Merge two colums, multiple rows ignoring duplicates - MySQL - mysql

This is, maybe, a stupid question. Not for me: honestly, I'm not so skilled with MySql queries so I'm looking for a little help.
I have a table:
id | type_a | type_b |
__________________________________________________
1 | *color_1*color_2*color_3*| *color_1* |
2 | *color_3* | *color_3*color_2*|
3 | *color_2*color_3* | *color_4* |
4 | *color_1*color_3*color_4*| |
5 | *color_4* | *color_5* |
__________________________________________________
I would like to move "type_b" column content in "type_a" column ignoring duplicate fields (delimited by * and *, ex: color_1. This kind of storage is builded by a Joomla component).
I would like to have this final result:
id | type_a | type_b |
_________________________________________
1 | *color_1*color_2*color_3*| |
2 | *color_3*color_2* | |
3 | *color_2*color_3*color_4*| |
4 | *color_1*color_3*color_4*| |
5 | *color_4*color_5* | |
_________________________________________
What's the best way to accomplish something similar?
Thanks to all!

You could do it with this statement (no, it's not looking nice), assuming the name of your table is example:
UPDATE
example e1
SET
e1.type_a = (
SELECT
CONCAT('*', GROUP_CONCAT(DISTINCT n1.value ORDER BY n1.value SEPARATOR '*'), '*') as type_a
FROM (
SELECT
id,
CASE
WHEN SUBSTRING_INDEX(SUBSTRING_INDEX(TRIM(BOTH '*' FROM e.type_a), '*', n.n), '*', -1) = '' THEN NULL
ELSE SUBSTRING_INDEX(SUBSTRING_INDEX(TRIM(BOTH '*' FROM e.type_a), '*', n.n), '*', -1)
END value
FROM example e CROSS JOIN (
SELECT
a.N + b.N * 10 + 1 AS n
FROM
(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) a
,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) b
ORDER BY n
) n
WHERE
n.n <= 1 + (LENGTH(e.type_a) - LENGTH(REPLACE(e.type_a, '*', '')))
UNION
SELECT
id,
CASE
WHEN SUBSTRING_INDEX(SUBSTRING_INDEX(TRIM(BOTH '*' FROM e.type_b), '*', n.n), '*', -1) = '' THEN NULL
ELSE SUBSTRING_INDEX(SUBSTRING_INDEX(TRIM(BOTH '*' FROM e.type_b), '*', n.n), '*', -1)
END value
FROM example e CROSS JOIN (
SELECT
a.N + b.N * 10 + 1 AS n
FROM
(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) a
,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) b
ORDER BY n
) n
WHERE
n.n <= 1 + (LENGTH(e.type_b) - LENGTH(REPLACE(e.type_b, '*', '')))
) n1
WHERE
n1.id = e1.id
GROUP BY
id
),
e1.type_b = ''
;
Demo of the SELECT statement
Explanation
Basically I adapted the method of peterm to get the split done. I had to remove the outer * first by TRIM.
To allow the empty string as column value, I've added the CASE construct, to eliminate such values. If your column has NULL values instead, you could substitute the CASE by
SUBSTRING_INDEX(SUBSTRING_INDEX(TRIM(BOTH '*' FROM e.type_a), '*', n.n), '*', -1)
and
SUBSTRING_INDEX(SUBSTRING_INDEX(TRIM(BOTH '*' FROM e.type_a), '*', n.n), '*', -1)
The UNION (without the ALL keyword) of this construct will give us the list of distinct color values and with GROUP BY id and GROUP_CONCAT we'll get the * separated value list. Last we add a leading and a trailing * to match your requirements.
For the update you've got to modificate the select, so that it returns just one column with one row (with the where clause).
Note
As stated by peterm this will allow up to 100 values in your value list. I don't believe you will need more, but if you will, then you've got to adapt the generating of the numbers up to your needs.

Related

How to split string token and group by count them in mysql?

How to split the string and grouping them by splited token?
I want to get that grouping splited token's each count.
I have a varchar column and it store a string which can split by ',' .
below is the row data of the column. (column name is LogData)
[LogData]
1,2,3,4
1,3,1,9
2,1,3
6,2
And then i want to show(select) like below.
[token] [count]
1 : 4
2 : 3
3 : 3
4 : 1
6 : 1
9 : 1
If possible, then may i have a answer about this with some explanation? (I'm not skilled in db)
Using the and adapting the comment from undefined_variable the correct query looks like this:
SELECT value,COUNT(*) FROM
(SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(t0.logdata, ',', n.n), ',', -1) value
FROM t0 CROSS JOIN
(
SELECT a.N + b.N * 10 + 1 n
FROM
(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) a
,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) b
ORDER BY n
) n
WHERE n.n <= 1 + (LENGTH(t0.logdata) - LENGTH(REPLACE(t0.logdata, ',', '')))
ORDER BY value) nt0 GROUP BY value

Mysql - Convert String Array into multiple rows of a table [duplicate]

I want to a MySQL query to select the records separately from following table
ID AgentID Name Return Date
1 1,2,3 A 2016-05-22,2016-02-1,2016-1-15
2 2,4 B 2016-03-22,2016-04-1
Expecting Answer
ID AgentID Name Return Date
1 1 A 2016-05-22
1 2 A 2016-02-1
1 3 A 2016-1-15
2 2 B 2016-03-22
2 4 B 2016-04-1
You can use MySQL SUBSTRING_INDEX(). It will return the sub-string from the given comma separated string before a specified number of occurrences of the delimiter.
Try this, It seems to work fine:
SELECT ID
,SUBSTRING_INDEX(SUBSTRING_INDEX(t.AgentID, ',', n.n), ',', -1) Agent
,Name
,SUBSTRING_INDEX(SUBSTRING_INDEX(t.Return_Date, ',', n.n), ',', -1) Return_Date
FROM table1 t CROSS JOIN
(
SELECT a.N + b.N * 10 + 1 n
FROM
(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) a
,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) b
ORDER BY n
) n
WHERE n.n <= 1 + (LENGTH(t.Return_Date) - LENGTH(REPLACE(t.Return_Date, ',', '')))
ORDER BY ID;
Check this..
SQL Fiddle HERE
For further Study go on MySQL Split String Function
if your values in tblA and you want to insert into tblB than query like this
insert into tblB (date) select date from tblA;
INSERT INTO second_table (
Field_1,
Field_2,
Field_3)
SELECT Field_1,
Field_2,
Field_3
FROM first_table;

How to retrieve multiple data that store inside the same database column?

My database is like
Name | IC | Item
--------------------------
lee | xxx | pear,bear
--------------------------
ron | xxx | apple,dog
what should I do to retrieve the 4 values contained in the column "Item" and then separate them?
Do you have only two items separated by comma in Item? Or it may vary?
LE: you can use this SQL split comma separated row
LLE: just played around with that and this what I've done:
create table myTable(name varchar(7), ic varchar(7), item varchar(200));
insert into myTable(name,ic,item) values ('lee','xxx','pear,bear');
insert into myTable(name,ic,item) values ('ron','xxx','apple,dog');
insert into myTable(name,ic,item) values ('a','xxx','gamma');
insert into myTable(name,ic,item) values ('b','xxx','a,b,c,d');
SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(t.item, ',', n.n), ',', -1) value
FROM myTable t CROSS JOIN
(
SELECT a.N + b.N * 10 + 1 n
FROM
(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) a
,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) b
ORDER BY n
) n
WHERE n.n <= 1 + (LENGTH(t.item) - LENGTH(REPLACE(t.item, ',', '')))
ORDER BY value;

How to count occurences in comma separated column?

Question table:
id | tags
--------------------------------------
1 | css,javascript,html
2 | mysql,sql,html
3 | css,spring,php
4 | css,java,html
I am trying to figure out how to return the number of times a string occurs in each of the tags's.
Result Table:
tags | count
--------------------------------------
css | 3
html | 3
javascript | 1
php | 1
You can use:
SqlFiddleDemo
SELECT sub.val AS tags, COUNT(*) AS `count`
FROM
(
SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(t.tags, ',', n.n), ',', -1) AS val
FROM tab t
CROSS JOIN
(
SELECT a.N + b.N * 10 + 1 n
FROM
(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) a
,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) b
ORDER BY n
) n
WHERE n.n <= 1 + (LENGTH(t.tags) - LENGTH(REPLACE(t.tags, ',', '')))
) sub
GROUP BY sub.val
You can simply try like this:
SELECT COUNT(*) FROM my_table WHERE tags like '%css%';
SELECT COUNT(*) FROM my_table WHERE tags like '%html%';
SELECT COUNT(*) FROM my_table WHERE tags like '%javascript%';
SELECT COUNT(*) FROM my_table WHERE tags like '%php%';
One other way is to use it like this:
(LENGTH(`tags`) - LENGTH(REPLACE(`tags`, 'searchword', '')))/LENGTH('searchword')

SQL split comma separated row [duplicate]

This question already has answers here:
MySQL: Split comma separated list into multiple rows
(4 answers)
Closed 9 years ago.
I have a column with a variable number of comma seperated values:
somethingA,somethingB,somethingC
somethingElseA, somethingElseB
And I want the result to take each value, and create a row:
somethingA
somethingB
somethingC
somethingElseA
somethingElseB
How can I do this in SQL (MySQL)?
(I've tried googling "implode" and "lateral view", but those don't seem to turn up related questions. All the related SO questions are trying to do much more complicated things)
You can do it with pure SQL like this
SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(t.values, ',', n.n), ',', -1) value
FROM table1 t CROSS JOIN
(
SELECT a.N + b.N * 10 + 1 n
FROM
(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) a
,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) b
ORDER BY n
) n
WHERE n.n <= 1 + (LENGTH(t.values) - LENGTH(REPLACE(t.values, ',', '')))
ORDER BY value
Note: The trick is to leverage tally(numbers) table and a very handy in this case MySQL function SUBSTRING_INDEX(). If you do a lot of such queries (splitting) then you might consider to populate and use a persisted tally table instead of generating it on fly with a subquery like in this example. The subquery in this example generates a sequence of numbers from 1 to 100 effectively allowing you split up to 100 delimited values per row in source table. If you need more or less you can easily adjust it.
Output:
| VALUE |
|----------------|
| somethingA |
| somethingB |
| somethingC |
| somethingElseA |
| somethingElseB |
Here is SQLFiddle demo
This is how the query might look with a persisted tally table
SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(t.values, ',', n.n), ',', -1) value
FROM table1 t CROSS JOIN tally n
WHERE n.n <= 1 + (LENGTH(t.values) - LENGTH(REPLACE(t.values, ',', '')))
ORDER BY value
Here is SQLFiddle demo