Selecting sets with the top 10% of combined votes among objects - mysql

Question

For some background, I previously asked about retrieving sets with highest number of combined votes among objects. That works great for getting the top 25, but now I would like to get the top 10%, ordered by rankset's timestamp. Here are the tables in question:
CREATE TABLE IF NOT EXISTS `rankset` (
`id` INT NOT NULL AUTO_INCREMENT ,
`name` TEXT NOT NULL ,
PRIMARY KEY (`id`) )
ENGINE = InnoDB
CREATE TABLE IF NOT EXISTS `item` (
`id` BIGINT NOT NULL AUTO_INCREMENT ,
`name` VARCHAR(128) NOT NULL ,
`rankset` BIGINT NOT NULL ,
`image` VARCHAR(45) NULL ,
`description` VARCHAR(140) NULL ,
PRIMARY KEY (`id`) )
ENGINE = InnoDB
CREATE TABLE IF NOT EXISTS `mydb`.`vote` (
`id` BIGINT NOT NULL AUTO_INCREMENT ,
`value` TINYINT NOT NULL ,
`item` BIGINT NOT NULL ,
`user` BIGINT NOT NULL ,
PRIMARY KEY (`id`) )
ENGINE = InnoDB
I'd list what I've tried so far, but I honestly don't even know where to begin with this one. Here's the SQL fiddle:
http://sqlfiddle.com/#!2/fe315/9

Answer 1

From the comments:
Look at this answer: https://stackoverflow.com/a/4474389/97513, He generates a column for the ranking of his items, use a WHERE clause that uses rank <= (SELECT COUNT(1) / 10 FROM rankset) to identify the top 10%.
I put together an SQL fiddle to demonstrate: http://sqlfiddle.com/#!2/fe315/21 - Here's another with more results so you can see it scales up when you add more rows: http://sqlfiddle.com/#!2/a02ea/1
SQL Used:
SET #rn := 0;
SELECT (#rn:=#rn+1) AS rank, q.*
FROM (
SELECT rankset.*, COALESCE(COUNT(vote.id), 0) AS votes
FROM rankset, vote, item
WHERE item.rankset = rankset.id
AND vote.item = item.id
GROUP BY rankset.id
ORDER BY votes DESC
) q
WHERE
#rn <= (SELECT COUNT(1)/10 FROM rankset);