Mysql sort alphanumeric data - mysql

Question

I have two tables tt1 and tt2 both contains same fields. I want to sort data by no from both table.
Table : tt1
CREATE TABLE IF NOT EXISTS `tt1` (
`id` bigint(20) NOT NULL AUTO_INCREMENT,
`no` varchar(5) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=4 ;
INSERT INTO `tt1` (`id`, `no`) VALUES
(1, '1A'),
(2, '3A'),
(3, '2A');
Table : tt2
CREATE TABLE IF NOT EXISTS `tt2` (
`id` bigint(20) NOT NULL AUTO_INCREMENT,
`no` varchar(5) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=4 ;
INSERT INTO `tt2` (`id`, `no`) VALUES
(1, '2A'),
(2, '3A'),
(3, '1A');
Expected output
ID | No
========
1 | 1A
3 | 1A
1 | 2A
3 | 2A
2 | 3A
2 | 3A
I want to ascending order of no field from both table as given output how I can get.
SQLFiddle

Answer 1

In this case using order by after every select is wrong (won't return desired output), because that will order both row-sets separately and union them after that.
What you want here is to order already combined data, therefore you should be using order by only once, after mysql makes union of tables (i.e. combines), because once it combines tables it has all data together but unordered, so when mysql sees order by it orders whole data for you.
Sample:
select * from `tt1`
union all
select * from `tt2`
order by `no`
Note: I've noticed you have wrong syntax in your fiddle. You need to add parentheses:
(select * from tt1 order by no)
union
(select * from tt2 order by no)
Note 2: Thanks #AlmaDo's notice. You should not use * with union queries. Because modification of your tables columns will break query. Use column names that you actually need. E.g. query in sample becomes:
select `id`, `no` from `tt1`
union all
select `id`, `no` from `tt2`
order by `no`