How to find duplicate rows with similar part of string - mysql

Question

I have thousands of rows in a table. Which is some rows has similar keyword but can be categorize to the same group. For example :
Table : Birds_Name
+-------+---------------------+
|ID |Name |
+-------+---------------------+
|1 |Blue Peckwood |
+-------+---------------------+
|2 |North Peckwood |
+-------+---------------------+
|3 |Northern Peckwood |
+-------+---------------------+
|4 |Northern Peckwood |
+-------+---------------------+
|5 |Red Heron |
+-------+---------------------+
|6 |Red Heron |
+-------+---------------------+
As for the table above there should be 2 groups of birds. They are Peckwook and Heron.
But after I run this mySQL I get :
SELECT *
FROM birds_name
WHERE name IN (
SELECT name
FROM birds_name
GROUP BY name
HAVING COUNT(*) > 1
)
After I run the query. This is what I've got:
+-------+---------------------+
|3 |Northern Peckwood |
+-------+---------------------+
|4 |Northern Peckwood |
+-------+---------------------+
|5 |Red Heron |
+-------+---------------------+
|6 |Red Heron |
+-------+---------------------+
Actually, I expect any row which share a similar string to be chosen (in this case it's Peckwood. So it should have only 2 groups - Peckwood and Heron.
Is it possible to do so? And how to adapt mysql code to achieve it?
Regards.

Answer 1

Try this
SELECT SUBSTRING_INDEX(name,' ',-1),count(*)
FROM birds_name
GROUP BY SUBSTRING_INDEX(name,' ',-1) HAVING count(*)>0;
Manual for SUBSTRING_INDEX function in mysql.

Answer 2

Can you try this.
SELECT count(id),name
FROM birds_name
group by name
having count(id) >1
Thanks
SQL Fiddle

Answer 3

I think you can separate those words using MySQL String functions, like below:
mysql> SELECT SUBSTRING_INDEX('www.mysql.com', '.', 2);
-> 'www.mysql'
mysql> SELECT SUBSTRING_INDEX('www.mysql.com', '.', -2);
-> 'mysql.com'
Then, use it in the GROUP BY clause of your query.
UPDATE :
Here is my SQLFiddle.