SQL UNION not working with 2 HAVING clauses - mysql

Question

I want to use UNION to join two SQL SELECT queries. I need the final data to use the HAVING clause to filter the entire query. Here is my statement:
SELECT CLIENT,
BIZNAME,
BIZSTREET,
BIZCITY,
BIZSTATE,
BIZZIP,
BIZPHONE,
URL,
LAT,
LNG,
CONSOLIDATED,
( 3959 * ACOS(COS(RADIANS('%s')) * COS(RADIANS(LAT)) * COS(
RADIANS(LNG) - RADIANS('%s'))
+ SIN
(RADIANS('%s')) * SIN(RADIANS(LAT))) ) AS distance
FROM BizInfo
INNER JOIN WebSites
ON WebSites.CUSTOMER = BizInfo.CUSTOMER
WHERE BizInfo.CLIENT = 'GCB'
AND WebSites.STATUS <> 'Cancel'
AND WebSites.STATUS <> 'In Progress'
AND WebSites.STATUS <> 'Review'
AND WebSites.STATUS <> 'Testing'
UNION
SELECT CLIENT,
BIZNAME,
BIZSTREET,
BIZCITY,
BIZSTATE,
BIZZIP,
BIZPHONE,
'http://www.abc-site.com',
LAT,
LNG,
'0',
( 3959 * ACOS(COS(RADIANS('%s')) * COS(RADIANS(LAT)) * COS(
RADIANS(LNG) - RADIANS('%s'))
+ SIN
(RADIANS('%s')) * SIN(RADIANS(LAT))) ) AS distance
FROM BizInfo
WHERE CLIENT = 'GCB'
AND BIZNAME = 'Acme'
HAVING DISTANCE < '%s'
ORDER BY DISTANCE
LIMIT 0, 200
I read on this site http://www.really-fine.com/SQL_union.html (GROUP BY and HAVING clauses can be used only within individual queries and cannot be used to affect the final results set. ), but I don't understand how to implement this or if it is correct.
How do I properly write this SQL query?

Answer 1

You can probably solve that very easily by wrapping everything into a subquery. Something like :
SELECT
*
FROM
(
SELECT Client, BizName, BizStreet, BizCity, BizState, BizZip, BizPhone, url, lat, lng, Consolidated,
( 3959 * acos( cos( radians('%s') ) * cos( radians( lat ) ) * cos( radians( lng ) - radians('%s') ) + sin( radians('%s') ) * sin( radians( lat ) ) ) )
AS distance FROM BizInfo
INNER JOIN WebSites ON WebSites.Customer = BizInfo.Customer
WHERE BizInfo.Client = 'GCB'
AND WebSites.Status <> 'Cancel' AND WebSites.Status <> 'In Progress' AND WebSites.Status <> 'Review' AND WebSites.Status <> 'Testing'
UNION SELECT Client, BizName, BizStreet, BizCity, BizState, BizZip, BizPhone, 'http://www.abc-site.com', lat, lng, '0',
( 3959 * acos( cos( radians('%s') ) * cos( radians( lat ) ) * cos( radians( lng ) - radians('%s') ) + sin( radians('%s') ) * sin( radians( lat ) ) ) )
AS distance FROM BizInfo WHERE Client = 'GCB' AND BizName = 'Acme'
) AS ClientInfo
WHERE
distance < '%s'
ORDER BY
distance
LIMIT 0 , 200
This is the fastest path to what you want but it is not very clean.
Also please tell me that all those parameters are not vulnerable to SQL injection...?

Answer 2

HAVING can only be used in an aggregate query with a GROUP BY clause. Your queries do not. Use WHERE instead.

Answer 3

Those are scalar functions, not aggregate functions. So to filter on the result, use the WHERE clause, not the HAVING clause. You are filtering horizontally, not vertically.
You cannot use a column alias in the WHERE clause, so you have to restate the functions used in the SELECT list (I've done that in the query below).
Try the following. There are 2 issues at play.
SELECT Client,
BizName,
BizStreet,
BizCity,
BizState,
BizZip,
BizPhone,
url,
lat,
lng,
Consolidated,
(3959 * acos(cos(radians('%s')) * cos(radians(lat)) *
cos(radians(lng) - radians('%s')) +
sin(radians('%s')) * sin(radians(lat)))) AS distance
FROM BizInfo
INNER JOIN WebSites
ON WebSites.Customer = BizInfo.Customer
WHERE BizInfo.Client = 'GCB'
AND WebSites.Status <> 'Cancel'
AND WebSites.Status <> 'In Progress'
AND WebSites.Status <> 'Review'
AND WebSites.Status <> 'Testing'
UNION
SELECT Client,
BizName,
BizStreet,
BizCity,
BizState,
BizZip,
BizPhone,
'http://www.abc-site.com',
lat,
lng,
'0',
(3959 * acos(cos(radians('%s')) * cos(radians(lat)) *
cos(radians(lng) - radians('%s')) +
sin(radians('%s')) * sin(radians(lat)))) AS distance
FROM BizInfo
WHERE Client = 'GCB'
AND BizName = 'Acme'
and (3959 * acos(cos(radians('%s')) * cos(radians(lat)) *
cos(radians(lng) - radians('%s')) +
sin(radians('%s')) * sin(radians(lat)))) < '%s'
ORDER BY distance LIMIT 0, 200