I'm trying to order a mysql query according to the month name but it is ordering in reverse order .I have tried both the ASC and DESC order but not working!This is what i'm getting :
order_amount month_number
370.245 Dec
0.01 Aug
0.02 July
0.01 May
2 Apr
3 Mar
4 Feb
5 Jan
This is the query:
select sum(amnt) as order_amount,month_number from orders where paid =1 GROUP BY month_number ORDER BY MONTH(month_number) ASC
This is a sample table 'order' on which i'm running query
order_amount month_number paid
370.245 Jan 1
0.01 Aug 1
0.02 July 1
0.01 Apr 1
2 May 0
3 Mar 1
4 Feb 0
5 Nov 0
month_number() is a lousy name for a string name for the month. That said, your attempts will not work, because month() takes a date, not a string representation. The best way is probably just to use case:
order by (case when month_number = 'Jan' then 1
when month_number = 'Feb' then 2
. . .
when month_number = 'Dec' then 12
end)
I would strongly suggest you include a date or actual month number in the table. And, rename month_number to something like month_name.
According to your sample, you've got 'Dec', 'Aug' and so on in your month_number field.
How is month(month_number) supposed to work if you don't pass a valid date type? if you pass some random text you'll just get NULL and can't order by NULL
http://sqlfiddle.com/#!2/3a774d/3/0
http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_month
SELECT * FROM my_table;
+-------+
| month |
+-------+
| Apr |
| Aug |
| Dec |
| Feb |
| Jan |
| Jul |
| Jun |
| Mar |
| May |
| Nov |
| Oct |
| Sep |
+-------+
SELECT * FROM my_table ORDER BY STR_TO_DATE(CONCAT('2014-',month,'-01'),'%Y-%b-%d');
+-------+
| month |
+-------+
| Jan |
| Feb |
| Mar |
| Apr |
| May |
| Jun |
| Jul |
| Aug |
| Sep |
| Oct |
| Nov |
| Dec |
+-------+
... or something like that
Related
I have a table like this
userID time NoOfVisits
1 2014 50
2 2015 60
3 2016 70
4 2017 80
5 2018 90
6 2019 100
I need to write a sql query which will print time and average of past 3 years NoOfVisits for a particular site.
output should be as
userID time NoOfVisits
1 2014 50.0000
2 2015 55.0000
3 2016 60.0000
4 2017 70.0000
5 2018 80.0000
6 2019 90.0000
Explanation :
For user Id 6 (80+90+100)/3=90.0000
Please help me to solve this problem.
You can use a cumulative average, available in MySQL 8+:
select t.*,
avg(visits) over (order by time rows between 2 preceding and current row) as avg_visits_3
from t;
Assuming there are no gaps between the years (like your sample data), you can self join the table and group by userid, time to get the average:
select
t.userid, t.time, avg(tt.noofvisits) NoOfVisits
from tablename t inner join tablename tt
on tt.time between t.time - 2 and t.time
group by t.userid, t.time
See the demo.
Results:
| userid | time | NoOfVisits |
| ------ | ---- | ---------- |
| 1 | 2014 | 50 |
| 2 | 2015 | 55 |
| 3 | 2016 | 60 |
| 4 | 2017 | 70 |
| 5 | 2018 | 80 |
| 6 | 2019 | 90 |
I have 3 tables as below :
1/ Table 'order_fruit'
-------------------------------------------------------------
id_fruit_table | fruit_name | order_quantity | delivery_date
---------------+------------+----------------+---------------
1 |mango | 10 | 04 2018
2 |mango | 5 | 05 2018
3 |banana | 20 | 04 2018
4 |pineapple | 9 | 06 2018
2/ Table 'stock_fruit'
---------------------------------------------------
id_stock | fruit_name_stock | stock_quantity
--------------+-------------------+----------------
1 | mango | 5
2 | pineapple | 10
3/ Table 'pipeline'
--------------------------------------------------------------------
id_pipeline | fruit_pipeline | receive_date | pipeline_quantity
--------------+------------------+--------------+-------------------
1 | mango | 04 2018 | 5
2. | banana | 05 2018 | 15
How can i make a query/ view/ report like below:
-----------------------------------------------------------------------------------
fruit | 04 2018 | 05 2018 | 06 2018
---------+---------------------------------------------------------------+---------
| order_qty-| stock-| pipeline | order_qty- | stock- | pipeline | ...
---------+-----------+-------+----------+------------+--------+----------+---------
mango | 10 | 5 | 5 | 5 | 0 | 0 | ...
banana | 20 | 0 | 0 | 0 | 0 | 15 | ...
pineapple| 0 | 10 | 0 | 0 | 10 | 0 | ...
Here opening stock for 05 2018 = 04 2018(stock + pipeline - order_qty)
Opening stock for 06 2018 = 05 2018(stock + pipeline - order_qty)
Try to use the following way
-- the first query returns all distinct dates
SELECT delivery_date oper_date
FROM order_fruit
UNION
SELECT receive_date
FROM pipeline
And you can use this information to generate the second query
-- the second query is generated using information about dates from the first query
SELECT
fruit_name
,SUM(stock_quantity) stock_quantity
-- 04 2018
,SUM(CASE WHEN oper_date='04 2018' THEN order_quantity END) order_quantity_04_2018
,SUM(CASE WHEN oper_date='04 2018' THEN pipeline_quantity END) pipeline_quantity_04_2018
-- 05 2018
,SUM(CASE WHEN oper_date='05 2018' THEN order_quantity END) order_quantity_05_2018
,SUM(CASE WHEN oper_date='05 2018' THEN pipeline_quantity END) pipeline_quantity_05_2018
-- 06 2018
,SUM(CASE WHEN oper_date='06 2018' THEN order_quantity END) order_quantity_06_2018
,SUM(CASE WHEN oper_date='06 2018' THEN pipeline_quantity END) pipeline_quantity_06_2018
-- ...
FROM
(
SELECT delivery_date oper_date,fruit_name,order_quantity,NULL stock_quantity,NULL pipeline_quantity
FROM order_fruit
UNION ALL
SELECT NULL,fruit_name_stock,NULL,stock_quantity,NULL
FROM stock_fruit
UNION ALL
SELECT receive_date,fruit_pipeline,NULL,NULL,pipeline_quantity
FROM pipeline
) q
GROUP BY fruit_name
SQL Fiddle - http://www.sqlfiddle.com/#!9/ceb1680/2
I have a table called Offers in which I have several offers:
ID | List Name | Arrival | Depart | Price
1 | Plus | 12 August | 18 August | $ 100.00
2 | Plus | 19 August | 25 August | $ 120.00
3 | Plus | 26 August | 1 September | $ 80.00
4 | Weekend | 11 August | 13 August | $ 50.00
5 | Weekend | 18 August | 20 August | $ 60.00
6 | Weekend | 25 August | 27 August | $ 40.00
Then I have a guest in my hotel which has a check-in and check-out date.
In need to find all the offers with the same List Name that cover all the days of my vacation's guest (from check-in date to check-out date).
Example
If my guest spends his time in my hotel from the 13th of August to the 20th of August I need to be returned only ids 1 and 2.
If my guest spends his time in my hotel from the 13th of August to the 27th of August I need to be returned only ids 1, 2, and 3. That's because the ids 6 and 7 cover only weekend and not all the days between check-in and check-out dates.
If my guest spends his time in my hotel from the 18th of August to the 20th of August I need to be returned only ids 1, 2 and 5.
You are looking for logic like this:
select o.*
from offers o
where o.arrival <= $arrival and o.depart >= $depart;
$arrival and $depart are the dates for your guest.
You need to do something like this :
SQL Fiddle
MySQL 5.6 Schema Setup:
CREATE TABLE offers
(`ID` int, `Arrival` date, `Depart` date, `Price` float)
;
INSERT INTO offers
(`ID`, `Arrival`, `Depart`, `Price`)
VALUES
(1, '2016-08-12', '2016-08-18', 100.00),
(2, '2016-08-19', '2016-08-25', 120.00),
(3, '2016-08-26', '2016-09-01', 80.00),
(4, '2016-08-11', '2016-08-13', 50.00),
(5, '2016-08-18', '2016-08-20', 60.00),
(6, '2016-08-25', '2016-08-27', 40.00)
;
Query 1:
select *
from offers
where (((arrival >= '2016-08-13' and arrival <= '2016-08-20') or
(depart >= '2016-08-13' and depart <= '2016-08-20'))
and datediff(depart,arrival) = 6)
or
(arrival = '2016-08-13' and depart = '2016-08-20'
and datediff(depart,arrival) = 2)
Results:
| ID | Arrival | Depart | Price |
|----|--------------------------|--------------------------|-------|
| 1 | August, 12 2016 00:00:00 | August, 18 2016 00:00:00 | 100 |
| 2 | August, 19 2016 00:00:00 | August, 25 2016 00:00:00 | 120 |
Query 2:
select *
from offers
where (((arrival >= '2016-08-13' and arrival <= '2016-08-27') or
(depart >= '2016-08-13' and depart <= '2016-08-27'))
and datediff(depart,arrival) = 6)
or
(arrival = '2016-08-13' and depart = '2016-08-27'
and datediff(depart,arrival) = 2)
Results:
| ID | Arrival | Depart | Price |
|----|--------------------------|-----------------------------|-------|
| 1 | August, 12 2016 00:00:00 | August, 18 2016 00:00:00 | 100 |
| 2 | August, 19 2016 00:00:00 | August, 25 2016 00:00:00 | 120 |
| 3 | August, 26 2016 00:00:00 | September, 01 2016 00:00:00 | 80 |
Query 3:
select *
from offers
where (((arrival >= '2016-08-18' and arrival <= '2016-08-20') or
(depart >= '2016-08-18' and depart <= '2016-08-20'))
and datediff(depart,arrival) = 6)
or
(arrival = '2016-08-18' and depart = '2016-08-20'
and datediff(depart,arrival) = 2)
Results:
| ID | Arrival | Depart | Price |
|----|--------------------------|--------------------------|-------|
| 1 | August, 12 2016 00:00:00 | August, 18 2016 00:00:00 | 100 |
| 2 | August, 19 2016 00:00:00 | August, 25 2016 00:00:00 | 120 |
| 5 | August, 18 2016 00:00:00 | August, 20 2016 00:00:00 | 60 |
I have a database with a table containing information on some images, each row containing a createdAt date and a viewCount. The data ranges from September 2014 until today (July 2016). I want to get a monthly sum of the amount of views across all images for the month
When I run the query
SELECT YEAR(createdAt), MONTH(createdAt), SUM(viewCount)
FROM Images
GROUP BY MONTH(createdAt);
I'm only returned 12 rows with results between September 2014 and August 2015
Year | Month | Views
-------------------
2014 | 9 | 1452
2014 | 10 | 279
2014 | 11 | 34428
2014 | 12 | 4763
2015 | 1 | 2826
2015 | 2 | 777
2015 | 3 | 568
2015 | 4 | 1309
2015 | 5 | 46744
2015 | 6 | 1541
2015 | 7 | 8160
2015 | 8 | 91
If I add a date restraint it will give me the latest data, but again only 12 rows
SELECT YEAR(createdAt), MONTH(createdAt), SUM(viewCount)
FROM Images WHERE createdAt > DATE('2015-08-01 00:00:00')
GROUP BY MONTH(createdAt);
Year | Month | Views
--------------------
2015 | 8 | 981
2015 | 9 | 1031
2015 | 10 | 2566
2015 | 11 | 3325
2015 | 12 | 411
2016 | 1 | 2140
2016 | 2 | 710
2016 | 3 | 714
2016 | 4 | 1985
2016 | 5 | 426
2016 | 6 | 119
2016 | 7 | 81
I do realise that since it's July the second query stops there as that's where the data ends, but why does the first query not return all the results?
Group by year/month:
SELECT YEAR(createdAt), MONTH(createdAt), SUM(viewCount)
FROM Images
--WHERE createdAt > DATE('2015-08-01 00:00:00')
GROUP BY YEAR(createdAt), MONTH(createdAt);
Related Group by clause in mySQL and postgreSQL, why the error in postgreSQL?
Keep in mind that from MySQL 5.7.6+ your initial query may not even work because of only_full_group_by which is set by default.
You can simply add Year to you group by
SELECT YEAR(createdAt), MONTH(createdAt), SUM(viewCount)
FROM Images
GROUP BY YEAR(createdAt), MONTH(createdAt)
ORDER BY YEAR(createdAt), MONTH(createdAt)
I have to find the difference in the value of a single column of table as current row value-previous row value for some 'n' number of rows in one column and also I don't have ID to use as reference for increment
date: box_count : total_no_of_boxes_used
1/12/12 2 2
2/12/12 8 6
3/12/12 14 6
I have box_count column and I am trying to get total_no_of_boxes_used column.
Please help me.
Thanks in advance
Given your records are sequential by date.....
SQLFIDDLE DEMO
Query:
select a.date, a.bc, case when (a.bc-b.bc) is null then a.bc else a.bc-b.bc end tot
from tt a
left join
tt b
on a.date > b.date
group by b.date
;
Results:
DATE BC TOT
December, 01 2012 00:00:00+0000 2 2
December, 02 2012 00:00:00+0000 8 6
December, 03 2012 00:00:00+0000 14 6
December, 04 2012 00:00:00+0000 23 9
One way to do this, is using a correlated subquery like so:
SELECT
t1.`date`,
t1.box_count,
t1.box_count -
IFNULL((SELECT t2.box_count
FROM table1 t2
WHERE t2.`date` < t1.`date`
ORDER BY t2.`date` DESC
LIMIT 1),
0 ) AS total_no_of_boxes_used
FROM table1 t1;
SQL Fiddle Demo
This will give you:
| DATE | BOX_COUNT | TOTAL_NO_OF_BOXES_USED |
------------------------------------------------------------------------
| January, 12 2012 00:00:00+0000 | 2 | 2 |
| February, 12 2012 00:00:00+0000 | 8 | 6 |
| March, 12 2012 00:00:00+0000 | 14 | 6 |
Try this:
SELECT date,
(box_count - #diff) total_no_of_boxes_used,
(#diff:=box_count) box_count
FROM table1, (SELECT #diff:=0) A;
Check this SQL FIDDLE DEMO
OUTPUT
| DATE | TOTAL_NO_OF_BOXES_USED | BOX_COUNT |
------------------------------------------------------------------------
| January, 12 2012 00:00:00+0000 | 2 | 2 |
| February, 12 2012 00:00:00+0000 | 6 | 8 |
| March, 12 2012 00:00:00+0000 | 6 | 14 |