here's the problem
I need to fetch rows from my table where date created is less than 24 hours ago and ORDER them by likes and then UNION them with the rest of rows in the same table but I want the remaining rows to be ORDERED by date created.
in other words I need separate ORDER BY clause for each SELECT.
to be more clear, it's something like this:
SELECT *
FROM (SELECT *
FROM 'table'
WHERE 'date_created' > timestampadd(hour, -24, now())
ORDER BY 'likes' DESC
UNION
SELECT *
FROM 'table'
WHERE
ORDER BY date_created DESC ) AS Results
LIMIT 10 OFFSET 0
thanks for this awesome community :)
Try this:
SELECT *, (date_created > timestampadd(hour, -24, now()) AS recent
FROM table
ORDER BY recent DESC, IF(recent, likes, 0) DESC, IF(!recent, date_created, 0) DESC
LIMIT 10 OFFSET 0
Related
I have a table with some events like this
id----------title-----------date-------------status
1-----------birthday-------2018-03-12--------1
2-----------match----------2018-03-13--------2
3-----------anniversary----2018-03-10--------1
4-----------trip-----------2018-03-15--------1
5-----------birthday-------2018-03-17--------2
6-----------birthday-------2018-03-11--------1
Expected Result
id----------title-----------date-------------status
1-----------birthday-------2018-03-12--------1
4-----------trip-----------2018-03-15--------1
5-----------birthday-------2018-03-17--------2
2-----------match----------2018-03-13--------2
6-----------birthday-------2018-03-11--------1
3-----------anniversary----2018-03-10--------1
I need to query it like the first rows which have dates greater than today with status 1 should appear first and then the rest in desc.
Suppose today is 2018-03-11 then row with id 1 should appear first and then the rest of the rows is desc order
This is what I have tried so far
SELECT *
FROM events
ORDER BY (date > CURDATE() and status = 1) asc,
date desc
You can use multiple keys in an order by:
order by (date >= curdate() and status = 1) desc,
date desc
I believe your SQL should be something like this but is hard to say without expected results.
Query
SELECT
*
FROM
[table]
WHERE
date > CURDATE()
AND
status = 1
ORDER BY
date ASC
LIMIT 1
UNION
SELECT
*
FROM
[table]
WHERE
id NOT IN (
SELECT
id
FROM
[table]
WHERE
date > CURDATE()
AND
status = 1
LIMIT 1
)
AND
date > CURDATE()
ORDER BY
date DESC
I need to select 40 rows with date from today and 10 records with older date, ordered by date.
If MySQL supported negative offset, it would look like this:
SELECT * FROM `mytable` WHERE `date` >= '2013-10-29' ORDER BY date LIMIT -10, 40;
Negative offset is not supported. How can I solve the problem? Thanks!!!
Use UNION to combine two queries:
(
SELECT *
FROM mytable
WHERE date < '2013-10-29'
ORDER BY date DESC
LIMIT 10
) UNION ALL (
SELECT *
FROM mytable
WHERE date >= '2013-10-29'
ORDER BY date
LIMIT 40
)
ORDER BY date -- if results need to be sorted
I have a table which has 3 columns. (day, month and year)
This statement gives results in chronological order.
SELECT * FROM table WHERE = 'condition' ORDER BY year, month, day
How can I get it in the inverse order?
You need to invert your sort order in your query:
SELECT * FROM table WHERE = 'condition' ORDER BY year DESC, month DESC, day DESC
Having separate columns for year, month, and day is counter-productive, though, as all of these could be represented in a singular DATE type column. This can be indexed and is much faster in practice:
SELECT * FROM table WHERE ... ORDER BY date_column DESC
Try this:
SELECT * FROM table
WHERE = 'condition'
ORDER BY year DESC, month DESC, day DESC
You can use the ASC or DESC keywords.
https://dev.mysql.com/doc/refman/5.0/en/order-by-optimization.html
For example:
SELECT *
FROM table WHERE = 'condition'
ORDER BY year DESC,
month DESC,
day DESC
I want to show the last 10 lines of a table ordered by date added ascending.
I know I can select count(*) as total from tableName and $offset = 10 - total then select * from tableName order by dateadded asc limit 10 offset $offset
NOTE: I need the results to be displayed in reverse, oldest at the top, newest at the bottom therefore simply ordering by desc does not produce what i need
Can this be done in one query?
Just order DESC...
SELECT *
FROM tableName
order by dateadded DESC
Limit 10
To swap the order of the results
SELECT *
FROM (
SELECT *
FROM tableName
order by dateadded DESC
Limit 10
) r
ORDER BY dateadded
I am collecting data every five minutes and entering it into a MySQL database. I would like to extract the most recent row that's over 2 hours old, followed by over 1 hour old, followed by the most recent row.
I was thinking something along the lines of the following, but I think this will get me the last row of each hour. Meaning if I run the query at 8:05 I might get back rows from 6:57, 7:57 and 8:02, the last 2 of which are much less than an hour apart.
SELECT *
FROM (
SELECT *
FROM mytable
ORDER BY Date DESC
GROUP BY HOUR(Date) LIMIT 3
) x
ORDER BY Date ASC
Thanks for any help or suggestions you can provide.
SELECT * FROM (
SELECT * FROM mytable
WHERE `Date`<DATE_SUB(NOW(), INTERVAL 2 HOUR)
ORDER BY DATE DESC LIMIT 1
)
UNION
SELECT * FROM (
SELECT * FROM mytable
WHERE `Date`<DATE_SUB(NOW(), INTERVAL 1 HOUR)
ORDER BY DATE DESC LIMIT 1
)
UNION
SELECT * FROM (
SELECT * FROM mytable
ORDER BY DATE DESC LIMIT 1
)
ORDER BY `Date`ASC