Get available stocks to sell - mysql

What I have until now: http://sqlfiddle.com/#!2/bbfec/6
I want to get the quanity of shares for a given stock, that a given company has available to sell - grouped by price. For example, for company number 9 and stock number 1, I want the data like this:
| id | name | price | date | quantity | total |
------------------------------------------------------------------
| 3 | ALTR | 2.240 | 2015-05-12 04:29:29 | 50 | 112.00 |
| 7 | ALTR | 2.449 | 2014-06-10 18:21:02 | 50 | 122.45 |
Because company 9 bought 200 stocks on 2015-05-12 04:29:29, sold 100 on 2014-06-10 15:50:17, more 50 on 2014-06-10 17:06:18 and bought 50 on 2014-06-10 18:21:02.
I don't want the total of all shares, because they have different prices when a company acquires them. The price and the date are the purchasing price and date but the quantity is what is left from a certain purchasing.
Thanks in advance.
Strawberry, the desired result:
| id | price | date | quantity |
-----------------------------------------------
| 3 | 2.240 | 12-05-2015 | 50 |
| 7 | 2.449 | 10-06-2014 | 50 |

Start with:
select id_acao, id_empresa, ifnull(bought,0) - ifnull(sold,0) as stock
from
(
select id_acao, id_empresa,
(select sum(quantidade) from acao_trans where tipo='C' and id_acao=a.id_acao and id_empresa=a.id_empresa) as bought,
(select sum(quantidade) from acao_trans where tipo='V' and id_acao=a.id_acao and id_empresa=a.id_empresa) as sold
from acao_trans a group by id_acao,id_empresa
) x
;
+---------+------------+-------+
| id_acao | id_empresa | stock |
+---------+------------+-------+
| 1 | 4 | 1500 |
| 1 | 9 | 100 |
| 8 | 9 | 3500 |
| 13 | 9 | 5000 |
+---------+------------+-------+
And join this query to your base acao and empresa tables.
Remark: For statistics etc. it would be easier to use negative quantities for selling transactions instead of a transaction type 'C' and 'V'.

For ease of (my) comprehension, I translated and adjusted your stock table slightly...
SELECT a.stock_id
, a.company_id
, a.transaction_date
, a.price
, COALESCE(a.quantity - SUM(b.quantity),a.quantity) quantity
, COALESCE(a.quantity - SUM(b.quantity),a.quantity) * a.price subtotal
FROM stock_company a
LEFT
JOIN
( SELECT x.stock_id
, x.company_id
, MAX(x.transaction_date) min_transaction_date
, y.quantity
FROM stock_company x
JOIN stock_company y
ON y.stock_id = x.stock_id
AND y.company_id = x.company_id
AND y.transaction_date <= x.transaction_date
AND y.transaction_type <> x.transaction_type
WHERE y.transaction_type = 'SELL'
GROUP
BY x.stock_id
, x.company_id
, y.quantity
) b
ON b.stock_id = a.stock_id
AND b.company_id = a.company_id
AND b.min_transaction_date = a.transaction_date
WHERE a.stock_id = 1
AND a.company_id = 9
AND a.transaction_type = 'BUY'
GROUP
BY stock_id
, company_id
, transaction_date;
+----------+------------+---------------------+-------+----------+----------+
| stock_id | company_id | transaction_date | price | quantity | subtotal |
+----------+------------+---------------------+-------+----------+----------+
| 1 | 9 | 2014-06-10 18:21:02 | 2.449 | 50 | 122.450 |
| 1 | 9 | 2015-05-12 04:29:29 | 2.240 | 50 | 112.000 |
+----------+------------+---------------------+-------+----------+----------+
http://www.sqlfiddle.com/#!2/cfa4d/1
Note that this hasn't been tested extensively so there may be a flaw (or perhaps several flaws!) in my logic, but it seems to work well enough on the data set provided.
EDIT: I made a slight adjustment - still not sure if it's enough. Let me know.

Maybe now I've understood it. How about this:
select c.id,c.id_empresa,c.id_acao,c.data as c_data,c.quantidade as c_quantidade,v.preco,v.id as v_id,v.data as v_data,ifnull(v.quantidade,0) as v_quantidade, c.preco*v.quantidade as bought, v.preco*v.quantidade as sold
from acao_trans c
left join acao_trans v
on c.id=v.parent
order by id_empresa, id_acao,c_data,v_data
which results in
+----+------------+---------+---------------------+--------------+-------+------+---------------------+--------------+----------+----------+
| id | id_empresa | id_acao | c_data | c_quantidade | preco | v_id | v_data | v_quantidade | bought | sold |
+----+------------+---------+---------------------+--------------+-------+------+---------------------+--------------+----------+----------+
| 4 | 4 | 1 | 2014-06-10 08:59:09 | 2000 | 2.385 | 8 | 2014-06-11 10:39:48 | 500 | 1184.000 | 1192.500 |
| 8 | 4 | 1 | 2014-06-11 10:39:48 | 500 | NULL | NULL | NULL | 0 | NULL | NULL |
| 5 | 9 | 1 | 2014-06-10 15:50:17 | 100 | NULL | NULL | NULL | 0 | NULL | NULL |
| 6 | 9 | 1 | 2014-06-10 17:06:18 | 50 | NULL | NULL | NULL | 0 | NULL | NULL |
| 7 | 9 | 1 | 2014-06-10 18:21:02 | 50 | NULL | NULL | NULL | 0 | NULL | NULL |
| 3 | 9 | 1 | 2015-05-12 04:29:29 | 200 | 2.430 | 5 | 2014-06-10 15:50:17 | 100 | 224.000 | 243.000 |
| 3 | 9 | 1 | 2015-05-12 04:29:29 | 200 | 2.449 | 6 | 2014-06-10 17:06:18 | 50 | 112.000 | 122.450 |
| 2 | 9 | 8 | 2015-05-12 04:27:56 | 3500 | NULL | NULL | NULL | 0 | NULL | NULL |
| 1 | 9 | 13 | 2015-05-12 04:25:52 | 5000 | NULL | NULL | NULL | 0 | NULL | NULL |
+----+------------+---------+---------------------+--------------+-------+------+---------------------+--------------+----------+----------+
Can you go on from there?

Ok, now I think I got it.
Here's the query resulting what I wanted:
SELECT p.id
, a.nome
, p.preco
, date_format(p.`data`,'%m/%d/%Y') AS `data`
, COALESCE(p.quantidade-SUM(f.quantidade), p.quantidade) AS quantidade
, p.preco*COALESCE(p.quantidade-SUM(f.quantidade), p.quantidade) AS total
FROM acao_trans p
LEFT JOIN acao_trans f
ON p.id=f.parent
INNER JOIN acao a
ON p.id_acao=a.id
WHERE p.parent IS NULL
AND p.id_acao=1
AND p.id_empresa=9
GROUP BY p.id
Fiddle: http://sqlfiddle.com/#!2/bbfec/64.
What I did: I joined the table that matters (acao_trans "p") with itself ("f") and I used Sum function to aggregate all the quantities of second argument, giving me the total of all sold shares. If there are records on "f" I want to subtract that total of the quantity of purchasing shares ("p"). If there is not a correspondence it will show null fields and I show purchased quantity. After it's done it's kind of simple. Quantity was what really mattered here, with that I was able to reach other things easily.

Related

Select the entire row of the lowest price for distinct product

I have the below table about products:
| id | name | product_id | price | seller_id | discount_id |
--------------------------------------------------------------
| 1 | phone | 11 | 400 | 7 | 19 |
| 2 | cpu | 78 | 120 | 33 | 4 |
| 3 | phone | 11 | 380 | 8 | 22 |
| 4 | phone | 11 | 460 | 5 | 19 |
| 5 | memory | 80 | 45 | 12 | 16 |
| 6 | router | 98 | 115 | 7 | 16 |
| 7 | cpu | 78 | 115 | 33 | 66 |
I need to select all the columns of distinct product_id with the lowest price. Also to ORDER the result by price ASC. For this example:
| id | name | product_id | price | seller_id | discount_id |
--------------------------------------------------------------
| 5 | memory | 80 | 45 | 12 | 16 |
| 6 | router | 98 | 115 | 7 | 16 |
| 7 | cpu | 78 | 115 | 33 | 66 |
| 3 | phone | 11 | 380 | 8 | 22 |
I have no problems doing this using GROUP BY product_id and min(price) but I also need other columns (seller_id & discount_id)
MySQL version: 5.7.17
sql_mode=only_full_group_by
Table is temporary (ENGINE=MEMORY) and can't JOIN multiple times
How can I produce the result above from MySQL?
Add a subquery with the min price and join on min price and product.
SELECT id, name,product_id,price,seller_id,discount_id FROM t
JOIN
(SELECT tt.product_id,MIN(tt.price) minp FROM t as tt
GROUP BY tt.product_id)x
ON x.product_id=t.product_id AND x.price = t.price
Another option with LIMIT
SELECT * FROM T WHERE EXISTS
(SELECT 1 FROM T as TT ORDER BY TT.price ASC LIMIT 1
WHERE t.id= TT.id)
Given that the MEMORY engine is so restricting go the caveman way
SELECT SUBSTRING_INDEX(GROUP_CONCAT(id ORDER BY price),',',1),
SUBSTRING_INDEX(GROUP_CONCAT(name ORDER BY price),',',1),
product_id,MIN(price),
SUBSTRING_INDEX(GROUP_CONCAT(seller_id ORDER BY price),',',1),
SUBSTRING_INDEX(GROUP_CONCAT(discount_id ORDER BY price),',',1) FROM t
GROUP BY product_id
You can join the table with itself (on product_id). As a join-condition add left.price > right.price - and then choose the rows, where right.price is null, because for that join, there is no lower right price, meaning the one you have left is the lowest:
SELECT l.id, l.name, l.product_id, l.price, l.seller_id, l.discount_id
FROM
products l
LEFT JOIN
products r
on
l.product_id = r.product_id AND l.price > r.price
WHERE
isnull (r.price) -- that means: no cheaper price for this position.
intermediate result (SELECT * no WHERE) would look like (shortened):
| l.id | l.name | l.product_id | l.price | r.id | r.name | r.product_id | r.price
| 3 | phone | 11 | 380 | null | null | null | null
| 4 | phone | 11 | 460 | 3 | phone | 3 | 380
Side node: For very large datasets there might be performance-issues, because every additional line of a component would add multiple result rows. i.e. consider another phone:
| l.id | l.name | l.product_id | l.price | r.id | r.name | r.product_id | r.price
| 3 | phone | 11 | 380 | null | null | null | null
| 4 | phone | 11 | 460 | 3 | phone | 3 | 380
| 5 | phone | 11 | 500 | 3 | phone | 3 | 380
| 5 | phone | 11 | 500 | 4 | phone | 3 | 460
So, if you want to get the lowest price in the past 60 days with daily changes, that will be a huge amount of rows just for "that"... (Actually 60+59+58+...+2+1 I think, cause the most expensive price will produce 59 comparision rows and so on)

MySQL Join Query without duplicate values

invoice table
SELECT id, fname, gtotal, `date` FROM invoice WHERE id = 1;
| id | fname | gtotal | date |
|----|---------|--------|-----------------------|
| 1 | Brandon | 860 | May, 11 2016 00:00:00 |
invoice_contents table,
SELECT * FROM invoice_contents WHERE invoice_id = 1;
| id | invoice_id | item | price | quantity | discount | total |
|----|------------|------------|-------|----------|----------|-------|
| 1 | 1 | Dextrose | 10 | 10 | 5 | 95 |
| 2 | 1 | Nescaine | 20 | 30 | 10 | 540 |
| 3 | 1 | Anticavity | 30 | 10 | 25 | 225 |
This JOIN query
SELECT invoice.id, invoice.fname, invoice_contents.item,
invoice_contents.price, invoice_contents.quantit,
invoice_contents.discount, invoice_contents.total,
invoice.gtotal
FROM invoice_contents
INNER JOIN invoice ON invoice_contents.invoice_id=1 AND invoice.id=1;
gives this result.
| id | fname | item | price | quantity | discount | total | gtotal |
|----|---------|------------|-------|----------|----------|-------|--------|
| 1 | Brandon | Dextrose | 10 | 10 | 5 | 95 | 860 |
| 1 | Brandon | Nescaine | 20 | 30 | 10 | 540 | 860 |
| 1 | Brandon | Anticavity | 30 | 10 | 25 | 225 | 860 |
I need this result.
| id | fname | item | price | quantity | discount | total | gtotal |
|----|---------|------------|-------|----------|----------|-------|--------|
| 1 | Brandon | Dextrose | 10 | 10 | 5 | 95 | 860 |
| | | Nescaine | 20 | 30 | 10 | 540 | |
| | | Anticavity | 30 | 10 | 25 | 225 | |
I am just a beginner in MySQL. I have been trying from this morning to get this kind of output by experimenting on different combinations please help me out.
#Rex, Your select is correct. You should make desired output using some script e.g. PHP.
try this in SQL:
in this Query i save everytime fname in a variable is not equal and at the next row i compare it and return a empty string is it equal. and the same for gtotal.
the cross join is only to initialize the variables.
in this case it is important that the rows are order by fname to ensure that the same name is behind each other
SELECT
invoice.id,
IF(#last_fname = invoice.fname, '', (#last_fname:=invoice.fname)) as fname,
invoice_contents.item,
invoice_contents.price,
invoice_contents.quantity,
invoice_contents.discount,
IF(#last_gtotal = invoice.gtotal, '', (#last_gtotal:=invoice.gtotal)) as gtotal
FROM invoice_contents
INNER JOIN invoice ON invoice_contents.invoice_id=1 AND invoice.id=1
CROSS JOIN ( select #last_fname := '' , #last_gtotal := '' ) AS parameter
ORDER BY invoice.fname;
Sample
MariaDB [bb]> SELECT
-> invoice.id,
-> IF(#last_fname = invoice.fname, '', (#last_fname:=invoice.fname)) AS fname,
-> invoice_contents.item,
-> invoice_contents.price,
-> invoice_contents.quantity,
-> invoice_contents.discount,
-> IF(#last_gtotal = invoice.gtotal, '', (#last_gtotal:=invoice.gtotal)) AS gtotal
-> FROM invoice_contents
-> INNER JOIN invoice ON invoice_contents.invoice_id=1 AND invoice.id=1
-> CROSS JOIN ( SELECT #last_fname:='' , #last_gtotal:='' ) AS parameter
-> ORDER BY invoice.fname;
+----+---------+------------+-------+----------+----------+--------+
| id | fname | item | price | quantity | discount | gtotal |
+----+---------+------------+-------+----------+----------+--------+
| 1 | Brandon | Dextrose | 10.00 | 10 | 5.00 | 860.00 |
| 1 | | Nescaine | 20.00 | 30 | 10.00 | |
| 1 | | Anticavity | 30.00 | 10 | 25.00 | |
+----+---------+------------+-------+----------+----------+--------+
3 rows in set, 1 warning (0.00 sec)
MariaDB [bb]>

SQL reduce number of columns in inner query

I have a query:
select
count(*), paymentOptionId
from
payments
where
id in (select min(reportDate), id
from payments
where userId in (select distinct userId
from payments
where paymentOptionId in (46,47,48,49,50,51,52,53,54,55,56))
group by userId)
group by
paymentOptionId;
The problem place is "select min(reportDate), id", this query must return 1 column result, but I can't realize how to do it while I need to group min.
The data set looks like
+----+--------+--------+-----------+---------------------+--------+----------+-----------------+
| id | userId | amount | userLevel | reportDate | buffId | bankQuot | paymentOptionId |
+----+--------+--------+-----------+---------------------+--------+----------+-----------------+
| 9 | 12012 | 5 | 5 | 2014-02-10 23:07:57 | NULL | NULL | 2 |
| 10 | 12191 | 5 | 6 | 2014-02-10 23:52:12 | NULL | NULL | 2 |
| 11 | 12295 | 5 | 6 | 2014-02-11 00:12:04 | NULL | NULL | 2 |
| 12 | 12295 | 5 | 6 | 2014-02-11 00:12:42 | NULL | NULL | 2 |
| 13 | 12256 | 5 | 6 | 2014-02-11 00:26:25 | NULL | NULL | 2 |
| 14 | 12256 | 5 | 6 | 2014-02-11 00:26:35 | NULL | NULL | 2 |
| 16 | 12510 | 5 | 5 | 2014-02-11 00:42:58 | NULL | NULL | 2 |
| 17 | 12510 | 5 | 5 | 2014-02-11 00:43:08 | NULL | NULL | 2 |
| 18 | 12510 | 18 | 5 | 2014-02-11 00:45:16 | NULL | NULL | 3 |
| 19 | 12510 | 5 | 6 | 2014-02-11 01:00:10 | NULL | NULL | 2 |
+----+--------+--------+-----------+---------------------+--------+----------+-----------------+
select count(*), paymentOptionId
from
(select userId, min(reportdate), paymentOptionId
from payments as t1
group by userId, paymentOptionId) as t2
group by paymentOptionId
Fiddle
It first gets the minimum report date (so the first entry) for every user, for every type (so there are two records for a user who has 2 types) and then counts them grouping by type (aka paymentOptionId).
By the way, you can of course cut the attributes chosen in select in from clause, they are only there so you can copy-paste it and see the results it is giving step by step.
You seem to want to report on various payment options and their counts for the earliest ReportDate for each user.
If so, here is an alternative approach
select p.paymentOptionId, count(*)
from payments p
where paymentOptionId in (46,47,48,49,50,51,52,53,54,55,56) and
not exists (select 1
from payments p2
where p2.userId = p.userId and
p2.ReportDate < p.ReportDate
)
group by paymentOptionId;
This isn't exactly the same as your query, because this will only report on the list of payment types, whereas you might want the first payment type for anyone who has ever had one of these types. I'm not sure which you want, though.

Select total members and amount paid

I need help generating SQL for MySQL database.
I have three tables:
Organisations
Members
Payments
Organisations table:
+------------+---------+--------+
| id | name |website |
+------------+---------+--------+
| 1 | AAA | a.com |
|-------------------------------+
| 2 | BBB | b.com |
+------------+---------+--------+
Members table:
+------------+-------------------+--------+-----------------+-----------+
| id | organisation_id |name | Payment_confirm | join_date |
+------------+-------------------+--------+-----------------+-----------+
| 1 | 1 | james | 1 | 2013-8-02 |
|-----------------------------------------+-----------------+-----------+
| 2 | 1 | Jimmy | 0 | 2013-6-25 |
+------------+-------------------+--------+-----------------+-----------+
| 3 | 2 | Manny | 1 | 2013-07-02|
|-----------------------------------------+-----------------+-----------+
| 4 | 1 | Kim | 1 | 2013-09-02|
+------------+-------------------+--------+-----------------+-----------+
Payments table:
+------------+-------------------+--------+-----------------+----------------+
| id | member_id |amount | transaction_id | transferred_at |
+------------+-------------------+--------+-----------------+----------------+
| 1 | 1 | 100 | T1001 | 2013-8-03 |
|-----------------------------------------+-----------------+--------------- +
| 2 | 2 | 0 | null | Null |
+------------+-------------------+--------+-----------------+----------------+
| 3 | 3 | 200 | T1002 | Null |
|-----------------------------------------+-----------------+----------------+
| 4 | 4 | 50 | T1005 | 2013-09-05 |
+------------+-------------------+--------+-----------------+----------------+
How can I select the following?
Expecting the following output:
+------------+-------------------+--------+-----------------+---------------+--------------+
| Org name | Revenue |untransferred amount | Total members | last 30 days |
+------------+-------------------+--------------------------+---------------+--------------+
| AAA | 150 | 0 | 3 | 2 |
|-----------------------------------------------------------+---------------+--------------+
| BBB | 200 | 200 | 1 | 0 |
+------------+-------------------+--------------------------+---------------+--------------+
Org name = organisation name
Revenue = Total amount received
untransferred amount = transferred_at is null (payments table)
Total members = total members joined till today
last 30 days = total members joined last 30 days
You need to join your tables, group the results and select the desired logic:
SELECT org.name,
SUM(pmt.amount) AS revenue,
SUM(IF(pmt.transferred_at IS NULL, pmt.amount, 0)) AS untransferred
FROM Organisations org
JOIN Members mem ON mem.organisation_id = org.id
JOIN Payments pmt ON pmt.member_id = mem.id
GROUP BY org.id
See it on sqlfiddle.
select o.name,
sum(amount) as Revenue,
sum(if(transferred_at is null, amount, 0)) as untransfered_ammt,
sum(if(join_date>=curdate() - interval 30 day, 1, 0)) as last_30_d
from organisations o
inner join members m on o.id=m.organisation_id
inner join payments p on p.member_id=m.member_id
group by 1

Order by and group by

I am trying to show delivery charges for a shop I am building, there are three tables in the database 1 for the service ie Royal Mail, Carrier..., one for the band ie. UK, Europe, Worldwide1 etc.. and one for the charges (qty = weight)
I have a database of three tables that, when joined form the following
+------------------+-----+-----------+-------+---------+---------------+----------+-------+-------------+
| name | qty | serviceID | basis | bandID | initial_charge | chargeID | price | total_price |
+------------------+-----+-----------+-------+---------+---------------+----------+-------+-------------+
| Collect in store | 0 | 3 | | 1 | 3 | 0.00 | 2 | 0.00 |
| Royal mail | 0 | 1 | 2 | 4 | 2.00 | 3 | 0.00 | 2.00 |
| Royal mail | 1 | 1 | 2 | 4 | 2.00 | 4 | 1.00 | 3.00 |
| APC | 0 | 2 | 1 | 1 | 0.00 | 6 | 5.95 | 5.95 |
+------------------+-----+-----------+-------+---------+---------------+----------+-------+-------------+
Basically what I want to do is (as you can see) Royal Mail has two entries as there are more than one entry in the joined table. What I would like to do is show the highest of the two royal mail entries (I was initially trying to group by service_id) whilst also maintaining the two other services with different service id's
Any assistance would be great as this is driving me mad. I feel like I have tried every combination going!
In the example below the qty (weight) of the items is 3kg
SELECT
`service`.`name`,
`charge`.`qty`,
`service`.`serviceID`,
`band`.`bandID`,
`band`.`initial_charge`,
`charge`.`chargeID`,
`charge`.`price`,
`band`.`initial_charge` + `charge`.`price` AS `total_price`
FROM
`delivery_band` AS `band`
LEFT JOIN
`delivery_charge` AS `charge`
ON
`charge`.`bandID` = `band`.`bandID`
AND
`charge`.`qty` < '3'
LEFT JOIN
`delivery_service` AS `service`
ON
`service`.`serviceID` = `band`.`serviceID`
WHERE
FIND_IN_SET( '225', `band`.`accepted_countries` )
AND
(
`band`.`min_qty` >= '3'
OR
`band`.`min_qty` = '0'
)
AND
(
`band`.`max_qty` <= '3'
OR
`band`.`max_qty` = '0'
)
delivery_service
+-----------+------------------+
| serviceID | name |
+-----------+------------------+
| 1 | Royal mail |
| 2 | APC |
| 3 | Collect in store |
+-----------+------------------+
delivery_band
+--------+-----------+-----------------+----------------+---------+---------+-------------------------------------------------------+
| bandID | serviceID | name | initial_charge | min_qty | max_qty | accepted_countries |
+--------+-----------+-----------------+----------------+---------+---------+-------------------------------------------------------+
| 1 | 2 | UK Mainland | 0.00 | 0 | 0 | 225 |
| 2 | 2 | UK Offshore | 14.00 | 0 | 0 | 240 |
| 3 | 3 | Bradford Store | 0.00 | 0 | 0 | 225 |
| 4 | 1 | UK | 2.00 | 0 | 0 | 225 |
| 5 | 2 | World wide | 15.00 | 0 | 0 | 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20... |
| 6 | 1 | World wide Mail | 5.00 | 0 | 0 | 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20... |
+--------+-----------+-----------------+----------------+---------+---------+-------------------------------------------------------+
delivery_charge
+----------+--------+-----+-------+
| chargeID | bandID | qty | price |
+----------+--------+-----+-------+
| 1 | 2 | 0 | 5.00 |
| 2 | 3 | 0 | 0.00 |
| 3 | 4 | 0 | 0.00 |
| 4 | 4 | 1 | 1.00 |
| 5 | 4 | 5 | 3.00 |
| 6 | 1 | 0 | 5.95 |
| 7 | 1 | 10 | 10.95 |
| 8 | 2 | 10 | 14.00 |
| 9 | 5 | 0 | 0.00 |
| 10 | 5 | 3 | 5.00 |
| 11 | 5 | 6 | 10.00 |
| 12 | 5 | 9 | 15.00 |
| 13 | 6 | 0 | 0.00 |
| 14 | 6 | 2 | 5.00 |
| 15 | 6 | 4 | 10.00 |
| 16 | 6 | 6 | 15.00 |
+----------+--------+-----+-------+
When I tried adding the charge table as a sub query and then limiting that query it gave me NULL's for all the charge table fields
If I try the following query:
SELECT
`service`.`name`,
`charge`.`qty`,
`service`.`serviceID`,
`band`.`bandID`,
`band`.`initial_charge`,
`charge`.`chargeID`,
MAX( `charge`.`price` ) AS `price`,
`band`.`initial_charge` + `charge`.`price` AS `total_price`
FROM
`delivery_band` AS `band`
LEFT JOIN
`delivery_charge` AS `charge`
ON
`charge`.`bandID` = `band`.`bandID`
AND
`charge`.`qty` < '3'
LEFT JOIN
`delivery_service` AS `service`
ON
`service`.`serviceID` = `band`.`serviceID`
WHERE
FIND_IN_SET( '225', `band`.`accepted_countries` )
AND
(
`band`.`min_qty` >= '3'
OR
`band`.`min_qty` = '0'
)
AND
(
`band`.`max_qty` <= '3'
OR
`band`.`max_qty` = '0'
)
GROUP BY
`service`.`serviceID`
I get this returned:
+------------------+-----+-----------+--------+----------------+----------+-------+-------------+
| name | qty | serviceID | bandID | initial_charge | chargeID | price | total_price |
+------------------+-----+-----------+--------+----------------+----------+-------+-------------+
| Royal mail | 0 | 1 | 4 | 2.00 | 3 | 1.00 | 2.00 |
| APC | 0 | 2 | 1 | 0.00 | 6 | 5.95 | 5.95 |
| Collect in store | 0 | 3 | 3 | 0.00 | 2 | 0.00 | 0.00 |
+------------------+-----+-----------+--------+----------------+----------+-------+-------------+
Which looks fine in principle until you realise that the chargeID = 3 has a price of 0.00 and yet the table is showing a price of 1.00 so the values seem to have become disassociated
What I would like to do is show the highest of the two royal mail entries
You can use MAX to obtain the maximum of a given column, e.g.
SELECT … MAX(charge.price) … FROM …
If you absolutely need the other columns (like charge.chargeID) to match, things will become a lot more complicated. So make sure you actually need that. For details on the general idea behind this kind of query, have a closer look at Select one value from a group based on order from other columns. Adapting this answer by #RichardTheKiwi, I came up with the following query:
SELECT s.name,
c.qty,
s.serviceID,
b.bandID,
b.initial_charge,
c.chargeID,
c.price,
b.initial_charge + c.price AS total_price
FROM delivery_band AS b,
delivery_service AS s,
(SELECT chargeID, price, qty,
#rowctr := IF(bandId = #lastBand, #rowctr+1, 1) AS rowNumber,
#lastBand := bandId AS bandId
FROM (SELECT #rowctr:=0, #lastBand:=null) init,
delivery_charge
WHERE qty < 3
ORDER BY bandId, price DESC
) AS c
WHERE FIND_IN_SET(225, b.accepted_countries)
AND (b.min_qty >= 3 OR B.min_qty = 0)
AND (b.max_qty <= 3 OR B.max_qty = 0)
AND s.serviceID = b.serviceID
AND c.bandID = b.bandID
AND c.rowNumber = 1
See this fiddle for the corresponding output. Note that I only do inner queries, not left queries, since that seems sufficient for the query in question, and keeps things a lot more readable so you can concentrate on the important parts, i.e. those involving rowNumber. The idea is that the subquery generates row numbers for the items of the same band, resetting them for the next band. When you select only rows with rowNumber being 1, you only get the highest price, with all other columns associated with that.