Google Apps Script - Find Row number based on a cell value - google-apps-script

Question

I'm looking for some assistance on find the row number for a cell that contains a specific value.
The spreadsheet has lots of data across multiple rows & columns. I'm looping over the .getDataRange and can located the cell containing the value I'm looking for. Once found I'd like to know the row that his cell is in, so that I can further grab additional cell values since I know exactly how many rows down and/or columns over the additional information is from the found cell.
Here is a bit of the code for finding the cell containing a specific string.
function findCell() {
var ss = SpreadsheetApp.getActiveSpreadsheet();
var sheet = ss.getActiveSheet();
var dataRange = sheet.getDataRange();
var values = dataRange.getValues();
for (var i = 0; i < values.length; i++) {
var row = "";
for (var j = 0; j < values[i].length; j++) {
if (values[i][j] == "User") {
row = values[i][j+1];
Logger.log(row);
}
}
}
}
When outputting Logger.log(row) it gives me the values I'm looking for. I want to determine what row each value is in, so I can then go down X number of rows and over X columns to get the contents of other cells.

Answer 1

I don't know much about google apps but it looks like [i] is your row number in this circumstance.
So if you did something like:
function findCell() {
var ss = SpreadsheetApp.getActiveSpreadsheet();
var sheet = ss.getActiveSheet();
var dataRange = sheet.getDataRange();
var values = dataRange.getValues();
for (var i = 0; i < values.length; i++) {
var row = "";
for (var j = 0; j < values[i].length; j++) {
if (values[i][j] == "User") {
row = values[i][j+1];
Logger.log(row);
Logger.log(i); // This is your row number
}
}
}
}

Answer 2

This method finds the row number in a particular column for a given value:
function rowOf(containingValue, columnToLookInIndex, sheetIndex) {
var ss = SpreadsheetApp.getActiveSpreadsheet();
var sheet = ss.getSheets();
var dataRange = sheet[sheetIndex].getDataRange();
var values = dataRange.getValues();
var outRow;
for (var i = 0; i < values.length; i++)
{
if (values[i][columnToLookInIndex] == containingValue)
{
outRow = i+1;
break;
}
}
return outRow;
}
But if you do it like that, it won't refresh unless you change any of the parameters, that's because a custom function should be deterministic, that is, for the same parameters, it should always give the same result.
So instead, it's better to do it this way:
function rowOf(containingValue, range) {
var outRow = null;
if(range.constructor == Array)
{
for (var i = 0; i < range.length; i++)
{
if(range[i].constructor == Array && range[i].length > 0)
{
if (range[i][0] == containingValue)
{
outRow = i+1;
break;
}
}
}
}
return outRow;
}
In this case, you need to pass the full column range your looking for like so:
rowOf("MyTextToLookFor", 'MySheetToLookIn'!A1:A)
Where you would replace A by the colum of your choice, and MySheetToLookIn by your sheet's name and MyTextToLookFor by the text you are looking for.
This will allow it to refresh on adding rows and removing rows.

Answer 3

Since 2018 this can be done without a loop using flat().
function findRow(searchVal) {
var sheet = SpreadsheetApp.getActiveSheet();
var data = sheet.getDataRange().getValues();
var columnCount = sheet.getDataRange().getLastColumn();
var i = data.flat().indexOf(searchVal);
var columnIndex = i % columnCount
var rowIndex = ((i - columnIndex) / columnCount);
Logger.log({columnIndex, rowIndex }); // zero based row and column indexes of searchVal
return i >= 0 ? rowIndex + 1 : "searchVal not found";
}

Answer 4

ES6 gave us a one liner for this (but expanded for full detail).
function findRow() {
const ss = SpreadsheetApp.getActiveSpreadsheet();
const sheet = ss. getActiveSheet(); // OR GET DESIRED SHEET WITH .getSheetByName()
const dataRange = sheet.getDataRange();
const values = dataRange.getValues();
const columnIndex = 3 // INDEX OF COLUMN FOR COMPARISON CELL
const matchText = "User"
const index = values.findIndex(row => row[columnIndex] === matchText)
const rowNumber = index + 1
return rowNumber
}

Answer 5

This can be done with the Text Finder:
function findRow(searchValue){
var ss = SpreadsheetApp.getActiveSpreadsheet();
var thisSheet = ss.getActiveSheet();
var tf = thisSheet.createTextFinder(searchValue)
var thisRow = tf.findNext().getRow()
return thisRow
}
Discovered through this post: Google App Scripts find text in spreadsheet and return location index
Implementing: https://developers.google.com/apps-script/reference/spreadsheet/text-finder

Answer 6

To find a row in a Google Sheets sheet based on the value of a specific column (in this case, the invoice_id column) and edit another column (in this case, the send column) in that row, you can use the following script:
// Replace "Sheet1" with the name of your sheet
var sheet = SpreadsheetApp.getActive().getSheetByName("Sheet1");
// Replace "A" with the column letter for the invoice_id column
// and "B" with the column letter for the send column
var invoiceIdColumn = "A";
var sendColumn = "B";
// Replace "12345" with the invoice_id you want to search for
var invoiceIdToSearch = "12345";
// Find the row number of the row with the matching invoice_id
var data = sheet.getDataRange().getValues();
var row = data.findIndex(row => row[invoiceIdColumn - 1] == invoiceIdToSearch) + 1;
// If a row with the matching invoice_id was found
if (row) {
// Set the value of the send column in that row to "true"
sheet.getRange(row, sendColumn).setValue(true);
}
This script will search through the entire sheet for a row with an invoice_id value that matches the invoiceIdToSearch variable, and then set the value of the send column in that row to true.
Note that this script assumes that the invoice_id column is the first column in the sheet (column A) and the send column is the second column (column B). If your columns are in different positions, you will need to adjust the invoiceIdColumn and sendColumn variables accordingly.