I am trying to build a product review page where users can comment any submitted reviews like Amazon. I want the page to display 3 user reviews as well as 2 responses to each of the reviews if they exist.
Here's the table
CREATE TABLE product_review
(`ID` int, `username` varchar(21), `review_title` varchar(30), `review_or_reply` int)
;
INSERT INTO product_review
(`ID`, `username`, `review_title`, `review_or_reply`)
VALUES
(1, 'Tom', 'Rip-off', 0),
(2, 'Peter', 'Rip-off', 1),
(3, 'May', 'Rip-off', 1),
(4, 'June', 'Rip-off', 1),
(5, 'Tommy', 'Worth the Price', 0),
(6, 'Sammy', 'Worth the Price', 1),
(7, 'Sam', 'Worth the Price',1),
(8, 'Bryan','Worth the Price',1),
(9, 'Sally', 'Average Product', 0)
;
The review_or_reply field is effectively a Yes or No field, where 0 means it's a review and 1 is the review's comments by other users.
Is there a single select statement that can limit 3 reviews and bring up two of their comments? For example:
Select `username`,`review_title`,`reply` from product_review where review_or_reply ='0' Limit 3
Select `username`,`review_title`,`reply` from product_review where review_or_reply = '1' and title = 'Rip-off' Limit 2
Select `username`,`review_title`,`reply` from product_review where review_or_reply = '1' and title = 'Worth the Price' Limit 2
Select `username`,`review_title`,`reply` from product_review where review_or_reply = '1' and title = 'Average Product' Limit 2
I want the output to be like this:
username review_title review_or_reply
Tom Rip-off 0
Peter Rip-off 1
May Rip-off 1
Tommy Worth the Price 0
Sammy Worth the Price 1
Sam Worth the Price 1
Sally Average Product 0
this will return 3 review_titles and then pull out two responses to that
SELECT
pr.*,
IF( #A = t.review_title,
IF(#B = 3, #B := 1, #B := #B +1)
, #B
) AS group_col,
#A := t.review_title
FROM (
SELECT
id,
username,
review_title
FROM product_review
WHERE reply ='0' LIMIT 3
) t
JOIN product_review pr ON pr.review_title=t.review_title
CROSS JOIN (SELECT #A := "", #B := 1) AS temp
GROUP BY group_col, review_title
ORDER BY id;
EDIT:
if there are more than one reply that is 0 in the database like so then this query will check for that. (since you did specify in the other queries that the reply had to be 1).
INSERT INTO product_review
(`ID`, `username`, `review_title`, `reply`)
VALUES
(1, 'Tom', 'Rip-off', 0),
(2, 'Peter', 'Rip-off', 1),
(3, 'May', 'Rip-off', 0),
(4, 'June', 'Rip-off', 1),
(5, 'Tommy', 'Worth the Price', 0),
(6, 'Sammy', 'Worth the Price', 1),
(7, 'Sam', 'Worth the Price',1),
(8, 'Bryan','Worth the Price',1),
(9, 'Sally', 'Average Product', 0),
(10, 'Timothy', 'Rip-off', 1)
notice that at id 3 there is a reply of 0 with id 10 a reply of 1. this query will correctly skip the reply = 0.
SELECT
pr.*,
IF( #A = t.review_title,
IF(pr.reply = 0, 1,
IF(#B = 3, #B := 1, #B := #B +1)
), #B
) AS group_col,
#A := t.review_title
FROM (
SELECT
DISTINCT
id,
username,
review_title
FROM product_review
WHERE reply ='0'
GROUP BY review_title
LIMIT 3
) t
JOIN product_review pr ON pr.review_title=t.review_title
CROSS JOIN (SELECT #A := "", #B := 1) AS temp
GROUP BY group_col, review_title
ORDER BY id;
DEMO
...or slower but simpler...
SELECT x.*
FROM product_review x
JOIN product_review y
ON y.review_title = x.review_title
AND y.id <= x.id
GROUP
BY x.id
HAVING COUNT(*) <= 3
ORDER
BY MIN(y.id)
LIMIT 3;
Related
My Database table is as shown below. I need to get latest mark of each student. Latest entry is the row with maximum udate and maximum oder. (The oder will be incremented by one on each entry with same date)
In my example, I have two students Mujeeb, Zakariya and two subjects ENGLISH, MATHS. I need to get latest mark of each student for each subject. My expectd result is as follows
My sample data is
DROP TABLE IF EXISTS `students`;
CREATE TABLE IF NOT EXISTS `students` (
`uid` int(11) NOT NULL AUTO_INCREMENT,
`udate` date NOT NULL,
`oder` int(11) NOT NULL,
`name` varchar(20) NOT NULL,
`Subject` varchar(20) NOT NULL,
`mark` int(11) NOT NULL,
PRIMARY KEY (`uid`)
) ENGINE=MyISAM AUTO_INCREMENT=13 DEFAULT CHARSET=latin1;
INSERT INTO `students` (`uid`, `udate`, `oder`, `name`, `Subject`, `mark`) VALUES
(1, '2021-08-01', 1, 'Mujeeb', 'ENGLISH', 10),
(2, '2021-08-01', 1, 'Zakariya', 'ENGLISH', 20),
(3, '2021-08-10', 2, 'Mujeeb', 'ENGLISH', 50),
(4, '2021-08-11', 2, 'Zakariya', 'ENGLISH', 60),
(5, '2021-08-02', 1, 'Mujeeb', 'ENGLISH', 100),
(6, '2021-08-03', 1, 'Zakariya', 'ENGLISH', 110),
(7, '2021-08-10', 1, 'Mujeeb', 'ENGLISH', 500),
(8, '2021-08-11', 1, 'Zakariya', 'ENGLISH', 600),
(9, '2021-08-01', 2, 'Mujeeb', 'MATHS', 100),
(10, '2021-08-01', 2, 'Zakariya', 'MATHS', 75),
(11, '2021-08-10', 3, 'Mujeeb', 'MATHS', 50),
(12, '2021-08-11', 3, 'Zakariya', 'MATHS', 60);
Use NOT EXISTS:
SELECT s1.*
FROM students s1
WHERE NOT EXISTS (
SELECT 1
FROM students s2
WHERE s2.name = s1.name AND s2.Subject = s1.Subject
AND (s2.udate > s1.udate OR (s2.udate = s1.udate AND s2.oder > s1.oder))
);
Or with a correlated subquery in the WHERE clause:
SELECT s1.*
FROM students s1
WHERE s1.uid = (
SELECT s2.uid
FROM students s2
WHERE s2.name = s1.name AND s2.Subject = s1.Subject
ORDER BY s2.udate DESC, s2.oder DESC LIMIT 1
);
See the demo.
As ROW_NUMBER() function doesn't work at lower version of MySQL, So alternate way of row_number() is used for this solution.
-- MySQL (v5.6)
SELECT p.uid, p.udate, p.oder, p.name, p.Subject, p.mark
FROM (SELECT #row_no := IF((#prev_val = t.name && #prev_val1 = t.Subject), #row_no + 1, 1) AS row_number
, #prev_val := t.name AS name
, #prev_val1 := t.Subject AS Subject
, t.mark
, t.oder
, t.uid
, t.udate
FROM students t,
(SELECT #row_no := 0) x,
(SELECT #prev_val := '') y,
(SELECT #prev_val1 := '') z
ORDER BY t.name, t.Subject, t.udate DESC, t.oder DESC ) p
WHERE p.row_number = 1
ORDER BY p.name, p.Subject;
Please check the url http://sqlfiddle.com/#!9/b5befe/18
I want to make a ranking with the best 5 scores of the players summed and put in a ranking. Players have more or less then 5 scores.
For now I have the following query:
set #count:=0, #player:='';
SELECT SEIZOEN
, WEDSTRIJDTYPE
, ATLEET_ID
, GROEP_NAAM
, GROEP_OMS
, SUM(PUNTEN_WC) as WC_RESULT
FROM
( SELECT ATLEET_ID
, PUNTEN_WC
, SEIZOEN
, WEDSTRIJDTYPE
, GROEP_NAAM
, GROEP_OMS
FROM
( SELECT PUNTEN_WC
, SEIZOEN
, WEDSTRIJDTYPE
, GROEP_NAAM
, GROEP_OMS
, #count := if (#player != ATLEET_ID,0,#count + 1) as count
, #player := ATLEET_ID as ATLEET_ID
FROM
( SELECT ATLEET_ID
, PUNTEN_WC
, k.SEIZOEN
, k.WEDSTRIJDTYPE
, g.GROEP_NAAM
, g.GROEP_OMS
FROM RESULTATEN r
LEFT
JOIN KALENDER k
ON r.KALENDER_ID = k.KALENDER_ID
JOIN GROEP_SNB g
ON r.GROEP_NAAM = g.GROEP_NAAM
JOIN SKIER s
ON r.ATLEET_ID = s.SKIER_ID
WHERE k.WEDSTRIJDTYPE = 'Dutch Cup snowboard '
AND k.SEIZOEN = '2016-2017'
order
by ATLEET_ID
, PUNTEN_WC DESC
) x
) y
where count < 6
) z
GROUP
BY ATLEET_ID
ORDER
BY GROEP_NAAM
, WC_RESULT DESC
LIMIT 0,2000;
The problem is this query doesn't take the five best scores of each player.
When I run the most inner query it's sorts the scores fine.
SELECT ATLEET_ID
, PUNTEN_WC
, k.SEIZOEN
, k.WEDSTRIJDTYPE
, g.GROEP_NAAM
, g.GROEP_OMS
FROM RESULTATEN r
LEFT
JOIN KALENDER k
ON r.KALENDER_ID = k.KALENDER_ID
JOIN GROEP_SNB g
ON r.GROEP_NAAM = g.GROEP_NAAM
JOIN SKIER s
ON r.ATLEET_ID = s.SKIER_ID
WHERE k.WEDSTRIJDTYPE = 'Dutch Cup snowboard '
AND k.SEIZOEN = '2016-2017'
order
by ATLEET_ID
, PUNTEN_WC DESC
I've put a count on the records so I can limit it to best of 5. But then the trouble starts. With the second query the highscores are still ordered correctly but the count-field is not 0 to 5?
So when I put the third query in it stops when count-field is 5, but I want a maximum of 5 scores per player.
You can sum the top N values for each person with this query:
Creating a simple test table and populating it -
CREATE TABLE Scores
(`id` int, `playerName` varchar(16), `score` int)
;
INSERT INTO Scores
(`id`, `playerName`, `score`)
VALUES
(1, 'Joe', 5),
(2, 'Joe', 5),
(3, 'Joe', 5),
(4, 'Joe', 1),
(5, 'Joe', 10),
(6, 'Joe', 10),
(7, 'Joe', 15),
(8, 'Bob', 5),
(9, 'Bob', 5),
(10, 'Bob', 2),
(11, 'Bob', 10),
(12, 'Bob', 3),
(13, 'Bob', 10),
(14, 'Bob', 20)
;
The query:
SET #score_rank := 0;
SET #current_player = '';
SET #topN = 5;
Select playerName, SUM(score)
From (Select playerName, score,
#score_rank := IF(#current_player = playerName, (#score_rank + 1), 1) AS score_rank,
#current_player := playerName
From Scores
Order By playerName, score DESC) sorted
Where score_rank <= #topN
Group By playerName;
The inner query assigns values to two variables - #current_player and #score_rank. If the #current_player value matches playerName, it increments #score_rank, otherwise it sets the #score_rank to 1. By doing this, we can grab only the top 5 for each player. The outer query then sums those top 5 scores. You can change the value of #topN if you want to sum a different set (like top 10).
Results with the above sample table:
playerName SUM(score)
---------- ----------
Bob 50
Joe 45
See it here: http://rextester.com/CLO11640
I need to count whether there are three consecutive failed login attempts of the user in last one hour.
For example
id userid status logindate
1 1 0 2014-08-28 10:00:00
2 1 1 2014-08-28 10:10:35
3 1 0 2014-08-28 10:30:00
4 1 0 2014-08-28 10:40:00
In the above example, status 0 means failed attempt and 1 means successful attempt.
I need a query that will count three consecutive records of a user with status 0 occurred in last one hour.
I tried below query
SELECT COUNT( * ) AS total, Temp.status
FROM (
SELECT a.status, MAX( a.id ) AS idlimit
FROM loginAttempts a
GROUP BY a.status
ORDER BY MAX( a.id ) DESC
) AS Temp
JOIN loginAttempts t ON Temp.idlimit < t.id
HAVING total >1
Result:
total status
2 1
I don't know why it display status as 1. I also need to add a where condition on logindate and status field but don't know how would it work
For consecutive count you can use user defined variables to note the series values ,like in below query i have use #g and #r variable, in inner query i am storing the current status value that could be 1/0 and in case expression i am comparing the value stored in #g with the status column if they both are equal like #g is holding previous row value and previous row's status is equal to the current row's status then do not change the value stored in #r,if these values don't match like #g <> a.status then increment #r with 1, one thing to note i am using order by with id column and assuming it is set to auto_increment so for consecutive 1s #r value will be same like #r was 3 for first status 1 and the again status is 1 so #r will 3 until the status changes to 0 same for status 0 vice versa
SELECT t.userid,t.consecutive,t.status,COUNT(1) consecutive_count
FROM (
SELECT a.* ,
#r:= CASE WHEN #g = a.status THEN #r ELSE #r + 1 END consecutive,
#g:= a.status g
FROM attempts a
CROSS JOIN (SELECT #g:=2, #r:=0) t1
WHERE a.`logindate` BETWEEN '2014-08-28 10:00:00' AND '2014-08-28 11:00:00'
ORDER BY id
) t
GROUP BY t.userid,t.consecutive,t.status
HAVING consecutive_count >= 3 AND t.status = 0
Now in parent query i am grouping results by userid the resultant value of case expression i have name is it as consecutive and status to get the count for each user's consecutive status
One thing to note for above query that its necessary to provide the
hour range like i have used between without this it will be more
difficult to find exactly 3 consecutive statuses with in an hour
Sample data
INSERT INTO attempts
(`id`, `userid`, `status`, `logindate`)
VALUES
(1, 1, 0, '2014-08-28 10:00:00'),
(2, 1, 1, '2014-08-28 10:10:35'),
(3, 1, 0, '2014-08-28 10:30:00'),
(4, 1, 0, '2014-08-28 10:40:00'),
(5, 1, 0, '2014-08-28 10:50:00'),
(6, 2, 0, '2014-08-28 10:00:00'),
(7, 2, 0, '2014-08-28 10:10:35'),
(8, 2, 0, '2014-08-28 10:30:00'),
(9, 2, 1, '2014-08-28 10:40:00'),
(10, 2, 1, '2014-08-28 10:50:00')
;
As you can see from id 3 to 5 you can see consecutive 0s for userid 1 and similarly id 6 to 8 userid 2 has consecutive 0s and they are in an hour range using above query you can have results as below
userid consecutive status consecutive_count
------ ----------- ------ -------------------
1 2 0 3
2 2 0 3
Fiddle Demo
M Khalid Junaid's answer is great, but his Fiddle Demo didn't work for me when I clicked it.
Here is a Fiddle Demo which works as of this writing.
In case it doesn't work later, I used the following in the schema:
CREATE TABLE attempts
(`id` int, `userid` int, `status` int, `logindate` datetime);
INSERT INTO attempts
(`id`, `userid`, `status`, `logindate`)
VALUES
(1, 1, 0, '2014-08-28 10:00:00'),
(2, 1, 1, '2014-08-28 10:10:35'),
(3, 1, 0, '2014-08-28 10:30:00'),
(4, 1, 0, '2014-08-28 10:40:00'),
(5, 1, 0, '2014-08-28 10:50:00'),
(6, 2, 0, '2014-08-28 10:00:00'),
(7, 2, 0, '2014-08-28 10:10:35'),
(8, 2, 0, '2014-08-28 10:30:00'),
(9, 2, 1, '2014-08-28 10:40:00'),
(10, 2, 1, '2014-08-28 10:50:00')
;
And this as the query:
SELECT t.userid,t.consecutive,t.status,COUNT(1) consecutive_count
FROM (
SELECT a.* ,
#r:= CASE WHEN #g = a.status THEN #r ELSE #r + 1 END consecutive,
#g:= a.status g
FROM attempts a
CROSS JOIN (SELECT #g:=2, #r:=0) t1
WHERE a.`logindate` BETWEEN '2014-08-28 10:00:00' AND '2014-08-28 11:00:00'
ORDER BY id
) t
GROUP BY t.userid,t.consecutive,t.status
HAVING consecutive_count >= 3 AND t.status = 0;
I have the below query which comes from this post count number of items in a row in mysql which counts how many times in a row a student has been present/absent from a class.
SELECT
classlist.studentid,
student.name,
classStatus.name status,
COUNT(*) presentcnt
FROM
classlist
INNER JOIN student ON classlist.studentid=student.id
INNER JOIN classstatus ON classlist.presentid=classstatus.id
INNER JOIN (
SELECT
studentid,
max(CASE WHEN presentid=0 THEN id END) max_0,
max(CASE WHEN presentid=1 THEN id END) max_1
FROM classlist
GROUP BY studentid
) s
ON coalesce(classlist.id>least(max_0,max_1) AND classlist.id<=greatest(max_0,max_1),1) AND s.studentid=classlist.studentid
GROUP BY classlist.studentid
This works as expected,
STUDENTID NAME STATUS PRESENTCNT
111 John Present 1
222 Kate Absent 2
333 Matt Present 5
I want to extend the query so that I have a column showing if the student particpated in the class.
If I run an independent query I get the results I want
SELECT
classlist.studentid,
student.name,
participatedStatus.name status,
COUNT(*) participatedcnt
FROM
classlist
INNER JOIN student ON classlist.studentid=student.id
INNER JOIN participatedStatus ON classlist.participatedid=participatedStatus.id
INNER JOIN (
SELECT
studentid,
max(CASE WHEN participatedid=0 THEN id END) max_0,
max(CASE WHEN participatedid=1 THEN id END) max_1
FROM classlist
group by studentid
) s
ON coalesce(classlist.id>least(max_0,max_1)
AND classlist.id<=greatest(max_0,max_1),1)
AND s.studentid=classlist.studentid
group by classlist.studentid
STUDENTID NAME STATUS PARTICIPATEDCNT
111 John Yes 1
222 Kate No 2
333 Matt Yes 2
However I want to merge them into the one query so I get
STUDENTID NAME STATUS PRESENTCNT STATUS2 PARTICIPATEDCNT
111 John Present 1 Yes 1
222 Kate Absent 2 No 2
333 Matt Present 5 Yes 2
I am confused about how this can be achieved as I am selecting count *, how can I acheive this?
A sample of the data I am using is in this fiddle and below
CREATE TABLE classlist
(`id` int, `studentid` int, `subjectid` int, `presentid` int, `participatedid` int);
CREATE TABLE student
(`id` int, `name` varchar(4));
CREATE TABLE subject
(`id` int, `name` varchar(4));
CREATE TABLE classStatus
(`id` int, `name` varchar(8));
CREATE TABLE participatedStatus
(`id` int, `name` varchar(8));
INSERT INTO classlist (`id`, `studentid`, `subjectid`, `presentid`, `participatedid`)
VALUES (1, 111, 1, 1, 0), (2, 222, 3, 0, 0), (3, 333, 2, 1, 0), (4, 111, 4, 0, 0), (5, 111, 1, 1, 0), (6, 222, 3, 0, 0), (7, 333, 2, 1, 1), (8, 111, 4, 0, 0), (9, 111, 4, 0, 0), (10, 111, 4, 0, 0), (11, 111, 1, 1, 1), (12, 333, 3, 1, 0), (13, 333, 2, 1, 1), (14, 333, 3, 1, 1);
INSERT INTO student (`id`, `name`)
VALUES (111, 'John'),(222, 'Kate'),(333, 'Matt');
INSERT INTO subject (`id`, `name`)
VALUES (1, 'MATH'),(2, 'ENG'),(3, 'SCI'),(4, 'GEO');
INSERT INTO classStatus (`id`, `name`)
VALUES (0, 'Absent'), (1, 'Present');
INSERT INTO participatedStatus (`id`, `name`)
VALUES (0, 'No'),(1, 'Yes');
SELECT
studid,
studname,
status,
presentcnt,
status1,
participatedcnt FROM
(SELECT
classlist.studentid studid,
student.name studname,
classStatus.name status,
COUNT(*) presentcnt
FROM
classlist
INNER JOIN student ON classlist.studentid=student.id
INNER JOIN classstatus ON classlist.presentid=classstatus.id
INNER JOIN (
SELECT
studentid,
max(CASE WHEN presentid=0 THEN id END) max_0,
max(CASE WHEN presentid=1 THEN id END) max_1
FROM classlist
GROUP BY studentid
) s
ON coalesce(classlist.id>least(max_0,max_1) AND classlist.id<=greatest(max_0,max_1),1) AND s.studentid=classlist.studentid
GROUP BY classlist.studentid)x
JOIN
(SELECT
classlist.studentid,
student.name,
participatedStatus.name status1,
COUNT(*) participatedcnt
FROM
classlist
INNER JOIN student ON classlist.studentid=student.id
INNER JOIN participatedStatus ON classlist.participatedid=participatedStatus.id
INNER JOIN (
SELECT
studentid,
max(CASE WHEN participatedid=0 THEN id END) max_0,
max(CASE WHEN participatedid=1 THEN id END) max_1
FROM classlist
group by studentid
) s
ON coalesce(classlist.id>least(max_0,max_1)
AND classlist.id<=greatest(max_0,max_1),1)
AND s.studentid=classlist.studentid
group by classlist.studentid)y
ON x.studid=y.studentid
Fiddle
I have a list of students that shows whether they were present or absent from a particular class.
CREATE TABLE classlist
(`id` int, `studentid` int, `subjectid` int, `presentid` int)
;
CREATE TABLE student
(`id` int, `name` varchar(4))
;
CREATE TABLE subject
(`id` int, `name` varchar(4))
;
CREATE TABLE classStatus
(`id` int, `name` varchar(8))
;
INSERT INTO classlist
(`id`, `studentid`, `subjectid`, `presentid`)
VALUES
(1, 111, 1, 1),
(2, 222, 3, 0),
(3, 333, 2, 1),
(4, 111, 4, 0),
(5, 111, 1, 1),
(6, 222, 3, 0),
(7, 333, 2, 1),
(8, 111, 4, 0),
(9, 111, 4, 0),
(10, 111, 4, 0),
(11, 111, 1, 1),
(12, 333, 3, 1),
(13, 333, 2, 1),
(14, 333, 3, 1)
;
INSERT INTO student
(`id`, `name`)
VALUES
(111, 'John'),
(222, 'Kate'),
(333, 'Matt')
;
INSERT INTO subject
(`id`, `name`)
VALUES
(1, 'MATH'),
(2, 'ENG'),
(3, 'SCI'),
(4, 'GEO')
;
INSERT INTO classStatus
(`id`, `name`)
VALUES
(0, 'Absent'),
(1, 'Present')
;
See Fiddle http://sqlfiddle.com/#!2/a2d93/5
I can count who is absent and present overall with something like the below.
SELECT
studentid,
students.name AS NAME,
SUM(presentid = 1) AS present,
SUM(presentid = 0) AS absent
FROM classlist
INNER JOIN student as students ON classlist.studentid=students.id
GROUP BY studentid, NAME
But I want to know how many classes in a row a student has attended/missed, so that the teachers can easily see if someone has missed a lot of time or someone is rewarded for good attendance etc. I have seen some posts which talk about streaks but none of them seem to match the way the data has been presented to me so I am not sure how to acheive this?
Just to be clear based on my sample data below the out put for the streaks should be.
(1, 111, 1, 1), /* John Present 1 times in a row */
(2, 222, 3, 0), /* Kate Absent 1 times in a row */
(3, 333, 2, 1), /* Matt Present 1 times in a row */
(4, 111, 4, 0), /* John Absent 1 times in a row */
(5, 111, 1, 1), /* John Present 1 times in a row */
(6, 222, 3, 0), /* Kate Absent 2 times in a row */
(7, 333, 2, 1), /* Matt Present 2 times in a row */
(8, 111, 4, 0), /* John Absent 1 times in a row */
(9, 111, 4, 0), /* John Absent 2 times in a row */
(10, 111, 4, 0), /* John Absent 2 times in a row */
(11, 111, 1, 1), /* John Present 1 times in a row */
(12, 333, 3, 1), /* Matt Present 3 times in a row */
(13, 333, 2, 1), /* Matt Present 4 times in a row */
(14, 333, 3, 1) /* Matt Present 5 times in a row */
/*Showing the latest status for each user*/
/* John Present 1 times in a row */
/* Kate Absent 2 times in a row */
/* Matt Present 5 times in a row */
John present 1.
Kate absent 2.
Matt Present 5.
This should give the count of the consecutive rows with the same value as the last row:
select
classlist.studentid,
student.name,
classStatus.name status,
count(*) presentcnt
from
classlist inner join student
on classlist.studentid=student.id
inner join classstatus
on classlist.presentid=classstatus.id
inner join (
select
studentid,
max(case when presentid=0 then id end) max_0,
max(case when presentid=1 then id end) max_1
from classlist
group by studentid
) s
on coalesce(classlist.id>least(max_0,max_1) and
classlist.id<=greatest(max_0,max_1),1)
and s.studentid=classlist.studentid
group by classlist.studentid
On the subquery I'm extracting the max id where presentid = 0 and the max id where presentid = 1.
On the outer query I'm extracting and counting all rows where id is > than the least of max_0 and max_1, and <= than the greatest of those two. No matter what the last value is, these are all the rows with the same value as the last one.
If either max_0 or max_1 is null, it means that all rows have just one value, 1 or 0, and we have to get all of them. If one of max_0 or max_1 is null, the whole conditions will be null as well. Using Coalesce( condition, 1) I'm returning all rows in that case.
Notice that I am grouping by classlist.studentid and showing some nonaggregated columns, but this is a situation in which it is allowed since all nonaggregated columns have the same value.
Do you want this?:
SELECT
studentid,
name,
SUM(present = 1) AS present,
SUM(present = 0) AS absent,
count(subject) as classTimes,
subject
FROM your_table GROUP BY studentid, name,subject
If id from classlist can be used for ordering then you will get your expected result with
SELECT
s.name,
CASE t1.presentid
WHEN 0 THEN 'absent'
WHEN 1 THEN 'present'
END state,
t1.pc
FROM (
SELECT
c.id,
c.studentid,
c.presentid,
#pcount := IF( #pid = presentid AND #sid = studentid, #pcount + 1, 1 ) as pc,
#pid := presentid,
#sid := studentid
FROM
classlist c
ORDER BY
studentid, id ) t1
JOIN student s
ON t1.studentid = s.id
WHERE
( t1.studentid, t1.id ) IN ( SELECT
studentid,
MAX( id )
FROM classlist
GROUP BY studentid );
SQL Fiddle DEMO
Try this:
SELECT A.studentid, s.name, IF(presentid = 1, 'present', 'absent') STATUS,
ABS(SUM(IF(presentid = 1, 1, -1))) AS presentcnt
FROM classlist A
INNER JOIN student s ON A.studentid = s.id
LEFT JOIN (SELECT MAX(id) id, studentid
FROM classlist GROUP BY studentid
) B ON A.studentid = B.studentid AND A.id = B.id
GROUP BY A.studentid
Check this SQL FIDDLE DEMO
OUTPUT
| STUDENTID | NAME | STATUS | PRESENTCNT |
-------------------------------------------
| 111 | John | present | 1 |
| 222 | Kate | absent | 2 |
| 333 | Matt | present | 5 |
I'm not sure what point about your question.
If this you want
John present 1.
Kate absent 2.
Matt Present 5.
U may try this:
SELECT
studentid,
students.name AS NAME,
SUM(presentid = 1) AS present,
SUM(presentid = 0) AS absent,
IF( SUM(presentid = 1)-SUM(presentid = 0)>=0,SUM(presentid = 1)-SUM(presentid = 0),SUM(presentid = 0)-SUM(presentid = 1)) AS aliase
FROM classlist
INNER JOIN student as students ON classlist.studentid=students.id
GROUP BY studentid, NAME