Simplifying MySQL query - 2 queries into 1 - mysql

I have a table that looks like this:
+----+--------+-------+
| id | entity | word |
+----+--------+-------+
| 1 | 1 | red |
| 2 | 1 | green |
| 3 | 1 | blue |
| 4 | 2 | car |
| 5 | 2 | truck |
| 6 | 2 | train |
| 7 | 3 | water |
| 8 | 3 | milk |
| 9 | 3 | soda |
+----+--------+-------+
If I do a search for blue I would like to get red, green and blue as an answer. Right now I am using 2 queries. One to find the 'entity' number and one to find all the words with the same 'entity' number.

Try this. Join is much faster than subquery
select distinct t2.word from Table t1
INNER JOIN Table t2 on t2.entity=t1.entity
where t1.word="blue";

SELECT *
FROM TABLE_NAME
WHERE entity IN
(SELECT entity
FROM TABLE_NAME
WHERE word='blue');

Related

Does Cross Join not work between two different tables with same column name?

As written on the title, does CROSS JOIN not work for different tables with the same column name?
For example,
I have one table named Fruits:
| name | price |
| apple | 1 |
| banana | 2 |
and another table named Snacks:
| name | price |
| chips | 3 |
| cookies | 4 |
Then does
SELECT Fruits.price, Snacks.price FROM Fruits CROSS JOIN Snacks
does not work properly?
I am working on a same issue, but the result shows like:
| price | price |
| 3 | 3 |
| 4 | 4 |
| 3 | 3 |
| 4 | 4 |
But what I expect is:
| price | price |
| 1 | 3 |
| 1 | 4 |
| 2 | 3 |
| 2 | 4 |
As I mentioned in the comment, it is not possible. Either your tables values are different or your query.
Check this dbfiddle showing the result value same as your expected values.
In MySQL CROSS JOIN works as expected:
price price
------ -----
1 3
2 3
1 4
2 4
See running example at DB Fiddle.

Find unique/duplicated rows from has and belongs to many association

I have following DB structure:
Table cars:
+----+-----------------------+
| id | few other columns.... |
+----+-----------------------+
| 1 | ... |
| 2 | ... |
| 3 | ... |
+----+-----------------------+
Table properties:
+----+-------+
| id | name |
+----+-------+
| 1 | title |
| 2 | type |
| 3 | brand |
| 4 | color |
+----+-------+
Table cars_properties:
+----+--------+-------------+------------+
| id | car_id | property_id | txt |
+----+--------+-------------+------------+
| 1 | 1 | 1 | Volvo V70 |
| 2 | 1 | 2 | personal |
| 3 | 1 | 3 | Volvo |
| 4 | 1 | 4 | white |
| 5 | 2 | 1 | Volvo VV |
| 6 | 2 | 2 | personal |
| 7 | 2 | 3 | Volvo |
| 8 | 2 | 4 | blue |
| 9 | 3 | 1 | Volvo XXL |
| 10 | 3 | 2 | truck |
| 11 | 3 | 3 | Volvo |
| 12 | 3 | 4 | white |
+----+--------+-------------+------------+
I would like to get all cars that have unique/duplicated values in one or many properties. Currently I'm using this SQL pattern to get duplicates for car type and brand:
SELECT cars.id FROM cars
LEFT JOIN cars_properties AS cp_0 ON cp_0.car_id = cars.id AND cp_0.property_id = 2 # => type
LEFT JOIN cars_properties AS cp_1 ON cp_1.car_id = cars.id AND cp_1.property_id = 3 # => brand
INNER JOIN (
SELECT cp_0.txt AS type_txt, cp_1.txt AS brand_txt FROM cars
LEFT JOIN cars_properties AS cp_0 ON cp_0.car_id = cars.id AND cp_0.property_id = 2
LEFT JOIN cars_properties AS cp_1 ON cp_1.car_id = cars.id AND cp_1.property_id = 3
GROUP BY cp_0.txt, cp_1.txt
HAVING COUNT(cars.id) > 1
) dupes ON cp_0.txt=dupes.type_txt AND cp_1.txt=dupes.brand_txt;
And expected result is:
+----+
| id |
+----+
| 1 |
| 2 |
+----+
Explanation: Both cars with id = 1 and 2 has type and brand that is present in more than one car (multiple times).
As for unique cars, I'm just altering: HAVING COUNT(cars.id) = 1 and I want to find all rows where the combination of properties is present only in one car (once).
It works fine, but it's extremely slow with more than 2 properties I want to check.
I cannot change the DB structure, and I'm not sure how to optimize the query, or if there are better ways of achieving this.
It feels like I would need to implement counter table, where each property id and value (txt) would also store corresponding number of occurrences in cars, and update this counter on every insert/update/delete... But I still hope there is some better SQL, that could help. Do you know some? Any advice greatly appreciated, thanks!
PS: I tried to create fiddle for it, but after I build schema I cannot run any SQL on it. To quickly setup DB with data, you can check SQL Fiddle

Inner Join not working after two rows?

Here is my query and it's not showing the 3rd row even though the tables contents match.
SELECT shopcategory_idcategory_name
FROM shopcategory
INNER JOIN category ON shopcategory_id=category_id;
Result:
================================================================
| shopcategory_id | shopcategory_shopid | category_name |
================================================================
| 1 | 1 | Gadgets |
| 2 | 2 | Analog Device |
================================================================
Here is my query that shows it has 3 rows
SELECT * FROM shopcategory;
Result:
===================================================================
| shopcategory_id | shopcategory_shopid | shopcategory_categoryid |
===================================================================
| 1 | 1 | 1 |
| 2 | 2 | 2 |
| 3 | 3 | 3 |
===================================================================
EDIT: Query for my category table
SELECT * category;
Result:
==============================================
| category_id | category_name |
==============================================
| 1 | Gadgets |
| 2 | Analog Device |
| 3 | Beauty |
| 4 | Keyboard |
| 5 | Instruments |
| 6 | Monitor |
| 7 | Chairs |
==============================================
You should use LEFT JOIN here instead and add aliases for tables that you are joining on, like this:
SELECT
tableName1.shopcategory_id,
tableName1.category_name,
tableName2.category_id
FROM
tableName1 as tb1
LEFT JOIN
tableName2 AS tb2
ON
tb1.shopcategory_id = tb2.category_id
GROUP BY
tb1.shopcategory_id;

What happens if I select two tables with no WHERE clause?

I had a technical interview last week, and my interviewer asked me what happens if I run the following query:
SELECT * FROM tbl1, tbl2
I think I answered it correctly, but it wasn't an in-depth answer.
I said that I would select all the columns in both tables. For example if tbl1 has 3 columns, and tbl2 has 4 columns. The result set would have 7 columns.
Then he asked me why 7? and I said because I was selecting everything from each table.
That was a bad answer, but I couldn't think of anything else.
To cut to the chase, after the interviewed I executed the latter statement using two tables.
Table A, had 3 animal: dog, cat and elephant.
Table B had 2 names: Mat and Beth
This is the result set that I got after the statement being executed:
*********************************************
| id_tbl1 | name_tbl1 | id_tbl2 | name_tbl2 |
*********************************************
| 1 | dog | 1 | Mat |
| 2 | cat | 1 | Mat |
| 3 | elephant | 1 | Mat |
| 1 | dog | 2 | Beth |
| 2 | cat | 2 | Beth |
| 3 | elephant | 2 | Beth |
*********************************************
So my question is, why does the statement behaves like that?
In other words:
Why does the Table B's records repeat themselves until I reach the end of table A, and then it starts all over again?
How would you have answered the question in a way that it would've "WOW'd" the interviewer?
If this question does not belong to SO, feel free to delete it or close it!
If you do a select like this, all rows in one resultset are joined to all rows in the other resultset (Cartesian Product).
So you get a list of all rows of the first table with the first row of the second table, Then all entries for the second row and so on. The order may be an implementation detail. Not sure if it is defined that the first order is by the first table, it might be different across implementations.
If you join three tables (or more), then the same happens with all rows of all tables. This, of course, is not only for tables, but for any result set from joins.
The result will be a cartisian product
take a look at this example
SQL Example
You can see there are two tables one has 5 records and the other has 4 and the result is 20 records. Means 5 * 4 = 20 instead of 5 + 4 = 9 as you are assuming.
Table1
| IDX | VAL |
---------------
| 1 | 1val1 |
| 1 | 1val2 |
| 2 | 2val1 |
| 2 | 2val2 |
| 2 | 2val3 |
Table2
| ID | POINTS |
---------------
| 1 | 2 |
| 2 | 10 |
| 3 | 21 |
| 4 | 29 |
Result of below query
SELECT * FROM Table1 , Table2
| IDX | VAL | ID | POINTS |
-----------------------------
| 1 | 1val1 | 1 | 2 |
| 1 | 1val1 | 2 | 10 |
| 1 | 1val1 | 3 | 21 |
| 1 | 1val1 | 4 | 29 |
| 1 | 1val2 | 1 | 2 |
| 1 | 1val2 | 2 | 10 |
| 1 | 1val2 | 3 | 21 |
| 1 | 1val2 | 4 | 29 |
| 2 | 2val1 | 1 | 2 |
| 2 | 2val1 | 2 | 10 |
| 2 | 2val1 | 3 | 21 |
| 2 | 2val1 | 4 | 29 |
| 2 | 2val2 | 1 | 2 |
| 2 | 2val2 | 2 | 10 |
| 2 | 2val2 | 3 | 21 |
| 2 | 2val2 | 4 | 29 |
| 2 | 2val3 | 1 | 2 |
| 2 | 2val3 | 2 | 10 |
| 2 | 2val3 | 3 | 21 |
| 2 | 2val3 | 4 | 29 |
I think you are confusing yourself by running an example with two tables that have identical fields. You are referring to a Union, which will combine the values of 1 table with another, and using your example this would give you 3 + 4 = 7 results.
The comma separated FROM statement is doing JOIN, which will go through all values in Table X and pair them with all the values of Table Y. This would result in Size of X * Size of Y results, and using your example this would be 3 * 4 = 12.

Counting from another table [mysql]

I have one table like this:
+----+---------+-------------+
| id | site_id | search_term |
+----+---------+-------------+
| 1 | 2 | apple |
| 2 | 2 | banana |
| 3 | 3 | cheese |
| 4 | 1 | aubergine |
+----+---------+-------------+
And another like this:
+----+---------+-------------+
| id | site_id | search_term |
+----+---------+-------------+
| 1 | 2 | 1 |
| 2 | 2 | 2 |
| 3 | 2 | 1 |
| 4 | 2 | 1 |
| 5 | 3 | 3 |
| 6 | 1 | 4 |
+----+---------+-------------+
I want to find out how many times each search_term shows up in the 2nd table, and how many times.
In other words, from this data, if I was asking about site_id 2, I'd want this to be returned:
+-------------+-------+
| search_term | count |
+-------------+-------+
| apple | 3 |
| banana | 1 |
+-------------+-------+
I'm familiar with basic joins and such, as well as COUNT, but I'm not sure how to count things from another table.
Thanks!
You could join the tables together, and count the number of rows in the second table:
select t1.search_term
, count(t2.id)
from table1 t1
left join table2 t2
on t1.id = t2.search_term
group by t1.search_term
Give this a try:
select t1.search_term, count(*) from t1
join t2 on t1.id = t2.search_term and t1.site_id = t2.site_id
where t1.site_id = 2
group by t1.search_term