table_store
store_id title slug
1 Jabong jabong
2 Amazon amazon
table_coupon
coupon_id title store_id
1 Now 50% Off 1
2 New 2020 Sale 2
table_tag
tag_id title priority
1 Latest 5
2 Trending 4
3 Hot 3
table_tag_bind
id tag_id main_id(is coupon_id)
1 1 1
2 1 2
3 2 1
How can i list the products related to store based on tag priority. But dont repeat the same product if it has more than 1 tag. higher the number more tha priority:
my query: please what is wrong in this query?
SELECT DISTINCT(t1.`coupon_id`), t1.`title`
FROM `coupon` AS t1
LEFT JOIN `tag_bind` AS t2 ON t1.coupon_id = t2.main_id
LEFT JOIN `tag` AS t3 ON t3.id = t2.tag_id
WHERE t1.`store_id`='1'
ORDER BY t3.`priority` DESC
You want to order rows in coupons based on their maximum priority in table tag. I would suggest using a correlated subquery for ordering; this seems to me like the simplest way to phrase your requirement:
select c.coupon_id, c.title
from coupon as c
where c.store_id = 1
order by (
select max(t.priority)
from tag_bind tg
inner join tag t on t.id = tg.tag_id
where tg.main_id = c.coupon_id
) desc
Im trying to get a combination of ids from a table like this:
Table activation:
user_id product_id reseller_id range_id Name
-------------------------------------------------
1 1 5 2 Oscar
1 1 5 3 Luis
2 1 5 4 Julian
Table prices (compType_id = reseller_id):
product_id compType_id price range_id
------------------------------------------------
1 5 38.60 2
1 5 48.60 3
1 5 58.60 4
Table users:
user_id name
----------------
1 lloyd
2 Mark
I want to select the activation Name and the price of prices based on the user_id.
How can i do that?
I tried something like this:
SELECT a.name
(SELECT price FROM prices WHERE product_id = 1 AND range_id =
AND compType_id = 5) AS price
FROM activation AS a
LEFT JOIN users AS u ON u.user_id = a.u_id
WHERE u.user_id = 1
The price columns have the same value in each row.
name price
Oscar 21.30
Luis 21.30
How can i change it to show the correct price?
I solved it with something like this:
SELECT a.company, a.name, a.email, a.phone, a.ruc, a.code, a.active,
a.numlic, (SELECT p.price FROM prices AS p WHERE p.product_id =
a.product_id AND p.range_id = a.range_id AND p.compType_id = c.type_id)
AS price
FROM activation AS a
LEFT JOIN users AS u ON u.user_id = a.u_id
LEFT JOIN companies AS c ON a.reseller_id = c.id
WHERE u.user_id = 1
As I am not good with MySQL query's so I wish someone help me for creating this kind of sql query.
I having two MySQL tables which is describe bellow:
Table Name: rating
-------------------
property_id user_id area_rate_count safety_rate_count friendly_rate_count walkability_rate_count
4 28 1 1 1 2
5 38 2 3 4 1
5 40 2 2 3 1
6 40 2 3 1 4
10 43 2 2 3 1
Table Name: listing
-------------------
property_id title
4 Sample 1
5 Sample 2
6 Sample 3
10 Sample 4
11 Sample 5
12 Sample 6
Now first I want to sum each column and divide. (area_rate_count, safety_rate_count, friendly_rate_count, walkability_rate_count). For example In property_id:5 having two times so first calculate column sum and divide by 2.
After calculation we will get this output:
Table Name: rating (After Calculation)
--------------------------------------
property_id rate
4 5
5 9 (Divided by 2 because this property_id is two times in table)
6 10
10 8
And Finally I want join this result to my listing table and result looks something like this:
Table Name: listing
-------------------
property_id title rate
4 Sample 1 5
5 Sample 2 9 (Divided by 2 becouse property_id is two times in table)
6 Sample 3 10
10 Sample 4 8
11 Sample 5 0
12 Sample 6 0
Thanks.
I think you want the avg() aggregation function along with a join:
select l.property_id, l.title,
coalesce(avg(area_rate_count + safety_rate_count + friendly_rate_count + walkability_rate_count
), 0) as rate
from listing l left outer join
property_id p
on l.property_id = p.property_id
group by l.property_id, l.title ;
If I understood it right I think you need this:
select l.property_id, l.title, coalesce(r.ssum/if(r.ct=0,1,r.ct), 0) as rate
from listing l LEFT JOIN
(select property_id,
sum(area_rate_count+safety_rate_count
+friendly_rate_count+walkability_rate_count) ssum,
count(*) ct
from rating
group by property_id ) r
ON l.property_id = r.property_id
order by l.property_id
See it here on fiddle: http://sqlfiddle.com/#!2/589d6/5
Edit
As OP asked on the comments that he wants all columns from listing here is what he want:
select l.*, coalesce(r.ssum/if(r.ct=0,1,r.ct), 0) as rate
from listing l LEFT JOIN
(select property_id,
sum(area_rate_count+safety_rate_count
+friendly_rate_count+walkability_rate_count) ssum,
count(*) ct
from rating
group by property_id ) r
ON l.property_id = r.property_id
order by l.property_id
CREATE TEMPORARY TABLE IF NOT EXISTS
temp_table ( INDEX(col_2) )
ENGINE=MyISAM
AS (
SELECT
property_id,
AVG(area_rate_count) as area_rate_count,
AVG(safety_rate_count) as safety_rate_count,
AVG(friendly_rate_count) as friendly_rate_count,
AVG(walkability_rate_count) as walkability_rate_count
FROM rating
GROUP BY property_id
)
SELECT * FROM listing L
JOIN temp_table T
ON L.property_id = T.property_id
Use the below statement to get distinct property_id with its own rate
select property_id, sum(separaterating)/count(property_id) from (
select property_id,sum(area_rate_count , safety_rate_count , friendly_rate_count , walkability_rate_count) as separaterating from rating group by property_id AS temp ) group by
property_id
you can then join with the other table to get the final result as below
select * from ( select property_id, sum(separaterating)/count(property_id) from (
select property_id,sum(area_rate_count , safety_rate_count , friendly_rate_count , walkability_rate_count) as separaterating from rating group by property_id AS temp ) group by
property_id) AS A inner join listing AS B on A.property_id = B.property_id
try this:
select a.prop_id as property_id, l.title, a.allratings / b.numberofreviews as rate
from
(
select property_id as prop_id, SUM(coalesce(area_rate_count,0) + coalesce(safety_rate_count,0) + coalesce(friendly_rate_count,0) + coalesce(walkability_rate_count,0)) as allratings
from rating
group by property_id
) a inner join
(
select property_id, count(distinct user_id) as numberofreviews
from rating
group by property_id
) b on a.property_id = b.property_id
inner join listing l on a.property_id = l.property_id
Try This Query
select ls.property_id,ls.title,inr.rate from listing as ls
left join
(select r.property_id as pid,r.rate/r.cnt as rate from
(select property_id,user_id,(area_rate_count+safefty_rate_count+friendly_rate_count+walkability_rate_count) as rate,count(*) as cnt from rating group by property_id) as r) as inr on inr.pid=ls.property_id
Ok I have siple table which contains data:
id cat_id title (with random values)
1 1 test
2 1 tstt
3 3 tewt
4 2 4324
5 3 rterter
Now, I need to create a query which selects only ONE raw per category (cat_id)
(possibly with lowest ID and ordered by cat_id)
So the result should be:
1 1 test
4 2 4324
3 3 tewt
Use GROUP BY :
SELECT MIN(id), cat_id, title FROM table GROUP BY cat_id
SELECT a.*
FROM tableName a
INNER JOIN
(
SELECT cat_id, MIN(id) id
FROM tableName
GROUP BY cat_id
) b ON a.cat_id = b.cat_id AND
a.id = b.id
ORDER BY a.cat_id
I've got a budget table:
user_id product_id budget created
-----------------------------------------------------------------
1 1 300 2011-12-01
2 1 400 2011-12-01
1 1 500 2011-12-03
2 2 400 2011-12-04
I've also got a manager_user table, joining a manager with the user
user_id manager_id product_id
------------------------------------
1 5 1
1 9 2
2 5 1
2 5 2
3 5 1
What I'd like to do is grab each of the user that's assigned to Manager #5, and also get their 'budgets'... but only the most recent one.
Right now my statement looks like this:
SELECT * FROM manager_user mu
LEFT JOIN budget b
ON b.user_id = mu.user_id AND b.product_id = mu.product_id
WHERE mu.manager_id = 5
GROUP BY mu.user_id, mu.product_id
ORDER BY b.created DESC;
The problem is it doesn't pull the most recent budget. Any suggestions? Thanks!
To accomplish your task you can do as follows:
select b1.user_id,
b1.budget
from budget b1 inner join (
select b.user_id,
b.product_id,
max(created) lastdate
from budget b
group by b.user_id, b.product_id ) q
on b1.user_id=q.user_id and
b1.product_id=q.product_id and
b1.created=q.lastdate
where b1.user_id in
(select user_id from manager_user where manager_id = 5);
I'm assuming here that your (user_id, product_id, created) combination is unique.
For what it's worth, here's the code that returned what I was looking for:
SELECT DISTINCT(b1.id),mu.user_id,mu.product_id,b1.budget,b1.created
FROM budget b1
INNER JOIN (
SELECT b.user_id, b.product_id, MAX(created) lastdate
FROM budget b
GROUP BY b.user_id, b.product_id) q
ON b1.user_id=q.user_id AND
b1.product_id=q.product_id AND
b1.created=q.lastdate
RIGHT JOIN manager_user mu
ON mu.user_id = b1.user_id AND
mu.product_id = b1.product_id
WHERE mu.manager_id = 5;
Thanks for the help Andrea!