I am trying to to perform an insert using the following:
INSERT INTO stock_withholds (s_id, mob, paddock, product, completed_date, withhold_until_date, ESI_withhold_until_date)
SELECT stk_id AS s_id,
mob,
paddock,
product,
completed_date,
withhold_until_date,
ESI_withhold_until_date
FROM stock_current
WHERE (withhold_until_date >=CURDATE()
OR (ESI_withhold_until_date >= CURDATE()
AND stock_current.stk_id NOT IN
(SELECT s_id
FROM stock_withholds)
If I rerun the query it duplicates the records.
Desired result is if either the withhold_until_date or ESI_withhold_until_date are greater then current date the records would inserted.
Thanks
I have a very simple table phone_calls with these columns:
id, timestamp, phone_number
How to write a query which returns a daily count of returning users? It should have two columns:
Date, Number of Returning Users
Returning user:
A returning user for any given day D is the one, who has called at least once before D.
A user who has called multiple times on D, but hasn't called before D won't be counted as a returning user.
UPDATE
So here is what I have tried:
SELECT DATE(timestamp) AS date, COUNT(DISTINCT phone_number) AS user_count
FROM phone_calls
WHERE phone_number IN (SELECT phone_number FROM phone_calls GROUP BY phone_number HAVING COUNT(consumer_id) > 1)
GROUP BY DATE(timestamp)
But it's not a correct solution, because it doesn't comply with definition of Returning User mentioned above.
What I am struggling with?
For any given date, how do I filter out those phone numbers from the count, who never dialed in before that day?
SELECT
DATE(timestamp) AS date,
COUNT(DISTINCT phone_number) AS user_count
FROM
phone_calls pc
WHERE EXISTS (
SELECT *
FROM phone_calls pc1
WHERE
pc1.phone_number = pc.phone_number AND
DATE(pc1.timestamp) < DATE(pc.timestamp)
)
GROUP BY DATE(pc.timestamp)
Updated try this query
Select date(pc.timestamp) AS RDate ,count(*)
from phone_calls pc INNER JOIN phone_calls pcc
on pcc.phone_number=pc.phone_number
and date(DATE_ADD(pcc.timestamp, INTERVAL -1 DAY))= DATE (pc.timestamp) group by DATE (pc.timestamp);
I have the following table:
table 1
columns are as following:
date , time , user_id , channel
I wish to find for a list of USERS watching in 2 different DATES , channel(lets say CNN, NBC...) all the entries relevant.
Means the channel in DATE 1 and DATE 2 is the same, also the user_id.
I try allready following:
select distinct monthname(date),max(date), min(date) count(distinct user_id)
from iptv_clean
group by monthname(date)
having min(date)!= max(date)
But it seems not to work well.
Any ideas?
The following gives a list of users and channels that users watched on more than one date:
select user_id, channel, count(distinct date)
from iptv_clean
group by user_id, channel
having count(distinct date) > 1;
Is this what you want?
I need a report with the count of the different values a column has, grouped by date, one output line per date.
The table columns are date, location ID (var) and rating (var). Rating can have only one of four values, ‘A’, ‘B’, ‘C’ or null/blank. I can get one line per date per value with this select, but how can I get the counts for all four values on the same line, for each date?
SELECT date, rating, count(rating) AS ratings
FROM table
GROUP BY date, rating
Use SUM with a boolean as follows:
SELECT
date,
SUM(rating = 'A') AS count_A,
SUM(rating = 'B') AS count_B,
SUM(rating = 'C') AS count_C,
SUM(rating = '' OR rating IS NULL) AS count_blank
FROM yourtable
GROUP BY date
I am attempting to write an SQL query for a reservations system to find the earliest available rental date for an item.
Items are categorized in the database by SKU. There can be multiple copies of an item, each uniquely identified in the database by its serial number.
When searching for the earliest available rental date for an item, it doesn't matter which serial number is chosen; simply the next one available.
The database has 2 tables; "Reservations" and "Items". There is also a Calendar table of several thousand YYYY-MM-DD future dates to work with.
The Reservations table contains columns; "record_number","sku", "serial_number", "start_date", "end_date" plus customer data. This is where each reservation is recorded as it is made.
The Items table contains columns; "sku" and "serial_number". This is an inventory of all rental items in the system.
I've worked the problem for over 2 days, but my SQL knowledge isn't enough to solve this puzzle.
I've progressed as far as generating a list of dates that have at least one reservation for a particular SKU:
SELECT calendar.dt
FROM calendar
LEFT JOIN reservations ON calendar.dt >= reservations.start_date
AND calendar.dt <= reservations.end_date
WHERE reservations.sku = 'ABC123'
I can sub-query the above into a "NOT IN ..." select statement but that only accomplishes finding dates having NO reservations for a particular SKU. I need to find the first date where at least one item is available.
I have imagined joining the dates of the Calendar table with the SKUs from the Items table with the reservation numbers of the Reservation table looking for "NULL" in the reservation_record, indicating no reservation exists for that date and serial-number combination. But I have been unable to write such a query that works.
Questions are welcome.
The following should get you going. you may want to adjust my sample of "Current_Date()" function for whatever may be your reservation start date and going out so many days....
This uses MySQL inline variables in the query. The inner query is a simple prepare of a reservation (#r) variable based on some starting date ( current_date() ), and joins to the item table. By doing no join clause, it would otherwise grab one date for every item. In my scenario, I'm only considering going out 30 days, so I've applied a limit of the first 30 items. No basis other than give me enough records so I don't have to create a temp table of 30 records (or however many days you want to go out). This creates an aliased query "JustDates" and has a single column "OpenDate". This is the basis of date ranges to test for.
This is now joined to the items table, but no condition creates a Cartesian to say for each date, compare with every item... per the WHERE clause, I am only concerned with items having SKU of "ABC123" weather they have 10 serial #s or 100. This would now give me a possible 300 or 3000 (10 serial items # 30 days, or 100 serial items # 30 days.
Now that I have a "range" of all individual serial numbers and possible days to check availability, I can now query against the reservations system. So, via a sub-select, and NOT IN for a given matching SKU, SERIAL #, and the POSSIBLE Date being found in reservations, I only want to keep those where the given OpenDate is NOT found. I've simulated your table structures and put in a handful of items, multiple serial numbers and staggared reservation date ranges and it works great...
Obviously, I would ensure indexes on sku / serial for performance. The only additional change I might make is when querying against the reservations, to exclude any reservations where the end date is prior to the starting date in question for YOUR query, and optionally, no Start Date > the LAST date you are considering. If you have a ton of reservations spanning years, who cares about something ancient, or something way in the future from the date range in question.
select items.sku,
items.serial_number,
JustDates.OpenDate
from
( SELECT
#r:= date_add(#r, interval 1 day ) OpenDate
FROM
(select #r := current_date()) vars,
items limit 30 ) JustDates,
items
where
sku = "ABC123"
and sku not in ( select sku from Reservations
where items.sku = reservations.sku
and items.serial_number = reservations.serial_number
and justDates.OpenDate >= reservations.start_date
and justDates.OpenDate <= reservations.end_date )
order by
items.serial_number,
justDates.OpenDate
Unfortunately, you can't look for missing rows (you can for rows that don't exist, but it's not the same).
You had a good start, querying the calendar table and left joining to the reservations, but you made a mistake by putting the filtering condition in the WHERE clause where it will return no rows instead of in the join ON clause.
SELECT calendar.dt,
COUNT(DISTINCT reservations.id) AS reserved,
COUNT(DISTINCT items.id) AS inventory
FROM calendar
LEFT JOIN reservations
ON calendar.dt >= reservations.start_date
AND calendar.dt <= reservations.end_date
AND reservations.sku = 'ABC123'
LEFT JOIN items ON items.sku=reservations.sku
GROUP BY calendar.dt
HAVING inventory > reserved OR reserved = 0
ORDER BY calendar.dt ASC
LIMIT 1
This query looks for the earliest date in the calendar table where the existing number of items in the items table is more than the number of reservations for those dates (ie, first date where you have stock available).
(EDIT: Substitute 'id' with the primary column in those tables)
I learned a really valuable lesson from a SQL expert a long time ago.
Don't let what you have blind you to what you need. Think about where reservations are used in the real world.
Hotels
Airlines
Cruise ships
Arenas
Football stadiums
Every one of these has a fixed inventory of seats on a particular day. Each of those seats might be either open or reserved--tied to a specific customer.
You have a fixed inventory of items on a particular day. Each of those items might be either available or reserved--tied to a specific customer.
I think your life would be a lot easier if you created a table of availability rather than a table of reservations.
create table availability (
sku varchar(15) not null,
sn varchar(15) not null,
av_date date not null,
customer_id integer, --references customers (customer_id)
primary key (sku, sn, av_date),
foreign key (sku, sn) references items (sku, sn)
);
insert into availability values
('1', '1', '2011-01-01', 1), -- reserved by customer_id 1
('1', '1', '2011-01-02', 1),
('1', '1', '2011-01-03', 1),
('1', '1', '2011-01-04', NULL), -- not yet reserved
('1', '1', '2011-01-05', NULL),
('1', '1', '2011-01-06', NULL),
('1', '1', '2011-01-07', NULL),
('1', '1', '2011-01-08', NULL),
('1', '1', '2011-01-09', NULL),
('1', '1', '2011-01-10', NULL),
('1', '2', '2011-01-01', NULL),
('1', '2', '2011-01-02', 2),
('1', '2', '2011-01-03', 2),
('1', '2', '2011-01-04', 3),
('1', '2', '2011-01-05', 3),
('1', '2', '2011-01-06', NULL),
('1', '2', '2011-01-07', NULL),
('1', '2', '2011-01-08', NULL),
('1', '2', '2011-01-09', NULL),
('1', '2', '2011-01-10', NULL);
(For production, I'd build a stored procedure to populate the availability table.)
Now it's just dead simple to select the earliest available date for a given sku.
select sku, sn, av_date, customer_id
from availability
where sku = '1' and customer_id is null
order by av_date asc
limit 1
The request start and end dates are the periods of time over which someone wants to reserve the given item. (E.g., "I want to reserve the widget sometime between July and September")
Revised to handle existing stock on-hand. Although, it isn't clear how that is actually stored. Do you have an on-hand value for each SKU or is each item given its own row?
Select Min( C.dt ) As EarliestAvailableDate
From Calendar As C
Left Join Reservations As R
On R.StartDate <= C.dt
And R.EndDate >= C.dt
And R.Sku = 'ABC123'
Where C.dt Between '[Request Start Date]' And '[Request End Date]'
And R.record_number Is Null
And Exists (
Select 1
From Items As I1
Left Join Reservations As R1
On R1.StartDate <= C.dt
And R1.EndDate >= C.dt
And R1.Sku = I1.SKU
Where I.SKU = 'ABC123'
Having Count(*) > Count(R1.record_number)
)
If your items table actually stores an on-hand value for the number of a given SKU in stock, then yo can simply change the query like so:
Select Min( C.dt ) As EarliestAvailableDate
From Calendar As C
Left Join Reservations As R
On R.StartDate <= C.dt
And R.EndDate >= C.dt
And R.Sku = 'ABC123'
Where C.dt Between '[Request Start Date]' And '[Request End Date]'
And R.record_number Is Null
And Exists (
Select 1
From Items As I1
Left Join Reservations As R1
On R1.StartDate <= C.dt
And R1.EndDate >= C.dt
And R1.Sku = I1.SKU
Where I.SKU = 'ABC123'
Having I1.OnHandCount > Count(R1.record_number)
)