Create INTERSECT query in MySQL - mysql

Question

I have a tables
ppv (product_id | property_id | value_id)
and
v (id | property_id | value)
I try to make query to get products where:
select product_id from v, ppv as t INNER JOIN ppv as t2
ON t.product_id = t2.product_id and t1.property_id = t2.property_id
where
( t1.property_id = 1 and v.value > $a and v.value < $b )
and
( t2.property_id = 2 and v.value > $c and v.value < $d )
But havn`t any results. Please help.
So,
ppv (product_id | property_id | value_id)
1 1 50
1 2 2
1 3 3
2 1 28
2 2 2
2 3 29
Next table
v( id | property_id | value)
2 2 3
3 3 2
28 1 2600000
29 3 3
50 1 2500000
** I found a solution to this problem in this way **
SELECT `product_id`,
CONVERT(GROUP_CONCAT(v.`property_id`) USING cp1251) as properties
FROM `values` as v INNER JOIN `product_property_values` as ppv
ON ppv.value_id = v.id
WHERE
(v.`property_id` = 1 and v.value >= 2500000 and v.value <= 3000000 )
or
(v.`property_id` = 2 and v.value >= 1 and v.value <= 3 )
GROUP by product_id
HAVING LOCATE('1', properties) and LOCATE('2', properties)
Th result:
test 1
v.`property_id` = 1 and v.value >= 2500000 and v.value < 3000000
v.`property_id` = 2 and v.value >= 1 and v.value <= 2
product_id properties
Empty
test2
v.`property_id` = 1 and v.value >= 2550000 and v.value < 3000000
v.`property_id` = 2 and v.value >= 1 and v.value <= 4
product_id properties
2 2,1
test3
v.`property_id` = 1 and v.value >= 2000000 and v.value < 3000000
v.`property_id` = 2 and v.value >= 1 and v.value <= 4
product_id properties
1 1,2
2 2,1
It's OK!

Answer 1

It doesn't look like you are actually joining table v. Also, I don't believe it is necessary to link to ppv twice. Try:
SELECT ppv.product_id
FROM v
INNER JOIN ppv ON v.property_id = ppv.property_id
WHERE
(ppv.property_id = 1 and v.value > $a and v.value < $b )
OR
(ppv.property_id = 2 and v.value > $c and v.value < $d )

Answer 2

First problem: what is t1 ?
Second problem:
t1.property_id = t2.property_id
t1.property_id = 1
t2.property_id = 2
Which means : 1 = 2.
If I understand well, you're looking for products which have :
a property_id = 1 set
a property_id = 2 set
a value superior to $a if property_id = 1 exists
a value superior to $c if property_id = 2 exists
a value inferior to $b if property_id = 1 exists
a value inferior to $d if property_id = 2 exists
I think you're looking for this request :
SELECT product_id
FROM v
JOIN ppv as t1 ON v.product_id = t1.product_id AND t1.property_id = 1
JOIN ppv as t2 ON v.product_id = t2.product_id AND t2.property_id = 2
WHERE v.value > GREATEST($a, $c)
AND v.value < LEAST($b, $d)

Answer 3

SELECT `product_id`,
CONVERT(GROUP_CONCAT(v.`property_id`) USING cp1251) as properties
FROM `values` as v INNER JOIN `product_property_values` as ppv
ON ppv.value_id = v.id
WHERE
(v.`property_id` = 1 and v.value >= 2500000 and v.value <= 3000000 )
or
(v.`property_id` = 2 and v.value >= 1 and v.value <= 3 )
GROUP by product_id
HAVING LOCATE('1', properties) and LOCATE('2', properties)
Th result:
test 1
v.`property_id` = 1 and v.value >= 2500000 and v.value < 3000000
v.`property_id` = 2 and v.value >= 1 and v.value <= 2
product_id properties
Empty
test2
v.`property_id` = 1 and v.value >= 2550000 and v.value < 3000000
v.`property_id` = 2 and v.value >= 1 and v.value <= 4
product_id properties
2 2,1
test3
v.`property_id` = 1 and v.value >= 2000000 and v.value < 3000000
v.`property_id` = 2 and v.value >= 1 and v.value <= 4
product_id properties
1 1,2
2 2,1
It's OK!