical-lines-or-border");
while defining it in your theme
.v-table-no-vertical-lines-or-border .v-table-header-wrap /* remove header-table borders */,
.v-table-no-vertical-lines-or-border .v-table-body /* remove body-table borders */,
.v-table-no-vertical-lines-or-border .v-table-cell-content /* remove cell borders */ {
border: none;
}
As for the cells, you can use a style generator, again with your custom defined styles for each cell, something along the lines of:
table.setCellStyleGenerator(new Table.CellStyleGenerator() {
#Override
public String getStyle(Table source, Object itemId, Object propertyId) {
if("description".equals(propertyId)){
return "style-name-with-F4F4F4-background";
} else {
return "style-name-with-E2E2E2-background";
}
}
});
P.S.: Given that you're experimenting, and if you're working with Vaadin versions 7.2+, take a look at the support for font icons which may come in very handy at times, for example the embedded FontAwesome:
How can I overwrite an entire CSS style for a class, id or other CSS selector?
For example:
If in styles1.css I have:
/* also, this file contains a lot of styles used on other pages */
.one-great-class {
background: white
...
/* a lot of properties */
}
... and in styles2.css (that is used only in one web page) I want to overwrite the class one-great-class completely what have I do to write?
.one-great-class {
/* Is possible that a line of code to delete all styles from this class? */
}
It's not possible in CSS at the moment.
But there may eventually be a property that does this: all
It can take three values:
initial | inherited | unset
Taken from the Cascading and Inheritance Module:
"For example, if an author specifies all: initial on an element it will block all inheritance and reset all properties, as if no rules appeared in the author, user, or user-agent levels of the cascade. "
According to the MDN documentation as of June 2017, all is currently supported by Chrome, Firefox/Mobile, and Opera. Safari supports only the CSS4 value revert, which is not supported by the other browsers.
.one-great-class {
border-radius: 50% 35% / 20% 25% 60%;
color: red;
font: 12px/14px Arial, serif;
height: 20em;
width: 20em;
/*... etc. */
}
.one-great-class {
all: initial;
}
Tested to work with IE9, Chrome and Opera. I had a problem with this when I wrote it, so decided that rather than changing existing rules, that I'd just append a new rule after the existing ones. From memory, the problem was with the default browser found in Android 2.3
Altering an existing rule seemed to be a better(cleaner) solution, though appending new rules ultimately proved to be chosen path. (I was changing background images by creating images with a canvas and then setting the background-image property. The images could be quite large, hence the preference for update)
Function
function replaceRuleAttrib(ruleSelector, attribText, newValue)
{
var nSheets, nRules, sheetNum, curSheet, curStyle, curAttrib;
var nSheets = document.styleSheets.length;
if (nSheets == 0)
document.head.appendChild(document.createElement('style'));
else
for (sheetNum = 0; sheetNum<nSheets; sheetNum++)
{
curSheet = document.styleSheets[sheetNum];
nRules = curSheet.cssRules.length;
for (ruleNum=0; ruleNum<nRules; ruleNum++)
{
curRule = curSheet.cssRules[ruleNum];
if (curRule.selectorText == ruleSelector)
{
for (styleI=0; styleI<curRule.style.length; styleI++)
{
styleName = curRule.style[styleI];
styleVal = curRule.style[styleName];
if (styleName == attribText)
{
curRule.style[styleName] = newValue;
return true;
}
}
}
}
}
document.styleSheets[0].insertRule( ruleSelector+'{' + attribText + ": " + newValue + "; }", 0);
}
Sample CSS (before)
<style>
h1
{
color: red;
}
</style>
Usage:
function onHeadingClick()
{
replaceRuleAttrib('h1', 'color', 'green');
}
Sample CSS (after)
<style>
h1
{
color: green;
}
</style>
Browser will apply css that come last.
.class {
font-size: 16px;
font-size: 14px;
}
The class will get font-size value 14px.
You can decleare a css as final.
.class {
font-size: 14px !important;
}
no genarel css rule can alter it.
Browser uses this method to give priority
inline < embeded < external < user-agent.
If you think you need more controll on css then use javascript to directly modfy dom.