Select fields based on aggregates results - mysql

Question

I have a typical products table with the fields name and price. I have to select the sum of all the prices, the name of the cheapest product and the name of the most expensive product and then return it all in the same result set. I've tried some combinations but the best I could come up with was an ugly query with multiple nested subselects. Can anyone help me with a good query example, please? Thanks in advance.
To illustrate the problem, here is a minimalistic products table:
+----+-------+------------------+
| id | price | name |
+----+-------+------------------+
| 1 | 2.20 | Shack Beer |
| 2 | 3.40 | Freeze IPA |
| 3 | 1.10 | Poor Man's Ale |
| 4 | 3.40 | Alabama Sour |
| 5 | 7.20 | Irish Stout |
+----+-------+------------------+
Given the table above, the query must return the following result set:
total_pricing = 17.30
cheapest_product = Poor Man's Ale
most_expensive_product = Irish Stout

Answer 1

Here are a couple of options for you (SQL Fiddle):
SELECT SUM(p.price) AS total_pricing,
(
SELECT name
FROM products
ORDER BY price
LIMIT 1
)AS cheapest_product,
(
SELECT name
FROM products
ORDER BY price DESC
LIMIT 1
)AS most_expensive_product
FROM products p;
Or in separate rows:
SELECT 'total_pricing' as Category, SUM(p.price) AS total_pricing
FROM products p
UNION
(
SELECT 'cheapest_product', name
FROM products
ORDER BY price
LIMIT 1
)
UNION
(
SELECT 'most_expensive_product', name
FROM products
ORDER BY price DESC
LIMIT 1
);

Answer 2

Check SQL Fiddle
SELECT DISTINCT price,
name
FROM products AS p1,
(SELECT MAX(price) AS `most_expensive_product`,
MIN(price) AS `cheapest_product`
FROM products) AS p2
WHERE p2.most_expensive_product = p1.price
OR p2.cheapest_product = p1.price
UNION
SELECT sum(price) AS price,
"Total_pricing" AS name
FROM products;