Sql Query to retrieve data using table ##
I need query to get the count of participants in each level .
Note: participant who is in level 4 should not be in other levels ex: Level 3,2,1
Table :
ID Level date
38 1 06 -05
38 2 08 -05
38 3 12 -05
38 4 13 -05
39 1 13 -05
39 2 13 -05
40 1 12 -05
Needed Output:
Count Level
1 1
1 2
0 3
1 4
You can define an artadditional table (or create a subquery) which would return the 30 rows
e.g
(select now() as d
union
select date_sub(now(), interval 1 day) as d
union
select date_sub(now(), interval 2 day) as d
union
...
select date_sub(now(), interval 29 day) as d) all_dates_source
Then you can LEFT JOIN your query result to the all_dates_source
SELECT i,
Logindate2,
ifnull(Logindate2,0, Logins2) as Logins2
FROM (...) all_dates_source
LEFT JOIN (yourQueryHere) sourceQuery
on all_dates_source.d=sourceQuery.Logindate2
SELECT count(t2.ppt) as count,t1.Level as level
FROM courselevel t1
LEFT JOIN
(SELECT ppt,MAX(Level) as Level
FROM courselevel
GROUP BY ppt ) t2 on t1.ppt=t2.ppt and t1.Level=t2.Level
GROUP BY t1.Level
Related
Hello there are two tables
Interval
id
is_full
1
1
2
0
3
0
entry_penalty
interval_id
entry_id
amount
2
14
55
3
14
7
3
14
1
1
15
4
1
15
8
2
15
11
So i am trying to display Sum of all entry_penalties per interval, twist is even if there is no relation between entry_penalty and interval table i should display full course interval sum per entry_id (related to is_full field).
For example total results should be in this case
interval_id
entry_id
amount
1
14
63
2
14
55
3
14
8
1
15
23
2
15
11
I have tried with sub query but it ignores to do calculation when there is no relation between entry_penalties and interval tables regarding is_full column.
My code so far.
SELECT
ep.interval_id,
IF (
i.is_full,
(
SELECT SUM(ep2.amount) * 1000 FROM entry_penalty as ep2
WHERE ep2.entry_id = ep.entry_id
),
SUM(ep.amount) * 1000
) as penalty_time,
ep.entry_id
FROM entry_penalty ep
INNER JOIN \`interval\` i ON i.id = ep.interval_id
WHERE ep.entry_id IN (:entryIds)
GROUP BY interval_id, entry_id`
I would propose to deal with the two cases (full, not full) separately, and then use union all to combine the two results:
SELECT i.id, ep.entry_id, SUM(ep.amount)
FROM `interval` i,
entry_penalty ep
WHERE i.is_full
GROUP BY i.id, ep.entry_id
UNION ALL
SELECT i.id, ep.entry_id, SUM(ep.amount)
FROM entry_penalty ep
INNER JOIN `interval` i
ON ep.interval_id = i.id
AND NOT i.is_full
GROUP BY i.id, ep.entry_id
ORDER BY 2, 1
See it run on dbfiddle.uk, where it outputs:
id
entry_id
SUM(ep.amount)
1
14
63
2
14
55
3
14
8
1
15
23
2
15
11
I have 3 tables that I have joined in the MySQL query below. All works well EXCEPT I would like the timeadj value with a 1 in column countingtime
to show from table 'data', not the first timeadj value the query finds.
I know this needs to be a query within a query but I am going around in circles and getting no where.
SELECT ttt_entries.tttid, ttt_teams.teamname, data.RacersInTeam,
ttt_entries.CoffeeClass, SEC_TO_TIME(data.timeadj),
COUNT(IF(data.division=5,1,NULL)) 'A+',
COUNT(IF(data.division=10,1,NULL)) A,
COUNT(IF(data.division=20,1,NULL)) B,
COUNT(IF(data.division=30,1,NULL)) C,
COUNT(IF(data.division=40,1,NULL)) D
FROM ttt_entries
INNER JOIN ttt_teams
ON ttt_entries.tttid = ttt_teams.tttid
INNER JOIN (SELECT * FROM data ORDER BY data.countingtime DESC) as data
ON ttt_entries.tttid = data.teamid
WHERE ttt_entries.eventDate = DATE_ADD(CURDATE(), INTERVAL (IF(DAYOFWEEK(CURDATE()) >4, -5, 2) + DAYOFWEEK(CURDATE())) * -1 DAY) -- last Thursday
AND data.wtrlid = '22'
GROUP BY ttt_teams.tttid
ORDER BY data.timeadj ASC
For example.... In Team 1 (data.teamid=1) there are 8 time values in timeadj. In the adjacent column (countingtime) is a value either 1 or 0 but only ever 1x 1 per team.
Table ttt_entries
ID tttid CoffeeClass
1 23 Mocha
2 52 Espresso
3 6 Frappe
Table ttt_teams
tttid Name
6 Team A
23 Team 1
52 Team 2
Table 'data'
id wtrlid teamid timeadj countingtime division
1 22 23 3467.123 0 10
2 22 23 3467.125 0 20
3 22 23 3467.432 0 10
4 22 23 3469.000 1 10
5 22 23 3469.112 0 10
6 22 23 3468.987 0 5
My code brings back
tttid teamname RacersInTeam CoffeeClass Time A+ A B C D
23 Team 1 6 Mocha 3467.123 1 4 1 0 0
I need it to bring back the same data but a different time:
tttid teamname RacersInTeam CoffeeClass Time A+ A B C D
23 Team 1 6 Mocha 3469.000 1 4 1 0 0
You can try below way -
SELECT ttt_entries.tttid, ttt_teams.teamname, data.RacersInTeam,
ttt_entries.CoffeeClass, SEC_TO_TIME(max(case when countingtime=1 then data.timeadj end)),
COUNT(IF(data.division=5,1,NULL)) 'A+',
COUNT(IF(data.division=10,1,NULL)) A,
COUNT(IF(data.division=20,1,NULL)) B,
COUNT(IF(data.division=30,1,NULL)) C,
COUNT(IF(data.division=40,1,NULL)) D
FROM ttt_entries
INNER JOIN ttt_teams
ON ttt_entries.tttid = ttt_teams.tttid
INNER JOIN (SELECT * FROM data ORDER BY data.countingtime DESC) as data
ON ttt_entries.tttid = data.teamid
WHERE ttt_entries.eventDate = DATE_ADD(CURDATE(), INTERVAL (IF(DAYOFWEEK(CURDATE()) >4, -5, 2) + DAYOFWEEK(CURDATE())) * -1 DAY) -- last Thursday
AND data.wtrlid = '22'
GROUP BY ttt_teams.tttid
ORDER BY data.timeadj ASC
The table ShopOrder's columns include:
id shopid starttime endtime
1 123 2018-04-27 2018-04-28
2 234 2018-04-23 2018-04-30
3 189 2018-05-01 2018-05-30
4 321 2018-05-01 2018-05-29
I wan't to query for valid shop counts between two days and count by each day of latest month,the valid shop counts means the starttime<= $curDate <= endtime,and curDate is a variable of the each day of the leatest month.
Today is 2018-04-27，so the query result should be:
day count
2018-04-27 2
2018-04-26 1
2018-04-25 1
2018-04-24 1
2018-04-23 1
2018-04-22 0
2018-04-21 0
……………………………………
2018-03-26 0
how can i achieve this use MySQL?
Converting between start and end dates and a range of individual dates is a challenge in SQL because you probably don't have a table which contains a row for each day in the current month to join on.
You can fill a table with dates using logic from one of the answers in How to populate a table with a range of dates?.
Or, since the range you want to produce is quite short, you can just create it manually in your query. It isn't completely clear what you mean by "the latest month" since your example ranges from 26 April to 27 March, but if the last 30 days is reasonable enough, you can use UNION to create this list.
Comparing date ranges discusses how to test whether a date is in a particular range or not, so putting the two things together gives you something like
SELECT
DATE_SUB(DATE(NOW()), INTERVAL days_ago.days DAY) day,
COUNT(ShopOrder.id) count
FROM
(SELECT 0 days UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION
SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 UNION
SELECT 10 UNION SELECT 11 UNION SELECT 12 UNION SELECT 13 UNION SELECT 14 UNION
SELECT 15 UNION SELECT 16 UNION SELECT 17 UNION SELECT 18 UNION SELECT 19 UNION
SELECT 20 UNION SELECT 21 UNION SELECT 22 UNION SELECT 23 UNION SELECT 24 UNION
SELECT 25 UNION SELECT 26 UNION SELECT 27 UNION SELECT 28 UNION SELECT 29)
AS days_ago
LEFT JOIN ShopOrder
ON DATE_SUB(DATE(NOW()), INTERVAL days_ago.days DAY) <= ShopOrder.endtime
AND DATE_SUB(DATE(NOW()), INTERVAL days_ago.days DAY) >= ShopOrder.starttime
GROUP BY days_ago.days;
Currently I am honestly at loss what I am doing wrong. It is a rather simple query I think.
Tables:
operations:
id processedon clientid
1 2018-01-01 9
2 2018-03-16 9
3 2018-04-21 9
4 2018-04-20 9
5 2018-05-09 9
items:
id operation_id quantity unitprice
1 1 10 2
2 1 5 3
3 2 20 4
4 3 10 2
5 4 8 4
6 4 10 4
7 5 2 2
The expected result of the operation/query is:
month total_value
1 35
3 80
4 92
5 4
That is quantity * unitprice based. For some reason, it only returns month=4
SELECT
month(`operations`.`processedon`) AS `month`,
SUM((`items`.`quantity` * `items`.`unitprice`)) AS `total_value`
FROM `items`
INNER JOIN `operations` ON (`items`.`operation_id` = `operations`.`id`)
GROUP BY 'month'
ORDER BY 'month'
According to the info provided the join should be
INNER JOIN operations ON items.operation_id = operations.id
Eg
SELECT
month(`operations`.`processedon`) AS `month`,
SUM((`items`.`quantity` * `items`.`unitprice`)) AS `total_value`
FROM `items`
INNER JOIN `operations` ON `items`.`operation_id` = `operations`.`id`
GROUP BY month(`operations`.`processedon`)
ORDER BY `month`
There is no efficiency gain by using a column alias in the group by clause, I prefer to avoid using them except perhaps in the order by clause.
The following query will give you the required answer
SELECT
month(`operations`.`processedon`) AS `month`,
SUM((`items`.`quantity` * `items`.`unitprice`)) AS `total_value`
FROM items
INNER JOIN operations ON (items.operation_id = operations.id)
GROUP BY month(operations.processedon)
ORDER BY month(operations.processedon)
You need to specify month correctly since it is not an existing column.
You'll get the following result
month total_value
1 35
3 80
4 92
5 4
I have two tables e_sku and e_availability, In e_sku table i have 45 rows with the default availability as 1, below is an example
id is_available name
1 1 UN001N
2 1 UN002N
3 1 UN003N
4 1 UN004N
5 1 UN005N
6 1 UN006N
7 1 UN007N
8 1 UN008N
9 1 UN009N
10 1 UN010N
11 1 UN011N
12 1 UN012N
13 1 UN013N
14 1 UN014N
15 1 UN015N
16 1 UN016N
17 1 UN017N
18 1 UN018N
19 1 UN019N
20 1 UN020N
21 1 UN021N
22 1 UN022N
23 1 UN023N
24 1 UN024N
25 1 UN025N
26 1 UN026N
27 1 UN027N
28 1 UN028N
29 1 UN029N
30 1 UN030N
31 1 UN031N
32 1 UN032N
33 1 UN033N
34 1 UN034N
35 1 UN035N
36 1 UN036N
37 1 UN037N
38 1 UN038N
39 1 UN039N
40 1 UN040N
41 1 UN041N
42 1 UN042N
43 1 UN043N
44 1 UN044N
45 1 UN045N
Second table is e_availability in this table i am only storing the unavailability with dates below is the example
id e_sku_id is_available working_date
1 5 0 10/20/2016
2 8 0 10/20/2016
3 10 0 10/20/2016
4 1 0 10/20/2016
5 15 0 10/20/2016
6 11 0 10/19/2016
7 1 0 10/19/2016
Because the data is capturing every date for unavailability so i am only gathering the unavailable product's data in e_availability table w.r.t. dates, Now i am looking to show the data for each day as complete skus in such a way that every day report will show 45 skus and for available sku it will show 1 from e_sku table's column is_available and for unavailable sku it will show the column of is_availability from e_availability table
I am using mysql database, I tried many join queries but not getting the report.
can any one guide about which join i require
I got the result by using this query
SELECT * FROM (SELECT id,NAME,1 AS is_available FROM e_sku
WHERE company_id = 2
AND id NOT IN (SELECT id FROM (SELECT e_sku.id,e_sku.name, edge_availability.is_available FROM edge_availability
JOIN edge_working ON edge_working.`id` = edge_availability.`working_id`
JOIN e_sku ON e_sku.id = edge_availability.`sku_id`
WHERE edge_working.`working_date` = '2016-10-19' AND edge_availability.`store_id` = 84) X)
UNION
SELECT e_sku.id,e_sku.name, edge_availability.is_available FROM edge_availability
JOIN edge_working ON edge_working.`id` = edge_availability.`working_id`
JOIN e_sku ON e_sku.id = edge_availability.`sku_id`
WHERE edge_working.`working_date` = '2016-10-19' AND edge_availability.`store_id` = 84) Y
ORDER BY id
You can use a LEFT JOIN to detect when a date isn't found in the e_availability table. The join will return NULL for all the columns in that table, then you can default to the value from e_sku.
SELECT d.date, s.id, IFNULL(a.is_available, s.is_available) AS is_available
FROM all_dates AS d
CROSS JOIN e_sku AS s
LEFT JOIN e_availability ON d.working_date = a.date AND s.id = a.e_sku_id
You need to create an additional table all_dates that contains all the dates that you want to report on. See What is the most straightforward way to pad empty dates in sql results (on either mysql or perl end)? for how you can create such a table dynamically.