I need to filter a table in mysql but can't get past the beginning.
The table has 2 fields:
ID_house house_feature
1 1
1 2
1 4
1 5
2 1
2 3
2 4
3 1
3 2
3 3
I need to filter this table using the following parameters:
house feature = 1
AND
house feature = 2
AND
house feature = 3
So that I get all houses with the requested feature.
I already tried to create something similar to this:
SELECT *
FROM houses
WHERE
house_feature = 1
AND
house_feature = 2
AND
house_feature = 3
But it doesn't work as I expected.
Is there a way to get this result with MySQL?
It seems that I acn filter the table using only the OR operator but this way I can't get the right result.
Thanks in advance for any help.
tony
You can do so ,by matching the distinct count of features per house ,so the house with exactly these 3 features will be returned
SELECT *
FROM t
WHERE
house_feature IN(1 ,2,3)
group by ID_house
having count(distinct house_feature) = 3
Demo
Related
I have table where the data is like bellow
Combination_id combination
1 1
1 3
1 4
2 1
2 3
2 5
I want to find the combination_id based on combination.
Test case
1 . For the combination of 1,3,4 I should get combination id 1
2 . For the combination of 1,3,5 I should get combination id 2
I tried many MySQL queries but failed. Can anyone help me here??
Thanks in advance...
There are many ways, but it depends on how your combination is used
For example
select t1.Combination_id
from tab1 t1
where t1.combination in (1,3,4)
group by t1.Combination_id
having count(1) = 3
I have the following table
TABLE store
store name level
1 Tom 4
2 Joe 2
1 Chris 4
3 Tom 2
4 Ed 2
2 Tom 4
3 Chris 2
I want to return the number of level 4's from each distinct store
I know I can
select distinct store from store;
To get distinct stores and
select count(*) as level from store where level = 4;
to get the count of level 4's
How do I combine to return a query of number of level 4's in each distinct store
So the data above would return
store level4
1 2
2 1
3 0
4 0
It is not clear why your table is called store. Shouldn't you have a table with that name that has one row per store?
In any case, probably the simplest method for getting the 0 counts is conditional aggregation:
select store, sum(level = 4) as level4
from store
group by store;
I'm trying to join a few tables in MySQL. Our setup is a little unique so I try to explain as good as I can.
I have a table 'INVENTORY' that represents the current items on stock.
These items are stored in a table 'COMPONENT'
Components are being used in installations.
Every user can have multiple installations and the same component can be used in multiple installation as well.
To uniquely map a component to an installation, it can be assigned to a PRODUCT. a product as has a 1-1 relationship with an installation. A component is not directly related to an installation
To finally assign a product to a specific installation a mapping table COMPOMENT_PRODUCT is used.
Example:
A component is like a part, lets say a screw. This screw is used in a computer. The very same screw can be used on multiple computers. But each computer can only be used on one specific installation.
TABLE COMPOMENT_PRODUCT
COMPOMENT_ID PRODUCT_ID
1 1
1 2
2 1
2 2
So we have the components C1 and C2 relevant for two installations.
TABLE INVENTORY
COMPOMENT_ID INSTALLATION_ID ON_STOCK
1 1 5
1 2 2
What I want to achieve
Now, I want to retrieve the inventory state for all components. But, not every component has an inventory record. In these cases, the ON_STOCK value from the inventory shall be NULL
That means, for this example I'd expect the following results
COMPOMENT_ID PRODUCT_ID ON_STOCK
1 1 5
1 2 2
2 1 NULL
2 2 NULL
But executing this query:
SELECT DISTINCT
COMPONENT_PRODUCT.COMPONENT_ID,
COMPONENT_PRODUCT.PRODUCT_ID,
INVENTORY.ON_STOCK
FROM INVENTORY
RIGHT JOIN COMPONENT_PRODUCT ON COMPONENT_PRODUCT.COMPONENT_ID =
INVENTORY.COMPONENT_ID
returns the following resultset:
COMPONENT_ID PRODUCT_ID ON_STOCK
1 1 5
1 2 5
1 1 2
1 2 2
2 1 (null)
2 2 (null)
Now, my next thought was, "of course, this is how joins behave, okay I need to group the results". But the way SQL works, the aggregation is not entirely predictable. SO when I
GROUP BY COMPONENT_PRODUCT.COMPONENT_ID,COMPONENT_PRODUCT.PRODUCT_ID
I get this result:
COMPONENT_ID PRODUCT_ID ON_STOCK
1 1 5
1 2 5
2 1 (null)
2 2 (null)
I have prepared a Fiddle here: http://sqlfiddle.com/#!9/71ca87
What am I forgetting here? Thanks in advance for any pointers.
Try this query -
SELECT DISTINCT
COMPONENT_PRODUCT.COMPONENT_ID,
COMPONENT_PRODUCT.PRODUCT_ID,
INVENTORY.ON_STOCK
FROM INVENTORY
RIGHT JOIN COMPONENT_PRODUCT ON COMPONENT_PRODUCT.COMPONENT_ID =
INVENTORY.COMPONENT_ID
AND COMPONENT_PRODUCT.PRODUCT_ID = INVENTORY.INSTALLATION_ID
i was trying to solve a problem which just looks like the code written below, but from lack of knowledge and reading through the sqlalchemy documentation, i do not really find any solution on how to solve my problem, yet.
Objective:
Get summed value of sales_in_usd if year in year_column is same
What I got so far is by debugging and reading a bit through stackoverflow and documentations, google by using following query:
session.query(fact_corporate_sales, Company, Sales,
Time, Sector, func.sum(Sales.sales_in_usd).label('summary')).\
join(Sales).\
join(Time).\
join(Company).\
join(Segment).\
order_by(Time.year.desc()).\
filter(Company.company_name.like(filtered)).\
group_by(fact_corporate_sales.fact_cps_id, Company.company_name,fact_corporate_sales.cps_id).\
all()
And well the fact_cps_id is unique in the fact_table and the same table stores, the keys of the dimension tables as well..
I have a fact table which stores 4 foreign keys from 4 dimension tables.
fact_cps_id company_id sales_id time_id sector_id
1 4 2 1 2
2 4 1 1 3
3 4 3 2 1
4 4 2 2 4
5 4 4 3 2
6 4 99 1 1
dim_company
company_id company_name
1 Nike
2 Adidas
3 Puma
4 Reebok
dim_segment
segment_id segment_nom
1 basketball
2 running
3 soccer
4 watersports
dim_time
time_id quarter year
1 1 2013
2 2 2013
3 1 2014
4 3 2014
dim_sales
sales_id sales_in_euro
1 2000
2 3200
3 1400
4 1590
.. ..
99 1931
So basically, as you can see in the table and query what I was trying to do was summing up all sales from the as example dim_Time.year <- from the same year.
If we look into the fact_table we can see, that we have time_id = 1 three times, here. So those values could be summed up and displayed as a summary.
I know from standard SQL that it was possible by using group by and aggregate function sum.
My result(time_id is only for help therefore was no output):
13132.0 <- time_id = 1
21201.0 <- time_id = 2
23923.0 <- time_id = 1
31232.0 <- time_id = 99
32021.0 <- time_id = 2
32342.0 <- time_id = 1
131231.0 <- time_id = 4
I printed the actual query into the console and got this [had to remove .all(), because 'list' has no attribute called 'statement']:
SELECT fact_corporate_sales.cps_fact_id, fact_corporate_sales.cps_id,
fact_corporate_sales.company_id, fact_corporate_sales.time_id, fact_corporate_sales.segment_id, sum(dim_corporate_sales.sales_in_usd) AS summary
FROM fact_corporate_sales INNER JOIN dim_corporate_sales ON dim_corporate_sales.cps_id = fact_corporate_sales.cps_id INNER JOIN dim_time ON dim_time.time_id = fact_corporate_sales.time_id INNER JOIN dim_company ON dim_company.company_id = fact_corporate_sales.company_id INNER JOIN dim_segment ON dim_segment.segment_id = fact_corporate_sales.segment_id
WHERE dim_company.company_name LIKE %s GROUP BY fact_corporate_sales.cps_fact_id ORDER BY dim_time.year DESC
And if I want to group by for example dim_time.Year only..I get following response from mysql or console
Error Code: 1055. Expression #1 of SELECT list is not in GROUP BY clause and contains nonaggregated column 'db.fact_corporate_sales.fact_cps_id' which is not functionally dependent on columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by
The solution was only to execute following sql:
engine.execute("SET sql_mode='';")
As the response of my failed query was:
"this is incompatible with sql_mode=only_full_group_by"
I had to disable the sql_mode and so did I and got my result.
Have a existing table of results like this;
race_id race_num racer_id place
1 0 32 2
1 1 32 3
1 2 32 1
1 3 32 6
1 0 44 2
1 1 44 2
1 2 44 2
1 3 44 2
etc...
Have lots of PHP scripts that access this table output the results in a nice format.
Now I have a case where I need to output the results for only certain race_nums.
So I have created this table races_included.
race_view race_id race_num
Day 1 1 0
Day 1 1 1
Day 2 1 2
Day 2 1 3
And can use this query to get the right results.
SELECT racer_id, place from results WHERE race_id=1
AND race_num IN
(SELECT race_num FROM races_included WHERE race_id='1' AND race_view='Day 1')
This is great but I only need this feature for a few races and to have it work in a compatible mode for the simple case show all races. I need to add alot of rows to the races_included table. Like
race_view race_id race_num
All 1 0
All 1 1
All 1 2
All 1 3
95% of my races don't use the daily feature.
So I am looking for a way to change the query so that if for race 1 there are no records in the races_included table it defaults to all races. In addition I need it to be close the same execution speed as the query without the IN clause, because this query Or variations of it are used a lot.
One way that does work is to redefine the table as races_excluded and use NOT IN. This works great but is a pain to manage the table when races are added or deleted.
Is there a simple way to use EXISTS and IN in tandem as a subquery to get the desired results? Or some other neat trick I am missing.
To clarify I have found a working but very slow solution.
SELECT * FROM race_results WHERE race_id=1
AND FIND_IN_SET(race_num, (SELECT IF((SELECT Count(*) FROM races_excluded
WHERE rid=1>0),(SELECT GROUP_CONCAT(rnum) FROM races_excluded
WHERE rid=1 AND race_view='Day 1' GROUP BY rid),race_num)))
It basically checks if any records exists for that race_id and if not return a set equal to the current race_num and if yes returns a list of included race nums.
You can do this by using or in the subquery:
SELECT racer_id, plac
from results
WHERE race_id = 1 AND
race_num IN (SELECT race_num
FROM races_included
WHERE race_id = '1' AND (race_view = 'Day 1' or raw_view = 'ANY')
);